UITestControl uiLinkAboutus = new UITestControl(_bw);
uiLinkAboutus.TechnologyName = "Web";
uiLinkAboutus.SearchProperties.Add("ControlType", "Image");
uiLinkAboutus.SearchProperties.Add("TagName", "IMG");
uiLinkAboutus.SearchProperties.Add("Alt", "Open Menu");
Mouse.Click(uiLinkAboutus);
/* Upon execution, the drop down button is clicked but the option listed below is not clicked. How to solve this problem?
In stead of searching for an image, search for the list or dropdown control using a wpfCombobox, winCombobox or HtmlComboBox control. There you set the selectedItem property to the value you want. that is the most robust way of selecting an item in the UI. so e.g. :
ApplicationUnderTest aut = ApplicationUnderTest.Launch(#"yourapp.exe");
WpfComboBox cbBox = new WpfComboBox(aut);
cbBox.SearchProperties.Add(WpfComboBox.PropertyNames.AutomationId,"cmbCountries");//AutomationId == xName roperty
cbBox.SelectedItem = "your value";
Related
I have dropped ComboBox on dialog form. Also I have added some text to it:
BOOL CMyAppDlg::OnInitDialog()
{
CComboBox *combo= (CComboBox *)GetDlgItem(IDC_COMBO_TT);
combo->AddString("s1");
combo->AddString("s2");
//...
return TRUE;
}
When I drop down ComboBox it shows only one selection line and adds arrows to select other items. How to increase dropdown size?
Click the combo button in dialog editor. You can now drag down to set the open size.
I want to create checkbox with text in the left side and the checkbox component on the right side. How I can switch their place?
CheckBox cb = new CheckBox("Show on Startup");
In JavaFX 8, you can do it like this:
Label lb = new Label("left check");
lb.setGraphic(new CheckBox());
lb.setContentDisplay(ContentDisplay.RIGHT); //You can choose RIGHT,LEFT,TOP,BOTTOM
There might be an easier way, but you can use a label and wrap it with the CheckBox in a HBox:
HBox box = new HBox();
CheckBox cb = new CheckBox();
Label text = new Label("Show on Startup");
box.getChildren().addAll(text, cb);
box.setSpacing(5);
It would be nice if the CheckBox considered the box as its "content" like some of the other controls based on Labeled. Then the contentDisplayProperty could be set to ContentDisplay.RIGHT to achieve this. A nice side-effect would be that we could change the rendering of the box with a setGraphic() call.
As of my release (1.8 EA b129), CheckBox doesn't work that way.
I have created a Sharepoint WebPart, and I have given it a custom ToolPart that includes a Grid (a Telerik RadGrid, to be exact, though that is rather irrelevant). I have populated the grid, and created a GridButtonColumn object to add to the grid:
protected override void CreateChildControls()
{
GridButtonColumn c = new GridButtonColumn();
c.ConfirmText = "Really Delete?";
c.ConfirmDialogType = GridConfirmDialogType.RadWindow;
c.ConfirmTitle = "Delete";
c.ButtonType = GridButtonColumnType.LinkButton;
c.Text = "Delete";
c.UniqueName = "DeleteColumn";
grid.Columns.Add(c);
// ...
grid.DeleteCommand += new GridCommandEventHandler(Grid_DeleteCommand);
}
The grid renders correctly - populated with data and with the delete button present.
Now, when I click any of the delete button, the Grid_DeleteCommand() event does not get triggered. However, when I add a random button outside of the grid, it's click event gets triggered:
Button b = new Button();
b.Text = "Hello World";
b.Click += new EventHandler(Button_Click);
I'm not able to debug on this installation of Sharepoint (or maybe I can, but attaching to the process hasn't allowed me to do so yet), so the method of both of those events is simply a redirection to Google. That is how I check to see if the events fire:
string AbsoluteUri ="http://www.google.com";
Page.Response.Redirect(AbsoluteUri);
The only difference I can see between the two is that, with the 'Delete' button, it is nested inside of a Grid control, whereas with the 'Hello World' button, there is no nesting.
How would I be able to have the Grid_DeleteCommand fire when I click the button in the grid?
Using the Telerik Grid control, you should specify button's CommandName in your code.
Adding this line should solve the problem:
c.CommandName = "Delete";
I was wondering if it was possible to replace one control in a TableLayoutPanel with another at runtime. I have a combo box and a button which are dynamically added to the TableLayoutPanel at runtime, and when the user selects an item in the combo box and hits the button, I'd like to replace the combobox with a label containing the text of the selected combo box item.
Basically, if I could simply remove the control and insert another at it's index, that would work for me. However I don't see an option like "splice" or "insert" on the Controls collection of the TableLayoutPanel, and I was wondering if there was a simple way to insert a control at a specific index. Thanks in advance.
Fixed this by populating a panel with the two controls I wanted to swap and putting that into the TableLayoutPanel. Then I set their visibility according to which I wanted to see at what time.
This is what I've been able to come up with for what I needed. It gets the position of the ComboBox and makes a new label using the selected value.
// Replaces a drop down menu with a label of the same value
private void lockDropMenu(ComboBox dropControl)
{
TableLayoutPanelCellPosition pos = myTable.GetCellPosition(dropControl);
Label lblValue = new Label();
myTable.Controls.Remove(dropControl);
if (dropControl.SelectedItem != null)
{
lblValue.Text = dropControl.SelectedItem.ToString();
lblValue.Font = lblValue.Font = dropControl.Font;
// Just my preferred formatting
lblValue.AutoSize = true;
lblValue.Dock = System.Windows.Forms.DockStyle.Fill;
lblValue.TextAlign = System.Drawing.ContentAlignment.MiddleCenter;
myTable.Controls.Add(lblValue, pos.Column, pos.Row);
}
}
I'm trying to set the assigned value to a YUI Menu Button in order to use values from previous operations.
Something like remembering previous choices.
For label I already know that I can change it with:
button.set("label", "my label")
unfortunatelly I cannot change the value using: button.set("value", "my value")
Any ideia on how can I do this?
Other way would be to force a selection, but I have no ideia on how to do that.
Thanks
just found out that you can use:
var menu = button.getMenu();
var item = menu.getItem(index);
button.set("selectedMenuItem", item);
all that is left for me now is finding the needed index