I am trying to use the following code
put 7 into lFoodID
lineoffset (lFoodID,gArrFood) into tArrFoodLine
to find the line that contain the number 7 in the array below
17 Banana
20 Beans
2 Beef
1 Bread
8 Cabagge
6 Chicken
5 Eggs
15 Ice Cream
3 Mango
7 Pork
18 Rice
4 Salad
19 fried fish
It's returning 1. I know that this is because 17 contains the number 7. I have tried
set the wholeMatches to true
but that does not work either. I believe that regex (^(7) should work but I can figure out how to use regex in lineoffset.
I'm not sure what you're really after and I wonder if your data really look like what you have provided here. I assume that your data are as displayed, but this may lead do a solution that's slightly different from what you really want.
If you want to get the product associated with an index, you can use the following script
put fld 1 into myList
replace space&space with tab in myList
repeat until (tab&tab is not in myList and space&space is not in myList)
replace space&space with space in myList
replace tab&tab with tab in myList
end repeat
split myList by cr and tab
put myList[7] into myProduct
put myProduct
MyProduct contains the product name. Note that you won't need the repeat loop if your data is formatted properly. If you really want to have the index, use this:
put fld 1 into myList
put 7 into myIndex
if word 1 of myList is not myIndex then
put number of lines of char 1 to offset(cr & "7" & space ,myList) of myList into myLine
else
put 1 into myLine
end if
put myLine
MyLine contains the complete record in your list.
Related
Here's my question. I'm using Lua and I have a string that looks something like this:
"Start1.2.3.4.5-1.2.3.4.5-1.2.3.4.5-1.2.3.4.5-1.2.3.4.5End"
The five numbers between each hyphen are all paired to the same "object" but each represents a separate set of data. The period between the numbers separates the data.
So after Start, 1 = our first value, 2 = our second value, 3 = our third value, 4 = our fourth value, and 5 = our fifth value. These 5 values are stored to the same object. Then we hit our first hyphen which separates the "objects". So there's 5 objects and 5 values per object.
I used 1.2.3.4.5 as an example but these numbers will be randomized with up to 4 digits. So it could say something like Start12.3.100.1025.50- etc...
Hopefully that makes sense. Here's what I have done so far:
MyString = the long string I posted above
local extracted = string.match(MyString, "Start(.*)")
This returns everything beyond Start in the string. However, I want it to return everything after Start and then cut off once it reaches the next hyphen. Then from that point on I'll repeat the process but instead find everything between the hyphens until I reach End. I also need to filter out the periods. Also, the hyphens/periods can change to something else as long as they aren't numbers.
Any ideas on how to do this?
Just use a pattern that captures anything that contains numbers and periods.
"([%d%.]+)" Note that you have to escape the period with % as it is a magic character.
local text = "Start1.2.3.4.5-1.2.3.4.5-1.2.3.4.5-1.2.3.4.5-1.2.3.4.5End"
for set in text:gmatch("([%d%.]+)") do
print(set)
local numbers = {}
for num in set:gmatch("%d+") do
table.insert(numbers, num)
end
print(table.unpack(numbers))
end
prints:
1.2.3.4.5
1 2 3 4 5
1.2.3.4.5
1 2 3 4 5
1.2.3.4.5
1 2 3 4 5
1.2.3.4.5
1 2 3 4 5
1.2.3.4.5
1 2 3 4 5
I have a data frame that has a column with text data in it. I want to remove words that mean nothing and convert negations like "isn't" to "is not" from the text data. Because when I remove the punctuations "isn't" becomes "isn t" and when I will remove words having letters less than length 2 "t" will be deleted completely. So, I want to do the following 3 tasks-
1) convert negations like "isn't" to "is not"
2) remove words that mean nothing
3) remove less than length 2 letters
For eg, the df column looks similar to this-
user_id text data column
1 it's the coldest day
2 they aren't going
3 aa
4 how are you jkhf
5 v
6 ps
7 jkhf
The output should be-
user_id text data column
1 it is the coldest day
2 they are not going
3
4 how are you
5
6
7
How to implement this?
def is_repetitive(w):
"""Predicate, true for words like jj or aaaaa."""
w = str(w) # caller should have provided a single word as input
return len(w) > 1 and all((c == w[0] for c in w[1:]))
Feed all words in the corpus to that function,
to accumulate a list of repetitive words.
