puppet, what is the difference between '=' and '=>' - puppet

Seriously, what's the difference between '=' and '=>'?
They both look and feel like variable binding operators.
Also, why does one require a comma after each declaration,
and the other generates a syntax error when it finds a comma?

= is used to assign a value to a variable, e.g.
$foo = 'bar'
There are some advanced ways to assign variables in Puppet 4, but generally speaking whenever it's a $variable on the left hand side of the expression, add no comma and always use =. Further variable assignments are simply separated by new lines.
=> is a key-value separator in hashes or lists of attributes in resources:
{
'foo' => 'bar',
'bar' => 'baz',
}
or
file { '/etc/foo.conf':
ensure => present,
content => 'bar',
}
Note that foo, bar, ensure and content are not variables themselves - they're keys in a hash or attributes.
You'll find a similar design in many languages, e.g. Perl.

Related

element => command in Terraform

I see a code as below in https://github.com/terraform-aws-modules/terraform-aws-efs/blob/master/examples/complete/main.tf#L58
# Mount targets / security group
mount_targets = { for k, v in toset(range(length(local.azs))) :
element(local.azs, k) => { subnet_id = element(module.vpc.private_subnets, k) }
}
I am trying to understand what => means here. Also this command with for loop, element and =>.
Could anyone explain here please?
In this case the => symbol isn't an independent language feature but is instead just one part of the for expression syntax when the result will be a mapping.
A for expression which produces a sequence (a tuple, to be specific) has the following general shape:
[
for KEY_SYMBOL, VALUE_SYMBOL in SOURCE_COLLECTION : RESULT
if CONDITION
]
(The KEY_SYMBOL, portion and the if CONDITION portion are both optional.)
The result is a sequence of values that resulted from evaluating RESULT (an expression) for each element of SOURCE_COLLECTION for which CONDITION (another expression) evaluated to true.
When the result is a sequence we only need to specify one result expression, but when the result is a mapping (specifically an object) we need to specify both the keys and the values, and so the mapping form has that additional portion including the => symbol you're asking about:
{
for KEY_SYMBOL, VALUE_SYMBOL in SOURCE_COLLECTION : KEY_RESULT => VALUE_RESULT
if CONDITION
}
The principle is the same here except that for each source element Terraform will evaluate both KEY_RESULT and VALUE_RESULT in order to produce a key/value pair to insert into the resulting mapping.
The => marker here is just some punctuation so that Terraform can unambiguously recognize where the KEY_RESULT ends and where the VALUE_RESULT begins. It has no special meaning aside from being a delimiter inside a mapping-result for expression. You could think of it as serving a similar purpose as the comma between KEY_SYMBOL and VALUE_SYMBOL; it has no meaning of its own, and is only there to mark the boundary between two clauses of the overall expression.
When I read a for expression out loud, I typically pronounce => as "maps to". So with my example above, I might pronounce it as "for each key and value in source collection, key result maps to value result if the condition is true".
Lambda expressions use the operator symbol =, which reads as "goes to." Input parameters are specified on the operator's left side, and statement/expressions are specified on the right. Generally, lambda expressions are not directly used in query syntax but are often used in method calls. Query expressions may contain method calls.
Lambda expression syntax features are as follows:
It is a function without a name.
There are no modifiers, such as overloads and overrides.
The body of the function should contain an expression, rather than a statement.
May contain a call to a function procedure but cannot contain a call to a subprocedure.
The return statement does not exist.
The value returned by the function is only the value of the expression contained in the function body.
The End function statement does not exist.
The parameters must have specified data types or be inferred.
Does not allow generic parameters.
Does not allow optional and ParamArray parameters.
Lambda expressions provide shorthand for the compiler, allowing it to emit methods assigned to delegates.
The compiler performs automatic type inference on the lambda arguments, which is a key advantage.

Can I unstring a literal in a macro?

I want to make a macro that does this
mac1!("foo", x)
emits
foo(x)
is it even possible?
No, it's not possible. By the time the macro is expanded, the matching is done on the fact that "foo" is an expression (or a literal). The compiler does not distinguish between an expression like "foo" in your example and 123u8, 1 + 2, foo() or { let f = fs::read("foo.txt"); ... } as all of those are expressions. All the macro-by-example knows is that the first parameter is any kind of valid expression and it can't look deeper into it, because the compiler doesn't know what a "type" or a "value" is at this point.
You can use a procedural macro, which can use a parameter's value to generate new tokens, including identifiers.

