ANTLR : Have errors with Fragment - antlr4

The error is :
mismatched input 'elseState' expecting RULE_TOKEN_REF
Can someone explain to me why do i have this error and how to fix it ?
Your help will be appreciated

Fragments are reserved to lexer rules definition and are not usable for parser rules, you don't need it in your case.
A fragment is used to split complex lexer rules and introduce reusability without producing a dedicated token, e.g.:
NUMBER : DIGIT+;
ID : LETTER (LETTER|DIGIT)*;
fragment LETTER : [a-zA-Z];
fragment DIGIT : [0-9];
In these lexer rules, I don't want LETTER and DIGIT as token, however, I want to use and reuse them in other lexer rules (NUMBER and DIGIT), so I 'mark' them as fragment. It makes the lexer more readable and easier to maintain.
You can read more details here: https://theantlrguy.atlassian.net/wiki/display/ANTLR4/Lexer+Rules

Related

antlr 4 lexer rule RULE: '<TAG>'; isn't recognized as token but if fragment rule then recognized

EDIT:
I've been asked if I can provide the full grammar. I cannot and here is the reason why:
I cannot provide my full grammar code because it is homework and I am not allowed to disclose my solution, and I will sadly understand if my question cannot be answered because of this. I am just hoping this is a simple thing that I am just failing to understand from the documentation and that this will be enough for someone who knows antlr4 to know the answer.
This was posted in the original answer but to prevent frustration from possible helpers I now promote it to the top of the post.
Disclaimer: this is homework related.
I am trying to tokenize a piece of text for homework, and almost everything works as expected, except the following:
TIME : '<time>';
This rule used to be in my grammar. When tokenizing the piece of text, I would not see the TIME token, instead I would see a '<time>' token (which I guess Antlr created for me somehow). But when I moved the string itself to a fragment rule and made the TIME rule point to it, like so:
fragment TIME_TAG : '<time>';
.
.
.
TIME : TIME_TAG;
Then I see the TIME token as expected. I've been searching the internet for several hours and couldn't find an answer.
Another thing that happens is the ATHLETE rule which is defined as:
ATHLETE : WHITESPACE* '<athlete>' WHITESPACE*;
Is also recognized properly and I see the token ATHLETE, but it wasn't recognized when
I didn't allow the WHITESPACE* before and after the tag string.
I cannot provide my full grammar code because it is homework and I am not allowed to disclose my solution, and I will sadly understand if my question cannot be answered because of this. I am just hoping this is a simple thing that I am just failing to understand from the documentation and that this will be enough for someone who knows antlr4 to know the answer.
Here is my piece of text:
World Record World Record
[1] <time> 9.86 <athlete> "Carl Lewis" <country> "United
States" <date> 25 August 1991
[2] <time> 9.69 <athlete> "Tyson Gay" <country> "United
States" <date> 20 September 2009
[3] <time> 9.82 <athlete> "Donovan Baily" <country>
"Canada" <date> 27 July 1996
[4] <time> 9.58
<athlete> "Usain Bolt"
<country> "Jamaica" <date> 16 August 2009
[5] <time> 9.79 <athlete> "Maurice Greene" <country>
"United State" <date> 16 June 1999
My task is simply to tokenize it. I am not being given the definitions of tokens, and I am supposed to decide that myself. I think '<sometag>' is pretty obvious, so are '"' wrapped strings, numbers, dates, and square-bracket surrounded enumerations.
Thanks in advance to any help or any useful knowledge.
(This will be something of a challenge, without just doing your homework, but maybe a few comments will set you on your way)
The TIME : '<time>'; rule should work just fine. ANTLR only creates tokens for you in parser rules. (parser rules begin with lower case letters, and Lexer rules with uppercase letters, so this wouldn't have been the case with this exact example (perhaps you had a rule name that began with a lower case letter?)
Note: If you dump your tokens, you'll see the TIME token represented like so:
[#3,5:10='<time>',<'<time>'>,2:4]
This means that ANTLR has recognized it as the TIME token (I suspect this may be the source of the confusion. It's just how ANTLR prints out the TIME token.)
