The aim
I am try to create a formula which will allow specific information from 90 different worksheets, with an example of one such worksheet being below. Each work sheet represents data from a participant.
I want the data from the 90 work sheets to be summarised into the worksheet below.
The problem
The problem is that I need to create a formula that takes counterbalancing into account.
So in cell A3 of the second image I would to record the number of times the value 1 and 3 appears in column I of the first image.
The conditions
However, I would only like the numbers in column I to count if:
a) in column M of image 1 there is a value of 1
and
b) when the number in Column L is 1 and Column K is 1 or 4 OR when the number in Column L is 2 and the number in Column K is 3 or 4.
My attempt
=SUM('[All_memories_301-389_improved.xlsx]Sirma 301:387Yanxin'!$M$2,1*(IF('[All_memories_301-389_improved.xlsx]Sirma 301:387Yanxin'!$L$2,1*(IF('[All_memories_301-389_improved.xlsx]Sirma 301:387Yanxin'!$K$2:$K$41,1,4*(IF('[All_memories_301-389_improved.xlsx]Sirma 301:387Yanxin'!$I$2:$I$54,1,3)))))))
This did not work however and I have spent a long time on this and made changes but I still can't seem to get it to work.
Extra information:
In column I I want to count all the occurrences of 1 and 3 provided the specified conditions are met. The rows are not important, but rather, the column I information for each of the 90 spreadsheets.
New attempt with formula:
=COUNTIFS('[All_memories_301-389_improved.xlsx]381Christie'!$M$2, 1, '[All_memories_301-389_improved.xlsx]381Christie'!$L$2, 1, '[All_memories_301-389_improved.xlsx]381Christie'!$K$2:$K$23, AND(1,4), '[All_memories_301-389_improved.xlsx]381Christie'!$I$2:$I$23, AND(1,3))
Related
I have a spreadsheet with sales data for a given month for a number of different stores. There are approximately 450 rows (stores) to go through. The days of the month are in row 1, starting in column B, with the store numbers in column A, starting in row 2. What I need to find are the rows that are missing data for different days. I can use conditional formatting to highlight the cells that are empty, but that is still a lot to look at. What I am trying to do is reduce the amount of cells to look at by deleting any rows that are not missing data. So if a row is not missing any days of data, then I don't need to look at it, and can delete it. But if it is missing data, then keep the row.
I'm stuck on figuring out the actual code, but I have come up with pseudo code for what I want:
foreach row in range ($B$2:$AB$450)
foreach cell in row
if cell < 1
delete row
end foreach
end foreach
Here is an example of the spreadsheet:
A B C D
1 12/1/2019 12/2/2019 12/3/2019
2 Site 1 1000 2000
3 Site 2 5000 5000 3000
4 Site 3 6000 4000 3000
In this example, rows 4 and 4 would be deleted because they are not missing any data.
Thanks
**assuming that you have 4 columns and they start in column B:
with an array formula you can see the length of characters in each row.
=MIN(LEN(B2:E2))
for example, you can use the above formula in row 2 (remember: ctrl+shift+enter to use it)
So, if you apply that formula per row, you should be able to know if you have missing value per row (all of them that have length 0 per row); then, use that column to filter. E.g. Filter anything that is not 0.
I have 7 columns to choose from and I need to pick 4 of those columns and generate a total for each row. I also need every combination of 4, which means I'll have 35 new columns with the totals for each of those combinations showing in each row. I need the code for this and if it can be done only using Excel. Here is an image of the columns and the grayed ones are the 7 columns I'm talking about. My knowledge of Excel is very limited. There are over 1,500 rows if that matters.
multi step approach that is going to use some helper rows. there may be a more elegant formula that will do this, and much slicker options in VBA, but this is a formula only approach.