Understanding Raku's `&?BLOCK` compile-time variable

I really appreciate the Raku's &?BLOCK variable – it lets you recurse within an unnamed block, which can be extremely powerful. For example, here's a simple, inline, and anonymous factorial function:
{ when $_ ≤ 1 { 1 };
$_ × &?BLOCK($_ - 1) }(5) # OUTPUT: «120»
However, I have some questions about it when used in more complex situations. Consider this code:
{ say "Part 1:";
my $a = 1;
print ' var one: '; dd $a;
print ' block one: '; dd &?BLOCK ;
{
my $a = 2;
print ' var two: '; dd $a;
print ' outer var: '; dd $OUTER::a;
print ' block two: '; dd &?BLOCK;
print "outer block: "; dd &?OUTER::BLOCK
}
say "\nPart 2:";
print ' block one: '; dd &?BLOCK;
print 'postfix for: '; dd &?BLOCK for (1);
print ' prefix for: '; for (1) { dd &?BLOCK }
};
which yields this output (I've shortened the block IDs):
Part 1:
var one: Int $a = 1
block one: -> ;; $_? is raw = OUTER::<$_> { #`(Block|…6696) ... }
var two: Int $a = 2
outer var: Int $a = 1
block two: -> ;; $_? is raw = OUTER::<$_> { #`(Block|…8496) ... }
outer block: -> ;; $_? is raw = OUTER::<$_> { #`(Block|…8496) ... }
Part 2:
block one: -> ;; $_? is raw = OUTER::<$_> { #`(Block|…6696) ... }
postfix for: -> ;; $_ is raw { #`(Block|…9000) ... }
prefix for: -> ;; $_ is raw { #`(Block|…9360) ... }
Here's what I don't understand about that: why does the &?OUTER::BLOCK refer (based on its ID) to block two rather than block one? Using OUTER with $a correctly causes it to refer to the outer scope, but the same thing doesn't work with &?BLOCK. Is it just not possible to use OUTER with &?BLOCK? If not, is there a way to access the outer block from the inner block? (I know that I can assign &?BLOCK to a named variable in the outer block and then access that variable in the inner block. I view that as a workaround but not a full solution because it sacrifices the ability to refer to unnamed blocks, which is where much of &?BLOCK's power comes from.)
Second, I am very confused by Part 2. I understand why the &?BLOCK that follows the prefix for refers to an inner block. But why does the &?BLOCK that precedes the postfix for also refer to its own block? Is a block implicitly created around the body of the for statement? My understanding is that the postfix forms were useful in large part because they do not require blocks. Is that incorrect?
Finally, why do some of the blocks have OUTER::<$_> in the but others do not? I'm especially confused by Block 2, which is not the outermost block.
Thanks in advance for any help you can offer! (And if any of the code behavior shown above indicates a Rakudo bug, I am happy to write it up as an issue.)
That's some pretty confusing stuff you've encountered. That said, it does all make some kind of sense...
Why does the &?OUTER::BLOCK refer (based on its ID) to block two rather than block one?
Per the doc, &?BLOCK is a "special compile variable", as is the case for all variables that have a ? as their twigil.
As such it's not a symbol that can be looked up at run-time, which is what syntax like $FOO::bar is supposed to be about afaik.
So I think the compiler ought by rights reject use of a "compile variable" with the package lookup syntax. (Though I'm not sure. Does it make sense to do "run-time" lookups in the COMPILING package?)
There may already be a bug filed (in either of the GH repos rakudo/rakudo/issues or raku/old-issues-tracker/issues) about it being erroneous to try to do a run-time lookup of a special compile variable (the ones with a ? twigil). If not, it makes sense to me to file one.
Using OUTER with $a correctly causes it to refer to the outer scope
The symbol associated with the $a variable in the outer block is stored in the stash associated with the outer block. This is what's referenced by OUTER.
Is it just not possible to use OUTER with &?BLOCK?
I reckon not for the reasons given above. Let's see if anyone corrects me.
If not, is there a way to access the outer block from the inner block?
You could pass it as an argument. In other words, close the inner block with }(&?BLOCK); instead of just }. Then you'd have it available as $_ in the inner block.
Why does the &?BLOCK that precedes the postfix for also refer to its own block?
It is surprising until you know why, but...
Is a block implicitly created around the body of the for statement?
Seems so, so the body can take an argument passed by each iteration of the for.
My understanding is that the postfix forms were useful in large part because they do not require blocks.
I've always thought of their benefit as being that they A) avoid a separate lexical scope and B) avoid having to type in the braces.
Is that incorrect?
It seems so. for has to be able to supply a distinct $_ to its statement(s) (you can put a series of statements in parens), so if you don't explicitly write braces, it still has to create a distinct lexical frame, and presumably it was considered better that the &?BLOCK variable tracked that distinct frame with its own $_, and "pretended" that was a "block", and displayed its gist with a {...}, despite there being no explicit {...}.
Why do some of the blocks have OUTER::<$_> in them but others do not?
While for (and given etc) always passes an "it" aka $_ argument to its blocks/statements, other blocks do not have an argument automatically passed to them, but they will accept one if it's manually passed by the writer of code manually passing one.
To support this wonderful idiom in which one can either pass or not pass an argument, blocks other than ones that are automatically fed an $_ are given this default of binding $_ to the outer block's $_.
I'm especially confused by Block 2, which is not the outermost block.
I'm confused by you being especially confused by that. :) If the foregoing hasn't sufficiently cleared this last aspect up for you, please comment on what it is about this last bit that's especially confusing.
During compilation the compiler has to keep track of various things. One of which is the current block that it is compiling.
The block object gets stored in the compiled code wherever it sees the special variable $?BLOCK.
Basically the compile-time variables aren't really variables, but more of a macro.
So whenever it sees $?BLOCK the compiler replaces it with whatever the current block the compiler is currently compiling.
It just happens that $?OUTER::BLOCK is somehow close enough to $?BLOCK that it replaces that too.
I can show you that there really isn't a variable by that name by trying to look it up by name.
{ say ::('&?BLOCK') } # ERROR: No such symbol '&?BLOCK'
Also every pair of {} (that isn't a hash ref or hash index) denotes a new block.
So each of these lines will say something different:
{
say $?BLOCK.WHICH;
say "{ $?BLOCK.WHICH }";
if True { say $?BLOCK.WHICH }
}
That means if you declare a variable inside one of those constructs it is contained to that construct.
"{ my $a = "abc"; say $a }"; # abc
say $a; # COMPILE ERROR: Variable '$a' is not declared
if True { my $b = "def"; say $b } # def
say $b; # COMPILE ERROR: Variable '$b' is not declared
In the case of postfix for, the left side needs to be a lambda/closure so that for can set $_ to the current value.
It was probably just easier to fake it up to be a Block than to create a new Code type just for that use.
Especially since an entire Raku source file is also considered a Block.
A bare Block can have an optional argument.
my &foo;
given 5 {
&foo = { say $_ }
}
foo( ); # 5
foo(42); # 42
If you give it an argument it sets $_ to that value.
If you don't, $_ will point to whatever $_ was outside of that declaration. (Closure)
For many of the uses of that construct, doing that can be very handy.
sub call-it-a (&c){
c()
}
sub call-it-b (&c, $arg){
c( $arg * 10 )
}
for ^5 {
call-it-a( { say $_ } ); # 0␤ 1␤ 2␤ 3␤ 4␤
call-it-b( { say $_ }, $_ ); # 0␤10␤20␤30␤40␤
}
For call-it-a we needed it to be a closure over $_ to work.
For call-it-b we needed it to be an argument instead.
By having :( ;; $_? is raw = OUTER::<$_> ) as the signature it caters to both use-cases.
This makes it easy to create simple lambdas that just do what you want them to do.

