I have used the following data validation for enabling/disabling a cell depending upon the condition of the previous cell. But now, I want to copy the same condition to the whole column which I tried doing using copy>paste special>validation but this is not working. Please somebody help me with this.
B2=IF($A$2="Ocean","",$D$11:$D$12)
If 'but this is not working' mean that you are able to copy validation but not getting expected result than you probably need not anchor row number of column 'A'
Try: =IF($A2="Ocean","",D$11:D$12)
Related
I have some materials in column B, a few among these are in a Table definition called Material_List. In D49 I am trying to write a conditional statement such that, if the data in B49 already exists in the table definition, then print the header name or else INDIRECT($49). C49 has the independent dropdown list and D49 will be the dependent.
In D49 I have used the following formula within the Data-->Data Validation-->Source=
=IF(MAX((ISNUMBER(MATCH(Material_List;$B49;0))*COLUMN(Material_List)))=0;
INDIRECT($C49);
INDEX(Material_List[#Headers];1;MAX((ISNUMBER(MATCH(Material_List;$B49;0))*
COLUMN(Material_List))))))
with Allow=List. But it says Error "There is a problem with this formula"
When typed the following formula in cell D50 directly, it works well but obviously without dropdown.
=IF(MAX((ISNUMBER(MATCH(Material_List;$B50;0))*COLUMN(Material_List)))=0;
INDIRECT($C50);
INDEX(Material_List[#Headers];1;MAX((ISNUMBER(MATCH(Material_List;$B50;0))*
COLUMN(Material_List))))))
I am trying to build a dropdown list based on the mentioned criteria. could anyone please tell what is wrong with my formula?
I think the main issue with your formula is that you cannot use table references in the data validation.
Don't ask me why. I think it is just an outstanding Excel bug which hasn't been fixed yet. Please see this link for further info: https://exceloffthegrid.com/using-an-excel-table-within-a-data-validation-list/
The best way I have found to work around this is to create a named range which refers to the table references you need ("Material_List" and "Material_List[#Headers]" in your case). Then you can use those named ranges in your data validation instead of the table references directly.
However, I think there are also other issues with your formula. For example, this part:
MATCH(Material_List;$B50;0)
Normally a MATCH would be in the format of:
MATCH(<single value to look for>, <range to look in>, 0)
You appear to have that reversed, meaning that it should always return a #VALUE! error.
Also, I don't think you can use match on a 2D array, so if your "Material_List" table is more than a single column, that would also cause it to return a #VALUE! error.
UPDATE:
The way I would tackle dependent dropdowns would be as follows.
I would create a "Material_List" table similar to below (could be on a hidden sheet):
Then I would create 3 named ranges.
One for the table body range, called "MaterialList_TblRange":
=Material_List
One for the table header range, called "MaterialList_TblHeaderRange":
=Material_List[#Headers]
And one to refer to the dependant dropdown options, called "DropDownOptions" (this is by far the most complicated part):
=INDEX(MaterialList_TblRange,1,MATCH(Sheet1!$B23,MaterialList_TblHeaderRange,0)):INDEX(MaterialList_TblRange,COUNTA(INDEX(MaterialList_TblRange,1,MATCH(Sheet1!$B23,MaterialList_TblHeaderRange,0)):INDEX(MaterialList_TblRange,ROWS(MaterialList_TblRange),MATCH(Sheet1!$B23,MaterialList_TblHeaderRange,0))),MATCH(Sheet1!$B23,MaterialList_TblHeaderRange,0))
I will explain what this is doing in a moment.
The last step is to set up the data validation where we want our lists.
Where we want the master lists to appear, we can simply enter:
=MaterialList_TblHeaderRange
And the defendant dropdown validation can be entered as:
=DropDownOptions
This is the result:
Now back to the long "DropDownOptions" named range formula...
Basically, we use INDEX:INDEX to select the first/last cell in the range we want to use in out dropdown.
The first INDEX:
=INDEX(MaterialList_TblRange,1,MATCH(Sheet1!$B23,MaterialList_TblHeaderRange,0))
Simply selects the first cell from the column whose header matches the selection in our first dropdown.
The second index does the same, except that instead of selecting the first cell in the column, it counts the number of cells that contain text and uses that as the last cell in the range.
This does mean that we mustn't have any gaps in this table, otherwise an option might be missed off the end.
I hope this makes sense.
I'm looking to use the filter formula on a named range but there hasn't been a resource that has explicitly showed how to reference columns within a named range. I might add that the whole named range includes the headers due to the nature of the original data. It has 13 Columns.
The columns I want with their position is: "Injury Date" (6) and "INCURRED" (8)
=filter(Loss_Run,[Insert Chosen Columns Here])
This is the syntax I am trying to use but I cannot get it to work. I am not sure how to tell it to use the columns I want. Do I use the name of the columns or the number either way is fine to me.
I am trying to filter by a specfic value of a row and that is where the main hiccup is.
I got
=FILTER(Loss_Run,(Loss_Columns="Injury Date")+(Loss_Columns="INCURRED"))
to work.
