I have 2 Excel files and I'm trying to compare two numbers (one has 7 digits and the second 5 digits).
For example in an excel file I have the following number 1234567 and in another file I have 12345 in one cell in another cell I have the remaining digits 67. I want to compare the first number with the second and if they are the same i need to identify the cells that have the value 67 and to print what is in the next cell.
They are constantly changing so I'm having problems getting this right
I made this formula but it doesn't work properly. Did I miss something?
=IFERROR(IF(INT(RIGHT(A5;2))=VLOOKUP(INT(LEFT(A5;5));'Path[file.xls]
Sheet1'!$S$3:$AA$200;2;FALSE);VLOOKUP(INT(LEFT(A5;5));'path[file.xls]
Sheet1'!$S$3:$AA$200;3;FALSE);VLOOKUP(INT(LEFT(A5;5));'path[file.xls]
Sheet1'!$S$3:$AA$200;5;FALSE));"")
From your description and sample formula, I pieced together some sample data in File.xls.
Note by the right alignment, these are true numbers. This is important. A VLOOKUP or MATCH function will not find RIGHT(A2, 5) amongst numbers; it has to be --RIGHT(A2, 5). With 7 digit numbers in another workbook, I used this standard formula.
=INDEX([File.xls]Sheet1!$S:$AA, MATCH(--LEFT(A2, 5), [File.xls]Sheet1!$S:$S, 0), MATCH(--RIGHT(A2, 2), INDEX([File.xls]Sheet1!$S:$AA, MATCH(--LEFT(A2, 5), [File.xls]Sheet1!$S:$S, 0), ), 0)+1)
Note that every values is expected to be found. If this is not the case, then an IFERROR function should be used to handle non-matches.
The results were as follows.
Related
I've been trying to write a formula to summarise in one cell the presence/ absence of certain values in a different range of of cells in Excel
So in the one table and worksheet, I wrote
=IF(B1:F1=1,1,0) Formula 1
which is supposed to mean
If any of the values in cells B1:F1 are equal to 1, then note 1, otherwise not 0.
But somehow the syntax isn't working.
I've applied "" and ; and brackets right left and centre, but to no avail.
I'm pretty sure I done this before and it was pretty simple when I hit upon the right synstax, but the how and where fell through the colander which is my brain today :-?
Additionally I will want to ask the formula to apply another condition to the output cell which is
=if (A1 = value n or certain values, 1, 0) Formula2
Column A has numerically coded ordinal values 0-9, so an aexample of teh 1 conditions might be any of values 1, 2 or 9 in column, should produce a 1 in the result cell in which Formula 1 and 2 will be written.
So the result cell would contain somelike
=Formula1_or_Formula2_contain_certain_values, 1, 0) Formula 3
Obviously the systax of Formulas 2 and 3 is awol, but I write to demonostrate the formulae intended purposes.
The easiest way to make the first formula is like this:
=IF(SUM(B1:E1)>0,1,0)
No arrays, no problems :)
I'm trying to write a SUM(IF(zero, add 8), A1:G1) kind of excel function.
What it should do:
If the cell contains a number, add that number to the sum.
If the cell contains a number = 0, add 8 to the sum.
if the cell is empty, add nothing to the sum
I have tried using SUMIF, but it only "adds the numbers if they meet a criteria", and I rather need "add this when the criteria is met"
You could just make a longer formula:
=SUM(A1:G1)+COUNTIF(A1:G1, 0)*8
The first sum will only do your numbers ignore blanks and 0's, the second part counts the number of 0's and multiplies it by 8.
You can do this with the following formula:
=SUMIF(A1:G1,">0")+8*COUNTIFS(A1:G1,0,A1:G1,"<>")
should be self-explaining :)
Method 1
If you can spare another column, just use an IF statement to replace all 0's by 8's and blanks by 0's (not really necessary) in a new column
=IF(A1=0,8,A1) and take a SUM of this column.
Method 2
Just SUM over your original data, count the number of zeros in your data and multiply this number by 8.
=SUM(A1:A10)+8*COUNTIF(A1:A10,"=0")
Note: The data is in A1:A10 in this case.
I have a sheet with rows of data, with many columns. I am looking for help on a formula that will extract the sum of the smallest 3 numbers in a row based on the last 5 values entered. Note that not all the rows will have values for each column, so the first value found on each row will may be found in a different column.
To determine the sum of the smallest 3 I am using the formula =SUM(SMALL(B3:R3,{1,2,3})), Unfortunately, that formula is looking at the entire range. Again, I am looking for help that with a formula that will select only the last 5 values posted.
Here is simple example. The results for each line show the totals that should be determined. Again, it needs to look for the sum of the smallest 3 based on the last 5 posted (in the example below the range would be col. 1 thru 10, with col 10 having the latest postings).
Ex.
1.....2.....3......4......5.....6.....7.....8......9.....10...... Result
31.........44....51....36..........44...34....36....38.......106 (34+36+34)
35..31...44...40.....38...52..........42....37...............115 (37+38+40)
Hope this is understandable. I am looking for a formula solution vs a VBA macro solution because of my users. Thanks for any help!!
