Pandas read_excel with Hyperlink - excel

Question

I have an Excel spreadsheet that I am reading into a Pandas DataFrame:
df = pd.read_excel("file.xls")
However, one of the columns of the spreadsheet contains text which have a hyperlink associated with it. How do I access the underlying hyperlink in Pandas?

Answer 1

This can be done with openpyxl, I'm not sure its possible with Pandas at all. Here's how I've done it:
import openpyxl
wb = openpyxl.load_workbook('yourfile.xlsm')
ws = wb.get_sheet_by_name('Sheet1')
print(ws.cell(row=2, column=1).hyperlink.target)
You can also use iPython, and set a variable equal to the hyperlink object:
t = ws.cell(row=2, column=1).hyperlink
then do t. and press tab to see all the options for what you can do with or access from the object.

Answer 2

Quick monkey patching, without converters or anything like this, if you would like to treat ALL cells with hyperlinks as hyperlinks, more sophisticated way, I suppose, at least be able to choose, what columns treat as hyperlinked or gather data, or save somehow both data and hyperlink in same cell at dataframe. And using converters, dunno. (BTW I played also with data_only, keep_links, did not helped, only changing read_only resulted ok, I suppose it can slow down your code speed).
P.S.: Works only with xlsx, i.e., engine is openpyxl
P.P.S.: If you reading this comment in the future and issue https://github.com/pandas-dev/pandas/issues/13439 still Open, don't forget to see changes in _convert_cell and load_workbook at pandas.io.excel._openpyxl and update them accordingly.
import pandas
from pandas.io.excel._openpyxl import OpenpyxlReader
import numpy as np
from pandas._typing import FilePathOrBuffer, Scalar
def _convert_cell(self, cell, convert_float: bool) -> Scalar:
from openpyxl.cell.cell import TYPE_BOOL, TYPE_ERROR, TYPE_NUMERIC
# here we adding this hyperlink support:
if cell.hyperlink and cell.hyperlink.target:
return cell.hyperlink.target
# just for example, you able to return both value and hyperlink,
# comment return above and uncomment return below
# btw this may hurt you on parsing values, if symbols "|||" in value or hyperlink.
# return f'{cell.value}|||{cell.hyperlink.target}'
# here starts original code, except for "if" became "elif"
elif cell.is_date:
return cell.value
elif cell.data_type == TYPE_ERROR:
return np.nan
elif cell.data_type == TYPE_BOOL:
return bool(cell.value)
elif cell.value is None:
return "" # compat with xlrd
elif cell.data_type == TYPE_NUMERIC:
# GH5394
if convert_float:
val = int(cell.value)
if val == cell.value:
return val
else:
return float(cell.value)
return cell.value
def load_workbook(self, filepath_or_buffer: FilePathOrBuffer):
from openpyxl import load_workbook
# had to change read_only to False:
return load_workbook(
filepath_or_buffer, read_only=False, data_only=True, keep_links=False
)
OpenpyxlReader._convert_cell = _convert_cell
OpenpyxlReader.load_workbook = load_workbook
And after adding this above in your python file, you will be able to call df = pandas.read_excel(input_file)
After writing all this stuff it came to me, that maybe it would be easier and cleaner just use openpyxl by itself ^_^

Answer 3

as commented by slaw it doesnt grab the hyperlink but only the text
here text.xlsx contains links in the 9th column
from openpyxl import load_workbook
workbook = load_workbook('test.xlsx')
worksheet = workbook.active
column_indices = [9]
for row in range(2, worksheet.max_row + 1):
for col in column_indices:
filelocation = worksheet.cell(column=col, row=row) # this is hyperlink
text = worksheet.cell(column=col + 1, row=row) # thi is your text
worksheet.cell(column=col + 1, row=row).value = '=HYPERLINK("' + filelocation.value + '","' + text.value + '")'
workbook.save('test.xlsx')

Answer 4

You cannot do that in pandas. You can try with other libraries designed to deal with excel files.