Step 1 - Generate List of Column Combination
To generate the list 4 helper rows will need to be insert at the top of your data. either above or below you header row. These 4 rows will represent the column number you are going to pick. To keep the math simpler for me I just assumed the 1 for the first column and 7 for the last column. those numbers will get converted to later to account for column in between in your spreadsheet. For the sake of this example The first combination sum will occur in column AO and the first helper row will be row 1. The first combination will be hard coded and it will seed the pattern for the remainder of column combinations. Enter the following values in the corresponding cells:
AO1 = 1
AO2 = 2
AO3 = 3
AO4 = 4
In the adjacent column a formula will be placed and copied to the right. It will automatically augment the bottom value by 1 until it hits its maximum value at which point the value in the row above will increase by 1 and the the value of the current will be 1 more than the cell above. This will produce a pattern that covers all 35 combinations by the time column BW is reached. Place the formulas below in the appropriate cell and copy to the right:
AP1
=IF(AO2=5,AO1+1,AO1)
AP2
=IF(AO2=5,AP1+1,IF(AO3=6,AO2+1,AO2))
AP3
=IF(AO3=6,AP2+1,IF(AO4=7,AO3+1,AO3))
AP4
=IF(AO4=7,AP3+1,AO4+1)
Step2 - Sum The Appropriate Columns
I was hoping to use a some sort of array type operation to read through the column reference numbers above, but I could not get my head around it. Since it was just 4 entries to worry about I simply added each reference manually in a SUM function. Now the important thing to note is that we will be using the INDEX function over the 13 columns that cover the range of your columns so to convert the index number we figured out above, to something that will work to grab every second row, the number that was calculated will be multiplied by 2 and then 1 will be subtracted. That means 1,2,3,4 for the first column combination becomes 1,3,5,7. You can see this in the following formula. Place the following formula in the appropriate cell and copy down and to the right as needed.
AO5
=INDEX($AB5:$AN5,AO$1*2-1)+INDEX($AB5:$AN5,AO$2*2-1)+INDEX($AB5:$AN5,AO$3*2-1)+INDEX($AB5:$AN5,AO$4*2-1)
pay careful attention to the $ which will lock row or column reference and prevent them from changing as the formula is copied.
Now you may need to adjust the cell references to match your sheet.
how can I merge two columns of data into one like the following:
Col1 Col2 Col3
========================
A 1 A
B 2 1
C 3 B
2
C
3
You can use the following formula in column D as per my example. Keep in mind to increase the $A$1:$B$6 range according to your data.
=INDEX($A$1:$B$6,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
Result:
Thank you to #Koby Douek for the answer. Just an addition--if you are using Open Office Calc, you replace the commas with semi-colons.
=INDEX($A$1:$B$6;INT((ROWS(D$2:D2)-1)/2)+1;MOD(ROWS(D$2:D2)-1;2)+1)
Expanding #koby Douek's answer to more columns and explaining some of the terms
Original Code for 2 columns to 1 alternating
=INDEX($A$1:$B$6,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
$A$1:$B$6 Defines the columns and rows to source the final set of data from, the $s are only present to keep the formula from changing the columns and rows selects if it is copied and pasted or dragged.
To extend to work on any values you dump into the columns instead of having to expand the range every time it should be amended to $A:$B or A:B so you can easily copy it to other sets of columns and create new merges, but it will also give the 1st value in every column as one of the alternating values so if you instead have headers you would be able to do this by instead using a large number so $A$1:$B$99999 or A$1:B$99999 if you want to past and move the columns ymmv which is better by situation.
lets assume you are fine including the values in the 1st row
This changes the formula to
=INDEX($A:$B,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
Now on to D$2:D2
This is the row that is being used to calculate the difference between the current row the formula is in (D2) and the reference row (D$2) The important thing to make sure you do is to set the reference row number to the 1st row you will be putting values in, so if your 1st row is a header in the sort column you will use the 2nd row as the reference, if your values in the combined column D begin on the 3rd row then the reference row would be D$3
Since I like the more general form where the 1st row isn't a header row I'll use D$1:D1 but you could still mix source rows without headers into a combined row with a header of as many rows as you like just by incrementing that reference row number to be the 1st row where your values should begin.
