Shell Script to unzip files and read them sequentially - linux

I have a list of zipped folders which contains xml files in it.
I want to write a linux shell script which unzips the folder sequentially , read them and print the file name if it contains particular string say "Apple INC."
I have tried following code.
for x in *.zip
do unzip $x
if grep -i "Apple INC" $x
then
echo $x
fi
done
can anyone help me in getting it right?
Thank you.

You can use unzip -p to unzip files to standard output, and pipe the output directly to grep. The -q options prevents grep from outputting the matching lines.
for z in *.zip ; do
if unzip -p "$z" | grep -qi 'apple inc' ; then
echo "$z"
fi
done
Have you noticed how the code is indented?

Related

Not every command is being for in a while loop

I am trying to make a script what looks at a folder and will automatically encode files that go into that folder using hand brake. I want to do this doing monitoring the folder using inotify putting the new additions to the folder into a list then using a cron job to encode them overnight. However when using a while loop to loop over the list handbrake only encodes the first file exists then the scripts carrys on to after the loop without doing every file in the list. Here is the script that is calling handbrake:
#!/bin/bash
while IFS= read -r line
do
echo "$(basename "$line")"
HandBrakeCLI -Z "Very Fast 1080p30" -i "$line" -o "$line.m4v"
rm "$line"
done < list.txt
> list.txt
When testing the loop with a simple echo instead of the HandBrakeCLI it works fine and prints out every file so I have no idea what is wrong.
Here is the scripts that is monitoring the folder incase that is the problem:
#!/bin/bash
if ! [ -f list.txt ]
then
touch list.txt
fi
inotifywait -m -e create --format "%w%f" tv-shows | while read FILE
do
echo "$FILE" >> list.txt
done
Any help would be great, thanks
EDIT:
Just to be more specific, the script works fine for the first file in the list.txt, it encodes it no problem and removes the old version, but then it doesn't do any of the others in the list
Taken from here
To solve the problem simply
echo "" | HandBrakeCLI ......
or
HandBrakeCLI ...... < /dev/null

How to pipe files one by one from list into script?

I have a list of files that I need to pipe into a shell script. I can list the files within a directory by using the following:
ls ~/data/2121/*SOMEFILE*
resulting in:
2121.SOMEFILEaa
2121.SOMEFILEab
2121.SOMEFILEac
and so on...
I have another script that performs some processing on a single file (2121.SOMEFILEaa) which I run by using the following command:
bash runscript ../data/2121/2121.SOMEFILEaa
However, I need to make this more efficient by piping individual files from the list of files generated via ls into the script. How can I pipe the results from the ls ~/data/2121/*SOMEFILES* command--file by file--into the runscript script?
Another option
ls ~/data/2121/*SOMEFILE* | xargs -L1 bash runscript
I think you are looking for this:
for file in ~/data/2121/*SOMEFILE*; do
bash runscript "$file"
done
In this way, you're calling bash runscript for each file.
$ cat pipe.sh
#!/bin/bash
## Store data from pipe to variable $PIPE ------#
_read_pipe(){ #
while read -t 10 pipe; do
if [ -n "$pipe" ] ;then
PIPE="$PIPE $pipe" ;fi ;done ;}
## your code -----------------------------------#
_read_pipe #
for kung_foo in $PIPE ;do
echo $kung_foo ;done
$ ls 2121.SOMEFILE* | ./pipe.sh
2121.SOMEFILEaa
2121.SOMEFILEab
2121.SOMEFILEac
and so on...
[ -t ] is for timeout
I hope this helps,
cheers Karim

Output archive comment of a zip file

How can I output the comment archive of a zip file? Basically I want to copy the zip archive comment to the clipboard.
zip -z file
prompts me to enter a new comment, how can I only output it, without prompt?
You need to use unzip and not zip to do so.
unzip -z file
will output the comments saved in the zip file.
In android, busybox unzip has no -z option (assuming busybox is even installed).
ZIP="/path/to/archive.zip"; X=$(echo . | zip -z "$ZIP" | head -2 | tail -1); echo $X | zip -z "$ZIP" >/dev/null; echo $X

grep from tar.gz without extracting [faster one]

