Here's my dilemma:
I have columns of colours (red, blue, etc). For each there's either 0 or 1 (1 if the item has blue in it, 0 if not). BUT there can be 2 (or 10) colours in an item. Is there a way to formulate this in Excel?
I tried using IF, but this is limiting me to 2 conditions: if the red is false, then it'd go to blue, but I cannot seem to find a simultaneous way of showing both blue and red for an item.
For example:
My skirt is both green and yellow. I have 0 for red, 0 for blue, 1 for green, 1 for yellow. I'd like this condensed in 1 column only, that would say: green, yellow (with a comma in between).
Help?
Guessing what is where, ie that red is in B1, the following seems to work for the example provided:
=LEFT(IF(B2=1,B$1&", ","")&IF(C2=1,C$1&", ","")&IF(D2=1,D$1&", ","")&IF(E2=1,E$1&", ",""),LEN(IF(B2=1,B$1&", ","")&IF(C2=1,C$1&", ","")&IF(D2=1,D$1&", ","")&IF(E2=1,E$1&", ",""))-2)
(Returns error where all colour flags are 0). Most of that is stripping off the last two characters so might be better to use a helper column and two formulae (but much shorter overall).
This part:
=IF(B2=1,B$1&", ","")&IF(C2=1,C$1&", ","")&IF(D2=1,D$1&", ","")&IF(E2=1,E$1&", ","")
may be extended with further IF statements to cover more than four colours.
Were the latter version in R2 then the last two characters (comma space) may be stripped with:
=LEFT(R2,LEN(R2)-2)
A VBA version (copy/paste to a regular code module in your workbook)
Function Colors(names, flags)
Dim rv, i
rv = ""
For i = 1 To names.Cells.Count
If flags(i) = 1 Then rv = rv & _
IIf(Len(rv) > 0, ", ", "") & names(i)
Next i
Colors = rv
End Function
Usage:
=Colors($B$1:$J$1,B2:J2)
Assuming your color names are in B1:J1 and first row of 1/0 is in B2:J2
Related
I'm out of idea how I could format consecutive same (respectively only even) values in Excel tables without using VBA.
The conditional formatting shall color only consecutive values and only
all 0s or all even values, when there are not more than 2.
A: ID
B: binary
C: counting
1
1
1
2
0
2
3
0
2
4
1
3
5
0
4
6
0
4
7
0
4
8
1
5
9
1
5
I tried to format with: =COUNTIF(C1:C9, C1) < 3, but then it also colors the 1s and C6:C7, eventho there are more than 2.
I also tried =AND( COUNTIF(C1:C9,C1) < 3, ISEVEN(C1:C9) ) but then it colors nothing.
I could replace the 0s with empty cells so I could check ISEMPTY(B1:B9) but it again colors nothing. Using $ to set absolute changes nothing as well.
Formating duplicates also colors triplets, which also doesn't work for me.
=OR(COUNTIF($C$1:$C$9,C1) = 1, COUNTIF($C$1:$C$6,C1) = 2) works so far, but also colors the 1s (uneven).
=AND(OR(COUNTIF($C$1:$C$9,C1) = 1, COUNTIF($C$1:$C$6,C1) = 2), ISEVEN($C$1:$C$9)) doesn't work.
=AND(OR(COUNTIF($C$1:$C$9,C1) = 1, COUNTIF($C$1:$C$6,C1) = 2), $B$1:$B$9 <> 1) doesn't work as well.
My only solution so far is using 2 formating rules:
color =OR(COUNTIF($C$1:$C$9,C1) = 1, COUNTIF($C$1:$C$6,C1) = 2)
do not color =$B$1:$B$9 = 1
but I think it is terrible.
I worked on it for some hours, maybe I'm missing something really obvious.
I'm not allowed to use VBA, therefore this is ot an option.
EDIT: My 2.rule-solution can be simplificed with:
color =COUNTIF($C$1:$C$9,C1) < 3
do not color =$B$1:$B$9 = 1
I'm still confused why combining both doesn't work:
AND(COUNTIF($C$1:$C$9,C1) < 3; $B$1:$B$9 <> 1)
EDIT2: I know why it didn't work. Don't check <>1 with absolute value-range $B$1$:$B$9
Solution: B1 <> 1 then it loops through.
Now combining both works:
=AND( COUNTIF($C$1:$C$9, C1) < 3, B1 <> 1)
I can't see an easy answer for the binary numbers. You have two cases:
(1) Current cell is zero, previous cell is 1, next cell is zero and next cell but one is 1.
(2) Current cell is zero, previous cell is zero, previous cell but one is 1, next cell is 1.
But then the first pair of numbers is a special case because there is no previous cell.
Strictly speaking the last pair of numbers is a special case as well because there is no following cell.
