How to override "=" - haxe

I was looking into Haxe abstracts and was very interested in building an abstract that would wrap a class and unify it to, in my case, an Int.
#:forward()
abstract Abs(Op)
{
public inline function new(value:Int = 0, name:String = "unnamed" )
{
this = new Op();
this.value = value;
this.name = name;
}
#:to
private inline function toInt():Int
{
return this.value;
}
}
class Op
{
public var value:Int = 0;
public var name:String = "no name";
public function new()
{
}
}
The problem I ran in to is when defining a #:from method - it has to be static and can take only one parameter - a new value. So whenever I set the abstract's instance value from the #:from method I will have to create a new instance of the abstract, thus resetting all the variables.
Basically what I'm talking about is this:
var a = new Abs(5, "my abs"); // value is 5; name is "my abs"
a = 100; // value is 100; name is reset to "unnamed" but I want it to be preserved
As much as I could find out we cannot overload the = operator in abstracts other than through implicit casting with a #:from method and I haven't found a way to really achieve this with macros.
If you have any ideas on how this can be done, please provide a minimalist example.

It depends what you want to do, but if you use this:
var a = new Abs(5, "my abs");
var myInt:Int = a;
It will use the abstract Abs.toInt function.
#:to
private inline function toInt():Int
{
return this.value;
}
The other way around also works:
var million = 1000000;
var myAbs:Abs = million;
It will use the static Abs.fromInt function.
#:from
static inline function fromInt(value:Int)
{
return new Abs(value, "what");
}
This is because it uses the implicit cast. http://haxe.org/manual/types-abstract-implicit-casts.html
Try it yourself: http://try.haxe.org/#Ae1a8
Is that what you are looking for?

Related

How to use class functions in another class?

How can i use class instance in another class like a pointer in C++ to class instance functions?
Example:
class A {
constructor()
{
this.block = [];
}
method()
{
return this.blocks.length;
}
}
another class:
class B {
constructor(instance)
{
this.instance = instance;
}
method()
{
this.instance.method(); // here i'm getting cannot get length of undefined
}
}
If i'm trying to to like that i'm getting problems to call it
You can try this. Here, when creating B class's instance I give into it an A class's instance as argument. Then inside B we can call A instance's methods, and access its properties.
Also, as #ViaTech posted you can use static methods to access them without needing to initialize an object of the class. That is what static methods is. Refer Static Methods
class B {
constructor(instance)
{
this.instance = instance;
}
method()
{
this.instance.method();
}
}
class A {
constructor()
{
}
method()
{
console.log("A's method");
}
}
var a = new A();
var b = new B(a);
b.method(); // A's method
You can easily do this in JS by calling a static method like so:
class A {
static write(){ //static method
console.log("Called write from A");
}
}
class B {
doIt(){
A.write();
}
}
let b = new B();
b.doIt();
Option 2, you instantiate the class in the constructor of the other like so:
class A {
write(){
console.log("Non-static write() called from class A");
}
}
class B {
constructor() {
this.a = new A();
}
doIt(){
this.a.write();
}
}
let b = new B();
b.doIt();
There are a few ways:
I accidentally switched between PHP and Javascript, but the principles are the same for both)
Use static functions:
Normally, you have a this in the class. Say you have this code:
class Car {
let color;
public function setColor(newColor){ this.color = newColor;}
}
let car = new Car();
car->setColor('green')`
The setColor function's this refers to that car. You can make let anotherCar = new Car(), then when you do anotherCar->setColor('red') you only change that car, not the first one. Simplistic: You can create multiple instances.
If you do not need that, but need the class once, you can make it static. A simple way to explain would be "you have a collection of seperate functions, just put into a wrapping class (which doesn't do a lot really)". For instance, you might have some sanatizing methods:
class Sanitize {
static function makeHtmlSave(input){
return doYourMagicHere(input);
}
static function removeXssCode(input){
return doMoreMagicHere(input);
}
}
This way, you can reuse it multiple times. If you want to use it, you do Sanitize::makeHtmlSave(someCode) where you need it. There isn't a Sanitize thing, it's just a wrapper to access the frunctions inside it.
Use extend:
You can extend a class. Say you have a generic class Vehicle, which has some properties (eg a motor, numberWeels, color) and you can extend that with more specific classes:
class Vehicle {
let color;
public function setColor(newColor){ this.color = newColor}
}
class Car extends Vehicle {
let hasAirco = false;
public function hasAirco(newValue){ this.hasAirco = newValue};
}
If you do let car = new Car(), you get a Car object, that extends/enlarges/complements the Vehicle class, so you can use both its (public) functions. Internally, Car can use the functions of Vehicle too.
Just pass it
class One {
// some stuff
}
class Two{
let otherObject;
construct(givenObject){
this.otherObject = givenObject;
}
}
You can now do this let a = new One(); let b = new Two(a);. You can not use the functions of One inside Two, but you can still use a->doSomething(). This solution feels like the easiest, but it almost never is. Classes/objects are tricky stuff, but I've rarely uses this solutions. There are use cases, but often it's a bad smell indicator.