Then add such words to your list of stop words.
1) Use SpaCy or NLTK's lemmatization tools to convert strings (though they do other things like convert plural to singular as well - so you may end up needing to write your own code to do this).
2) Use stopwords from NLTK or spacy to remove the obvious stop words. Alternatively, feed them your own list of stop words (their default stop words are things like is, a, the).
3)Use a basic filter, if len<2 remove row
I have two Lists in an excel spreadsheet.
The first list has strings such as
1234 blue 6 abc
xyz blue/white 1234
abc yellow 123
The other list contains substrings of the first list
yellow
blue/white
blue
Result
1234 blue 6 abc blue
xyz blue/white 1234 blue/white
abc yellow 123 yellow
Now I need some kind of match formula to assign the correct value from the second list to the first. The problem, there is no specific pattern to determine where the color substring is positioned. The other problem, the values are not totally unique. As my example above shows, the lookup needs to be in an order (checking for "blue/white" before checking for "blue").
I played around the formulas like match, find also using wildcards * but couldn't come to any result.
A similar question asked here on SO covers the opposite case How to find if substring exists in a list of strings (and return full value in list if so)
Any help is appriciated. A formula would be cool, but using vba is also okay.
=INDEX(D$7:D$9, AGGREGATE(15, 7, ROW($1:$3)/ISNUMBER(SEARCH(D$7:D$9, A2)), 1))
Here is a solution with VBA
List 1 (strings) is in column A
List 2 (substrings) is in column C
The code basically contains to nested while loops checking whether the substring is inside the string.
row_1 = 1
While .Cells(row_1, "A") <> ""
row_2 = 1
While .Cells(row_2, "C") <> ""
color = .Cells(row_2, "C").Value
If InStr(1, .Cells(row_1, "A"), color, vbBinaryCompare) > 0 Then
.Cells(row_1, "B") = color
End If
row_2 = row_2 + 1
Wend
row_1 = row_1 + 1
Wend
I have 2 string formatted as such:
(1234, 4567)
And I have a list
points {0 1 2 4}
I would like to extract 2 integers from the first list and replace the first two integers in the list, after that extract two more integers from the 2nd list and replace the 3rd and 4th integers in the list so at the end I will have a list of 4 integers from the two strings.
So far I have tried all kind of things but always end up with errors or brackets in the list which I do not want. I feel I am missing out on the easy way to do that.
With the first set of values, you can parse with scan or regexp; in this case, I think scan looks better:
set input "(1234, 5678)"
scan $input "(%d,%d)" a b
To update a Tcl list (formally, one in a variable), you use lset; you can give a sequence of (zero-based) indices to it to navigate into the exact place in the list where you want to update:
set workingArea "points {0 1 2 4}"
lset workingArea 1 2 $a
lset workingArea 1 3 $b
puts $workingArea
# prints: points {0 1 1234 5678}
I need to count how many times same string happens in 30 different cells.
Example:
"kat"
"hund"
"kat"
"mus"
"hund"
"kat"
I tried Countif(A1:A6,"kat"). It shows "3" because "kat" appears 3 times. After that I would make a line with "hund" and one with "mus". This does not work, can anyone help?
In the column next to it put: =COUNTIF(A$1:A$6,A1) (or =TÆL.HVIS(A$1:A$6,A1) in a Danish Excel)
Drag that down, and you'll get:
kat 3
hund 2
kat 3
mus 1
hund 2
kat 3
With a slight modification you can figure out the n'th occurence of a word, just use =COUNTIF(A$1:A1,A1), which would give:
kat 1
hund 1
kat 2
mus 1
hund 2
kat 3
For future reference: Names for Excel functions in English and Danish, Official list of Danish Excel functions. Click on the function in the official list to get more information and to make sure you get the correct name (the overview misses "." in some functions).
What you have is already nearly correct, let's assume you have Column A full of Animals (30)
Now you need 3 Formulas, one for each animal.
=COUNTIF(A1:A30;"hund")
=COUNTIF(A1:A30;"kat")
=COUNTIF(A1:A30;"mus")
the A1:A30 defines the range and the name in " behind the : defines the word you search for