=OR(AND(ROW()=1,B$1=0,B$2=0,B$3=1),AND(ROW()=2,B$1=0,B$2=0,B$3=1),AND(B1=0,B1048576=1,B2=0,B3=1),AND(B1=0,B1048576=0,B1048575=1,B2=1))
where I have used the fact that you are allowed to wrap ranges to the end of the sheet (B1048576) in conditional formatting.
Adding the condition for the case where there there are two zeroes at the end of the range:
=OR(AND(ROW()=1,B$1=0,B$2=0,B$3=1),
AND(ROW()=2,B$1=0,B$2=0,B$3=1),
AND(B1=0,B1048576=1,B2=0,OR(B3=1,B3="")),
AND(B1=0,B1048576=0,B1048575=1,OR(B2=1,B2="")))
Even this could go wrong if there was something in the very last couple of rows of the sheet, so I suppose to be absolutely safe:
=OR(AND(ROW()=1,B$1=0,B$2=0,B$3=1),
AND(ROW()=2,B$1=0,B$2=0,B$3=1),
AND(Row()>1,B1=0,B1048576=1,B2=0,OR(B3=1,B3="")),
AND(Row()>2,B1=0,B1048576=0,B1048575=1,OR(B2=1,B2="")))
Shorter:
=OR(AND(ROW()<=2,B$1+B$2=0,B$3=1),
AND(B1+B2=0,B1048576=1,OR(B3=1,B3="")),
AND(B1+B1048576=0,B1048575=1,OR(B2=1,B2="")))
Not the cleanest wat but it works. You only need to move your data 1 row below, so headers would be in row 2 and data in row 3 for this formula to work:
=IF(AND(B3=B4,B3<>B5),IF(AND(B4=B3,B4<>B2),TRUE,FALSE),IF(AND(B3=B2,B3<>B1),IF(AND(B3=B4,B3<>B5),FALSE,TRUE),FALSE))
How about this approach (Office 365):
=LET(range,B$1:B$9,
s,IFERROR(TRANSPOSE(INDEX(range,ROW()+SEQUENCE(5,,-2))),1),
t,TEXTJOIN("",,(s=INDEX(range,ROW()))*ISEVEN(s)),
IFERROR(SEARCH("0110",t)<4,IFERROR(SEARCH("010",t)=2,FALSE)))
It creates an array s of 5 values starting point is the current row of the range, adding the 2 values above and below. If the value is out of range it will replace the error with a 1.
The array s is checked for being even (TRUE/FALSE, IFERROR created values are uneven) and the values to equal the value of the current row of the range (TRUE/FALSE).
These two booleans are multiplied creating 1 for both values being TRUE, else 0.
These values are joined and checked for 2 consecutive 1's (surrounded by 0) to be found in the 2nd or 3rd position of the range (this would be the case if two even consecutive equal numbers are found),
if it errors it will look if a unique even number is found (1 surrounded by 0 in 2nd position).
PS I'm unable to test if conditional formatting allows you to type the range as B:B instead of B$1:B$9 (working from a mobile) but that would make it more dynamical, because that way you can easily expand the conditional range.
Say I have columns
/670 - White | /650 - black | /680 - Red | /800 - Whitest
These have data in their rows. Basically, I want to SUM their values together if their headers contain my desired string.
For modularity's sake, I wanted to merely specify to sum /670, /650, and /680 without having to mention the rest of the header text.
So, something like =SUMIF(a1:c1; "/NUM & /NUM & /NUM"; a2:c2)
That doesn't work, and honestly I don't know what i should be looking for.
Additional stuff:
I'm trying to think of the answer myself, is it possible to mention the header text as condition for ifs? Like: if A2="/650 - Black" then proceed to sum the next header. Is this possible?
Possibility it would not involve VBA, a draggable formula would be preferable!
At this point, I may as well request a version which handles the complete header name rather than just a part of it as I believe it to be difficult for formula code alone.
Thanks for having a look!
Let me know if I need to elaborate.
EDIT: In regards to data samples, any positive number will do actually, damn shame stack overflow doesn't support table markdown. Anyway, for example then..:
+-------------+-------------+-------------+-------------+-------------+
| A | B | C | D | E |
+---+-------------+-------------+-------------+-------------+-------------+
| 1 |/650 - Black |/670 - White |/800 - White |/680 - Red |/650 - Black |
+---+-------------+-------------+-------------+-------------+-------------+
| 2 | 250 | 400 | 100 | 300 | 125 |
+---+-------------+-------------+-------------+-------------+-------------+
I should have clarified:
The number range for these headers would go from /100 - /9999 and no more than that.
EDIT:
Progress so far:
https://docs.google.com/spreadsheets/d/1GiJKFcPWzG5bDsNt93eG7WS_M5uuVk9cvkt2VGSbpxY/edit?usp=sharing
Formula:
=SUMPRODUCT((A2:D2*
(MID($A$1:$D$1,2,4)=IF(LEN($H$1)=4,$H$1&"",$H$1&" ")))+(A2:D2*
(MID($A$1:$D$1,2,4)=IF(LEN($I$1)=4,$I$1&"",$I$1&" ")))+(A2:D2*
(MID($A$1:$D$1,2,4)=IF(LEN($J$1)=4,$J$1&"",$J$1&" "))))
Apparently, each MID function is returning false with each F9 calculation.
EDIT EDIT:
Okay! I found my issue, it's the /being read when you ALSO mentioned that it wasn't required. Man, I should stop skimming!
Final Edit:
=SUMPRODUCT((RETURNSUM*
(MID(HEADER,2,4)=IF(LEN(Match5)=4,Match5&"",Match5&" ")))+(RETURNSUM*
(MID(HEADER,2,4)=IF(LEN(Match6)=4,Match6&"",Match6&" ")))+(RETURNSUM*
(MID(HEADER,2,4)=IF(LEN(Match7)=4,Match7&"",Match7&" ")))
The idea is that Header and RETURNSUM will become match criteria like the matches written above, that way it would be easier to punch new criterion into the search table. As of the moment, it doesn't support multiple rows/dragging.
I have knocked up a couple of formulas that will achieve what you are looking for. For ease I have made the search input require the number only as pressing / does not automatically type into the formula bar. I apologise for the length of the answer, I got a little carried away with the explanation.
I have set this up for 3 criteria located in J1, K1 and L1.
Here is the output I achieved:
Formula 1 - SUMPRODUCT():
=SUMPRODUCT((A4:G4*(MID($A$1:$G$1,2,4)=IF(LEN($J$1)=4,$J$1&"",$J$1&" ")))+(A4:G4*(MID($A$1:$G$1,2,4)=IF(LEN($K$1)=4,$K$1&"",$K$1&" ")))+(A4:G4*(MID($A$1:$G$1,2,4)=IF(LEN($L$1)=4,$L$1&"",$L$1&" "))))
Sumproduct(array1,[array2]) behaves as an array formula without needed to be entered as one. Array formulas break down ranges and calculate them cell by cell (in this example we are using single rows so the formula will assess columns seperately).
(A4:G4*(MID($A$1:$G$1,2,4)=IF(LEN($J$1)=4,$J$1&"",$J$1&" ")))
Essentially I have broken the Sumproduct() formula into 3 identical parts - 1 for each search condition. (A4:G4*: Now, as the formula behaves like an array, we will multiply each individual cell by either 1 or 0 and add the results together.
1 is produced when the next part of the formula is true and 0 for when it is false (default numeric values for TRUE/FALSE).
(MID($A$1:$G$1,2,4)=IF(LEN($J$1)=4,$J$1&"",$J$1&" "))
MID(text,start_num,num_chars) is being used here to assess the 4 digits after the "/" and see whether they match with the number in the 3 cells that we are searching from (in this case the first one: J1). Again, as SUMPRODUCT() works very much like an array formula, each cell in the range will be assessed individually.
I have then used the IF(logical_test,[value_if_true],[value_if_false]) to check the length of the number that I am searching. As we are searching for a 4 digit text string, if the number is 4 digits then add nothing ("") to force it to a text string and if it is not (as it will have to be 3 digits) add 1 space to the end (" ") again forcing it to become a text string.
The formula will then perform the calculation like so:
The MID() formula produces the array: {"650 ","670 ","800 ","680 ","977 ","9999","143 "}. This combined with the first search produces {TRUE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE} which when multiplied by A4:G4
(remember 0 for false and 1 for true) produces this array: {250,0,0,0,0,0,0} essentially pulling the desired result ready to be summed together.
Formula 2: =SUM(IF(Array)): [This formula does not work for 3 digit numbers as they will exist within the 4 digit numbers! I have included it for educational purposes only]
=SUM(IF(ISNUMBER(SEARCH($J$1,$A$1:$G$1)),A8:G8),IF(ISNUMBER(SEARCH($K$1,$A$1:$G$1)),A8:G8),IF(ISNUMBER(SEARCH($L$1,$A$1:$G$1)),A8:G8))
The formula will need to be entered as an array (once copy and pasted while still in the formula bar hit CTRL+SHIFT+ENTER)
This formula works in a similar way, SUM() will add together the array values produced where IF(ISNUMBER(SEARCH() columns match the result column.
SEARCH() will return a number when it finds the exact characters in a cell which represents it's position in number of characters. By using ISNUMBER() I am avoiding having to do the whole MID() and IF(LEN()=4,""," ") I used in the previous formula as TRUE/FALSE will be produced when a match is found regardless of it's position or cell formatting.
As previously mentioned, this poses a problem as 999 can be found within 9999 etc.
The resulting array for the first part is: {250,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE} (if you would like to see the array you can highlight that part of the formula and calculate with F9 but be sure to highlight the exact brackets for that part of the formula).
I hope I have explained this well, feel free to ask any questions about stuff that you don't understand. It is good to see people keen to learn and not just fishing for a fast answer. I would be more than happy to help and explain in more depth.
I start this solution with the names in an array, you can read the header names into an array with not too much difficulty.
Sub test()
Dim myArray(1 To 4) As String
myArray(1) = "/670 - White"
myArray(2) = "/650 - black"
myArray(3) = "/680 - Red"
myArray(4) = "/800 - Whitest"
For Each ArrayValue In myArray
'Find position of last character
endposition = InStr(1, ArrayValue, " - ", vbTextCompare)
'Grab the number section from the string, based on starting and ending positions
stringvalue = Mid(ArrayValue, 2, endposition - 2)
'Convert to number
NumberValue = CLng(stringvalue)
'Add to total
Total = Total + NumberValue
Next ArrayValue
'Print total
Debug.Print Total
End Sub
This will print the answer to the debug window.
I'm trying to build bubble chart from a scratch in excel. Below is piece of code I'm using. Everything works fine until SeriesCollection.NewSeries reaches 256. Then I'm getting error message: A Chart may only have up to 256 series.
Can you anybody help me, how to avoid this issue. Is there any more elegant solution? Thanks a lot for any of your hint or advice.
Source code for my bubble chart:
With wsAnalytics.ChartObjects.Add(Left:=0, Width:=995, Top:=0, Height:=580)
For i = 1 To Range("Config_BubbleChartData").Rows.Count
.Chart.SeriesCollection.NewSeries
.Chart.SeriesCollection(i).name = Range("Config_BubbleChartData").Rows(i).Cells(1, 1)
.Chart.SeriesCollection(i).XValues = Range("Config_BubbleChartData").Rows(i).Cells(1, 3)
.Chart.SeriesCollection(i).Values = Range("Config_BubbleChartData").Rows(i).Cells(1, 4)
Select Case BubbleColor
Case 1
.Chart.SeriesCollection(i).Format.Fill.ForeColor.RGB = RGB(255, 0, 0)
Case 2
.Chart.SeriesCollection(i).Format.Fill.ForeColor.RGB = RGB(0, 0, 255)
Case 3
.Chart.SeriesCollection(i).Format.Fill.ForeColor.RGB = RGB(0, 255, 0)
End Select
If i = 1 Then .Chart.ChartType = xlBubble3DEffect
.Chart.SeriesCollection(i).BubbleSizes = "=" & Range("Config_BubbleChartData").Parent.name _
& "!" & Range("Config_BubbleChartData").Rows(i).Cells(1, 5).Address(1, 1, xlR1C1)
Next i
You only need as many series as you have colors. Certainly you don't need more than 255 colors, since no human would be able to distinguish more than a dozen in a cluttered bubble chart.
Set up the data with four columns for X, Y, bubble size, and bubble color. Append another column for each color in the bubble color column, and use the color name as the column header. Use an IF formula in these columns to put the Y value for each color into the appropriate column.
In my example, I have X and Y in columns A and B, bubble size and color in C and D, plus the bubble color names in E1:G1. The formula in cell E2 is
=IF($D2=E$1,$B2,NA())
and I've filled this into E2:G16. The result is the Y value if the column header matches the color, and #N/A otherwise, which will not plot.
Select A2:C19 and create the bubble chart (top left chart).
Click the Select Data button on the Chart Tools > Design tab of the ribbon, select the only series in the chart, and Edit it, so cell E1 is used for the name, and E2:E16 is used for the Y values. Keep A2:A16 as the X values and C2:C16 as the bubble size. This series will have the default color for the first series, which in Excel 2013 and 2016 is blue (top right chart).
Stay in or return to the Edit Data dialog, and add a series. Use cell F1 for series name, A2:A16 as X values, F2:F16 as Y values, and C2:C16 as the bubble size. This series will use the default second color, orange (bottom left chart).
Add one more series, use cell G1 for series name, A2:A16 as X values, G2:G16 as Y values, and C2:C16 as the bubble size. This series uses the default third color, gray (bottom right chart).
Note that all series use the same X values and bubble sizes, but different Y values.
I'm looking to color a table of values in Excel 2010 by their absolute value. Basically, if I have the table:
...the cells are colored by the cell's raw value. What I would like to do is color by the cell's absolute value, so with the cell coloring of this table:
...but with the values of the first table (the real values). Any ideas on how one might do this? Through the GUI or with VBA?
I don't think that there is any way to do this with three colors (red, yellow, green), but you can do it with two colors (for example yellow and green). Simply make the color for the low value and the color for the high value the same. That way, the cells with the lower absolute value will have the middle color and cells with the higher absolute value will have the other color.
Select Your data
Conditional Formatting
Color Scale
More Rules
Select "3-Point Scale" under Format Style
Change the colors so that the Maximum and Minimum colors are the same
Here is my solution to this problem. The conditional format formula reads
=AND(ABS(B3)>0,ABS(B3)<=500)
for the darkest green, the scale changes to 500 to 1000, 1000 to 1500, and finally 1500 to 2000 for the red band.
Conditional Formats
Color Scale Values
Here is a picture of the dataset that I used to test these conditional formats:
A variation on this simple conditional formatting illustration may work for you.
Highlight the whole of the data range (you need the top LH cell to be the anchor for relative addressing) and enter the Formula: in 'relative notation' i.e. cell references without the dollar signs. You also have to consider the order of the rules.
The uppermost formula is obscured but reads =(ABS(B3)>39) * (ABS(B3)<41) Note that the * symbol applies an AND operation.
Ok, I have a solution that works with 3 color conditioning. Basically you supply a region to my code. It then creates two ranges, one of neg numbers and one of positive ones. It then applies conditional formatting
red-low yellow-mid green-high to the positive range and
red-high yellow-mid green-low to the negative range.
It was a quick solution so its sloppy and not robust (for instance it only works in columns A-Z because of a lazy ascii conversion for column numbers), but it works. (i'd post a pic but I don't have enough points)
---------------------edit-------------------------------
#pnuts is right, unless the data is symmetric this solution wont work as is. so with that in mind I came up with a new solution. First I will explain the general idea, then basically just dump the code, if you understand the logic the code should be fairly clear. It is a rather involved solution for such a seemingly simple problem, but isn't that always the way? :-P
We are still using the basic idea of the original code, create a negative range and apply colorscale to it, then create a positive range and apply the inverted color scale to it. As seen below
Negative ........... 0 ................ positive
green yellow red | red yellow green
So with our skewed data data_set={-1,-1,-2,-2,-2,-2,-3,-4,1,5,8,13} what I do is mirror the the extreme value. In this case 13, so now data_set={-13,-1,-1,-2,-2,-2,-2,-3,-4,1,5,8,13} Notice the additional -13 element. I assume you have a button to enact this macro so I store the extra -13 in a cell that is underneath the button so even though its there it isn't visible (yeah I know they can move the button etc, but it was the easiest thing I could think of)
Well that's all well and good green maps to 13 AND -13 but the color gradient is based on percentiles (in fact the color bar code uses the 50th percentile to determine the midpoint, or in our case where the yellow section is)
Selection.FormatConditions(1).ColorScaleCriteria(2).Value = 50
so with our distribution {-13,-1,-1,-2,-2,-2,-2,-3,-4,1,5,8,13} we could start seeing the yellow in the positive range around the number 8.5 Since 8.5 is 50th percentile. but in the neg range (even if we add a mirrored -13) the 50th percentile is -2, so our yellow in the negative range would start at 2!! Hardly ideal. just like pnuts mentioned, but we are getting closer. if you have fairly symmetric data this issue won't be present, but again we are looking at worst case of skewed datasets
What I did next is statistically match the midpoints....or at least their colors. So since our extreme value (13) is in the positive range we leave the yellow at the 50th percentile and try to mirror it to the negative range by changing what percentile the yellow color appears at (if the negative range had the extreme value we would leave the yellow at that 50th percentile and try to mirror it to the positive range). That means in our negative range we want to shift our yellow (50th percentile) from -2 to a number around -8.5 so it matches the positive range. I wrote a function called
Function iGetPercentileFromNumber(my_range As Range, num_to_find As Double) That does just that! More Specifically it takes a range and reads the values into an array. It then adds num_to_find to the array and figures out what percentile num_to_find belongs to as an integer 0-100 (hence the i in the function name). Again using our example data we would call something like
imidcolorpercentile = iGetPercentileFromNumber(negrange with extra element -13, -8.5)
Where the -8.5 is the negative(50th percentile number of positive range = 8.5). Don't worry the code automatically supplies the ranges and the numbers, this is just for your understanding. The function would add -8.5 to our array of negative values {-13,-1,-1,-2,-2,-2,-2,-3,-4,-8.5} then figure out what percentile it is.
Now we take that percentile and pass it in as the midpoint for our negrange conditional formatting. so we changed the yellow from 50th percentile
Selection.FormatConditions(1).ColorScaleCriteria(2).Value = 50
to our new value
Selection.FormatConditions(1).ColorScaleCriteria(2).Value = imidcolorpercentile 'was 50
which now deskewed the colors!! we have basically created a symmetric in appearance color bar. Even if our numbers are far from symmetric.
Ok, I know that was a TON to read and digest. but here are the main takeaways this code
- uses full 3-color conditional formatting (not simply setting the two extreme colors the same to look like abs value)
- creates symmetric color ranges by using a obstructed cell (say under a button) to hold the extreme values
- uses statistical analysis to match the color gradients even in skewed data sets
both steps are necessary and neither one on its own is sufficient to create a true mirror color scale
Since this solution requires statistical analysis of the data set, you would need to run it again any time you changed a number (which was actually the case before, I just never said it)
and now the code. Put it in vba or some other highlighting program. It is nearly impossible to read as is ..... takes deep breath
Sub main()
Dim Rng As Range
Dim Cell_under_button As String
Set Rng = Range("A1:H10") 'change me!!!!!!!
Cell_under_button = "A15"
Call AbsoluteValColorBars(Rng, Cell_under_button)
End Sub
Function iGetPercentileFromNumber(my_range As Range, num_to_find As Double)
If (my_range.Count <= 0) Then
Exit Function
End If
Dim dval_arr() As Double
'this is one bigger than the range becasue we will add "num_to_find" to it
ReDim dval_arr(my_range.Count + 1)
Dim icurr_idx As Integer
Dim ipos_num As Integer
icurr_idx = 0
'creates array of all the numbers in your range
For Each cell In my_range
dval_arr(icurr_idx) = cell.Value
icurr_idx = icurr_idx + 1
Next
'adds the number we are searching for to the array
dval_arr(icurr_idx) = num_to_find
'sorts array in descending order
dval_arr = BubbleSrt(dval_arr, False)
'if match_type is 0, MATCH finds an exact match
ipos_exact = Application.Match(CLng(num_to_find), dval_arr, 0)
'there is a runtime error that can crop up when num_to_find isn't formated as long
'so we converted it, if it was a double we may not find an exact match so ipos_Exact
'may fail. now we have to find the closest numbers below or above clong(num_to_find)
'If match_type is -1, MATCH finds the value <= num_to_find
ipos_small = Application.Match(CLng(num_to_find), dval_arr, -1)
If (IsError(ipos_small)) Then
Exit Function
End If
'sorts array in ascending order
dval_arr = BubbleSrt(dval_arr, True)
'now we find the index of our mid color point
'If match_type is 1, MATCH finds the value >= num_to_find
ipos_large = Application.Match(CLng(num_to_find), dval_arr, 1)
If (IsError(ipos_large)) Then
Exit Function
End If
'barring any crazy errors descending order = reverse order (ascending) so
ipos_small = UBound(dval_arr) - ipos_small
'to minimize color error we pick the value closest to num_to_find
If Not (IsError(ipos_exact)) Then
'barring any crazy errors descending order = reverse order (ascending) so
'since the index was WRT descending subtract that from the length to get ascending
ipos_num = UBound(dval_arr) - ipos_exact
Else
If (Abs(dval_arr(ipos_large) - num_to_find) < Abs(dval_arr(ipos_small) - num_to_find)) Then
ipos_num = ipos_large
Else
ipos_num = ipos_small
End If
End If
'gets the percentile as an integer value 0-100
iGetPercentileFromNumber = Round(CDbl(ipos_num) / my_range.Count * 100)
End Function
'fairly well known algorithm doesn't need muxh explanation
Public Function BubbleSrt(ArrayIn, Ascending As Boolean)
Dim SrtTemp As Variant
Dim i As Long
Dim j As Long
If Ascending = True Then
For i = LBound(ArrayIn) To UBound(ArrayIn)
For j = i + 1 To UBound(ArrayIn)
If ArrayIn(i) > ArrayIn(j) Then
SrtTemp = ArrayIn(j)
ArrayIn(j) = ArrayIn(i)
ArrayIn(i) = SrtTemp
End If
Next j
Next i
Else
For i = LBound(ArrayIn) To UBound(ArrayIn)
For j = i + 1 To UBound(ArrayIn)
If ArrayIn(i) < ArrayIn(j) Then
SrtTemp = ArrayIn(j)
ArrayIn(j) = ArrayIn(i)
ArrayIn(i) = SrtTemp
End If
Next j
Next i
End If
BubbleSrt = ArrayIn
End Function
Sub AbsoluteValColorBars(Rng As Range, Cell_under_button As String)
negrange = ""
posrange = ""
'deletes existing rules
Rng.FormatConditions.Delete
'makes a negative and positive range
For Each cell In Rng
If cell.Value < 0 Then
' im certain there is a better way to get the column character
