I need to create a running product from a column of numbers (I could use a row, but a column is easier to demonstrate here.) The input might be any arbitrary array. In fact, in the application where I would deploy this, it will not be a range, but rather another dynamic array within a LAMBDA formula. Here is an example of the Input column of numbers and the desired Output from the formula:
Inputs
Expected Dynamic Array Output
10
10
8
80
3
240
4
960
5
4800
The formula would spill the results.
There are lots of solutions for a running total, but I've found no solution for a running product. I have tried a few different approaches, including SUBTOTAL and AGGREGATE with no success. I have also built a number of approaches that get the result, but are hard-coded to a fixed number of rows. I need the formula to adapt to any arbitrarily sized number of rows. The following formula is the closest I have gotten so far.
This LET formula delivers the result, but, as you can see is fixed to 5 rows:
=LET( a, {10;8;3;4;5},
v, SEQUENCE( ROWS(a) ), h, TRANSPOSE( v ),
stagr, (v - h + 1) * (v >= h),
m, IFERROR(INDEX( a, IF(stagr>0,stagr,-1), ), 1),
almost, INDEX(m,v,h) * INDEX(m,v,h+1) * INDEX(m,v,h+2) * INDEX(m,v,h+3) * INDEX(m,v,h+4),
result, INDEX( almost, , 1 ),
result )
The arbitrary array of numbers input is placed in the variable a.
The next step is to create some indexes that will be used to address these numbers: v is a sequence of vertical rows for each number in a and h is a the same sequence, but transposed into columns. stagr is an index matrix that is created from v and h that will later be used to address each item in a to form it into a multiplication matrix. If you replace the last result with stagr, you can see the shape of stagr. It just shifts a column down by one row until they are shifted all the way down.
Now we create the mulitplication matrix m using stagr by simply using INDEX, like this: INDEX(a,stagr). But this is not exactly what is needed because it takes the first row value (10) and replicates it because an INDEX of 0 is treated the same as 1. To get what we want, I forced an error by using and internal IF statement like this: INDEX( a, IF(stagr>0,stagr,-1) ) to replace the 0 results with -1. i.e. it will produce this:
Now, replace the errors with 1's by using IFERROR, so this explains how m is created and why. The result is a matrix like this:
and by multiplying m row-wise, we get the output we want, but this is where I fail.
For illustration, I created a variable almost that shows how I am trying to do a row-wise multiplication.
almost, INDEX(m,v,h) * INDEX(m,v,h+1) * INDEX(m,v,h+2) * INDEX(m,v,h+3) * INDEX(m,v,h+4)
You can see that I crudely multiplied one column times the next and the next... and using h + offset to get there. This produces the almost matrix and result just delivers the first column of that matrix, which contains the answer.
While an answer might be a good replacement for almost that would be dynamically sized, that is not my real question. I want a running product and I suspect that there is a wholly different approach than simply replacing my almost.
Just to be clear, the result must be a dynamic array that spills with no helper cells or CSE drag-down.
oh... and no VBA. (#stackoverflow - please add a no-VBA tag)
The only way I can find is to use DPRODUCT with OFFSET, but that requires a title row. It does not matter what is in the title row(it can even be empty), just that it is included.
=DPRODUCT(OFFSET(A1,0,0,SEQUENCE(COUNT(A:A),,2)),1,$ZZ1:$ZZ2)
The $ZZ1:$ZZ2 can be any empty cell reference.
If the values in A are dynamic then we can do:
=DPRODUCT(OFFSET(A1,0,0,SEQUENCE(ROWS(A2#),,2)),1,$ZZ:$ZZ)
There are plenty of interesting answers here. But, if summation is easy why not take logarithms of the number you want to multiply, sum those logarithms and then calculate the exponent of your sum to return to the product of the original numbers.
i.e. exploit the fact that ln(a * b) = ln(a) + ln(b)
Whilst not available to everybody (yet) we can use SCAN()
Formula in A1:
=SCAN(1,{10,8,3,4,5},LAMBDA(a,b,a*b))
The 1st parameter is our starting value, meaning the 1st calculation in the nested LAMBDA() is '1*10'.
