how to create a room based on 2 users in socket.io? - node.js

Question

My goal is to create a one to one chat based on two different users. The only way that I could think of is to use socket.io rooms
But the problem right now is that how do i create unique room?
For example
socket.on('join', function(room) {
socket.join(room);
});
Do i need to emit the room from the client, if so , how do I make it unique. Imagine there are thousands of users.
The chat application, is similar like facebook chat application. Where you can chat one on one.
Do i need redis or mongodb to store the room? Anyone of you who have experience using socket.io in scale, please do share your opinion
Thanks!

Answer 1

A room always will be unique, when you do socket.join('roomname') if the room not exist it will created and this socket will join it, if exist the socket just will join it.
So if you want that client A join in the room where is client B for example, from client A you can send a event like:
socket.emit('joinroom', roomname);
On sever:
socket.on('joinroom', function(data){
socket.join(data)
})
Anyway when a socket connect , it create and join his own room automatically , the name of this room will be the id of the socket, so i think is not neccessary create new rooms for a chat based on two different users.
Everything that you need is link the socket id with a permanent property of the user.
EDIT:
I leave you here a simple chat app example where you can open multiple conversations:
server.js: https://gist.github.com/pacmanmulet/b30d26b9e932316f54b2
index.html: https://gist.github.com/pacmanmulet/6481791089effb79f25f
You can test it here :https://chat-socket-io-example.herokuapp.com/
I did not use rooms, it have more sense when you want emit to a group of sockets, not to a only one.
Hope you can understand better my idea with that.

Answer 2

you need to store the room number somewhere(any database).You have to do this because you have to keep your server stateless.
Let us assume that you are creating a private chat only for two people.The room number has to be unique. so one approach is to use the user's email id and join them to create a new string and emit it back to the users.this is tricky because we don't know the order in which the strings are joined. so we join them by a string not used in normal email name(eg :'"#!#!#!!#!#!#!').we can split it on the server side and compare emit the results.
The actual message body will be
{
room:a#gmail.comb#gmail.com,
from:a,
message:'hi buddy how are you?'
}
CLIENT side code
const roomName = a#gmail.com+'#!#!2!#!#"+b#gmail.com
socket.emit('room', { room: roomName });
this.socket.on('joined', data => {
console.log('i have joined', data.room)
store the room name room: data.room })
})
socket.on('chat',data=>console.log(`received chat from ${data.from} from the message room ${data.room}`)
used '#!#!2#!#' just because we can separate them on the server side and check if the room already exists.
SERVER side code
const room =[]//this variable you have store in database and retrieve it when needed.
socket.on('room',data=>{
if(room.length!=0){
const temp = data.room.split('!#!#2#!#!').reverse().join('!#!#2#!#!');
if(room.includes(temp)){
socket.join(temp)
console.log('joined room',temp)
socket.emit('joined',{room:temp})
console.log(room);
} else if(room.includes(data.room)){
socket.join(data.room)
console.log('joined room', data.room)
socket.emit('joined', { room: data.room})
console.log(room);
}
}else{
socket.join(data.room);
room.push(data.room)
console.log('joined room',data.room);
socket.emit('joined', { room: data.room })
console.log(room);
}
})

Answer 3

I tried to do a minimal example of where you can only be in one room at a time (apart from your default socket.id room) and only other sockets in the same room as you will receive your messages. Also you can change rooms.
The basic premise is, if socket A is in room 'xyz' and so is socket B, on the server side you can do socket.to('xyz').emit('message', 'hello') for socket A, and socket B will receive the message, but another connected socket C which isn't in room 'xyz' won't.

Answer 4

You can create room at server runtime, I used both users id as room id, Ex : '100-200' for demo purpose. May be you can use some more complex approach.