Passing PartialView through child action - asp.net-mvc-5

I'm new to MVC, and now I'm trying to understand the conception of partial views. So, the question is: Does client fully recieve a a whole markup of new html page, when I'm passing a PartialViewRezult from controller to a View by child action. May be it uses AJAX?

In MVC, If you are returning a PartialView to/from an action method then It will return only markup available in your PartialView. It will not wrap your partial view markup in html or body tag. and There is no ajax involved to render a partial view unless you are using an explicit Ajax call.

Related

.net 6 what is the proper way to add a form to a _Layout and handle the post

I need to add a subscribe form to my Layout so it is on all pages in the right side area.
How do I handle the post action as layouts dont have a codefile?
What I have so far is my layout has a signup partial and in that partial is the form. At this point I ponder what to do and what is the correct and safe way on handling user input and the action handler.
Create a Razor page e.g. Subscribe.cshtml that handles the form submission and specify that page in the asp-page attribute of the form tag helper:
<form method="post" asp-page="/Subscribe">
Process the submission in the OnPost handler of SubscribeModel.

substitute for asp.net web form server side controls in mvc 5

I am rather new to ASP.NET MVC5. I know server side controls are not working directly in MVC, but there will be some way by which we will get similar controls in MVC5 for rapid development. Can you suggest me how can I find such controls? Can you list out all such mostly used common controls for MVC5?
Thanks in advance.
There's no concept of a "control" in MVC. There's various things that function similar to Web Form controls, but it depends on what you're trying to do.
HTML Helpers are similar in that you essentially call a function that returns rendered HTML. You can extend HtmlHelper to add your own.
Child actions function as a sort of separate request within the context of the main request. They accept parameters like an action, can do all the backend stuff an action can do (query database, etc.) and return a view rendered based on a model, like a normal view.
A partial view, in general, can function as a control as it allows you to insert a snippet of HTML somewhere.
Editor templates and display templates can be used in conjunction with Html.EditorFor and Html.DisplayFor, respectively to render a form field or some sort of HTML display for a particular property on your model.

How can I implement dynamic scrolling with ajax / JSF2.2?

I have a list of items that I would like to present. I want to ajax load items as the user scrolls down (I have no problem doing this using JS). The problem that I am experiencing is that I can only re-render the whole ui:repeat and not just a component that contains new items.
Is there an common way to do this? Can I code a bean method that returns only the <li> part of the dom and handle the weaving on the client-side? Should I just write a method that returns raw data and then use JS to handle rendering?
PS .I am sure this has been asked before, but I can't find the relevant posts

JSF: Bookmarkability with ViewScoped

I am trying to make my app "Bookmarkable", and i am using view parameters to achieve it.
And i think i still do not get the right way to do it right in JSF, even after reading this, and many others.
My problem is that the get parameters get lost after any non-ajax postback, i mean, the parameter value is still set in the bean and the app works correctly, but it gets removed from the URL making the URL invalid.
For instance, having an URL like http://company.com/users?id=4, as soon as that page executes a non-ajax postback (for uploading data, for instance) the URL becomes just http://company.com/users. The app continues to work correctly, but the link is not any more "Bookmarkable".
Is there any way to prevent the non-ajax postbacks removing the viewParams from the URL?
My use case is to be able to bookmark a page to EDIT an object, and there i need to be able to upload data (if not i would not use non-ajax postbacks). I know i would not need any postback if i would want to bookmark the page to only VIEW the data of the object, but that is not my case.
I could also do a redirect to the same page with the same params, and let the app to recreate the view scoped bean, but then i really do not see any benefit over request scoped beans...
Any suggestion is very appreciated.
This behaviour is "by design". The <h:form> generates a HTML <form> element with an action URL without any view parameters. The synchronous POST request just submits to exactly that URL which thus get reflected as-is in browser's address bar. If you intend to keep the view parameters in the URL, while using ajax is not an option, then you basically need to create a custom ViewHandler which has the getActionURL() overridden to include the view parameters. This method is used by <h:form> to generate the action URL.
public String getActionURL(FacesContext context, String viewId) {
String originalActionURL = super.getActionURL(context, viewId);
String newActionURL = includeViewParamsIfNecessary(context, originalActionURL);
return newActionURL;
}
Or, as you're based on the comments already using OmniFaces, you could also use its <o:form> component which basically extends the <h:form> with the includeViewParams attribute which works much like the same as in <h:link> and <h:button>.
<o:form includeViewParams="true">
...
</o:form>
This way all <f:viewParam> values will end up in the form action URL.
See also:
Handling view parameters in JSF after post

Wicket : Can a Panel or Component react on a form submit without any boilerplate code?

I am currently evaluating Wicket and I am trying to figure out how things work.
I have a question regarding form submit and panels (or other components).
Imagine a custom wicket panel which contains a text field, doing as-you-type validation using ajax. This panel is added to a form.
How can the Panel react a form submit (let's say because javascript/ajax is unavailable)?
I am currently only aware of one solution: calling a panel's method inside the Form onSubmit() method. But this seems not like a "reusable" approach here, because I have to add boilerplate code to every form's onSubmit() which contains the panel (and every developer which use the panel must know this).
So here comes my question: Is there any way that a Panel/Component can "detect" a form submit in some way? Or is there any other solution beside this?
Thank you.
Make your panels implement org.apache.wicket.markup.html.form.IFormModelUpdateListener, and the updateModel() method should be called when the containing form is submitted and passes validation.
There's a good example of code using this by one of the wicket authors at the Wicket In Action blog.
Well, you could simply do the following:
Panel{
Form{
onSubmit(){
Panel.this.onSubmit();
}
}
protected void onSubmit(){}
}
...
This means that any panel that extends your panel need only override the onSubmit and the form no matter what it is in html will call that method. That way you can extend the panel and only override one method for each form.
With regard to form components, the framework handles it for you transparently. Forms are aware of any child form components, even if they haven't been added directly to the parent form.
I would have a Form inside that Panel. This way, you can reuse that Panel without requiring an external Form. As Forms can not be nested inside each other in HTML, Wicket will swap the inner Form(s) into 's transparently, but will make sure that each of the inner Forms takes part of the form processing (validation,..).
You can override the OnSubmit() function of the Form in your Panel. Wicket will call it for you.
what do you mean by "react"? I have only started recently with Wicket, but FWIK, form submit updates the model of a component, and then it calls onSubmit(), which you can override to take special actions beyond that. See Wicket in Action, chapter 6.
After that, the page (and it's components) get re-rendered, using the updated model, so basically, they really "react" on a submit, with quite few lines of code.
For your mentioned case with Component in a Form, have a look at the CompoundPropertyModel.
Implementing IFormSubmitListner and IFormModelUpdateListener shall call the respective methods during a form submit.
However, if you want to do some processing after form submit, I'm afraid you have no choice but to write some boilerplate code yourself.

Resources