As #kaby76 mentions, we usually skip whitespace or throw it into a hidden channel as we don't want to be explicit in parser rules about everywhere we allow whitespace. Either of those options causes them to be ignored by the parser. A very common Whitespace rule is:
WS: [ \t\r\n]+;`.
Since you're only tokenizing, you won't need to worry about parser rules.
Adding this Lexer rule will tokenize whitespace into separate tokens for you so you don't need to account for it in rules like ATHLETE.
You'll need work out Lexer rules for your content, but perhaps this will help you move forward.
The following implementation is a split lexer/parser grammar that "tokenizes" your input file. You can combine the two if you like. I generally split my grammars because of constraints with Antlr lexer grammars, such as when you want to "superClass" the lexer.
But, without a clear problem statement, this implementation may not tokenize the input as required. All software must begin with requirements. If none were given in the assignment, then I would state exactly what are the token types recognized.
In most languages, whitespace is not included in the set of token types consumed by a parser. Thus, I implemented it with "-> skip", which tells the lexer to not produce a token for the recognized input.
It's also not clear whether input such as "[1]" is to be tokenized as one token or separately. In the following implementation, I produce separate tokens for '[', '1', and ']'.
The use of "fragment" rules is likely unnecessary so I don't include any use of the feature. "fragment" rules cannot be used to produce a token in itself, and the symbol cannot be used in a parser rule. They are useful for reuse of a common RHS. You can read more about it here.
FooLexer.g4:
lexer grammar FooLexer;
Athlete : '<athlete>';
Date : '<date>';
Time : '<time>';
Country : '<country>';
StringLiteral : '"' .*? '"';
Stray : [a-zA-Z]+;
OB : '[';
CB : ']';
Number : [0-9.]+;
Ws : [ \t\r\n]+ -> skip;
FooParser.g4:
parser grammar FooParser;
options { tokenVocab = FooLexer; }
start: .* EOF;
Tokens:
$ trparse input.txt | trtokens
Time to parse: 00:00:00.0574154
# tokens per sec = 1219.1850966813781
[#0,0:4='World',<6>,1:0]
[#1,6:11='Record',<6>,1:6]
[#2,13:17='World',<6>,1:13]
[#3,19:24='Record',<6>,1:19]
[#4,27:27='[',<7>,2:0]
[#5,28:28='1',<9>,2:1]
[#6,29:29=']',<8>,2:2]
[#7,31:36='<time>',<3>,2:4]
[#8,38:41='9.86',<9>,2:11]
[#9,43:51='<athlete>',<1>,2:16]
[#10,53:64='"Carl Lewis"',<5>,2:26]
[#11,66:74='<country>',<4>,2:39]
[#12,76:91='"United\r\nStates"',<5>,2:49]
[#13,93:98='<date>',<2>,3:8]
[#14,100:101='25',<9>,3:15]
[#15,103:108='August',<6>,3:18]
[#16,110:113='1991',<9>,3:25]
[#17,116:116='[',<7>,4:0]
[#18,117:117='2',<9>,4:1]
[#19,118:118=']',<8>,4:2]
[#20,120:125='<time>',<3>,4:4]
[#21,127:130='9.69',<9>,4:11]
[#22,132:140='<athlete>',<1>,4:16]
[#23,142:152='"Tyson Gay"',<5>,4:26]
[#24,154:162='<country>',<4>,4:38]
[#25,164:179='"United\r\nStates"',<5>,4:48]
[#26,181:186='<date>',<2>,5:8]
[#27,188:189='20',<9>,5:15]
[#28,191:199='September',<6>,5:18]
[#29,201:204='2009',<9>,5:28]
[#30,207:207='[',<7>,6:0]
[#31,208:208='3',<9>,6:1]
[#32,209:209=']',<8>,6:2]
[#33,211:216='<time>',<3>,6:4]
[#34,218:221='9.82',<9>,6:11]
[#35,223:231='<athlete>',<1>,6:16]
[#36,233:247='"Donovan Baily"',<5>,6:26]
[#37,249:257='<country>',<4>,6:42]
[#38,260:267='"Canada"',<5>,7:0]
[#39,269:274='<date>',<2>,7:9]
[#40,276:277='27',<9>,7:16]
[#41,279:282='July',<6>,7:19]
[#42,284:287='1996',<9>,7:24]
[#43,290:290='[',<7>,8:0]
[#44,291:291='4',<9>,8:1]
[#45,292:292=']',<8>,8:2]
[#46,294:299='<time>',<3>,8:4]
[#47,301:304='9.58',<9>,8:11]
[#48,308:316='<athlete>',<1>,9:1]
[#49,318:329='"Usain Bolt"',<5>,9:11]
[#50,333:341='<country>',<4>,10:1]
[#51,343:351='"Jamaica"',<5>,10:11]
[#52,353:358='<date>',<2>,10:21]
[#53,360:361='16',<9>,10:28]
[#54,363:368='August',<6>,10:31]
[#55,370:373='2009',<9>,10:38]
[#56,378:378='[',<7>,12:0]
[#57,379:379='5',<9>,12:1]
[#58,380:380=']',<8>,12:2]
[#59,382:387='<time>',<3>,12:4]
[#60,389:392='9.79',<9>,12:11]
[#61,394:402='<athlete>',<1>,12:16]
[#62,404:419='"Maurice Greene"',<5>,12:26]
[#63,421:429='<country>',<4>,12:43]
[#64,432:445='"United State"',<5>,13:0]
[#65,447:452='<date>',<2>,13:15]
[#66,454:455='16',<9>,13:22]
[#67,457:460='June',<6>,13:25]
[#68,462:465='1999',<9>,13:30]
[#69,466:465='',<-1>,13:34]

