randomly rotate objects in adobe illustrator - object

How to randomly rotate objects in Adobe illustrator. I wanted to ask you that how I could rotate many selected objects which are at the same angle and rotate them at random angle.
Script for adobe illustrator in javascript.

Your selected objects it's just an array in Document.selection, so:
var min = Number(prompt("Minimum angle?","0"));
var max = Number(prompt("Maximum angle?","360"));
for(var i in activeDocument.selection){
var angle = Math.floor(Math.random() * (max - min + 1)) + min;
activeDocument.selection[i].rotate(angle);
}

Related

How to stretch geometry so its bounding box fits precisely the screen in Three.js

I am looking for the way of stretching a geometry (with all vertices z = 0) into visible screen (HTML Canvas Element).
For now I have worked out how to fit the geometry to the screen, like this:
with following code that basically adjusts camera.z to fit geometry to the height of canvas.
geometry.computeBoundingBox();
const bbox = geometry.boundingBox;
const geometryCenter = bbox.getCenter(new THREE.Vector3());
const geometrySize = bbox.getSize(new THREE.Vector3())
const cameraZ = getZFromGeometrySize(camera.fov, geometrySize);
const scale = getScaleFromZ(height, camera.fov, cameraZ);
const zoomTransform = d3.zoomIdentity
.translate(width * 0.5, height * 0.5)
.scale(scale);
zoom.transform(canvasSelection, zoomTransform);
camera.position.set(geometryCenter.x, geometryCenter.y, cameraZ)
camera.updateProjectionMatrix();
with below definitions of functions:
function getZFromGeometrySize(fov, geometrySize) {
const maxSize = Math.max( geometrySize.x, geometrySize.y );
const halfFOVRadians = toRadians(fov * 0.5);
return maxSize / ( 2 * Math.tan( halfFOVRadians ) );
}
function getScaleFromZ (height, fov, z) {
const halfFOVRadians = toRadians(fov * 0.5);
return height / (2 * Math.tan(halfFOVRadians) * z);
}
This however is using camera position so geometry will fit the view. However, I am looking for the way to stretch the geometry so its bounding box precisely fits the screen, ideally with some predefined padding.
Since this is not related to camera settings I need to manipulate geometry vertices values to stretch it horizontally. How to achieve this? I want to retain values of vertices as they relate to underlying data.
I assume this would need to be a function of canvas dimensions (width, height), geometry coordinates, and camera settings returning new geometry coordinates? Any hint is appreciated.
A short answer to this question is: to set camera's aspect ratio to 1.0.
This will work if geometry bounds are in clip space already [-1, 1 ]. If not they have to be converted to clip space first.

two meshes, same texture, different offset?

Using three.js, I'm working on a web page to display a flip cube (a.k.a. magic cube; see e.g. the video on this page).
On a flip cube, there are typically images that are spread out across multiple pieces of the cube. For example, the boat image shown above is spread across the faces of four cubelets. In three.js terms, there are multiple meshes that need to use the same image for their material texture, but each at a different offset.
As far as I understand it, in three.js, offset is a property of a texture, not of a material or a mesh. Therefore, it would appear that you cannot have a single texture that is used at a different offset in two different places.
So does that mean that in order to have different parts of the boat image shown on four different faces, I have to create four separate textures, meaning that we load the boat image into memory four times? I'm hoping that's not the case.
Here's a relevant piece of the code:
// create an array with the textures
var textureArray = [];
var texNames = ['boat', 'camels', 'elephants', 'hippo',
'natpark', 'ostrich', 'coatofarms-w', 'kenyamap-w', 'nairobi-w'];
texNames.map(function(texName) {
textureArray.push(THREE.ImageUtils.loadTexture(
'images/256/' + texName + '.jpg' ));
});
// Create a material for each texture.
for (var x=0; x <= 1; x++) {
for (var y=0; y <= 1; y++) {
for (var z=0; z <= 1; z++) {
var materialArray = [];
textureArray.map(function(tex) {
// Learned: cannot set this offset for one material,
// without it affecting all materials that use this texture.
tex.offset.x = x * 0.2;
tex.offset.y = y * 0.2;
materialArray.push(new THREE.MeshBasicMaterial( { map: tex }));
});
var cubeMaterial = new THREE.MeshFaceMaterial(materialArray.slice(0, 6));
var cube = new THREE.Mesh( cubeGeom, cubeMaterial );
cube.position.set(x * 50 - 25, y * 50 - 25, z * 50 - 25);
scene.add(cube);
}
}
}
If you look at it on http://www.huttar.net/lars-kathy/tmp/flipcube.html, you'll see that all the texture images are displayed offset by the same amount on each cubelet face, even though they are set to different offsets on different cubelets. This seems to confirm that you can't have different uses of the same texture with different offsets.
How can I get different meshes to use the same texture at different offsets, so I don't have to load the same image multiple times into multiple textures?
What you say is true. Instead of adjusting the texture offsets, adjust the face vertex UVs of the geometry.
EDIT: There is another solution more in line with what you want to do. You can clone a texture like so:
var tex = new THREE.Texture.clone();
Cloning a texture will result in the loaded image being reused, and the new texture can have it's own offsets. Do not try to clone the texture until the image loads, however.
With this alternate approach, you do not have to adjust UVs, and you do not have to load an image more than once.
three.js r.58

How to avoid the overlapping of text elements on the TreeMap when child elements are opened in D3.js?

