I am having a problem with a small number. I am using SUM function to sum certain numbers. If I add a zero to the range, it is not displaying zero. I don't know why.
A1
=SUM(B1:R1)*-1
C1 to L1
266864 -100000 -15136.15 -23688.82 -120870 -7169 -5550 1224 -0.03 4326
A2
=SUM(B2:R2)*-1
C2 to M2
=SUM(C3:C3) =SUM(D3:D3) =SUM(E3:E3) =SUM(F3:F3) =SUM(G3:G3) =SUM(H3:H3) =SUM(I3:I3) =SUM(J3:J3) =SUM(K3:K3) =SUM(L3:L3) =SUM(M3:M3)
A3
=SUM(B3:R3)*-1
C3 to M3
266864 -100000 -15136.15 -23688.82 -120870 -7169 -5550 1224 -0.03 4326 0
A1 is displaying 0, but A2 and A3 displays 9.09E-13
The number 9.09E-13 is another way (scientific notation) of saying 0.000000000000909495, a very small decimal number. What you are experiencing is a 15 digit precision floating point error.
Typically, you would use the ROUND function or something similar to remove the error (if you have to).
See Floating-point arithmetic may give inaccurate results in Excel for more information.
as I think,
might be some different formula on A1 cell is already placed or the type of A1 Cell is int and Value becomes in decimal or else, so make try this formula in different cell.
I wonder why you are using =SUM(C3:C3) etc. That is, Why use the sum function on a single cell. Unless there is a specific reason, I suggest you use = C3 instead. I've found that using the summation on a single cell can sometimes return answers that are incorrect. Don't know why, but it does. Therefore, long ago I quit using the sum unless there is a range that includes more than one cell.
Related
Ok, so I am trying to do something I thought was very simple, but it is turning out to be more complicated.
What I am trying to do:
Take a value through an if statement and return 1 or 0. But I want to be able to change the formula by changing values in cells and not editing the formula itself.
Example:
cell A1 = 41%
cell B1 = >
cell C1 = 40%
cell D1 = Formula with calculation
I want to create a formula that will tell me if that 41% is > than 40%, but if I change that > in B1 for a < (in a separate cell outside the cell with the formula) or I change C1 I want it to recalculate.
I have tried the following:
=IF(A1&B1&C1,1,0)
=IF(A1&INDIRECT(B1)&C1,1,0)
=IF(INDIRECT(A1)&INDIRECT(B1)&INDIRECT(C1),1,0)
all of these result in errors and I cannot figure out how to make it work. I am assuming it is taking the > and making it a string instead of a part of the formula.
Thanks for the help.
=COUNTIF( A1, B1&C1 )
... seems to do the trick, although converting C1 to text may give some rounding errors
An alternative would of course be to enumerate all the operations:
=--IFS( B1=">", A1>C1, B1="<", A1<C1 )
And add other operators as you come across them (NB the -- turns TRUE/FALSE into 1/0)
I have the following Excel formula but it is always returning False:
A1 Cell has the value 10%:
=IF(A1="10%","TRUE","FALSE")
I also tried the following:
=IF(A1=".10","TRUE","FALSE")
Or:
=A1=.1
Assuming your A1 cell is Number format and . for decimal.
Try =IF(A1=0.1,"TRUE","FALSE")
The answer depends on if you want to treat A1 as a string or as a percentage.
A1 is a string:
To ensure "35%" is a string, you can type the following in A1:
'35%
The single quote converts it to a string. Your formula should now work.
A1 is a percentage
You need to modify your formula like this, since 10% is really 10/100=0.1:
=IF(A1=10/100,"TRUE","FALSE")
If the value of your percentage is a floating-point number, you should consider that the rounding errors may affect your equality evaluation.
It may be safer to check if the two numbers (the value in the cell A1 and the percentage 10%) are almost equal (e.g. up to 5 digits):
=IF(ROUND(ABS(A1-0.1),5),"TRUE","FALSE")
How do I average a list of numbers whose values are greater than 0? I know I can use AVERAGEIF function in Excel
My data is located in A2, A5, A6, A10, A17.
I only want to average it if the data is greater than 0.
Since my data is not an range, I am not able to use AVERAGEIF Function range.
Need some help on this.
EDIT
For example,
I tried with three numbers:
1) 98.068 and 98.954 and 0 so my forumla looked like this:
=AVERAGE(IF(N(OFFSET(A2,{0,5,10},))>0,N(OFFSET(A2,{0,5,10},))))
The answer came out as 99.106. Not sure why.