The 2nd parameter can both take a 1D- & 2D-array (written or range-reference).
The 3rd parameter is a nested LAMBDA() where the result of our recursive function will then be used for the 2nd calculation; '10*8'. And the 3rd...etc. etc.
In the above sample a vertical array is spilled but when horizontal input is used this will obviously result in an horizontal spilled output. When a 2D-array is used this will spill a 2D-array as result.
I'm setting up a configuration excel sheet to be imported into a database.
It has four columns
Equipment Fleet Start Date End Date Highlight Me
=============================================
A X 1-Jan-20 5-Jan-20 X
A Y 6-Jan-20
B C 1-Jan-20 3-Jan-20
B D 4-Jan-20 10-Jan-20
A Z 3-Jan-20 X
A Z 5-Jan-20 X
I need to identify and highlight overlapping configs
I'd like lines 1, 5 and 6 to be highlighted.
They are all a configuration for the same Equipment, but their configuration dates overlap
Fleet is that attribute we are configuring for the date range but has no bearing on the validation
Constraints:
I'd like to use tables (not named ranges) for this. My table is called tblFleetConfig
Yes I could do this in VBA but I don't want to deal with trusted workbooks etc. etc.
So far I have pasted this into a column on the right
=
(tblFleetConfig[#[Start Date]] >= tblFleetConfig[Start Date])
*
(tblFleetConfig[#[Start Date]] <= tblFleetConfig[End Date])
*
(tblFleetConfig[#Equipment]=tblFleetConfig[Equipment])
The result I'm getting is a 1 for the first line and 0 for every other line.
Clearly I don't understand this syntax and I'm interested in learning.
You asked a complicated one, those blanks throw a wrench into it.
Your formula is the right syntax, you need to wrap it in a SUMPRODUCT() though.
=SUMPRODUCT((tblFleetConfig[End Date]<=tblFleetConfig[#[End Date]])*(tblFleetConfig[Start Date]>=tblFleetConfig[#[Start Date]])*(tblFleetConfig[Equipment]=tblFleetConfig[#Equipment]))
This is your formula wrapped it in a SUMPRODUCT().
This will return a 1 if there is a single occurrence and a number greater than 1 if multiple.
Let me know if it works.
I’ve used Excel in the past but the calculations including the Poisson-Distribution took a while, that’s why I switched to SQL. Soon I’ve recognized that SQL might not be a proper solution to deal with statistical issues. Finally I’ve decided to switch to Matlab but I’m not used to it at all, my problem Is the following:
I’ve imported a .csv-table and have two columns with values, let’s say A and B (110 x 1 double)
These values both are the input values for my Poisson-calculations. Since I wanna calculate for at least the first 20 events, I’ve created a variable z=1:20.
When I now calculated let’s say
New = Poisspdf(z,A),
it says something like non-scalar arguments must match in size.
Z only has 20 records but A and l both have 110 records. So I’ve expanded Z= 1:110 and transposed it:
Znew = Z.
When I now try to execute the actual calculation:
Results = Poisspdf(Znew,A).*Poisspdf(Znew,B)
I always get only a 100x1 Vector but what I want is a matrix that is 20x20 for each record of A and B (based on my actual choice of z=1:20, I only changed to z=1:110 because Matlab told that they need to match in size).
So in this 20x20 Matrix there should always be in each cell the result of a slightly different calculation (Poisspdf(Znew,A).*Poisspdf(Znew,B)).
For example in the first cell (1,1) I want to have the result of
Poisspdf(0,value of A).*Poisspdf(0,value of B),
in cell(1,2): Poisspdf(0,value of A).*Poisspdf(1,value of B),
in cell(2,1): Poisspdf(1,value of A).*Poisspdf(0,value of B),
and so on...assuming that it’s in the Format cell(row, column)
Finally I want to sum up certain parts of each 20x20 matrix and show the result of the summed up parts in new columns.
Is there anybody able to help? Many thanks!
