I have quite simple question, but my google research did not help.. I am pretty new to Lua, so..
I have string "XXXX_YYYYYY_zzzzzz" stored in local variable and I want to parse it and get 3 new local variables. Should I use string.find?
local str_ = "XXXX_YYYYY_zzzzzz"
local first_, second_, third_ = strind.find(str_, "^(%w+)_(%w+)_(%w+)$")
Use string.match instead:
local str_ = "XXXX_YYYYY_zzzzzz"
local first_, second_, third_ = str_:match "^([^_]+)_([^_]+)_([^_]+)$"
Have a look at the string library on lua-users wiki.
string.find would additionally return the indexes where the matched substring was located/found. These two (start and end) indices are not useful to your case, which is why string.match would be a better tool.
Related
I want to find a specific string within a string.
For example, let's say I have the string
string = "username:quantopia;password:blabla
How can I then find quantopia?
I am using python 3.
Update: I am sorry I did not mention what I try before..
string.split('username:',1)[1].split(';',1)[0]
But this look very bad and not efficient, I was hoping for something better.
Just use regex as such:
import re
username = re.search("username:(.*);password", "username:quantopia;password:blabla").group(1)
print("username:", username)
This will output quantopia.
In this expression "username:(.*);password" you are saying "give me everything from username: to ;password" So this is why you're getting quantopia. This might as well be ":(.*);" as it will output the same thing in this case.
The simple solution is:
string = "username:quantopia;password:blabla"
username = "username"
if username in string:
# do work.
You might be better to just use split to create a dictionary so you dont need to use multiple regex to extract different parts of data sets. The below will split stirng into key value pairs then split key value pairs then pass the list of lists to dict to create a dictionary.
string = "username:quantopia;password:blabla"
data = dict([pairs.split(':') for pairs in string.split(';')])
print(f'username is "{data["username"]}" and password is "{data["password"]}"')
OUTPUT
username is "quantopia" and password is "blabla"
I am fairly new to Puppet and Ruby. Most likely this question has been asked before but I am not able to find any relevant information.
In my puppet code I will have a string variable retrieved from the fact hostname.
$n="$facts['hostname'].ex-ample.com"
I am expecting to get the values like these
DEV-123456-02B.ex-ample.com,
SCC-123456-02A.ex-ample.com,
DEV-123456-03B.ex-ample.com,
SCC-999999-04A.ex-ample.com
I want to perform the following action. Change the string to lowercase and then replace the
-02, -03 or -04 to -01.
So my output would be like
dev-123456-01b.ex-ample.com,
scc-123456-01a.ex-ample.com,
dev-123456-01b.ex-ample.com,
scc-999999-01a.ex-ample.com
I figured I would need to use .downcase on $n to make everything lowercase. But I am not sure how to replace the digits. I was thinking of .gsub or split but not sure how. I would prefer to make this happen in a oneline code.
If you really want a one-liner, you could run this against each string:
str
.downcase
.split('-')
.map
.with_index { |substr, i| i == 2 ? substr.gsub(/0[0-9]/, '01') : substr }
.join('-')
Without knowing what format your input list is taking, I'm not sure how to advise on how to iterate through it, but maybe you have that covered already. Hope it helps.
Note that Puppet and Ruby are entirely different languages and the other answers are for Ruby and won't work in Puppet.
What you need is:
$h = downcase(regsubst($facts['hostname'], '..(.)$', '01\1'))
$n = "${h}.ex-ample.com"
notice($n)
Note:
The downcase and regsubst functions come from stdlib.
I do a regex search and replace using the regsubst function and replace ..(.)$ - 2 characters followed by another one that I capture at the end of the string and replace that with 01 and the captured string.
All of that is then downcased.
If the -01--04 part is always on the same string index you could use that to replace the content.
original = 'DEV-123456-02B.ex-ample.com'
# 11 -^
string = original.downcase # creates a new downcased string
string[11, 2] = '01' # replace from index 11, 2 characters
string #=> "dev-123456-01b.ex-ample.com"
I have a string in excel that I need to extract a substring from
This is an example of the string:
<\Text Name="Text5"><TextValue>Hostname: hostnamehere</TextValue>
I'm new to regex and powershell, but I'm trying to find a way to extract the "hostname here" portion of the string. It's variable length, so indexing won't be reliable.
since you changed the sample, the comment code i posted won't work. [grin] this will, tho ...
$InStuff = '<\Text Name="Text5"><TextValue>Hostname: hostnamehere</TextValue>'
$InStuff.Split(':')[-1].Split('<')[0].Trim()
output = hostnamehere
if you have a set of sample strings, then you likely otta post them so the code can be arranged to handle the needed variants.
If that were xml, it would be straightforward
[xml]$xml = '<Text Name="Text5"><TextValue>Hostname: hostnamehere</TextValue></Text>'
(-split $xml.text.textvalue)[1]
hostnamehere
I have a string that looks like:
local str = "rootFolder\\<subFolder>\\<...>\\nFolder\\fileName";
where <...> could be a list of other folder names making the path/string very long. Also, I do not know what <subFolder> will actually be called since the folder name could be anything, i.e:
rootFolder\\folderA\\...
rootFolder\\folderB\\...
rootFolder\\folderC\\...
...
We can assume I know the name of the root folder because this will be known at runtime, so for now lets assume it is called rootFolder.
How can I extract the sub-string <subFolder> using a pattern to match against str?
I was thinking of something like:
string.match(str, "rootFolder\\(.*)\\.*"); to capture the first folderName under rootFolder in the folder/directory hierarchy and ignore anything else that follows it but this is not working because, although it does match, it also gets everything else that follows it and not just the part I need (I also tried using .+ instead of .*).
For example, I want to be able to do this:
local str = "rootFolder\\hello\\anotherFolder\\myFile";
-- this pattern does not work as expected:
local folderName = string.match(str, "rootFolder\\(.*)\\.*");
print(folderName == "hello"); -- true
Hope that makes sense. Thank you.
The answer was to use a minus:
local folderName = string.match(str, "rootFolder\\(.-)\\");
Something like that is coming in:
str="Hello;this;is;a;text"
What I do want as result is this:
result="72:101:108:108:111;116:104:105:115;..."
which should be the Text in ASCII.
You could use string matching to get each word separated by ; and then convert, concat:
local str = "Hello;this;is;a;text"
for word in str:gmatch("[^;]+") do
ascii = table.pack(word:byte(1, -1))
local converted = table.concat(ascii, ":")
print(converted)
end
The output of the above code is:
72:101:108:108:111
116:104:105:115
105:115
97
116:101:120:116
I'll leave the rest of work to you. Hint: use table.concat.
Here is another approach, which exploits that fact that gsub accepts a table where it reads replacements:
T={}
for c=0,255 do
T[string.char(c)]=c..":"
end
T[";"]=";"
str="Hello;this;is;a;text"
result=str:gsub(".",T):gsub(":;",";")
print(result)
Another possibility:
function convert(s)
return (s:gsub('.',function (s)
if s == ';' then return s end
return s:byte()..':'
end)
:gsub(':;',';')
:gsub(':$',''))
end
print(convert 'Hello;this;is;a;text')
Finding certain character or string (such as ";") can be done by using string.find - https://www.lua.org/pil/20.1.html
Converting character to its ASCII code can be done by string.byte - https://www.lua.org/pil/20.html
What you need to do is build a new string using two functions mentioned above. If you need more string-based functions please visit official Lua site: https://www.lua.org/pil/contents.html
Okay...I got way further, but I can't find how to return a string made up of two seperate strings like
str=str1&" "&str2