ANTLR 4: Recognises 'and' but not 'or' without a space

I'm using the ANTLR 4 plugin in IntelliJ, and I have the most bizarre bug. I'll start with the relevant parser/lexer rules:
// Take care of whitespace.
WS : [ \r\t\f\n]+ -> skip;
OTHER: . -> skip;
STRING
: '"' [A-z ]+ '"'
;
evaluate // starting rule.
: textbox? // could be an empty textbox.
;
textbox
: (row '\n')*
;
row
: ability
| ability_list
ability
: activated_ability
| triggered_ability
| static_ability
triggered_ability
: trigger_words ',' STRING
;
trigger_words
: ('when'|'whenever'|'as') whenever_triggers|'at'
;
whenever_triggers
: triggerer (('or'|'and') triggerer)* // this line has the issue.
;
triggerer
: self
self: '~'
I pass it this text: whenever ~ or ~, and it fails on the or, saying line 1:10 mismatched input ' or' expecting {'or', 'and'}. However, if I add a space to the whenever_triggers rule's or string (making it ' or'|'and'), it works fine.
The weirdest thing is that if I try whenever ~ and ~, it works fine even without the rule having a space in the and string. This doesn't change if I make 'and'|'or' a lexer rule either. It's just bizarre. I've confirmed this bug happens when running the 'test rig' in Antlrworks 2, so it's not just an IntelliJ thing.
This is an image of the parse tree when the error occurs:
Alright you have found the answer more or less by yourself so with this answer of mine I will focus on explaining why the problem occured in the first place.
First of all - for everyone stumbling upon this question - the problem was that he had another implicit lexer rule defined that looked like this ' or' (notice the whitespace). Changing that to 'or' resolved the problem.
But why was that a problem?
In order to understand that you have to understand what ANTLR does if you write '<something>' in one of your parser rules: When compiling the grammar it will generate a new lexer rule for each of those declarations. These lexer rules will be created before the lexer rules defined in your grammar. The lexer itself will match the given input into tokens and for that it processes each lexer rule at a time in the order they have been declared. Therefore it will always start with the implicit token definitions and then move on to the topmost "real" lexer rule.
The problem is that the lexer isn't too clever about this process that means once it has matched some input with the current lexer rule it will create a respective token and moves on with the trailing input.
As a result a lexer rule that comes afterwards that would have matched the input as well (but as another token as it is a different lexer rule) will be skipped so that the respective input might not have the expected token type because the lexer rules have overwrritten themselves.
In your example the self-overwriting rules are ' or'(Token 1) and 'or'(Token 2). Each of those implicit lexer rule declarations will result in a different lexer rule and as the first one got matched I assume that it is declared before the second one.
Now look at your input: whenever ~ or ~ The lexer will start interpreting it and the first rule it comes across is ' or' (After the start is matched of course) and it will match the input as there really is a space before the or. Therefore it will match it as Token 1.
The parser on the other hand is expecting a Token 2 at this point so that it will complain about the given input (although it really is complaining about the wrong token type). Altering the input to whenever ~or ~ will result in the correct interpretation.
Exactly that is the reason why you shouldn't use implicit token definitions in your grammar (unless it is really small). Create a new lexer rule for every input and start with the most specific rules. That means rules that match special character sequences (e.g. keywords) should be declared before general lexer rules like ID or STRING or something like that. Rules that will match all the characters in order to prevent the lexer from throwing an error upon unrecognized input have to declared last as they would overwrite every lexer rule after them.