I created a Tree in D3.js based on Mike Bostock's Node-link Tree. The problem I have and that I also see in Mike's Tree is that the text label overlap/underlap the circle nodes when there isn't enough space rather than extend the links to leave some space.
As a new user I'm not allowed to upload images, so here is a link to Mike's Tree where you can see the labels of the preceding nodes overlapping the following nodes.
I tried various things to fix the problem by detecting the pixel length of the text with:
d3.select('.nodeText').node().getComputedTextLength();
However this only works after I rendered the page when I need the length of the longest text item before I render.
Getting the longest text item before I render with:
nodes = tree.nodes(root).reverse();
var longest = nodes.reduce(function (a, b) {
return a.label.length > b.label.length ? a : b;
});
node = vis.selectAll('g.node').data(nodes, function(d, i){
return d.id || (d.id = ++i);
});
nodes.forEach(function(d) {
d.y = (longest.label.length + 200);
});
only returns the string length, while using
d.y = (d.depth * 200);
makes every link a static length and doesn't resize as beautiful when new nodes get opened or closed.
Is there a way to avoid this overlapping? If so, what would be the best way to do this and to keep the dynamic structure of the tree?
There are 3 possible solutions that I can come up with but aren't that straightforward:
Detecting label length and using an ellipsis where it overruns child nodes. (which would make the labels less readable)
scaling the layout dynamically by detecting the label length and telling the links to adjust accordingly. (which would be best but seems really difficult
scale the svg element and use a scroll bar when the labels start to run over. (not sure this is possible as I have been working on the assumption that the SVG needs to have a set height and width).
So the following approach can give different levels of the layout different "heights". You have to take care that with a radial layout you risk not having enough spread for small circles to fan your text without overlaps, but let's ignore that for now.
The key is to realize that the tree layout simply maps things to an arbitrary space of width and height and that the diagonal projection maps width (x) to angle and height (y) to radius. Moreover the radius is a simple function of the depth of the tree.
So here is a way to reassign the depths based on the text lengths:
First of all, I use the following (jQuery) to compute maximum text sizes for:
var computeMaxTextSize = function(data, fontSize, fontName){
var maxH = 0, maxW = 0;
var div = document.createElement('div');
document.body.appendChild(div);
$(div).css({
position: 'absolute',
left: -1000,
top: -1000,
display: 'none',
margin:0,
padding:0
});
$(div).css("font", fontSize + 'px '+fontName);
data.forEach(function(d) {
$(div).html(d);
maxH = Math.max(maxH, $(div).outerHeight());
maxW = Math.max(maxW, $(div).outerWidth());
});
$(div).remove();
return {maxH: maxH, maxW: maxW};
}
Now I will recursively build an array with an array of strings per level:
var allStrings = [[]];
var childStrings = function(level, n) {
var a = allStrings[level];
a.push(n.name);
if(n.children && n.children.length > 0) {
if(!allStrings[level+1]) {
allStrings[level+1] = [];
}
n.children.forEach(function(d) {
childStrings(level + 1, d);
});
}
};
childStrings(0, root);
And then compute the maximum text length per level.
var maxLevelSizes = [];
allStrings.forEach(function(d, i) {
maxLevelSizes.push(computeMaxTextSize(allStrings[i], '10', 'sans-serif'));
});
Then I compute the total text width for all the levels (adding spacing for the little circle icons and some padding to make it look nice). This will be the radius of the final layout. Note that I will use this same padding amount again later on.
var padding = 25; // Width of the blue circle plus some spacing
var totalRadius = d3.sum(maxLevelSizes, function(d) { return d.maxW + padding});
var diameter = totalRadius * 2; // was 960;
var tree = d3.layout.tree()
.size([360, totalRadius])
.separation(function(a, b) { return (a.parent == b.parent ? 1 : 2) / a.depth; });
Now we can call the layout as usual. There is one last piece: to figure out the radius for the different levels we will need a cumulative sum of the radii of the previous levels. Once we have that we simply assign the new radii to the computed nodes.
// Compute cummulative sums - these will be the ring radii
var newDepths = maxLevelSizes.reduce(function(prev, curr, index) {
prev.push(prev[index] + curr.maxW + padding);
return prev;
},[0]);
var nodes = tree.nodes(root);
// Assign new radius based on depth
nodes.forEach(function(d) {
d.y = newDepths[d.depth];
});
Eh voila! This is maybe not the cleanest solution, and perhaps does not address every concern, but it should get you started. Have fun!