Non type type parameters

What if I have classes that are different only by some constant used in code. Is it possible to have one generic implementation without runtime cost?
Here is the example (it's a little bit too long...)
#:enum abstract Param(Int) {
var foo = 0;
var bar = 1;
}
class WorkBase {
public function new() {}
private inline function work_impl(p: Param): Void {
if(p == foo) {
trace('foo');
}
else {
trace('bar');
}
}
public function work(): Void {
}
}
class WorkFoo extends WorkBase{
override public function work(): Void {
work_impl(foo);
}
}
class WorkBar extends WorkBase {
override public function work(): Void {
work_impl(bar);
}
}
class Test {
public static function main() {
var workFoo = new WorkFoo();
var workBar = new WorkBar();
workFoo.work();
workBar.work();
}
}
After compilation with -D analyzer-optimize we will see that WorkFoo.work() and WorkBar.work() functions were optimized and contain only one branch of code that matches one of the Param values. In real life there are lot of such comparisons in work_impl(), and they all are optimized out. That's good.
But what if I do not want to create WorkFoo and WorkBar by hand. Is it possible to do something like this:
#:generic
class WorkBase<PARAM> {
private inline function work_impl(p: Param): Void {
...
}
public function work(): Void {
work_impl(PARAM);
}
}
The closest thing I know is const-type-parameter. But I do not feel generic build is a good choice here.
The closest thing I know is const-type-parameter. But I do not feel generic build is a good choice here.
Const type parameters can be used without #:genericBuild - a const type parameter in combination with #:generic is enough to get the desired optimization:
#:enum abstract Param(Int) from Int {
var foo = 0;
var bar = 1;
}
#:generic class Work<#:const PARAM:Int> {
public function new() {}
public function work():Void {
if (PARAM == foo) {
trace('foo');
} else {
trace('bar');
}
}
}
class Main {
public static function main() {
var workFoo = new Work<0>();
var workBar = new Work<1>();
workFoo.work();
workBar.work();
}
}
Due to #:generic, one class is generated for each constant value, for instance on JS the output looks like this:
var Work_$0 = function() {
};
Work_$0.prototype = {
work: function() {
console.log("source/Main.hx:11:","foo");
}
};
var Work_$1 = function() {
};
Work_$1.prototype = {
work: function() {
console.log("source/Main.hx:13:","bar");
}
};
Note that this example fails with a "constraint check failure" in Haxe 3.4.7 for some reason, but works fine with Haxe 4 preview 4 and later. Another limitation is that neither new Work<Param.foo>() nor new Work<foo>() work - you need to pass the actual constant value.