This changes the formula to
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/2)+1,MOD(ROWS(D$1:D1)-1,2)+1)
Now INT((ROWS(D$1:D1)-1)/2)+1 and MOD(ROWS(D$1:D1)-1,2)+1
INT returns an integer value so any decimal places are dropped, it essentially functions like rounding down to the nearest whole number
MOD functions by returning the remainder of a division, it's result will be a whole number between 0 and n-1 where n is the number we are dividing by. (eg: 0/3=0; 1/3=1; 2/3=2; 3/3=0; 4/3=1 ... etc)
So -1)/2)+1 and -1,2)+1
the first value is again the difference between the current row and the reference row. but D$1:D1 is going to be the count of the rows, which is 1 so we have to correct for the rows count starting at 1 instead of 0 which would throw off our calculations, so both are using the -1 to reduce the count of the rows by 1
in the case of /2 and ,2 both are because we are dividing by 2 in the first statement it's a normal division by 2 /2 in the modulus statement it's an argument of the Mod function so ,2
finally we need to add 1 using +1 to correct for the index's need to have a value series which begins at 1.
INT((ROWS(D$2:D2)-1)/2)+1 is finding the row number to select the value from.
MOD(ROWS(D$1:D1)-1,2)+1 is finding the column number to select the value from
Thus we can change /2 and ,2 to /3 and ,3 to do this with 3 columns
This yields:
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/3)+1,MOD(ROWS(D$1:D1)-1,3)+1)
So maybe that's the confusing way to look at it but it's closer to how my mind works on it. Here is an alternative view:
=INDEX([RANGE],[ROW_#],[COLUMN_#]) returns the value from a range of rows and columns
Using the example:
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/3)+1,MOD(ROWS(D$1:D1)-1,3)+1)
[RANGE] = $A:$B this is the range of source columns.
[ROW_#] = INT((ROWS(D$1:D1)-1)/3)+1
INT([VALUE_A])+1 returns an integer value so any decimal places are dropped. Then adds one to it. we add one to the value because the result of the next steps will be 1 less than the value we need.
[Value_A] = (ROWS(D$1:D1)-1)/3
ROWS(D$1:D1) returns the number of rows in the Range to the current row in the results column, we use D$1 to designate the row number where the values in the results column begin. D1 is the current row in the results column giving us a range from the source row, allowing us to count the rows. we have to subtract 1 from this value using -1 to get the difference between the source and current. This is then divided by /3 because we have three columns we want to look through in this example so we only change rows when the result is divisible by 3. the INT drops any decimal places as mentioned so it only increments when cleanly divisible by 3.
[COLUMN_#] = MOD(ROWS(D$1:D1)-1,3)+1
MOD([VALUE],[Divisor])+1 returns the remainder of the value when divided by the divisor.
Using the example:
MOD(ROWS(D$1:D1)-1,3)+1
In this case we still divide by 3 but it's an argument to the MOD function, we still need to count the number of rows and subtract 1 before dividing it, this will return a 0, 1, or 2 for the column, but as above we are shifted backwards by 1 as the column numbers begin with the number 1, so as before we must add 1
And here we add column A and D
two different formulas depending on if you add the formula to an odd row or an even row.
https://1drv.ms/x/s!AncAhUkdErOkguUaToQkVkl5Qw-l_g?e=5d9gVM
Odd Start row
=INDEX($A$2:$D$9;ROUND(ROW(A1)/2;0);IF(MOD(ROW()-ROW($A$2);2)=1;4;1))
Even Start row
=INDEX($A$2:$D$9;ROUND(ROW(A1)/2;0);IF(MOD(ROW()-ROW($A$1);2)=1;4;1))
What is A1 in the picture is the cell directly above your first data cell.
If you want to place it on a different sheet you just add the sheet name:
=INDEX(MySheet!$A$2:$D$9;ROUND(ROW(MySheet!A1)/2;0);IF(MOD(ROW()-ROW(MySheet!$A$2);2)=1;4;1))
=INDEX(MySheet!$A$2:$D$9;ROUND(ROW(MySheet!A1)/2;0);IF(MOD(ROW()-ROW(MySheet!$A$1);2)=1;4;1))
I have 2 sheets. Sheet 1 is set up similarly to:
Keyword Domain Rank
A Z 1
B Z 2
C Z 3
D Y 10
E Y 15
B Y 20
And sheet 2 is set up like:
Keyword (Domain Z) (Domain Y)
A 1 -
B 2 20
C 3 -
D - 10
I'm trying to have a formula that will compare the keywords in Sheet 2 with those in Sheet 1 and then return the rank that corresponds to the correct domain (that's specified in Sheet 2 for that column). I can't get any formula I use to evaluate. I've used 2 formulas so far:
=INDEX(Raw!$H$11:$H$322, MATCH(A3,IF(Raw!$D$11:$D$322=All!$B$2,Raw!$B$11:$B$322),0))
The above formula works, to a point. The problem is that it simple pulls the domain for the first instance of the keyword found, which doesn't always match the domain in the column of sheet 2. The second formula I've tried:
=INDEX(Raw!$H$11:$H$322, MATCH(B3,MATCH($C$2,Raw!$D$11:$D$322,0)))
To make the values appear in the Sheet 2 table, use the following formula:
=SUMPRODUCT(--($A$2:$A$7=E2),--($B$2:$B$7=$F$1),$C$2:$C$7)
This returns 0 for non-matches - you can either format the cells to display 0 how you want, or you can use the longer/uglier:
=IF(SUMPRODUCT(--($A$2:$A$7=E2),--($B$2:$B$7=$G$1),$C$2:$C$7)<>0,SUMPRODUCT(--($A$2:$A$7=E2),--($B$2:$B$7=$G$1),$C$2:$C$7),"-")
To calculate the rank on the first sheet based on the data from the second sheet:
=VLOOKUP(A2,$F$2:$H$5,MATCH(B2,$G$1:$H$1,0)+1,FALSE)
For sample purposes, this just put your sheet2 data in F1:H5.
This looks for the corresponding keyword and then uses match to pick the right column. I named the columns Z and Y, but if you need Domain included that can be done as well. Note that this causes an error since there is no E defined in your second table - is that the case? If so, it can be adjusted to account for no matches as follows (assuming Excel 2007):
=IFERROR(VLOOKUP(A6,$F$2:$H$5,MATCH(B6,$G$1:$H$1,0)+1,FALSE),"Rank Not Found")
You could also use PivotTable with Keywords in rows and Domain names in columns. It seems like that would do the job and be a more robust solution.
I have searched through many similar topics but could find nothing that will do what I need.
I am trying to create a worksheet that will track scores for a darts game.
On Sheet 1 I have two columns that simply tracks each players throws from 501 down to 0
Row 25 is the amount remaining for each player.
In Sheet 2 I have 2 columns. The Column A contains scores that you can check out on, and Column B contains the checkout e.g. (T20, T20, D18). So if the value in row 25 of Sheet 1 matches any of the values in Column A of sheet 2, the I want to display the Value of Column B in the matching row on Sheet 2 Underneath the remaining score on Sheet 1.
Can anyone point me in the right direction?
not sure what you mean exactly, but this formula in row 26 should do the trick:
=index('Sheet 2'!$B:$B;match(A25;'Sheet 2'!$A:$A;0))
if your list separator is comma ,, use that instead of semicolon ;
you might want to use 1 as the third argument of match function, if you want to display the checkout according to the nearest match that is bigger than the number in row 25 and the column A in Sheet 2 is sorted in ascending order (1-9)
or -1 if you want the nearest match that is smaller and column A is sorted in descending order (9-1)
You can use this:
=IFERROR(VLOOKUP(A4, Sheet2!$C$2:$E$65535, 3, FALSE),0)