BUT,
I want to first filter the first column, "ULGTACCT Code" (1) by a value (that is in cell A2 for our purposes). It is not allowing me to filter by the first column with or with out the other columns
What I have found says:
=FILTER(Loss_Run,(ULGTACCT Code=$A$2),"")
should work but I get #Name? error.
To answer about calling a column within a table with name ranges and the FILTER function is things are much smoother if you specify columns as =FILTER(TableName[ColumnName],include"argument") within brackets "[ ]", this means that your table will need to be named to make this easier. That's how you would call a specific column.
To the other point of specifying the columns to FILTER, I have only found that to do this you write it as =FILTER(TableName[#[ComlumnName1]:[ColumnName4]],include"argument") and that should do it but I get an #Value error doing that.
I'm looking for any help as well with this so if this helps to bring you to a answer please share.
I was using
=FILTER(TableName, (TableName[Column]="SearchValue")
And I got all table rows back that were matching the criteria.
Currently trying to make a formula that will automatically match a model number from one column and sheet, find it in another sheet and pull the second number from said row and sheet back into the others price field. So far I can get it to match find the model in the 2nd sheet and even get the price.. but it keeps coming back with an error after the formula inside of the MATCH tag is complete.
The first sheet with the model number on the left, the price on the right.
The Second sheets layout
And last where it says its erroring out at
My Formula
=INDEX(A:A,MATCH(TRUE,EXACT(A3,New!A:A)*New!C:C,),4,)
As a side note: I'm extremely new to Excel formulas so this might look sloppy and i could be doing it bad. Just trying to make my life easier with these formulas. Any help is appreciated, even if its just leading me in the right direction. Thank you!
use
=INDEX(New!C:C,MATCH(A3,New!A:A,1))
Or VLOOKUP:
=VLOOKUP(A3,New!A:C,3,FALSE)
I have a table in Excel for tracking projects. Whenever I create a new row for the table I'd like it to auto-populate one column that the project has "Not Invoiced". I would ALSO like that this column use Data Validation to only allow either "Not Invoiced" or "Invoiced" as content.
I have been able to make both of these things work, but I cannot seem to make them work together without error! The closest I have gotten:
Put a formula in the relevant column. Have tried both the super basic ="Not Invoiced" as well as an =IF formula based on the blankness of another column. This correctly carries down each time I make a new row.
I then add Data Validation on the column which also works fine at first since my default value from my formula is one of the options, HOWEVER when the project does invoice and I select "Invoiced" I then get an error that I'm violating the above formula. From what I've read selecting something from the drop down should just replace the auto-populated formula, but that doesn't seem to happen, it gives me an error that I've violating the column's formula instead.
I've read multiple places that if you correctly order things (create table, add formula for default value, then add data validation) the above method should work, but it will not for me and I continue to get the error every time I change to "Invoiced".
you can enter the stati "Not Invoiced" and "Invoiced" into cells that are close together, e.g. $G$3 and $G$4. Then, create a named range for $G$3:$G$4, let's say "ValList" (menu: Formula / Define Name).
Imagine column A to be the controlling column, and B the status column ("Invoiced" / "Not Invoiced"). Example for cell B5:
The initial status is =IF(A5=""; ""; $G$3)
The Validation (type "List") must be controlled by a formula =IF(A5=""; " "; ValList)
Good luck!
There's a simple way to do this.
Before you start using a new table, add list data validation to the cell in the first and only row:
Invoiced,Not Invoiced
Then, in the first row of your table in that same cell write:
=IF(TRUE,"Not Invoiced";"Not Invoiced")
This will put Not Invoiced as the default value on every new row that is added to the table and also keep data validation in place. You will still have access on every new row's cell to the dropdown list stored in the initial cell's data validation list parameter.
For some reason, data validation is overwritten if you try the same IF-function approach in reference to another cell, as you described it.
One way to solve this would be to use a helper column.
You can use the data validation list for the entry column, say column A.
You can use a formula in the hidden column B with the formula =IF(A1,"Invoiced","Invoiced","Not invoiced")
While i have seen this topic answered before i cant seem to understand the solution :(
Here is my worksheet:
https://docs.google.com/spreadsheet/pub?key=0AsCQyX3EZ40SdC1FNFBjVDh6d01iY2g0WnVXOU5GeFE&output=xls
As you can see i need the second INDEX in the first sheet to return the second value looked, but instead (as expected) it shows the first one again.
I am not the best with excel, explain slowly and i will understand fast!
Thanks in advance!
Try this "array formula" in Calculator sheet cell A3
=IFERROR(INDEX(IngredientDB!B$1:B$100,SMALL(IF(IngredientDB!$A$1:$A$100=$B$1,ROW(IngredientDB!$A$1:$A$100)),ROWS(A$3:A3))),"")
confirmed with CTRL+SHIFT+ENTER and copied across and down. When you run out of entries you get blanks - assumes up to 100 rows of data, increase as required
If you wanted to go the pivot table route you can start with this as a base and then customize it to your exact liking.:
Start with your info:
Then add a pivot of your data:
Then set the properties as so and then you can select the search terms, you can also change the settings to allow someone to type it in also:
The result will be as so: