How do I extract text between two commas in Excel?
92 4th Street North, Providence, RI 02904
In this case, how would I extract "Providence" substring using simple Excel formulas (LEN, FIND, LEFT, RIGHT, etc)?
Try the following formula.
=MID(A2,FIND("^",SUBSTITUTE(A2,",","^",1))+1,FIND("^",SUBSTITUTE(A2,",","^",2))-FIND("^",SUBSTITUTE(A2,",","^",1))-1)
Try the following formula
=LEFT(RIGHT(A1,FIND(",",A1)),FIND(",",RIGHT(A1,FIND(",",A1)))-1)
Considering your data is on A1
#RAJA-THEVAR's formula worked very well for me with a list of over 2500 addresses, as long as the address only contained two commas. With an address like "100 Washington Street, Suite 225, Denver, CO 80220" it returns "Suite 225." I used the following formula to identify and addresses that contained more than two commas:
=LEN(A1)-LEN(SUBSTITUTE(A1,",",""))
Many of these many-comma addresses had strange formats or information, and I found it better to fix them by hand.
Related
I have a problem to extract the suburb from a address.
For example, the dress is "143 Stephanie St, Upper Kedron, QLD, 4055."
How to set up a formula to extract the buburb, Upper Kedron, from the address?
I really appreciate your review :)
This will extract second word separated by comma:
=TRIM(MID(SUBSTITUTE(A1,",",REPT(" ",255)),255,255))
You will have problem if Upper Kedron is not 2nd word like for example:
143, Stephanie St, Upper Kedron, QLD, 4055 (this will extract Stephanie St).
So if you have cases that formula doesn't work give us more inputs.
As per the previous answer, looks like your suburb can be in any position. So the best way is to split the address to multiple columns and then choose a column of your suburb.
=TRIM(MID(SUBSTITUTE($A1,",",REPT(" ",999)),1+((COLUMN(A1)-1)*999),999))
So I have a cell that contain this text string. I was wondering if I can pull the text between from and upon. So it captures AAA (being varying degree of length)
life insurance policy #111 111 111 for the amount of $500,000.00 from AAA upon the life of xxx
So far I only managed this:
=MID(STP_Data!D71,FIND("from",STP_Data!D71), 42)
But if the text length changes it wouldn't capture it. Also how would I not capture from within my formula. Since my currently formula will include 'from' when it is pulled. Thanks guys!
How does this work?
=Trim(SUBSTITUTE(MID(A1,SEARCH("from",A1),SEARCH("upon",A1)-SEARCH("from",A1)),"from",""))
Edit: Added TRIM() per Scott's suggestion.
While I can extract the first word from a cell containing multiple text values with error checking to return the only word if no multiple values exist. I cannot seem to wrap my brain around adding more checks (or if it is even possible in the same nested formula) for situations where some of the source cells contain a comma between multiple words. Example, the formula below will return "James" from "James Marriott". But, it returns "James," from "James, Marriott". If all of my cells in the range were consistent that would be easy, but they aren't. Attempts to nest multiple find statements have resulted in failure. Suggestions?
=IFERROR(LEFT(A1,FIND(" ",A2)-1),A2)
To compound matters, there are also cells that contain abbreviations as the first word, so somehow I need to account for that as well. For example "J.W. Marriott" where I need to apply the above logic to extract "Marriott".
Here are some examples below:
Text Desired output
James Marriott James
James, Marriott James
Able Acme Able
Golden, Eagle Golden
J.W. Marriott Marriott
A.B. Acme Acme
you could use regex (to set up please look at the post here)
Then you can extract the desired word with a formula like:
=regex(A1, "(?![Etc])[a-zA-Z]{2,}")
(This is searching for a pattern of two or more lower or upper case letters in the cell A1...and not searching for Etc)
I've tried finding a formula but really just can't seem to find it at all!
My problem is i have thousands of addresses in different structures but i need to find the city in each of them!
So the different types of addresses i have are as follows:
Dornocktown, Dornock, Annan, DG12 6SU
Grainshore Road, Hatston, Kirkwall, KW15 1FL
Brandon Road, Watton, Thetford, IP25 6LW
Bainbridge, Leyburn, DL8 3EP
Shore Road, Dornoch, IV25 3LS
Boston Industrial Estate, Power Station Road, Rugeley, WS15 2HS
Parkfield Road, Wolverhampton, WV4 6EH
I need the city or the last word before the post code.
Any help would be great thanks!
Try this, values in A1:A7:
In B1 write:
=RIGHT(A1;LEN(A1)-1-FIND("#";SUBSTITUTE(A1;",";"#";LEN(A1)-LEN(SUBSTITUTE(A1;",";""))-1)))
copy till B7
now in C1 write:
=LEFT(B1;FIND(",";B1)-1)
copy till C7
Now you have the city names. It is possible to do everything in one formula but will be a very big one...
Depending on your settings you may need to replace ";" by "," for field separators
I have a list of addresses which are individual strings in an Excel spreadsheet:
123 Sesame St New York, NY 00000
123 Sesame Ct Atlanta, GA 11111
100 Sesame Way, 400 Jacksonville, FL 22222
As you can see above the third address is different. It has a suite number of 400 on what would normally be the street line 2 line. I am having trouble coming up with a formula that will parse the addresses above into its individual cells: Street 1 (with street 2 or suite information in this line), City, State and Zip.
My thought is to start from the right and extract information based on a space delimiter, but I am not sure how to do this. How would I go about this?
I guess you can do a combination of MID & FIND to extract parts of the address,
e.g.
=IF(IFERROR(MID(A1,1,FIND(",",A1,FIND(",",A1)+1)),1)=1,MID(A1, 1, FIND(",",A1)-1),MID(A1,1,FIND(",",A1,FIND(",",A1)+1)-1))
will extract the address from cell A1, depending of the number of commas it finds (1 or > 1).
ZIP and state won't be too difficult following the above mentioned pattern. I think the problem is extracting the city as you don't know where to set the limit between the city name and the street unless you have a finite set of street types, e.g. ct, st, way etc.
You can use a slightly shorter formula using SUBSTITUTE() and LEN() in addition to FIND() and LEFT():
=LEFT(A1,FIND("#",SUBSTITUTE(A1,",","#",LEN(A1)-LEN(SUBSTITUTE(A1,",",""))))-1)
The first part which gets executed is:
LEN(A1)-LEN(SUBSTITUTE(A1,",",""))
Which basically calculates the number of commas in the input string. This then goes into the next formula:
SUBSTITUTE(A1,",","#",[1])
Which substitutes the last occurrence of comma by # (if addresses have this, use another character which you won't find in the address).
=LEFT(A1,FIND("#",[2])-1)
And the last part is takes the characters up to the # we just inserted.