I am struggling a lot with trying to rotate a composite SVG. The SVG has rectangular proportions so when I rotate it around the center, parts of the SVG are rendered outside of the viewport.
My goals is to rotate the whole SVG document 90 degrees. The only way I got this working is by making the SVG width/height square and removing preserveAspectRatio attribute like this:
Original
<svg xmlns="http://www.w3.org/2000/svg" preserveAspectRatio="none" width="300" height="443" viewBox="0 0 77 112">
After rotating
<svg xmlns="http://www.w3.org/2000/svg" width="443" height="443" viewBox="0 0 77 112" transform="rotate(90)">
Now the rotated SVG is inside the viewbox because I made it square dimensions, but I have a blank spacing above and below.
This is obviously unwanted.
Tried to play around with the transform-origin and swapping width and height values around, but can't get it to work the way I want.
See this fiddle for the rotated SVG with the unwanted white spacing on top and bottom. https://jsfiddle.net/bdkst8er/
According to the standards I'm reading -- for example https://www.w3.org/TR/css-values-4/#viewport-relative-lengths -- a vmin unit should be 1% of the smallest dimension of the containing viewport.
Going for a minimal example illustrating my dilemma, this is square in my current instance of chrome:
<svg><rect height="30vmin" width="30vmin" fill="red">
But this is not:
<svg><rect height="50vmin" width="50vmin" fill="red">
Playing with variations on this theme (closing tags, adding width and height to the svg element, etc.) suggests that the rect is not using the svg viewport as its reference, but instead is using some containing browser context as its reference viewport.
So, my question is: how do I specify to the browser that I want vmin units to refer to the innermost containing svg viewport? (Specifically when working with svg elements embedded in html documents.)
Browser support for those units that were added in CSS3 may still be spotty. I haven't checked recently.
But the rule is that these units are resolved relative to the whole document. So in a browser, that will be the whole browser window.
This SVGWG issue may help clarify things.
https://github.com/w3c/svgwg/issues/207
how do I specify to the browser that I want vmin units to refer to the innermost containing svg viewport?
You can use percentage values for coordinates,
<rect height="50%" width="50%" fill="red">
However in SVG, percentage values are always relative to their associated axis. So percentage width values are relative to the X axis, and percentage height values are relative to the Y axis.
Alternatively you could use a suitable viewBox and appropriate coordinate values relative to that viewBox. For example, if your viewBox has a width and height of 100:
viewBox="0 0 100 100"
All coordinates values in the SVG would effectively be percentage values. However the same axis rule applies as described above.
svg {
width: 200px;
background-color: linen;
}
<svg viewBox="0 0 100 100">
<!-- rectnagle 50% x 33.3% -->
<rect width="50" height="33.3"/>
</svg>
This seemed to be working before I added a viewBox (which was required since paths are in user units).
<?xml version="1.0" encoding="UTF-8" ?>
<svg xmlns="http://www.w3.org/2000/svg" version="1.1" width="7in" height="7in" viewBox="0 0 7 7">
<rect x="2" y="2" width="1" height="1" style="fill:none;stroke-width:1px;stroke:rgb(0,0,0)" />
</svg>
Now, if I look in inkscape, the stroke-width is 90px (1in). Also, if I specify the rect size or position in inches, it gets a lot bigger (or moves to a bigger coordinate) than I would think it should. I know I'm missing something but reading through the viewbox and viewport docs are not leading me anywhere enlightening (they mostly discuss in terms of pixels). Could someone steer me in the right direction here?
Without the viewBox you have a viewport of 7in square. In CSS 1in is always 96px so your viewport would be 96 pixels across. If you drew a rect 1in across it would therefore occupy 96 pixels of the screen. (Inkscape may do something different but all browsers use 96px = 1in).
When you add a viewBox you add scaling into the mix. 1px on your drawing may no longer represent 1px on the screen. I.e. 1in on your drawing is still 96px on your drawing but no longer 96 pixels on the screen.
Your current viewBox says that 7px on the screen is now 7in or 7 x 96px so everything on the drawing is magnified by a factor of 96. 1in on the drawing is now 96 x 96 pixels on the screen.
I'm trying to have a SVG path scale to fit the entire container element, without stretching or being trimmed. The SVG is the one below. As you can see, it's a simple border.
<svg preserveAspectRatio="none" viewBox="0 0 370 80" height="100%" width="100%">
<path vector-effect="non-scaling-stroke" d="M359,70C359,70,300,70,185,70C84,70,9,70,9,70C9,70,9,60,9,40C9,24,9,10,9,10C9,10,84,10,185,10C300,10,359,10,359,10C359,10,359,24,359,40C359,60,359,70,359,70C359,70,359,70,359,70"/>
</svg>
Then I have an element that could have different sizes, because it's responsive and because I use it in various cases where width or height can be different. I can't succeed in having the SVG that expands its path by always staying inside the viewport, but scaling without preserving aspect ratio. It doesn't seem a difficult logical thing to do, but I tried various options without success.
EDIT
I was able to scale this SVG, by setting whatever dimensions I wanted. Why does the first not work, but this works instead?
<svg preserveAspectRatio="none" viewBox="0 0 404 77" height="100%" width="100%">
<path vector-effect="non-scaling-stroke" d="m0,0l404,0l0,77l-404,0l0,-77z"/>
</svg>
The short answer is no. What you want to do (as I understand it) is not possible. In SVG you can scale to fit the container (using constant aspect ratio), or you can stretch (ignoring aspect ratio).
There is no way currently to keep some parts of the SVG static and stretch other parts. Unless, of course, you use Javascript to manipulate the contents of the SVG.
What you may want to do is consider using an SVG as the source image for a CSS border-image (see http://www.w3.org/TR/css3-background/#border-images). Perhaps that is the sort of thing you were after?
I want to have a rectangle that takes all the place in a SVG file. It should also have a border (3px stroke width). The size of the graphic should be easy changeable (by changing attributes "width" and "height" of the "svg" node). I came up with following construction:
<svg width="150" height="35" >
<g>
<rect
id="rect6648"
style="fill:#ffffff; fill-opacity:1; stroke:#000000; stroke-width:3;"
x="0"
y="0"
width="100%"
height="100%" />
</g>
</svg>
But it produces following image with dirty border:
I need something like this:
Is it possible at all? As mentioned before it must work for any size of the graphic.
Thanks in advance!
Alas, no, at least not with purely declarative SVG. The stroke on a shape is painted on both sides of the geometric line that defines that shape (in your case, there's 1.5 on either side). Because of that, it will get clipped for a shape that fills the whole viewbox.
In which context are you using this? You should be able to script it: get the size of the viewbow, on rect set x and y to stroke-width/2, width to width - stroke-width and height to height - stroke-width. If in a dynamic context you will need to detect resizes, but that's often possible.
You need to place the ractangle at half pixel coordinates like x="0.5" y="0.5", then the borders won't be blurry. Also add vector-effect:non-scaling-stroke to the rectangle's CSS to be sure that the border is always 3px wide regardless of zoom level.