Am trying to grep pattern from dozen files .tar.gz but its very slow
am using
tar -ztf file.tar.gz | while read FILENAME
do
if tar -zxf file.tar.gz "$FILENAME" -O | grep "string" > /dev/null
then
echo "$FILENAME contains string"
fi
done
If you have zgrep you can use
zgrep -a string file.tar.gz
You can use the --to-command option to pipe files to an arbitrary script. Using this you can process the archive in a single pass (and without a temporary file). See also this question, and the manual.
Armed with the above information, you could try something like:
$ tar xf file.tar.gz --to-command "awk '/bar/ { print ENVIRON[\"TAR_FILENAME\"]; exit }'"
bfe2/.bferc
bfe2/CHANGELOG
bfe2/README.bferc
I know this question is 4 years old, but I have a couple different options:
Option 1: Using tar --to-command grep
The following line will look in example.tgz for PATTERN. This is similar to #Jester's example, but I couldn't get his pattern matching to work.
tar xzf example.tgz --to-command 'grep --label="$TAR_FILENAME" -H PATTERN ; true'
Option 2: Using tar -tzf
The second option is using tar -tzf to list the files, then go through them with grep. You can create a function to use it over and over:
targrep () {
for i in $(tar -tzf "$1"); do
results=$(tar -Oxzf "$1" "$i" | grep --label="$i" -H "$2")
echo "$results"
done
}
Usage:
targrep example.tar.gz "pattern"
Both the below options work well.
$ zgrep -ai 'CDF_FEED' FeedService.log.1.05-31-2019-150003.tar.gz | more
2019-05-30 19:20:14.568 ERROR 281 --- [http-nio-8007-exec-360] DrupalFeedService : CDF_FEED_SERVICE::CLASSIFICATION_ERROR:408: Classification failed even after maximum retries for url : abcd.html
$ zcat FeedService.log.1.05-31-2019-150003.tar.gz | grep -ai 'CDF_FEED'
2019-05-30 19:20:14.568 ERROR 281 --- [http-nio-8007-exec-360] DrupalFeedService : CDF_FEED_SERVICE::CLASSIFICATION_ERROR:408: Classification failed even after maximum retries for url : abcd.html
If this is really slow, I suspect you're dealing with a large archive file. It's going to uncompress it once to extract the file list, and then uncompress it N times--where N is the number of files in the archive--for the grep. In addition to all the uncompressing, it's going to have to scan a fair bit into the archive each time to extract each file. One of tar's biggest drawbacks is that there is no table of contents at the beginning. There's no efficient way to get information about all the files in the archive and only read that portion of the file. It essentially has to read all of the file up to the thing you're extracting every time; it can't just jump to a filename's location right away.
The easiest thing you can do to speed this up would be to uncompress the file first (gunzip file.tar.gz) and then work on the .tar file. That might help enough by itself. It's still going to loop through the entire archive N times, though.
If you really want this to be efficient, your only option is to completely extract everything in the archive before processing it. Since your problem is speed, I suspect this is a giant file that you don't want to extract first, but if you can, this will speed things up a lot:
tar zxf file.tar.gz
for f in hopefullySomeSubdir/*; do
grep -l "string" $f
done
Note that grep -l prints the name of any matching file, quits after the first match, and is silent if there's no match. That alone will speed up the grepping portion of your command, so even if you don't have the space to extract the entire archive, grep -l will help. If the files are huge, it will help a lot.
For starters, you could start more than one process:
tar -ztf file.tar.gz | while read FILENAME
do
(if tar -zxf file.tar.gz "$FILENAME" -O | grep -l "string"
then
echo "$FILENAME contains string"
fi) &
done
The ( ... ) & creates a new detached (read: the parent shell does not wait for the child)
process.
After that, you should optimize the extracting of your archive. The read is no problem,
as the OS should have cached the file access already. However, tar needs to unpack
the archive every time the loop runs, which can be slow. Unpacking the archive once
and iterating over the result may help here:
local tempPath=`tempfile`
mkdir $tempPath && tar -zxf file.tar.gz -C $tempPath &&
find $tempPath -type f | while read FILENAME
do
(if grep -l "string" "$FILENAME"
then
echo "$FILENAME contains string"
fi) &
done && rm -r $tempPath
find is used here, to get a list of files in the target directory of tar, which we're iterating over, for each file searching for a string.
Edit: Use grep -l to speed up things, as Jim pointed out. From man grep:
-l, --files-with-matches
Suppress normal output; instead print the name of each input file from which output would
normally have been printed. The scanning will stop on the first match. (-l is specified
by POSIX.)
Am trying to grep pattern from dozen files .tar.gz but its very slow
tar -ztf file.tar.gz | while read FILENAME
do
if tar -zxf file.tar.gz "$FILENAME" -O | grep "string" > /dev/null
then
echo "$FILENAME contains string"
fi
done
That's actually very easy with ugrep option -z:
-z, --decompress
Decompress files to search, when compressed. Archives (.cpio,