negrange = negrange & Chr(cell.Column + 64) & cell.Row & ","
Else
' im certain there is a better way to get the column character
posrange = posrange & Chr(cell.Column + 64) & cell.Row & ","
End If
Next cell
'removes trailing comma
If Len(negrange) > 0 Then
negrange = Left(negrange, Len(negrange) - 1)
End If
If Len(posrange) > 0 Then
posrange = Left(posrange, Len(posrange) - 1)
End If
'finds the data extrema
most_pos = WorksheetFunction.Max(Range(posrange))
most_neg = WorksheetFunction.Min(Range(negrange))
'initial values
neg_range_percentile = 50
pos_range_percentile = 50
'if the negative range has the most extreme value
If (most_pos + most_neg < 0) Then
'put the corresponding positive number in our obstructed cell
Range(Cell_under_button).Value = -1 * most_neg
'and add it to the positive range, to reskew the data
posrange = posrange & "," & Cell_under_button
'gets the 50th percentile number from neg range and tries to mirror it in pos range
'this should statistically skew the data
the_num = WorksheetFunction.Percentile_Inc(Range(negrange), 0.5)
pos_range_percentile = iGetPercentileFromNumber(Range(posrange), -1 * the_num)
Else
'put the corresponding negative number in our obstructed cell
Range(Cell_under_button).Value = -1 * most_pos
'and add it to the positive range, to reskew the data
negrange = negrange & "," & Cell_under_button
'gets the 50th percentile number from pos range and tries to mirror it in neg range
'this should statistically skew the data
the_num = WorksheetFunction.Percentile_Inc(Range(posrange), 0.5)
neg_range_percentile = iGetPercentileFromNumber(Range(negrange), -1 * the_num)
End If
'low red high green for positive range
Call addColorBar(posrange, False, pos_range_percentile)
'high red low green for negative range
Call addColorBar(negrange, True, neg_range_percentile)
End Sub
Sub addColorBar(my_range, binverted, imidcolorpercentile)
If (binverted) Then
'ai -> array ints
adcolor = Array(8109667, 8711167, 7039480)
' green , yellow , red
Else
adcolor = Array(7039480, 8711167, 8109667)
' red , yellow , greeb
End If
Range(my_range).Select
'these were just found using the record macro feature
Selection.FormatConditions.AddColorScale ColorScaleType:=3
Selection.FormatConditions(Selection.FormatConditions.Count).SetFirstPriority
'assigns a color for the lowest values in the range
Selection.FormatConditions(1).ColorScaleCriteria(1).Type = _
xlConditionValueLowestValue
With Selection.FormatConditions(1).ColorScaleCriteria(1).FormatColor
.Color = adcolor(0)
.TintAndShade = 0
End With
'assigns color to... midpoint of range
Selection.FormatConditions(1).ColorScaleCriteria(2).Type = _
xlConditionValuePercentile
Selection.FormatConditions(1).ColorScaleCriteria(2).Value = imidcolorpercentile 'originally 50
With Selection.FormatConditions(1).ColorScaleCriteria(2).FormatColor
.Color = adcolor(1)
.TintAndShade = 0
End With
'assigns colors to highest values in the range
Selection.FormatConditions(1).ColorScaleCriteria(3).Type = _
xlConditionValueHighestValue
With Selection.FormatConditions(1).ColorScaleCriteria(3).FormatColor
.Color = adcolor(2)
.TintAndShade = 0
End With
End Sub
I am going to borrow heavily from the answer of #barryleajo (won't hurt my feelings if you select that answer). As was stated in that answer the order of the conditional formatting is the key, start with the smallest absolute values and work your way up. The difference between that answer and this one is that there is no need to use an "and" statement, since the OP seems to indicate that all values within a certain range of absolute value should receive the same color format. Here is a small example:
Let's assume i have the following range from (a1:c3)
A B C
1 -1 1 1
2 -1 0 0
3 0 0 1
Now i have selected the following range, and formatted it using Conditional Formatting (using default red yellow green color scale).... now range colors became
A B C
1 Green Red Red
2 Green Yellow Yellow
3 Yellow Yellow Red
Now I want to ask the color of any cell in the range, for example MsgBox Range("A1").Interior.Color
but it does not say that it is Green, why? Plz can you help me?
Range("A1").Interior.Color always returns 16777215
Range("A1").Interior.ColorIndex always returns -4142
(no matter whether the color of A1 is red, blue, green, ...)
Range("A1", "C3").FormatConditions.Count
this one returns always 0, why?
.Interior.Color returns the "real" color, not the conditionally-formatted color result.
#sss: It's not available via the API.
The best you can do is to test the same conditions you used in the conditional formatting.