A few options:
1)=SUM(SUMIF(INDIRECT({"A2","A5","A6","A10","A17"}),">0"))/SUM(COUNTIF(INDIRECT({"A2","A5","A6","A10","A17"}),">0"))
2)=AVERAGE(IF(N(INDIRECT({"A2","A5","A6","A10","A17"}))>0,N(INDIRECT({"A2","A5","A6","A10","A17"}))))
3)
=AVERAGE(IF(N(OFFSET(A2,{0,3,4,8,15},))>0,N(OFFSET(A2,{0,3,4,8,15},))))
2) and 3) must be committed as array formulas**
Regards
(0) A simple method
=SUM(A2*(A2>0),A5*(A5>0),A6*(A6>0),A10*(A10>0),A17*(A17>0))/SUM(A2>0,A5>0,A6>0,A10>0,A17>0)
(4) A more general method
=SUM((A1:A20>0)*A1:A20*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))/
SUM((A1:A20>0)*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))
The second one is an array formula and must be entered with CtrlShiftEnter
If it's possible to have text in the cells rather than numbers, then this should replace the first formula:-
=SUM(N(A2)*(A2>0),N(A5)*(A5>0),N(A6)*(A6>0),N(A10)*(A10>0),N(A17)*(A17>0))/SUM(N(A2)>0,N(A5)>0,N(A6)>0,N(A10)>0,N(A17)>0)
(I haven't used N in the > brackets in the numerator because I reason that if A2 etc. is text, the product will always be zero)
I can't persuade N to work with arrays in the second formula, so at the moment I have the rather lengthy
=SUM((IF(ISNUMBER(A1:A20),A1:A20,0)>0)*IF(ISNUMBER(A1:A20),A1:A20,0)*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))/
SUM((IF(ISNUMBER(A1:A20),A1:A20,0)>0)*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))
but I have tested it on text values and negative numbers and it does seem fine.
The only exception is if one of the cells contains TRUE. In this case the first formula will count it as 1, the second formula will ignore it.
I have 3 numbers in excel.
A1. 498
A2. 899
A3. 5209
I want the numbers as the followings:
B1. 49800
B2. 89900
B3. 52090
I am still finding the solutions via online but most of the resource is discussing about leading zeros.
Please, could you kindly give me any ideas? Thanks.
I hope this formula may be of some use:
=A1 & REPT("0"; 5 - LEN(A1))
Thought this does not set the format of the cell itself (which I doubt can be done as you are changing the value of the cell by adding the zeros)
The formula only works if you are dealing with numbers as text, so you may need to convert them to text in the formula (TEXT(A1; "0") instead of A1)
you can do this one quite easily without VBA - using an IF and the very handy REPT function:
=IF(LEN(H13)<5,H13&REPT(0,5-LEN(H13)),H13)
Essentially - if the length is less than 5 - you repeat 0 up to the amount of times that its missing.
Seems like simple math to me. Essentially you want to shift left (base 10) a certain number of times. We can do this by:
Calculate the ceiling of the base-10 logarithm of the value to get it's "length"
Subtract the result from the target "length" of 5, this is the number of places we want to shift
Take 10 to this power and multiply back by the value.
In other words, where x represents the value in column A you want to transform:
In Excel, this would be expressed as:
=A1*POWER(10,(5-CEILING(LOG10(A1),1)))
Following is the which I am trying :
Let this number 6,123,456.33 in Cell A1,
Then in Cell B1 use this formula =TEXT(A1,"#,###,###.##"), will give you 6,123,456.33.
Then in Cell C1 use this formula = SUBSTITUTE(B1,",",".") ,will give you 6.123.456.33
Then in Cell D1 use this formula =","&RIGHT(H12,2), will give you ,33.
Then again come to Cell C1 Do text to columns or other options to remove the last digits with decimals and then concatenate result with Cell D1 shows the last three digits.
This tip will ends up in 6.123.456,33
But Problem is in point no. 5.
How should I remove .33 from cell C1?
TRUNC is not working on C1.
Any Suggestions ?
Seems like you don't mind having the result as text (and I can't seem to find a way to custom format it...) and as such, you can use the formula:
=SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(TEXT(A1,"#,###.00"),",","#"),".",","),"#",".")
There's a triple substitution, one to remove , for # (a dummy character), second to change . to ,, then last from the dummy # to ..
If A1 is always a 7 digit number with 2 decimals then you could use TEXT function like this:
=TEXT(A1*100,"0\.000\.000\,00")