Linux filename check if exist and delete - linux

Question

I have some problem in Shell scripting.
So I have to write a script that find every file in a directory with this string: "gom". So i found all of them. After I need to cut it off, and compare that the remaining filename is exist. If exist i need to remove the file that contains the string.
Example: there are 5 files: algomb, gomba, alb, algomba, alba.
I need to find the filenames with "gom". algomb, gomba, algomba.
After it i need to cut the "gom". And a remaining filenames is exist I need to remove the file with "gom" string.
So after the cutting "gom" there will be 5 files: alb, ba, alb, alba, alba
So there are two files that is extist: alb, alba....I need to remove the following files: algomb, albomba.
After it the will be 3 files: gomba, alb, alba.
Sorry for my bad english.
I can find, I can remove, but I cant compare the filenames.
Here's my code:
#!/bin/bash
sz="gom"
talal=`find . -type f -name "*$sz*" -exec basename {} \;`
ossz=`find . -type f -exec basename {} \;`
c=`echo ${talal%%:*}${talal##*:}`
for c in ossz; do
if [ ! -d ]; then
echo "This is a directory"
else
if [ -f ];
then
find .-type f -name "*$sz*" -exec basename {} \;
else
echo ${talal%%:*}${talal##*:}
fi
fi
done
So this is works. This echo ${talal%%:*}${talal##*:} is give back the filename without "gom". But I cant compare these values with find . -type f -exec basename {} \; results.
Sorry for my bad english.
Can sombody help me?
Best regards, Richard

Answer 1

I would do it this way, without find.
shopt -s globstar
for gom_file in **/*gom*; do
# Skip non-regular files
[[ -f $gom_file ]] || continue
# Delete the file if the gom-free file exists
[[ -f ${gom_file/$sz//} ]] && rm "$gom_file"
done
Using find is slightly less efficient, since you need to fork a new shell for each file:
find . -type f -name "*gom*" -exec bash -c 'echo rm -f "${1/gom/}"' {} \;
Run this to test that it outputs the rm commands you want to execute, then run it again with echo removed.

Answer 2

I think you want to use those bash features:
array (declare -a)
hashtable (declare -A)
regex ( ${a/b/c} ${a//b/c} )
Here is an example as a general idea:
#!/bin/bash
sz="gom"
declare -a ta
declare -A ossz
i=0
while read -r -d $'\0' ff
do ta[$i]=$ff
i=$((i+1))
done < <(find . -type f -name "*$sz*" -print0)
while read -r -d $'\0' ff
do ossz[${ff##*/}]=1
done < <(find . -type f -print0)
for ff in "${ta[#]}"
do subff=${ff/$sz/}
subff=${subff##*/}
if [ _${ossz[$subff]} = _1 ]
then echo "$ff"
fi
done