constraint on static fields and type inference

Is it possible to have constraint on static fields in Haxe? For example we may have classes which have static field instance of type of corresponding class. And we may want a function that will return an instance of class passed as parameter. This is my attempt:
class Foo {
static public var instance = new Foo();
function new() {}
}
class Test {
// get instance from every class that have static field instance
static function getInstance<T, ClassT:({instance:T}, Class<T>)>(t:ClassT):T {
return t.instance;
}
static function main() {
var a = getInstance(Foo);
$type(a); //Test.hx:14: characters 14-15 : Warning : Unknown<0>
}
}
but it fails, because type parameter constraints are checked lazily. Any ideas on how do this?
Have you considered using a typedef?
Heres a quick edit of your code showing the basic idea
typedef HasInstance = {
var instance:Dynamic;
}
class Foo {
static public var instance = new Foo();
function new() {}
}
class Bar {
static public var instance = new Bar();
function new() {}
}
class Test {
// get instance from every class that have static field instance
static function getInstance<T:HasInstance>(t:T):T {
trace(t);
return t.instance;
}
static function main() {
var a = getInstance(Foo);
trace(a);
$type(a);
var b = getInstance(Bar);
trace(b);
$type(b);
}
}
example on try haxe!
You would change the instance type within the typedef to be more appropriate for your needs, and you can also constrain typedefs too, which can be very useful
If you don't mind using macro, here is a possible solution:
http://try-haxe.mrcdk.com/#7d650
Foo.hx
class Foo {
static public var instance = new Foo();
public var foo:Int;
function new() {}
}
class Test {
macro static function getInstance(e) return Macro.getInstance(e);
static function _getInstance<T, ClassT:({instance:T}, Class<T>)>(t:ClassT):T
return t.instance;
static function main() {
var a = getInstance(Foo);
$type(a);
}
}
Macro.hx
import haxe.macro.Expr;
import haxe.macro.Context.*;
using tink.MacroApi;
class Macro {
public static function getInstance(e:Expr) {
var ct = TPath(e.toString().asTypePath());
return macro (Test._getInstance($e):$ct);
}
}

How to specify a literal initialiser for Stack or Queue?

This:
List<string> set = new List<string>() { "a","b" };
works fine, but:
Stack<string> set = new Stack<string>() { "a","b" };
Queue<string> set = new Queue<string>() { "a","b" };
fails with:
...does not contain a definition for 'Add'
which does make me wonder why the compiler was dumb enough to ask for Add.
So, how should one initialise at a Queue/Stack constructor?
Collection initializers are a compiler feature that call the Add method with each item you pass.
If there is no Add method, you can't use it.
Instead, you can call the Stack or Queue constructor that takes an IEnumerable<T>:
var stack = new Stack<int>(new [] { 1, 2, 3 });
in C# 6.0, you can do this:
var stack = new Stack<string> () {"a","b"};
with below extension method
public static class Util
{
public static void Add<T>(this Stack<T> me, T value)
{
me.Push(value);
}
}

How to Implicitly Convert an Enumerable of a type with Implicit Conversion Operators in C# 4.0

Given:
public struct Id
{
readonly int m_id;
public Id(int id)
{ m_id = id; }
public static implicit operator int(Id id)
{ return id.m_id; }
public static implicit operator Id(int id)
{ return new Id(id); }
}
Can you implicitly convert an
IEnumerable<int>
to
IEnumerable<Id>
and vice versa. In some way. Note that
var ids = new int[]{ 1, 2 };
ids.Cast<Id>();
does not appear to work and covariance does not appear to be working in this case, either. Of course, doing a select will work i.e.:
ids.Select(id => new Id(id));
But I am looking for something that would make this work implicitly, so writing:
IEnumerable<Id> ids = new int[]{ 1, 2 };
And yes, I know this can be written as:
IEnumerable<Id> ids = new Id[]{ 1, 2 };
But the issue is in cases where the enumerable of ints comes from a different source, such as a file for example.
I am sorry if there already is an answer for this, but I could not find it.
According to this answer what you want is not possible. But you can get close by not implicitly casting your id but your collection. Like this :
public class Ids : List<int>
{
public static implicit operator Ids(int[] intArray)
{
var result = new Ids();
result.AddRange(intArray);
return result;
}
}
then this is possible :
Ids t = new [] { 3,4 };
What's wrong with:
IEnumerable<int> data = GetDataFromSource();
IEnumerable<Id> ids = data.select(id => new Id(id));

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