Now that you clarified the question, I have an answer for you. This is fairly ugly but it gets the job done. You might want to hide the columns with the intermediate results - or you could get adventurous and "nest" the expressions. This makes it really hard to understand / debug though. If there's a smarter way to do this I am always open to learning.
Assuming you have the data in columns A through J, starting in row 2, put the following in cell L2:P2:
=MATCH(9999, A2:J2,1)
=MATCH(9999,OFFSET($A2,0,0, 1, L2-1)) ... copy this by dragging right to the next 2 columns
=MATCH(9999,OFFSET($A2,0,0, 1, M2-1))
=MATCH(9999,OFFSET($A2,0,0, 1, N2-1))
=MATCH(9999,OFFSET($A2,0,0, 1, O2-1))
The first line finds the last cell with data in it; the next ones find the last cell "not including the last cell", and so they work backwards. The result is a number corresponding to the columns with data. For your example, this gives
10 9 8 7 5
9 8 6 5 4
Now we want to find the sum of the smallest 3 of these: put the following equation in cell Q2:
=SUM(SMALL(INDIRECT("RC["&P2-17&"]:RC["&L2-17&"]",FALSE),{1,2,3}))
Working from the inside out:
RC["&P2-17"] results in RC[-12], which is "the cell 12 to the left of this one".
That is the first of the "last five cells with data", cell E2
RC["&L2-17"] results in RC[-7], the last cell with data in this row
FALSE use "RC" rather than "A1" indexing
INDIRECT turn string into an address (in this case a range)
SMALL find the 3 smallest values in this range
SUM and add them together.
This formula did indeed give me 106, 115 for the example you provided.
I would hide columns L through P so you only see the result (and not the intermediate stuff).
I have variating numeric entries (SF123456, SF142365, ...). Every number of the numeric entries corresponds to a specific code. For each number of each entry I need to enter on a separate cell the corresponding code (download here example sheet: www.nivpat.com/Example.zip) How can I create an automatic function as I have thousands of entries to divide into codes... thanks!
Alright. What I did to solve this one is this:
Remove the '=' sign in your match table to be able to do a VLOOKUP on it;
Add the position of the digit you want to look up in the row 9 right above the headings. You might want to hide this row for cleaner presentation;
I used the following formula in the cells to extract the values:
=VLOOKUP(VALUE(MID($A11, B$9, 1)), $A$2:$B$7, 2, 0)
The VLOOKUP does the lookup on your table in A2:B7. The MID() extract exactly one character beginning with the character specified in B9 (in this case it would be 3). And the VALUE() converts the text string to a number to be able to do a match with the table above.
The only thing you now have to do is to drag your formulas and it's working !
I am have a string with 6 spaces, e.g. 000000. Each space can hold one of three digits - 0, 1, or 2. I know that I can get a total of 120 permutations using the Permut function in Excel, i.e. =PERMUT(6,3) = 120. But I would actually like to have each individual permutation in a cell, e.g. 000001, 000010, etc.. Ideally, the end result would be 120 rows of unique 6-digit IDs.
Please help if you know a faster way of accomplishing this without entering the figures manually.
Thanks!
There is a VBA functionin the last post on this page. Copy it into a VBA module, then in Excel, create a column of integers from 0 to n where n = the number of IDs you want. In the next column, call the VBA function with the value from the first column as the first argument, and 3 as the second argument. Something like
Column A Column b
0 =baseconv(A1, 3)
1 =baseconv(A2, 3)
2 =baseconv(A3, 3)
... etc.
Your IDs are really just incremental values using a base 3 counting system. You can format the output to get leading zeros with a custom format of '000000'.
Incidentally, with 6 positions and 3 available values, you can get 3 ^ 6, or 729 unique IDs
First, I don't think you're using PERMUT correctly here. What PERMUT(6,3) gives you is the total number of ways to arrange three things picked out of a set of six things. So the result is 120 because you could have 6*5*4 possible permutations. In your case you have 3^6 = 729 possible strings, because each position has one of three possible characters.
Others have posted perfectly fine VBA-based solutions, but this isn't that hard to do in the worksheet. Here is an array formula that will return an array of the last six digits of the ternary (base-3) representation of a number:
=FLOOR(MOD(<the number>,3^({5,4,3,2,1,0}+1))/(3^{5,4,3,2,1,0}),1)
(As WarrenG points out, just getting a bunch of base-3 numbers is one way to solve your problem.)
You would drag out the numbers 0 through 728 in a column somewhere, say $A$1:$A$729. Then in $B$1:$G$1, put the formula:
=FLOOR(MOD(A1,3^({5,4,3,2,1,0}+1))/(3^{5,4,3,2,1,0}),1)
remembering to enter it as an array formula with Ctrl-Shift-Enter. Then drag that down through $B$729:$G$729.
Finally in cell $H$1, put the formula:
=CONCATENATE(B1,C1,D1,E1,F1,G1)
and drag that down through $H$729. You're done!