I have a list of values, some being integers and some being non-integers. I would like to return the values that are integers. My idea:
if(ISNUMBER(C1)=TRUE,C1,0)
The data is laid out as so
88
Francesc Fabregas
m
86
Andrey Arshavin
a
86
Therefore I would only return the 88, 86, and 86. 88 is in cell C1.
Update: THE CELLS HAVE THE VALUES STORED IN THEM AS TEXT. HOW MIGHT I CHANGE ALL THE CELLS FORMATTING TO NUMBERS?
Try:
=IFERROR(--C1,"")
It will try to multiply -1*-1 to the value, if it is like a number it will return the number but if not it will error out and return "".
If you are using 2003 or later then use:
=IF(ISERR(--C1),"",--C1)
To do it in place highlight the range and you will see a little box in the upper left corner:
Hit that button and you will have a drop down list of option. Choose the "Convert to Number" option.
The NUBMERVALUE() function converts text to numbers. So the formula
=IF(ISNUMBER(NUMBERVALUE(D14)), NUMBERVALUE(D14), 0)
would turn your data to
88
0
0
86
0
0
86
Related
20/11/2022 12:00:52 2 X 15.95 15.95 USD 57 5 689 5 689 1 4111 0 Amazing Lego Team
I need to get the position of No 4111 in the above text string, As an excel beginner any help will be greatly appreciated. Thanks.
All of the Text Strings will have a 4 digit number like 4111 which i have to get the position for.
Have tried using this formula to get four digit number in another column, LOOKUP(10^15,MID(A1,ROW(INDIRECT("1:"&LEN(A1))),5)+0) but I am looking to get position instead.
I have tried using lookup but I could only go so far as a beginner.
Use the formula you provided =LOOKUP(10^15,MID(A1,ROW(INDIRECT("1:"&LEN(A1))),5)+0) to identify the number, and use FIND to get the position of the number.
Cell A1="20/11/2022 12:00:52 2 X 15.95 15.95 USD 57 5 689 5 689 1 4111 0 Amazing Lego Team"
=FIND(LOOKUP(10^15,MID(A1,ROW(INDIRECT("1:"&LEN(A1))),5)+0),A1)
=58
This looks to be in a space (or some other character) delimited text string. If you have a bunch of rows of data like this, use the Text to Columns feature on the Data tab. Use the Delimited option and then click the check box next to space (or other if it's something custom not in the available options) and Excel will split the data into columns for you.
For your string example, if you know that your 4 digit is started 58 char from the beginning of the string, use =MID(A1,58,4) A1 is the cell with your string.
MID function returns a specific number of characters from a text string, starting at the position you specify, based on the number of characters you specify.
=LET(t,TEXTSPLIT(A1,," "),
FIND(FILTER(t,(LEN(t)=4)*(ISNUMBER(--(t)))),A1))
It splits the string at every space and filters the result for being of length of 4 characters and not being an error if converted to number.
I have Excel sheet with value and another column value that depend of theme
If value >48 the value will be 8 if <=40 value will be 0 if value inferior a 48 and supperieru a 40 value will be column -40 I tried this but didn't work
=SI(AH15>48,8,SI(ET(AH15>40,AH15<48,AH15-40))
Or english:
=IF(AH15>48,8,IF(AND(AH15>40,AH15<48,AH15-40))
You are throwing in an AND function to check multiple conditions in a wrong manner:
All these conditions ET(AH15>40,AH15<48,AH15-40) can never be true since the last parameter is a calculation. Either way, what you tried to do is maybe:
=SI(AH15<=40,0,SI(AH15>48,8,AH15-40))
Which translates to:
=IF(AH15<=40,0,IF(AH15>48,8,AH15-40))
Try this one:
=IF(AH15>48,8,IF(AND(AH15>40,AH15<=48),AH15-40,0))
Hope it helps
I have a list of numbers that i need to subtract to 60 when the number is greater than 60. is there any one here knows on what formula to use and how for me to do this????
for example:
61 = 1
75 = 15
52 = 52
using the needed formula this should be the result
Use IF condition.