To avoid this resulting in duplicate code, I suggest moving your conditional criteria to a UDF. Examples:
Function IsGroup1(ByVal testvalue As Variant) As Boolean
IsGroup1 = (testvalue < 0)
End Function
Function IsGroup2(ByVal testvalue As Variant) As Boolean
IsGroup1 = (testvalue = 0)
End Function
Function IsGroup3(ByVal testvalue As Variant) As Boolean
IsGroup1 = (testvalue > 0)
End Function
Then use these formulas in your Conditional formatting:
=IsGroup1(A1)
=IsGroup2(A1)
=IsGroup3(A1)
Then your code, rather than looking at the color of the cells, looks to see if the condition is met:
If IsGroup1(Range("$A$1").Value) Then MsgBox "I'm red!"
You need to refer the <Cell>.FormatConditions(index that is active).Interior.ColorIndex to retrieve the conditional formatting color of a cell.
You may refer to the below link for an example:
http://www.xldynamic.com/source/xld.CFConditions.html#specific
As a follow up to #richardtallent (sorry, I couldn't do comments), the following link will get you a function that returns you the color index by evaluating the conditional formatting for you.
http://www.bettersolutions.com/excel/EPX299/LI041931911.htm
To get the color of a cell in a Range, you need to reference the individual cell inside the array in the form of Range("A1","C3").Cells(1,1) (for cell A1). The Excel help is pretty good if you look up the name of the property you're having issues with.
Also, Excel 2007 uses Integers for its color types, so your best bet is to assign the color index to an integer, and using that throughout your program. For your example, try:
Green = Range("A1","C3").Cells(1,1).Interior.Color
Yellow = Range("A1","C3").Cells(1,3).Interior.Color
Red = Range("A1","C3").Cells(2,1).Interior.Color
And then to switch the colors to all red:
Range("A1","C3").Interior.Color = Red
Again, check the Excel help for how to use Cells([RowIndex],[ColumnIndex]).
If the above doesn't work for you, check to see what .Interior.PatternColorIndex is equal to. I typically leave it set at xlAutomatic (solid color), and it could be set to something else if the color isn't changing.
According to XlColorIndex Enumeration ColorIndex=-4142 means No color
As to why this happens I'm clueless. The returned value seems to be the decimal representation of the RGB value. The improved version of this script to decrypt the value into hex RGB notation
Function RGB(CellRef As Variant)
RGB = ToHex(Range(CellRef).Interior.Color)
End Function
Function ToHex(ByVal N As Long) As String
strH = ""
For i = 1 To 6
d = N Mod 16
strH = Chr(48 + (d Mod 9) + 16 * (d \ 9)) & strH
N = N \ 16
Next i
strH2 = ""
strH2 = Right$(strH, 2) & Mid$(strH, 3, 2) & Left$(strH, 2)
ToHex = strH2
End Function
It doesn't appear that the "Conditional Format"-color is available programmatically. What I'd suggest that, instead, you write a small function that calculates cell color, and then just set a macro to run it on the active cell whenever you've edited the value. For example (sorry for the psuedo-code - I'm not a VBA expert anymore):
Function GetColorForThisCell(Optional WhatCell as String) as Int
If WhatCell="" Then WhatCell = ActiveCell
If Range(WhatCell).value = -1 then GetColorForThisCell = vbGreen
If Range(WhatCell).value = 0 then GetColorForThisCell = vbYellow
If Range(WhatCell).value = 1 then GetColorForThisCell = vbRed
End Function
Sub JustEditedCell
ActiveCell.color = GetColorForThisCell()
End Sub
Sub GetColorOfACell(WhatCell as string)
Msgbox(GetColorForThisCell(WhatCell) )
End Sub
Though you wouldn't be able to use the built-in Excel Conditional Formatting, this would accomplish the same thing, and you'd be able to read the color from code. does this make sense?
since i may have more than three different colors in a time... i didn't find any good way of handling this with conditional formatting's default colors... i did it this way. then whenever i ask the color of the cell, i retrieve the correct color!
for (int t = 0; t < d_distinct.Length; t++ )
{
Excel.FormatCondition cond =
(Excel.FormatCondition)range.FormatConditions.Add(
Excel.XlFormatConditionType.xlCellValue,
Excel.XlFormatConditionOperator.xlEqual,
"="+d_distinct[t],
mis, mis, mis, mis, mis);
cond.Interior.PatternColorIndex =
Excel.Constants.xlAutomatic;
cond.Interior.TintAndShade = 0;
cond.Interior.Color = ColorTranslator.ToWin32(c[t]);
cond.StopIfTrue = false;
}
d_distinct holds all the distinct values in a range... c is a Color[] which holds distinct colors for every distinct value! this code can easily be translated to vb!