I want to replace a Section sign "§" in CSV files.
So i try some sed commands, but it did not work for me.
i tried:
sed -i 's/§/\;/g' file.csv
sed -i 's/\§/\;/g' file.csv
Is it a SED or Shell issue?
Thanks!
Related
I am trying to replace string into number from the file
So, I have variable &FLOW which need to change to 001, ex :
cat file.txt
This is file ' PISP &FLOW'
PISD.DATA.CYCLE&FLOW..ONE
desired output
This is file ' PISP 001'
PISD.DATA.CYCLE001.ONE
I tried below commands in a script :
for item in file.txt
do
sed 's/\&FLOW/\./001/g' $item
sed 's/\&FLOW/001/g' $item
done
It is giving error. The second sed command is working, but I need to run first the beginning sed command otherwise after running first the second sed command, it would ignore the beginning sed command.
Any help would be appreciated!
Use a single sed command and use -i to actually modify the file contents and you need to pass file.txt as the input for the sed command:
sed -i 's/&FLOW\.\{0,1\}/001/g' file.txt
See the online demo. If you are using it in Mac OS, you need sed -i '' 's/&FLOW\.\{0,1\}/001/g' file.txt. Also see sed edit file in place.
Pattern details
It is a POSIX BRE compliant pattern matching
&FLOW - a literal &FLOW substring
\.\{0,1\} - 0 or 1 occurrence of a . char.
try this:
for item in file.txt
do
sed 's/\&FLOW\./001/g' $item
sed 's/\&FLOW/001/g' $item
done
You had a redundant / in after FLOW
This might also work:
sed -i 's/\&FLOW[\.]?/001/g' file.txt
I'm trying to find in file this string:
"cPHulk":{"BruteForce":3,"Login":3,"*":3}
and replace it with this string:
"cPHulk":{"*":"1","Login":"1","BruteForce":"1"}
I'm using sed to do this but I struggle a lot. My sed command is as follow:
sed -i -e 's/"cPHulk":{"BruteForce":3,"Login":3,"*":3}/"cPHulk":{"*":"1","Login":"1","BruteForce":"1"}/g' /var/cpanel/icontact_event_importance.json
EDIT:
The correct sed formula:
sed -i -e 's/"cPHulk":{"BruteForce":3,"Login":3,"\*":3}/"cPHulk":{"\*":"1","Login":"1","BruteForce":"1"}/g' /var/cpanel/icontact_event_importance.json
I found on some *nix you must provide a blank as the suffix to get it make an in-place replacement:
sed -i '' -e 's/"cPHulk":{"BruteForce":3,"Login":3,"*":3}/"cPHulk":{"*":"1","Login":"1","BruteForce":"1"}/g' /var/cpanel/icontact_event_importance.json
Note the '' after -i
I have a flat file where I have multiple occurrences of strings that contains single quote, e.g. hari's and leader's.
I want to replace all occurrences of the single quote with space, i.e.
all occurences of hari's to hari s
all occurences of leader's to leader s
I tried
sed -e 's/"'"/ /g' myfile.txt
and
sed -e 's/"'"/" "/g' myfile.txt
but they are not giving me the expected result.
Try to keep sed commands simple as much as possible.
Otherwise you'll get confused of what you'd written reading it later.
#!/bin/bash
sed "s/'/ /g" myfile.txt
This will do what you want to
echo "hari's"| sed 's/\x27/ /g'
It will replace single quotes present anywhere in your file/text. Even if they are used for quoting they will be replaced with spaces. In that case(remove the quotes within a word not at word boundary) you can use the following:
echo "hari's"| sed -re 's/(\<.+)\x27(.+\>)/\1 \2/g'
HTH
Just go leave the single quote and put an escaped single quote:
sed 's/'\''/ /g' input
also possible with a variable:
quote=\'
sed "s/$quote/ /g" input
Here is based on my own experience.
Please notice on how I use special char ' vs " after sed
This won't do (no output)
2521 #> echo 1'2'3'4'5 | sed 's/'/ /g'
>
>
>
but This would do
2520 #> echo 1'2'3'4'5 | sed "s/'/ /g"
12345
The -i should replace it in the file
sed -i 's/“/"/g' filename.txt
if you want backups you can do
sed -i.bak 's/“/"/g' filename.txt
I had to replace "0x" string with "32'h" and resolved with:
sed 's/ 0x/ 32\x27h/'
I could do the following in python to clean and strip unwanted whitespaces, but can it be done just through the terminal by other means like sed , grep or something?
outfile = open('textstripped.txt','w+','utf8')
for i in open('textfile.txt','r','utf8'):
print>>outfile, i.strip()
Using perl on the command line:
perl -lpe 's/^\s+//; s/\s+$//' file.txt > stripped.txt
This solution is based on sed man page:
sed 'y/\t/ /;s/^ *//;s/ *$//' input > output
http://www.gnu.org/software/sed/manual/sed.html#Centering-lines
Description:
y\t/ / replaces tabs with spaces
s/^ *// removes leading spaces
s/ *$// removes trailing spaces
$ cat input.txt | sed 's/^[ \t]*//;s/[ \t]*$//' > output.txt
This gets rid of the leading and trailing white spaces..
EDIT: sed -e "s/^[ \t]+//; s/[ \t]+$//" -i .bk input.txt
This does in place file editing, and saves backup to input.txt.bk (and saves a process as some suggested)
sed -E "s/(^[ \t]+|[ \t]+$)//" < input > output
Or if you have a GNU-compliant version of SED:
sed -E "s/^\s+|\s+$//g" < in > out
If you have a Mac, I recommed getting homebrew and installing gnu-sed.
Then, alias sed=gsed.
I have file, with lines, contains ip with netmask
a.b.c.d/24
w.x.y.z/32
etc
How to delete delete specific row?
i'm using
sed -ie "s#a.b.c.d/24##g" %filname%
but after the removal is an empty string in file.
It should run inside a script, with ip as parameter and also work in freebsd under sh.
Sed solution
sed -i '/<pattern-to-match-with-proper-escape>/d' data.txt
-i option will change the original file.
Awk solution
awk '!/<pattern-to-match-with-proper-escape>/' data.txt
Using sed:
sed -i '\|a.b.c.d/24|d' file
Command line arg:
For the input being command line argument, say 1st argument($1):
sed -i "\|$1|d" file
Replace $1 with appropriate argument number as is your case.
You should use d (delete) not g. Also do not use s (replacement).
sed -ie '/a.b.c.d\/24/d' %filename%
In a script you should using it in this way
IP=$1
IPA=${IP////\\/}
sed -i /"${IPA}"/d %filename%
And the script parameter should be called in this way:
./script.sh a.b.c.d/24
perl -i -lne 'print unless(/a.b.c.d\/24/)' your_file
or in awk if you donot want to do inplace editing:
awk '$0!~/a.b.c.d\/24/' your_file