Resize image to one resolution

I have a bunch of images, with different resolution.
Also there is a mix of landscape and portrait pictures. I need to resize the images to one resolution (1024x768). If i have a portrait picture, the max height needs to be 768, and my landscape pictures has to have a max width of 1024.
The space that is over, has to be made black.
Right now i use mogrify -resize 1024x768 -verbose *.jpg
I know i can use 1024x!768 , but like i said i'm using different kind of pictures.
My exif information also doesn't contains information about if a picture is landscape or not.
I use ImageMagick for such tasks. When installed, you have the "convert" command, which is very common, and does your task easyly.
You will have to crop the image to get the same aspect ratio, then you can resize the image to get the desired resolution. Example code using nodejs (imagemagick command line tools):
var width = 166;
var height = 117;
var ratio_new = width/height;
var ratio_old = image_file.width_orig/image_file.height_orig;
var pixels_too_much = 0;
var geometry = '';
if (ratio_old > ratio_new)
{
config.debug && console.log ("remove horizontal pixel!");
pixels_too_much = parseInt(image_file.width_orig - (image_file.height_orig * ratio_new))-1;
geometry = parseInt(image_file.height_orig * ratio_new + 0.5) + 'x' + image_file.height_orig;
geometry += "+" + parseInt(pixels_too_much/2) + "+0\!";
}
else if (ratio_old < ratio_new)
{
config.debug && console.log ("remove vertikal pixel");
pixels_too_much = parseInt(image_file.height_orig - (image_file.width_orig / ratio_new));
geometry = image_file.width_orig + 'x' + (image_file.width_orig / ratio_new);
geometry += "+0+" + parseInt(pixels_too_much/2)+"\!";
}
im.convert([image_file.path, '-crop', geometry, '-resize', width + 'x' + height, thumb_path],function(){});