antlr4 token recognition error at: '$'

Trying to build a grammar for PowerScript language. I split the language in several parts and everything seems to be working except for the simple headers. It seems that the $ simbol can't be recognized. Could anyone help me a little? ( I just copy the small example I'm trying)
grammar PowerScript;
compilationUnit : Header EOF;
fragment
Header : ID '.' ID;
ID : [a-zA-Z0-9$_]+ ;
test file just contains:
$PBExportHeader$n_logversion.sru
Thanks
The compilationUnit rule is a parser rule. Parser rules cannot refer to lexer fragments. Just remove the fragment qualifier to make Header a proper lexer rule.
Update
Antlr4 is fully Unicode capable. Just include the characters in standard Unicode encoding form:
ID : ( [a-zA-Z0-9$_] | '\uD83D\uDCB2' )+ ; // Unicode heavy Dollar sign

Solving ambiguous input: mismatched input

I have this grammar:
grammar MkSh;
script
: (statement
| targetRule
)*
;
statement
: assignment
;
assignment
: ID '=' STRING
;
targetRule
: TARGET ':' TARGET*
;
ID
: ('a'..'z'|'A'..'Z'|'_') ('a'..'z'|'A'..'Z'|'0'..'9'|'_')*
;
WS
: ( ' '
| '\t'
| '\r'
| '\n'
) -> channel(HIDDEN)
;
STRING
: '\"' CHR* '\"'
;
fragment
CHR
: ('a'..'z'|'A'..'Z'|' ')
;
TARGET
: ('a'..'z'|'A'..'Z'|'0'..'9'|'_'|'-'|'/'|'.')+
;
and this input file:
hello="world"
target: CLASSES
When running my parser I'm getting this error:
line 3:6 mismatched input ':' expecting '='
line 3:15 mismatched input ';' expecting '='
Which is because of the parser is taking "target" as an ID instead of a TARGET. I want the parser to choose the rule based on the separator character (':' vs '=').
How can I get that to happen?
(This is my first Antlr project so I'm open to anything.)
First, you need to know that the word target is matched as a ID token and not as a TARGET token, and since you have written the rule ID before TARGET, it will always be recognized as ID by the lexer. Notice that the word target completely complies to both ID and TARGET lexer rule, (I'm going to suppose that you are writing a laguage), meaning that the target which is a keyword can also be used as an id. In the book - "The definitive ANTLR reference" there is a subtitle "Treating Keywords As Identifiers" that deals with exactely these kinds of issues. I suggest you take a look at that. Or if you prefer the quick answer the solution is to use lexer modes. Also would be better to split grammar into parser and lexer grammar.
As #cantSleepNow alludes to, you've defined a token (TARGET) that is a lexical superset of another token (ID), and then told the lexer to only tokenize a string as TARGET if it cannot be tokenized as ID. All made more obscure by the fact that ANTLR lexing rules look like ANTLR parsing rules, though they are really quite different beasts.
(Warning: writing off the top of my head without testing :-)
Your real project might be more complex, but in the possibly simplified example you posted, you could defer distinguishing the two to the parsing phase, instead of distinguishing them in the lexer:
id : TARGET
{ complain if not legal identifier (e.g., contains slashes, etc.) }
;
assignment
: id '=' STRING
;
Seems like that would solve the lexing issue, and allow you to give a more intelligent error message than "syntax error" when a user gets the syntax for ID wrong. The grammar remains ambiguous, but maybe ANTLR roulette will happen to make the choice you prefer in the ambiguous case. Of course, unambiguous grammers tend to make for languages that humans find more readable, and now you can see why the classic makefile syntax requires a newline after an assignment or target rule.

ANTLR 4 Lexer rule : how to ignore a part?

Here is a related topic for previous ANTLR version :
Java ANTLR how to ignore part of rule? ignore part after subrule
With a lexer rule like :
R1
: [a-zA-Z0-9]* ';'
;
For example i have this input text :
test;rezrezr
zrezrzerz
It will match "test;" wich is correct. I only need the "test" string.
Do i need to take care of ';' character manually in a custom listener for example ? Or is there a way to specify in the grammar that i want to avoid it (only using lexer rules) ?
UPDATE
test1;rezrezr
zrezrzerz
test2;rezrezr
zrezrzerz
If you want to avoid the ; character, simply remove it from the lexer rule. Note that I also changed the * to a + to ensure that R1 is never a zero-length token.
R1
: [a-zA-Z0-9]+
;

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