Write a bash script that accepts a time duration as arguments? - linux

Question

I'm looking for a bash script that can parse a time duration.
If three arguments are given, they represent hours, minutes, and seconds. If two arguments are given, they represent minutes and seconds, with the hours zero.

Answer 1

What about the following:
#!/bin/bash
h=0
if [ "$#" -ge 3 ]
then
h=$1
shift
fi
sec=$((3600*$h+60*$1+$2))
echo "The total number of seconds is $sec"
Since the question does not specify what you aim to do with the given time, the program calculates the total number of seconds. Furthermore perhaps it is useful to do a check if at least two arguments are given.
The script uses the shift operation, the shift makes makes $1 := $2; $2 := $3, etc. In other words, the first argument is processed, and then you "pretend" it never existed.
By default you set h to zero, and only if the number of arguments is greater than or equal to 3, it will set h.

Answer 2

This is a more or less general solution for that type of task. Sorry, if it is a monkeycode, but I think it is sufficient:
gettime() {
params=(
years months weeks days hours minutes seconds
)
for i in `seq ${#params}`; do
param_i=$((${#params} - i + 1)) # reversed params index
[ $i -le $# ] && {
eval "local ${params[$param_i]}=\$$(($# - i + 1))"
} || {
eval "local ${params[$param_i]}=0"
}
eval "echo ${params[$param_i]} '==' \$${params[$param_i]}" # debug output
done
}
Here's the sample output:
$ gettime 3 4 5 6 7
seconds == 7
minutes == 6
hours == 5
days == 4
weeks == 3
months == 0
years == 0
Note, that the shell you are using must be not only support POSIX standards, but also arrays.

Answer 3

First Argument: $1
Second Argument: $2
Third Argument: $3
and so on...
Example:
bash-2.05a$ ./parseDuration.sh 13 25 25
13 hours and 25 minutes and 25 seconds
bash-2.05a$ cat ./parseDuration.sh
#!/bin/bash
echo "$1 hours and $2 minutes and $3 seconds"