The syntax for the Microsoft Excel IF function is:
IF( condition, [value_if_true], [value_if_false] )
Formula
=IF(A1>60,A1-60,A1)
Test link
I'm assuming this is number of seconds or minutes, and you want to clip it at 60 to wrap it around. This will do it:
=MOD(A1,60)
Otherwise use the If function like Ullas indicated above.
This may be really easy for someone who used excel allot in the past but i just can't get the right formula.
I have a large spreadsheet which i need to add a mark up onto but the mark up which adds on is dependent on variables. Unfortunately this result has to go on the end of a already big formula, the ######## represents where the IF statement will be placed.
IF >55 and is square = 15
IF >55 and is not square = 15
IF <55 and is Square = 25
IF <55 and is not square = 30
Cell D2 = has the numerical value
Cell G2 = Has the shapes in it.
=(((100-V2)/100)*U2*D2)+((((100-V2)/100)*U2*D2)/100*##########)
I really recommend you break the formula into cells, but if it's needed to be in one single cell, the formula can be done as well...
IF(D2>55;IF(G2="square";15;15);IF(G2="square";25;30))
So it's gonna be like:
=(((100-V2)/100)*U2*D2)+((((100-V2)/100)*U2*D2)/100*IF(D2>55;IF(G2="square";15;15);IF(G2="square";25;30)))
A little shorter (addresses D2=55):
=15+15*(D2<55)-5*(D2<55)*(G2="Square")
I am not a big fan of the nested ifs in Excel, especially when they contain and/or conditions. The typical formula would look something like:
=if(and(c1,c2),x1,if(and(c3,c4),x2,...
YUCK!
I'm definitely a VBA minimalist, but this does appear to be a good application of it. Make a custom function like:
Function FooBoo(Val As Integer, Shape As String) As Integer
Dim result As Integer
If Val > 55 And Shape = "square" Then
result = 15
ElseIf Val > 55 Then
result = 15
ElseIf Val < 55 And Shape = "square" Then
result = 25
ElseIf Val < 55 Then
result = 30
End If
FooBoo = result
End Function
And then you can call it from within Excel:
=(((100-V2)/100)*U2*D2)+((((100-V2)/100)*U2*D2)/100*FooBoo(val,shape))
If it's part of the workbook itself, it's no less portable than any other Excel formula, and it's more transparent and easier to maintain.
Also, unrelated, but I did note some things in your logic:
15 seems to be the result for values > 55, whether or not it's a square. You really could limit your first condition to values > 55
You haven't defined what happens if the value is exactly 55. Was one of those conditions >= or <=?
I want a way to do the following
Original Data I want result as
507-413-0109 507-413-0110
507-430-5409 507-430-5410
507-450-6649 507-450-6650
507-450-8640 507-450-8651
507-451-1563 507-451-1574
if the original number is 2133-2322 , I want it as 2133-2333 .
The last two digits should increase by value 1.
But , if there is a 9,
9+1 = 0
and
0+1 = 1
how to do it in Excel ?
You have to extract the 3rd column of numer (0109, 5409, ...) in a particular column. You can use the function RIGHT(A1,1) (where A1 is the cell which contains the 207-413-0109 string).
Then you just add +1 to them.
=REPLACE($A1,11,2,TEXT(IF(VALUE(RIGHT($A1)) = 9, MOD(VALUE(RIGHT($A1,2))+1,100), VALUE(RIGHT($A1,2))+11),"00"))
Put this in cell C1, then copy to C2 through C5.
I assumed that if the number ends in 99, then it replaces 99 with 00.
This will handle the 99 case as a 4-digit number instead of two, all other things being same:
=REPLACE($A1,9,4,TEXT(IF(VALUE(RIGHT($A1)) = 9, MOD(VALUE(RIGHT($A1,4))+1,10000), VALUE(RIGHT($A1,4))+11),"0000"))
So 1599 will become 1600 instead of 1500. And 9999 will just become 0000.
Assuming that your data begins in the "A1" spreadsheet position, if you put the folling formula in the "B1" cell, and then copy it downward, it should derive the values you're for which you're looking
=LEFT(A2,10) & RIGHT(TEXT(VALUE(RIGHT(A2,2)) + 1,"00"),2)