useradd command option [-c comment] does not work - linux

-c option of useradd command does not work in Linux.
My command is:
useradd -c Hello fyit
Here, Hello is the comment and fyit is the username.
As soon as I press enter after typing this command it shows me the help related to all the options of useradd command.

Please try like,
useradd -c "Hello" fyit

Related

Running commands as different user from bash script

I have 2 users: usr1 and usr2. Neither is a root user.
usr1 starts a bash script. And from the script, I want to run some commands as usr2.
I understand that the way to do it is:
su -l <usr2> -c "command"
The issue is with passing the password. These are 2 different users with different privileges, so, skipping the password for usr2 is not an option.
This script can go interactive, and ask the user for the password. Is there a way to do this in bash script ?
Note: I am not an expert with scripting. And I have done some research before asking this question, but I couldnt find a suitable answer.
You can try using the read read man page command see example below:
#!/bin/bash
read -s -p "Enter your password: " pass
echo $pass
In that case you will need to use /bin/su -c along with sudo -S
#!/bin/bash
user=$1
read -s -p "Enter pass: " pass
cmd=$(echo $pass|sudo -S <some-command>)
su -c '$cmd' - $user
Where user=$1 additional bash argument, in this case the user id for usr2, then jut run it
$sudo bash -x ./password.sh <target-user>

How to run a script as a different user without authentication? [duplicate]

I have script.sh that must be run as user2. However, this script can only be run under user1 in my application.
I would like the following command to run:
su user2 -C script.sh
but be able to run without password.
I also want this to be very restrictive, as in user1 can only run script.sh under user2 and nothing else.
I've tried doing this with sudoers file and just got endlessly confused after hours of trying.
If somebody can provide an explicit example of how this can be accomplished (instead of something generic like use sudoers), it would be greatly appreciated.
try running:
su -c "Your command right here" -s /bin/sh username
This will run the command as username given that you have permissions to sudo as that user.
Call visudo and add this:
user1 ALL=(user2) NOPASSWD: /home/user2/bin/test.sh
The command paths must be absolute! Then call sudo -u user2 /home/user2/bin/test.sh from a user1 shell. Done.
`su -c "Your command right here" -s /bin/sh username`
The above command is correct, but on Red Hat if selinux is enforcing it will not allow cron to execute scripts as another user. example;
execl: couldn't exec /bin/sh
execl: Permission denied
I had to install setroubleshoot and setools and run the following to allow it:
yum install setroubleshoot setools
sealert -a /var/log/audit/audit.log
grep crond /var/log/audit/audit.log | audit2allow -M mypol
semodule -i mypol.p

How do you keep the password hidden when invoked during the su command?

This is the first time it has happened to me where I am using the su command and it actually displays the password on the terminal and doesn't stay hidden. Here is my code snippet:
sshpass -p "password" ssh -q username#74.11.11.11 "su -lc 'mkdir temp/'"
Code explanation: I am accessing a remote server and trying be root on that server to create a folder. In doing so I have to use the su command and it prompts me for the password. When I enter the password, it gets displayed and doesn't stay hidden. How do I fix that?
The solution is to allocate a pseudo TTY (using the -t option on ssh):
sshpass -p "password" ssh -t -q username#74.11.11.11 "su -lc 'mkdir temp/'"
Without this, there's no "terminal" in this context and su is unable to disable echo of the password.
Just like I replied to you here.
It's possible to keep it "hidden" from the command line:
Edit your /etc/profile and paste there:
export SSHPASS='my_pass_here'
Use the -e argument with sshpass command
$ sshpass -e ssh usernmane#hosting.example 'ls -ll'
Another option is to save your password in a different file and use the -f argument:
$ sshpass -f password_filename ssh usernmane#hosting.example 'ls -la'
But the best solution is to follow the #Hristo Mohamed suggestion:
In general please AVOID using sshpass with a password.
You can set up easily a generate ssh key just to do this job and then remove it.

How to run script as another user without password?

I have script.sh that must be run as user2. However, this script can only be run under user1 in my application.
I would like the following command to run:
su user2 -C script.sh
but be able to run without password.
I also want this to be very restrictive, as in user1 can only run script.sh under user2 and nothing else.
I've tried doing this with sudoers file and just got endlessly confused after hours of trying.
If somebody can provide an explicit example of how this can be accomplished (instead of something generic like use sudoers), it would be greatly appreciated.
try running:
su -c "Your command right here" -s /bin/sh username
This will run the command as username given that you have permissions to sudo as that user.
Call visudo and add this:
user1 ALL=(user2) NOPASSWD: /home/user2/bin/test.sh
The command paths must be absolute! Then call sudo -u user2 /home/user2/bin/test.sh from a user1 shell. Done.
`su -c "Your command right here" -s /bin/sh username`
The above command is correct, but on Red Hat if selinux is enforcing it will not allow cron to execute scripts as another user. example;
execl: couldn't exec /bin/sh
execl: Permission denied
I had to install setroubleshoot and setools and run the following to allow it:
yum install setroubleshoot setools
sealert -a /var/log/audit/audit.log
grep crond /var/log/audit/audit.log | audit2allow -M mypol
semodule -i mypol.p

How to useradd with multiple parameters

I'm trying to use multiple parameters with the useradd command in linux, and I'm not really sure exactly what I should do??
I have tried the following:
useradd -b /home/ -g admin -m -p PASSWD -s USERNAME
Needless to say, it doesn't work. Can anyone tell me the correct syntax to get this working? Thanks, your help is always appreciated!
EDIT: I'm not getting an error message, It is just returning the flag variables followed by an ng
The -s flag is for specifying the shell.
So either leave the -s flag out,
useradd -b /home/ -g admin -m USERNAME
or specify a shell:
useradd -b /home/ -g admin -m -s /bin/bash USERNAME
PS. Don't specify the password on the command line. It would be visible to other users listing the processes. Moreover, specifying the password this way requires you to enter the encrypted password.
hmmmm maybe the MAN page: useradd

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