Meaning for = in antlr4

I have a grammar like
rule1 : GO (count=DECIMAL)? ;
rule2 : name '=' expression
I dont understand the difference between '=' sign in rule1 and rule2
The assignment is a variable assignment. ANTLR4 will generate a member variable named count for you, which gets the DECIMAL token when matched (since it is optional, count might be empty/null).
You can use count for instance in your listener code to directly get that value, however you could also just use DECIMAL instead. So it's mostly useful for action code or predicates in your grammar. You can refer to such variables by using e.g. $count:
rule1: GO (count = DECIMAL)? { $count.toString().toInteger() < 4}?;
which matches only if GO is followed by a value less than 4.
Side note: toInteger() is just pseudo code here. Use your target's string-to-int conversion API.

Dropping various string variables in a loop in Stata

I want to a drop a great number of string variables that contain the word "Other" in their observations. As such, I tried the following loop to drop all the variables:
foreach var of varlist v1-v240 {
drop `var' if `var'=="Other"
}
What I get in return is the answer "syntax error". I would like to know not only a way to perform the task of dropping all the variables that contain the word "Other", but also why the code that I've entered returns an error.
The short answer on why your syntax is illegal, which #Dimitriy Masterov doesn't quite spell out, is that drop supports just two syntaxes, which can't be mixed, dropping variables and dropping observations. This is documented: see e.g. http://www.stata.com/help.cgi?drop and the corresponding on-line help and manual entry within Stata.
In addition to other solutions, findname from the Stata Journal would allow this solution:
findname, any(# == "Other")
drop `r(varlist)'
Your interpretation of contain is evidently 'is equal to' judging by your use of == as an operator, echoed above. If contain really means 'includes as substring', then you need a syntax such as
any(strpos(#, "Other"))
or
any(regexm(#, "Other"))
as #Dimitriy also explains.
If they are actual strings, this should work:
sysuse auto, clear
ds, has(type string) // get a list of string variables
// loop over each string variable, count observations that contain Buick anywhere, and drop the variable if N>0
foreach var of varlist `r(varlist)' {
count if regexm(`var',"Buick")
if r(N)>0 {
drop `var'
}
}
If "contains" means only contains, then you need to use "^Buick$" instead or
count if `var'=="Buick"
Beware of leading/trailing spaces.
The if qualifier restricts the scope of a command to those observations for which the value of the expression is true. Your code errors because you are asking Stata to drop a variable (a column) if some observations (rows) satisfy a condition. You could use the if qualifier to drop those observations or you can drop a variable, but not both simultaneously. My code uses the if command (a different beast) to verify the condition, and then drops the variable if that condition is satisfied.
You might be tempted to do something like
if `var'=="Other" {
drop `var'
}
but that will usually not work as expected (it would drop the variable only if the first observation was "Other").

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