i have some sting like "John-Raj " I would like to combine these two as a single field in logstash by using grok pattern.
So I want the output as like below. But I am not able to get the output as single field by using \%{WORD} and %{NOTSPACE}
"John-Raj"
And ideas how to create grok to output?
%{WORD} is alphanumeric and underscore, so it won't match your hyphen.
%{NOTSPACE} matches in the debugger.
If you have quoted text yo may use %{QS} pattern.
I was looking how to combine several patterns to build the one value as well.
Found here
Sometimes logstash doesn’t have a pattern you need. For this, you have
a few options.
First, you can use the Oniguruma syntax for named capture which will
let you match a piece of text and save it as a field:
(?<_field_name_>the pattern here)
So in your case the following will make value = "John-Raj" (tested in the debugger)
(?<value>%{WORD}%{NOTSPACE})
Related
I have the following log which was generated using log4net
2017-12-11 17:01:28,390 [6] INFO DAL.DBManager "FunctionName":"Dispose"
The problem is the 2 spaces after INFO. If the word is debug it seems to only have 1 space, so it could be "tab".
I'm using http://grokdebug.herokuapp.com/ but my pattern, below, doesn't seem to work.
%{TIMESTAMP_ISO8601} \[%{NUMBER:thread}\] %{LOGLEVEL:log-level} %{DATA:CLASS} %{DATA:Function} %{DATA:FunctionName} %{GREEDYDATA:remainder}
I've tried adding %{SPACE} instead of the space but it doesn't generate anything.
If you want to match exactly two whitespaces, you'll have to add two whitespaces in your pattern aswell. Following pattern seems to match the line you wrote:
%{TIMESTAMP_ISO8601} \[%{NUMBER:thread}\] %{LOGLEVEL:log-level} %{DATA:CLASS}\.%{DATA:Function} %{DATA:FunctionName}\:%{GREEDYDATA:remainder}
If you want to match one or two whitespaces you can use a whitespace and an optional whitespace ( )? like so:
%{TIMESTAMP_ISO8601} \[%{NUMBER:thread}\] %{LOGLEVEL:log-level} ( )?%{DATA:CLASS}\.%{DATA:Function} %{DATA:FunctionName}\:%{GREEDYDATA:remainder}
Please see image. How the heck do you get a simple [a-zA-Z] expression to work in the KIBANA X-Pack Grok debugger?
I've tried several flavors and have ran the regex just fine in normal regex testing environments where it finds all that I need but this debugger wants something that I cannot figure out. Again this is a CUSTOM regular expression not the pre-built ones.
[a-z]
[A-Z]
[a-zA-Z]
([a-zA-Z]+)
and more
The first box is the data string, the second box is the pattern and the last box is where you define custom patterns. You have no pattern and the syntax for defining a custom pattern is wrong.
In the second box type
%{MY_REGEX:results}
In the third box type
MY_REGEX [a-z]
This creates a new pattern called MY_REGEX which can be used in the actual search pattern.
That matches the first character of the data, which is unlikely to be what was intended, but that should get you started.
See also https://www.elastic.co/guide/en/kibana/current/grokdebugger-getting-started.html#grokdebugger-custom-patterns
This may be a simple question, but in my logs the spaces between different fields are uncertain, that mean in some logs I can see two spaces and in some three between the same fields. How do we accommodate this in GROK?
You can use %{SPACE}* in your grok pattern for matching uncertian number of spaces. It will match even if spaces are present or not.
Grok is at it's heart an overlay on Regex's. So in your grok pattern, you can directly use Regex syntax:
%{WORD} +%{WORD}
So "space+" means one or more spaces. "space*" means 0 or more spaces.
Grok also has a pattern %{SPACE} that is equivilent to " *"
I'm writing a shell script to modify a file and I have a line something like this in it:
sed s/here \(.*\n\)/gone \1/g
Unfortunately, the search seems to match the longest string (i.e., it goes all the way to the last \n -- thus giving me just one replacement) but I want it to match only up to the first \n it finds (so I can get replacements on every line).
Is this possible?
Thanks for your help!
Looks like you want the feature called non-greedy (or lazy) match. Unfortunately sed does not provide such feature. To emulate it you need to search for anything except separator match until separator match. Like this:
s/here \([^\n]*\n\)/gone \1/g
I have an XML file like this:
<fruit><apple>100</apple><banana>200</banana></fruit>
<fruit><apple>150</apple><banana>250</banana></fruit>
Now I want delete all the text in the file except the words in tag apple. That is, the file should contain:
100
150
How can I achive this?
:%s/.*apple>\(.*\)<\/apple.*/\1/
That should do what you need. Worked for me.
Basically just grabbing everything up to and including the tag, then backreferences everything between the apple begin and end tag, and matches to the rest of the line. Replaces it with the first backreference, which was the stuff between the apple tags.
I personally use this:
%s;.*<apple>\(\d*\)</apple>.*;\1;
Since the text contain '/' which is the default seperator,and by using ';' as sep makes the code clearer.
And I found that non-greedy match #Conspicuous Compiler mentioned should be
\{-}
instead of "{-}" in Vim.
However, I after change Conspicuous' solution to
%s/.*apple>(.\{-\})<\/apple.*/\1^M/g
my Vim said it can't find the pattern.
In this case, one can use the general technique for collecting pattern matches
explained in my answer to the question "How to extract regex matches
using Vim".
In order to collect and store all of the matches in a list, run the Ex command
:let t=[] | %s/<apple>\(.\{-}\)<\/apple>\zs/\=add(t,submatch(1))[1:0]/g
The command purposely does not change the buffer's contents, only collects the
matched text. To set the contents of the current buffer to the
newline-separated list of matches, use the command
:0pu=t | +,$d_