EDIT:
Poisson Matrix in Excel
In Excel there is Poisson-function: POISSON(x, μ, FALSE) = probability density function value f(x) at the value x for the Poisson distribution with mean μ.
In e.g. cell AD313 in the table above there is the following calculation:
=POISSON(0;first value of A;FALSE)*POISSON(0;first value of B;FALSE)
, in cell AD314
=POISSON(1;first value of A;FALSE)*POISSON(0;first value of B;FALSE)
, in cell AE313
=POISSON(0;first value of A;FALSE)*POISSON(1;first value of B;FALSE)
, and so on.
I am not sure if I completely understand your question. I wrote this code that might help you:
clear; clc
% These are the lambdas parameters for the Poisson distribution
lambdaA = 100;
lambdaB = 200;
% Generating Poisson data here
A = poissrnd(lambdaA,110,1);
B = poissrnd(lambdaB,110,1);
% Get the first 20 samples
zA = A(1:20);
zB = B(1:20);
% Perform the calculation
results = repmat(poisspdf(zA,lambdaA),1,20) .* repmat(poisspdf(zB,lambdaB)',20,1);
% Sum
sumFinal = sum(results,2);
Let me know if this is what you were trying to do.
I've been struggling with something in excel which is quite easy to do individual cases of using an array, but I want to do in a single cell.
Effectively, in row C I have the multipliers I need, lets call them i_k, for j from 1 to n. The equation I want to calculate in mathematical notation is;
Sigma(from j = 0 to n) (Pi(from k = j to n) (i_k))
But I'm not quite sure how best to go about this. Effectively it should be;
(i_1)^n + (i_2)^(n-1) + (i_3)^(n-2) + ...
In the end. Any help?
I dont know if this is an elegant solution but I think this might solve it for you.
The key is to make a table so that your formulas continue.
The screenshot I have taken explains the formula I have used with its explanation I have used on top of it.
-- The first column will have the intended values of I
-- The second column's first row will have the value of N
-- The third column will have a formula which says:
=IF(ISNUMBER([#[Values of N]]),[#[Values of N]],C2-1)
This will give you the decreasing value of N
Now just multiply N with I on the 4th column using a simple multiplication and add the final result:
I am having an issue with an excel problem and cannot use vba or add any extra columns. The problem goes along with the format of this image. I could not find anything on google that helped me with this problem and im sorry if it has been asked before.
Example Image
On a separate page in a cell i need to write a function that will check if Info 2 = "z" and Info4 = "x" and if that is true then i need to do the following equation with the numbers in Info1 and Info3: Info1*(1 - Info3)
I will also have to keep a sum of these numbers.
For this example I would want the cell with the formula to equal -34 by doing the following:
3*(1-4)+5*(1-6) = -34
I would want the cell to just display the finished sum
Any help would be greatly appreciated,
Thank you!
You are looking for the mighty powers of SUMPRODUCT
=SUMPRODUCT((B:B="z")*(D:D="x")*(A:A)*(1-C:C))
The first two multipliers will make sure we only evaluate those rows having z for B and x for D. While the latter two are your desired function. Excel will evaluate this for each row and sum up the results.
I am using psuedo values below but this should work:
= [value of cell above] + if(and([info2] = "z" , [info4] = "x"), [info1]*(1-[info3]),0)
so basically starting in the middle, you have a two truth tests,
[info2] = "z", [info4]= "x"
using AND() requires they both pass
and([info2] = "z", [info4]= "x")
if they do pass you want to do your formula:
if(and([info2] = "z" , [info4] = "x"), [info1]*(1-[info3]),FALSE)
but since we want to sum all values for each iterative row we make not passing this test 0:
if(and([info2] = "z" , [info4] = "x"), [info1]*(1-[info3]),0)
Ok so this works for one row, but doesn't sum the numbers from the tests on the previous row:
= [value of cell above or 0 for first row] + if(and([info2] = "z" , [info4] = "x"), [info1]*(1-[info3]),0)
an example written with real excel ranges that you may have to tweak depending on where your values are stored:
Sample picture