Connect 4 Like Game - python-3.x

Question

I am making a connect four like game in python, what I have so far is creating the board and implementing game play against the computer. I am running into the issue that does not allow me to play past the second row. Any ideas on why?
#Define the board
row = int(input("Please enter # of rows: ")) #User input Rows
column = int(input("Please enter # of columns: ")) #User input Columns
board = [] #empty board
space = ' '
p1 = 'x'
p2 = 'o'
#create board based on user input
for i in range(0,row):
board.append([])
for j in range(0, column):
board[i].append(space)
print(board)
#print board with character decorations
for i in board:
line=''
print('+'+'-+'*len(i))
for j in range(len(i)):
line = line + '|'+i[j]
line = line + '|'
print(line)
print('+'+'-+'*len(i))
print(len(board))
while True:
#User input column
myC = int(input("Player 1, choose your column: "))
i = len(board)-1
x = len(board)-1
while i >= 0:
if board[x][myC] == space:
i = i+1
board[x][myC] = 'x'
break
elif board[x][myC] == p1 or p2:
i = i+1
x = x - 1
print(x)
board[x][myC] = 'x'
break
# print the board!
for i in board:
line=''
print('+'+'-+'*len(i))
for j in range(len(i)):
line = line + '|'+i[j]
line = line + '|'
print(line)
print('+'+'-+'*len(i))
#Computer input column
from random import randint
theC = randint(0, len(board)-1)
print("Computer's Turn: Column " , theC)
i = len(board)-1
x = len(board)-1
while i >= 0:
if board[x][theC] == space:
board[x][theC] = 'o'
i = i+1
break
elif board[x][theC] == p1 or p2:
i = i+1
x = x - 1
print(x)
board[x][theC] = 'o'
break
# print the board!
for i in board:
line=''
print('+'+'-+'*len(i))
for j in range(len(i)):
line = line + '|'+i[j]
line = line + '|'
print(line)
print('+'+'-+'*len(i))

Answer 1

I believe I figured out what's going on. Your x is always initialized to len(board)-1 and then if the space is occupied it is reduced by one. If you make a (>2)x(>2) board and row 0 is occupied then this will always force x = 2.
This is close to correct, but what you actually need is to iterate through all rows until you find the first unoccupied row. I created a loop that will find the first row and assign that to the value of x. I tested it out and I'm now able to play passed 2 rows.
#Define the board
row = int(input("Please enter # of rows: ")) #User input Rows
column = int(input("Please enter # of columns: ")) #User input Columns
board = [] #empty board
space = ' '
p1 = 'x'
p2 = 'o'
#create board based on user input
for i in range(0,row):
board.append([])
for j in range(0, column):
board[i].append(space)
print(board)
#print board with character decorations
for i in board:
line=''
print('+'+'-+'*len(i))
for j in range(len(i)):
line = line + '|'+i[j]
line = line + '|'
print(line)
print('+'+'-+'*len(i))
print(len(board))
while True:
#User input column
myC = int(input("Player 1, choose your column: "))
i = len(board)-1
x = len(board)-1
while i >= 0:
if board[x][myC] == space:
i = i+1
board[x][myC] = 'x'
break
# Find last empty row for new piece
elif board[x][myC] == p1 or p2:
for j in range(x-1,-1,-1):
if board[j][myC] == space:
x = j
break
i = i+1
#x = x - 1
print(x)
board[x][myC] = 'x'
break
# print the board!
for i in board:
line=''
print('+'+'-+'*len(i))
for j in range(len(i)):
line = line + '|'+i[j]
line = line + '|'
print(line)
print('+'+'-+'*len(i))
#Computer input column
from random import randint
theC = randint(0, len(board)-1)
print("Computer's Turn: Column " , theC)
i = len(board)-1
x = len(board)-1
while i >= 0:
if board[x][theC] == space:
board[x][theC] = 'o'
i = i+1
break
# Find last empty row for new piece
elif board[x][theC] == p1 or p2:
for j in range(x-1,-1,-1):
if board[j][theC] == space:
x =j
break
i = i+1
#x = x - 1
print(x)
board[x][theC] = 'o'
break
# print the board!
for i in board:
line=''
print('+'+'-+'*len(i))
for j in range(len(i)):
line = line + '|'+i[j]
line = line + '|'
print(line)
print('+'+'-+'*len(i))