Rotating an Image in Silverlight without cropping

I am currently working on a simple Silverlight app that will allow people to upload an image, crop, resize and rotate it and then load it via a webservice to a CMS.
Cropping and resizing is done, however rotation is causing some problems. The image gets cropped and is off centre after the rotation.
WriteableBitmap wb = new WriteableBitmap(destWidth, destHeight);
RotateTransform rt = new RotateTransform();
rt.Angle = 90;
rt.CenterX = width/2;
rt.CenterY = height/2;
//Draw to the Writeable Bitmap
Image tempImage2 = new Image();
tempImage2.Width = width;
tempImage2.Height = height;
tempImage2.Source = rawImage;
wb.Render(tempImage2,rt);
wb.Invalidate();
rawImage = wb;
message.Text = "h:" + rawImage.PixelHeight.ToString();
message.Text += ":w:" + rawImage.PixelWidth.ToString();
//Finally set the Image back
MyImage.Source = wb;
MyImage.Width = destWidth;
MyImage.Height = destHeight;
The code above only needs to rotate by 90° at this time so I'm just setting destWidth and destHeight to the height and width of the original image.
It looks like your target image is the same size as your source image. If you want to rotate over 90 degrees, your width and height should be exchanged:
WriteableBitmap wb = new WriteableBitmap(destHeight, destWidth);
Also, if you rotate about the centre of the original image, part of it will end up outside the boundaries. You could either include some translation transforms, or simply rotate the image about a different point:
rt.CenterX = rt.CenterY = Math.Min(width / 2, height / 2);
Try it with a piece of rectangular paper to see why that makes sense.
Many thanks to those above.. they helped a lot. I include here a simple example which includes the additional transform necessary to move the rotated image back to the top left corner of the result.
int width = currentImage.PixelWidth;
int height = currentImage.PixelHeight;
int full = Math.Max(width, height);
Image tempImage2 = new Image();
tempImage2.Width = full;
tempImage2.Height = full;
tempImage2.Source = currentImage;
// New bitmap has swapped width/height
WriteableBitmap wb1 = new WriteableBitmap(height,width);
TransformGroup transformGroup = new TransformGroup();
// Rotate around centre
RotateTransform rotate = new RotateTransform();
rotate.Angle = 90;
rotate.CenterX = full/2;
rotate.CenterY = full/2;
transformGroup.Children.Add(rotate);
// and transform back to top left corner of new image
TranslateTransform translate = new TranslateTransform();
translate.X = -(full - height) / 2;
translate.Y = -(full - width) / 2;
transformGroup.Children.Add(translate);
wb1.Render(tempImage2, transformGroup);
wb1.Invalidate();
If the image isn't square you will get cropping.
I know this won't give you exactly the right result, you'll need to crop it afterwards, but it will create a bitmap big enough in each direction to take the rotated image.
//Draw to the Writeable Bitmap
Image tempImage2 = new Image();
tempImage2.Width = Math.Max(width, height);
tempImage2.Height = Math.Max(width, height);
tempImage2.Source = rawImage;
You need to calculate the scaling based on the rotation of the corners relative to the centre.
If the image is a square only one corner is needed, but for a rectangle you need to check 2 corners in order to see if a vertical or horizontal edge is overlapped. This check is a linear comparison of how much the rectangle's height and width are exceeded.
Click here for the working testbed app created for this answer (image below):
double CalculateConstraintScale(double rotation, int pixelWidth, int pixelHeight)
The pseudo-code is as follows (actual C# code at the end):
Convert rotation angle into Radians
Calculate the "radius" from the rectangle centre to a corner
Convert BR corner position to polar coordinates
Convert BL corner position to polar coordinates
Apply the rotation to both polar coordinates
Convert the new positions back to Cartesian coordinates (ABS value)
Find the largest of the 2 horizontal positions
Find the largest of the 2 vertical positions
Calculate the delta change for horizontal size
Calculate the delta change for vertical size
Return width/2 / x if horizontal change is greater
Return height/2 / y if vertical change is greater
The result is a multiplier that will scale the image down to fit the original rectangle regardless of rotation.
**Note: While it is possible to do much of the maths using matrix operations, there are not enough calculations to warrant that. I also thought it would make a better example from first-principles.*
C# Code:
/// <summary>
/// Calculate the scaling required to fit a rectangle into a rotation of that same rectangle
/// </summary>
/// <param name="rotation">Rotation in degrees</param>
/// <param name="pixelWidth">Width in pixels</param>
/// <param name="pixelHeight">Height in pixels</param>
/// <returns>A scaling value between 1 and 0</returns>
/// <remarks>Released to the public domain 2011 - David Johnston (HiTech Magic Ltd)</remarks>
private double CalculateConstraintScale(double rotation, int pixelWidth, int pixelHeight)
{
// Convert angle to radians for the math lib
double rotationRadians = rotation * PiDiv180;
// Centre is half the width and height
double width = pixelWidth / 2.0;
double height = pixelHeight / 2.0;
double radius = Math.Sqrt(width * width + height * height);
// Convert BR corner into polar coordinates
double angle = Math.Atan(height / width);
// Now create the matching BL corner in polar coordinates
double angle2 = Math.Atan(height / -width);
// Apply the rotation to the points
angle += rotationRadians;
angle2 += rotationRadians;
// Convert back to rectangular coordinate
double x = Math.Abs(radius * Math.Cos(angle));
double y = Math.Abs(radius * Math.Sin(angle));
double x2 = Math.Abs(radius * Math.Cos(angle2));
double y2 = Math.Abs(radius * Math.Sin(angle2));
// Find the largest extents in X & Y
x = Math.Max(x, x2);
y = Math.Max(y, y2);
// Find the largest change (pixel, not ratio)
double deltaX = x - width;
double deltaY = y - height;
// Return the ratio that will bring the largest change into the region
return (deltaX > deltaY) ? width / x : height / y;
}
Example of use:
private WriteableBitmap GenerateConstrainedBitmap(BitmapImage sourceImage, int pixelWidth, int pixelHeight, double rotation)
{
double scale = CalculateConstraintScale(rotation, pixelWidth, pixelHeight);
// Create a transform to render the image rotated and scaled
var transform = new TransformGroup();
var rt = new RotateTransform()
{
Angle = rotation,
CenterX = (pixelWidth / 2.0),
CenterY = (pixelHeight / 2.0)
};
transform.Children.Add(rt);
var st = new ScaleTransform()
{
ScaleX = scale,
ScaleY = scale,
CenterX = (pixelWidth / 2.0),
CenterY = (pixelHeight / 2.0)
};
transform.Children.Add(st);
// Resize to specified target size
var tempImage = new Image()
{
Stretch = Stretch.Fill,
Width = pixelWidth,
Height = pixelHeight,
Source = sourceImage,
};
tempImage.UpdateLayout();
// Render to a writeable bitmap
var writeableBitmap = new WriteableBitmap(pixelWidth, pixelHeight);
writeableBitmap.Render(tempImage, transform);
writeableBitmap.Invalidate();
return writeableBitmap;
}
I released a Test-bed of the code on my website so you can try it for real - click to try it
P.S. Yes this is my answer from another question, duplicated exactly, but the question does require the same answer as that one to be complete.

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