.pax, .tar, and .zip) and compressed archives (e.g. .taz, .tgz,
.tpz, .tbz, .tbz2, .tb2, .tz2, .tlz, and .txz) are searched and
matching pathnames of files in archives are output in braces. If
-g, -O, -M, or -t is specified, searches files within archives
whose name matches globs, matches file name extensions, matches
file signature magic bytes, or matches file types, respectively.
Supported compression formats: gzip (.gz), compress (.Z), zip,
bzip2 (requires suffix .bz, .bz2, .bzip2, .tbz, .tbz2, .tb2, .tz2),
lzma and xz (requires suffix .lzma, .tlz, .xz, .txz).
Which requires just one command to search file.tar.gz as follows:
ugrep -z "string" file.tar.gz
This greps each of the archived files to display matches. Archived filenames are shown in braces to distinguish them from ordinary filenames. For example:
$ ugrep -z "Hello" archive.tgz
{Hello.bat}:echo "Hello World!"
Binary file archive.tgz{Hello.class} matches
{Hello.java}:public class Hello // prints a Hello World! greeting
{Hello.java}: { System.out.println("Hello World!");
{Hello.pdf}:(Hello)
{Hello.sh}:echo "Hello World!"
{Hello.txt}:Hello
If you just want the file names, use option -l (--files-with-matches) and customize the filename output with option --format="%z%~" to get rid of the braces:
$ ugrep -z Hello -l --format="%z%~" archive.tgz
Hello.bat
Hello.class
Hello.java
Hello.pdf
Hello.sh
Hello.txt
All of the code above was really helpful, but none of it quite answered my own need: grep all *.tar.gz files in the current directory to find a pattern that is specified as an argument in a reusable script to output:
The name of both the archive file and the extracted file
The line number where the pattern was found
The contents of the matching line
It's what I was really hoping that zgrep could do for me and it just can't.
Here's my solution:
pattern=$1
for f in *.tar.gz; do
echo "$f:"
tar -xzf "$f" --to-command 'grep --label="`basename $TAR_FILENAME`" -Hin '"$pattern ; true";
done
You can also replace the tar line with the following if you'd like to test that all variables are expanding properly with a basic echo statement:
tar -xzf "$f" --to-command 'echo "f:`basename $TAR_FILENAME` s:'"$pattern\""
Let me explain what's going on. Hopefully, the for loop and the echo of the archive filename in question is obvious.
tar -xzf: x extract, z filter through gzip, f based on the following archive file...
"$f": The archive file provided by the for loop (such as what you'd get by doing an ls) in double-quotes to allow the variable to expand and ensure that the script is not broken by any file names with spaces, etc.
--to-command: Pass the output of the tar command to another command rather than actually extracting files to the filesystem. Everything after this specifies what the command is (grep) and what arguments we're passing to that command.
Let's break that part down by itself, since it's the "secret sauce" here.
'grep --label="`basename $TAR_FILENAME`" -Hin '"$pattern ; true"
First, we use a single-quote to start this chunk so that the executed sub-command (basename $TAR_FILENAME) is not immediately expanded/resolved. More on that in a moment.
grep: The command to be run on the (not actually) extracted files
--label=: The label to prepend the results, the value of which is enclosed in double-quotes because we do want to have the grep command resolve the $TAR_FILENAME environment variable passed in by the tar command.
basename $TAR_FILENAME: Runs as a command (surrounded by backticks) and removes directory path and outputs only the name of the file
-Hin: H Display filename (provided by the label), i Case insensitive search, n Display line number of match
Then we "end" the first part of the command string with a single quote and start up the next part with a double quote so that the $pattern, passed in as the first argument, can be resolved.
Realizing which quotes I needed to use where was the part that tripped me up the longest. Hopefully, this all makes sense to you and helps someone else out. Also, I hope I can find this in a year when I need it again (and I've forgotten about the script I made for it already!)
And it's been a bit a couple of weeks since I wrote the above and it's still super useful... but it wasn't quite good enough as files have piled up and searching for things has gotten more messy. I needed a way to limit what I looked at by the date of the file (only looking at more recent files). So here's that code. Hopefully it's fairly self-explanatory.
if [ -z "$1" ]; then
echo "Look within all tar.gz files for a string pattern, optionally only in recent files"
echo "Usage: targrep <string to search for> [start date]"
fi
pattern=$1
startdatein=$2
startdate=$(date -d "$startdatein" +%s)
for f in *.tar.gz; do
filedate=$(date -r "$f" +%s)
if [[ -z "$startdatein" ]] || [[ $filedate -ge $startdate ]]; then
echo "$f:"
tar -xzf "$f" --to-command 'grep --label="`basename $TAR_FILENAME`" -Hin '"$pattern ; true"
fi
done
And I can't stop tweaking this thing. I added an argument to filter by the name of the output files in the tar file. Wildcards work, too.
Usage:
targrep.sh [-d <start date>] [-f <filename to include>] <string to search for>
Example:
targrep.sh -d "1/1/2019" -f "*vehicle_models.csv" ford
while getopts "d:f:" opt; do
case $opt in
d) startdatein=$OPTARG;;
f) targetfile=$OPTARG;;
esac
done
shift "$((OPTIND-1))" # Discard options and bring forward remaining arguments
pattern=$1
echo "Searching for: $pattern"
if [[ -n $targetfile ]]; then
echo "in filenames: $targetfile"
fi
startdate=$(date -d "$startdatein" +%s)
for f in *.tar.gz; do
filedate=$(date -r "$f" +%s)
if [[ -z "$startdatein" ]] || [[ $filedate -ge $startdate ]]; then
echo "$f:"
if [[ -z "$targetfile" ]]; then
tar -xzf "$f" --to-command 'grep --label="`basename $TAR_FILENAME`" -Hin '"$pattern ; true"
else
tar -xzf "$f" --no-anchored "$targetfile" --to-command 'grep --label="`basename $TAR_FILENAME`" -Hin '"$pattern ; true"
fi
fi
done
zgrep works fine for me, only if all files inside is plain text.
it looks nothing works if the tgz file contains gzip files.
You can mount the TAR archive with ratarmount and then simply search for the pattern in the mounted view:
pip install --user ratarmount
ratarmount large-archive.tar mountpoint
grep -r '<pattern>' mountpoint/
This is much faster than iterating over each file and piping it to grep separately, especially for compressed TARs. Here are benchmark results in seconds for a 55 MiB uncompressed and 42 MiB compressed TAR archive containing 40 files:
Compression
Ratarmount
Bash Loop over tar -O
none
0.31 +- 0.01
0.55 +- 0.02
gzip
1.1 +- 0.1
13.5 +- 0.1
bzip2
1.2 +- 0.1
97.8 +- 0.2
Of course, these results are highly dependent on the archive size and how many files the archive contains. These test examples are pretty small because I didn't want to wait too long. But, they already exemplify the problem well enough. The more files there are, the longer it takes for tar -O to jump to the correct file. And for compressed archives, it will be quadratically slower the larger the archive size is because everything before the requested file has to be decompressed and each file is requested separately. Both of these problems are solved by ratarmount.
This is the code for benchmarking:
function checkFilesWithRatarmount()
{
local pattern=$1
local archive=$2
ratarmount "$archive" "$archive.mountpoint"
'grep' -r -l "$pattern" "$archive.mountpoint/"
}
function checkEachFileViaStdOut()
{
local pattern=$1
local archive=$2
tar --list --file "$archive" | while read -r file; do
if tar -x --file "$archive" -O -- "$file" | grep -q "$pattern"; then
echo "Found pattern in: $file"
fi
done
}
function createSampleTar()
{
for i in $( seq 40 ); do
head -c $(( 1024 * 1024 )) /dev/urandom | base64 > $i.dat
done
tar -czf "$1" [0-9]*.dat
}
createSampleTar myarchive.tar.gz
time checkEachFileViaStdOut ABCD myarchive.tar.gz
time checkFilesWithRatarmount ABCD myarchive.tar.gz
sleep 0.5s
fusermount -u myarchive.tar.gz.mountpoint
In my case the tarballs have a lot of tiny files and I want to know what archived file inside the tarball matches. zgrep is fast (less than one second) but doesn't provide the info I want, and tar --to-command grep is much, much slower (many minutes)1.
So I went the other direction and had zgrep tell me the byte offsets of the matches in the tarball and put that together with the list of offsets in the tarball of all archived files to find the matching archived files.
#!/bin/bash
set -e
set -o pipefail
function tar_offsets() {
# Get the byte offsets of all the files in a given tarball
# based on https://stackoverflow.com/a/49865044/60422
[ $# -eq 1 ]
tar -tvf "$1" -R | awk '
BEGIN{
getline;
f=$8;
s=$5;
}
{
offset = int($2) * 512 - and((s+511), compl(512)+1)
print offset,s,f;
f=$8;
s=$5;
}'
}
function tar_byte_offsets_to_files() {
[ $# -eq 1 ]
# Convert the search results of a tarball with byte offsets
# to search results with archived file name and offset, using
# the provided tar_offsets output (single pass, suitable for
# process substitution)
offsets_file="$1"
prev_offset=0
prev_offset_filename=""
IFS=' ' read -r last_offset last_len last_offset_filename < "$offsets_file"
while IFS=':' read -r search_result_offset match_text
do
while [ $last_offset -lt $search_result_offset ]; do
prev_offset=$last_offset
prev_offset_filename="$last_offset_filename"
IFS=' ' read -r last_offset last_len last_offset_filename < "$offsets_file"
# offsets increasing safeguard
[ $prev_offset -le $last_offset ]
done
# now last offset is the first file strictly after search result offset so prev offset is
# the one at or before it, and must be the one it is in
result_file_offset=$(( $search_result_offset - $prev_offset ))
echo "$prev_offset_filename:$result_file_offset:$match_text"
done
}
# Putting it together e.g.
zgrep -a --byte-offset "your search here" some.tgz | tar_byte_offsets_to_files <(tar_offsets some.tgz)
1 I'm running this in Git for Windows' minimal MSYS2 fork unixy environment, so it's possible that the launch overhead of grep is much much higher than on any kind of real Unix machine and would make `tar --to-command grep` good enough there; benchmark solutions for your own needs and platform situation before selecting.

Renaming xml file extension using bash script

I have a directory which has many folder and each folder contains a list of XML files. I am writing a bash script that traverses through the files and renames the extension of the file to "manual" if the size of the file is greater than 65Mb. This is my first writing a shell script and I was able to write the code for traversing the files but I am having difficulty in the renaming part.
for file in $dir
do
size=$(stat -c%s "$file")
if test "$size" -gt "68157440"; then
echo "Before Renaming...."
echo $file
echo "After renaming"
mv *.manual `basename $file`.xml
echo $file
else
echo $file >> outlog.log
fi
done
an example of $file is,
/apps/jAS/dev/products-app/BConverter/data/supplier-data/TF/output/Fiber Optics and Fiber Management Solutions/Fiber Optic Cable Assemblies.xml
mv *.manual `basename $file`.xml
If you want to change the extension of $file from xml to manual, do instead
mv "$file" "${file%.xml}".manual
What exactly is the difficulty you're having?
If it's white space in file names, try
mv *.manual `basename "$file"`.xml
Note that your script will not work if *.manual expands to more than one file name.
No need for a script on this, combination of find and xargs should do the trick:
find . -size +65M | xargs -IQ mv Q Q.manual
The little-used -I option to Xargs:
runs each input as a separate command, and
lets you replace the filename, so you can use it multiple time, ideal for a mv

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