I am trying to make an average of multiple cells, and I want to ignore to zero cells.
Here is my formula =IFERROR(AVERAGEIF(L4:L10;L12:L18;L20:L26;L28:L34;L36:L37);"") and I don't know where to put the condition to ignore zero "<>0" . Am I doing something wrong?
Assuming you only have positive values and zeroes you can average without zeroes, for non-contiguous ranges using this syntax
=IFERROR(SUM(L4:L10;L12:L18;L20:L26;L28:L34;L36:L37)/INDEX(FREQUENCY((L4:L10;L12:L18;L20:L26;L28:L34;L36:L37);0);2);"")
The FREQUENCY part gives you a two element array, one being the count of zeroes, the other the count of positive values, INDEX then retrieves the second of those (the number of positive values), so if you divide the sum by that count you get the average excluding zeroes. FREQUENCY function (unlike AVERAGEIF) accepts a non contiguous range argument (a "union")
....but if you can identify which rows to exclude by using values in another column then it's easier with AVERAGEIFS, e.g. if on the excluded rows, e.g. in K11, K21, K35 etc. they all have the value "Total" you can use this version:
=IFERROR(AVERAGEIFS(L4:L37;L4:L37;"<>0";K4:K37;"<>Total");"")
adjust depending on the exact text, wildcards are possible
Here is another way using SUMIF and COUNTIF.
Example data:
Values
1
-3
0
5
777
3
0
0
8
text
4
5
6
0
6
7
Formulas:
B18=SUMIF(A2:A17,"<>0",A2:A17)-SUM(A6,A11,A15)
B19=COUNTIF(A2:A5,"<>0")+COUNTIF(A7:A10,"<>0")+COUNTIF(A12:A17,"<>0")
B20=B18/B19
Related
I have two Excel lists:
One extensive with 20 thousand lines. In which:
Two columns are important: First: Unique ID, Second: a value (number formatted).
It can be a value that appears several times, or only once.
I have to create the second list. In this list I have only one column of values that I would like to have.
I need a formula that will look for values from List 2 in List 1 and then match a Unique ID to each value.
It is important that, when no direct value exist. In this case it has to search for a sample which is in about 3-5% value deviation.
Example: there was no value 127, but within 3%, 125 was found.
I've tried indexing and comparison, but it does not seem to work.
VLOOKUP worked, but without 3-5% deviation
I am very grateful for the help.
Example: http://www.filedropper.com/excellist1and2
If the value exists in the list, you can use VLOOKUP or INDEX(MATCH to find it - that's the easy part. If the value is not in the list, then you need to find the nearest value.
The nearest "low" value will be the MAX value ≤ our input, and the nearest "high" value will be the MIN value ≥ our input.
If you have Office 365, you can use MINIFS($D$1:$D$6,$D$1:$D$6,">="&B1,$D$1:$D$6,"<="&(B1*1.05)) and MAXIFS($D$1:$D$6,$D$1:$D$6,"<="&B1,$D$1:$D$6,">="&(B1*0.95)) )` here. If not, you'll need an Array Formula, we can build that "±5%" in early, to simplify the formula.
Starting with the Low values, we want the MAX value ≤ our input and ≥ 95% of our input. Putting an Array Formula in a SUMPRODUCT so that we can use it in a normal formula, we get =SUMPRODUCT(MAX($D$1:$D$6*--($D$1:$D$6<=B1)*--($D$1:$D$6>=(B1*0.95))))
The High values are slightly harder, because we can't just multiply be 0 to cancel out anything too low, or over 105% of the target. We need to add a huge number like 1E+99 (a 1 with ninty-nine 0s after it) instead, so that the MIN will ignore them: SUMPRODUCT(MIN($D$1:$D$6+1E+99*(--($D$1:$D$6<B1)+--($D$1:$D$6>(B1*1.05)))))
The last steps are to decide which of these numbers is closer to the target, and then to find the Unique ID to match. The %closeness calculations are (TARGET - LOW)/TARGET and (HIGH - TARGET)/TARGET), and subtracting one from the other gives you 2-(HIGH + LOW)/TARGET - a Positive number means "High" is closer, a Negative number means that "Low" is closer, and 0 means they are both the same distance (I'll default this to the Low number). We then use SIGN to change it to ±1, add 2 to get 1,2 or 3 and finish up with CHOOSE to output our number. In pseudo-code, CHOOSE(2+SIGN(2-(HIGH+LOW)/TARGET),LOW,LOW,HIGH), and the full thing:
CHOOSE(2+SIGN(2-(SUMPRODUCT(MAX($D$1:$D$6*--($D$1:$D$6<=B1)*--($D$6>B1*0.95)))+SUMPRODUCT(MIN($D$1:$D$6+1E+99*(--($D$1:$D$6<B1)+--($D$1:$D$6>(B1*1.05))))))/B1),SUMPRODUCT(MAX($D$1:$D$6*--($D$1:$D$6<=B1)*--($D$6>B1*0.95))),SUMPRODUCT(MAX($D$1:$D$6*--($D$1:$D$6<=B1)*--($D$6>B1*0.95))),SUMPRODUCT(MIN($D$1:$D$6+1E+99*(--($D$1:$D$6<B1)+--($D$1:$D$6>(B1*1.05))))))
Now, we have a number. All we need to do is either use VLOOKUP, or use MATCH to get the row it is on, and INDEX to pull the data for that row:
Office 365:
=IFERROR(VLOOKUP(B1,$D$1:$E$6,2,FALSE),VLOOKUP(CHOOSE(2+SIGN(2-(MAXIFS($D$1:$D$6,$D$1:$D$6,"<="&B1,$D$1:$D$6,">="&(B1*0.95))+MINIFS($D$1:$D$6,$D$1:$D$6,">="&B1,$D$1:$D$6,"<="&(B1*1.05)))/B1),MAXIFS($D$1:$D$6,$D$1:$D$6,"<="&B1,$D$1:$D$6,">="&(B1*0.95)),MAXIFS($D$1:$D$6,$D$1:$D$6,"<="&B1,$D$1:$D$6,">="&(B1*0.95)),MINIFS($D$1:$D$6,$D$1:$D$6,">="&B1,$D$1:$D$6,"<="&(B1*1.05))),$D$1:E$7,2,FALSE))
Otherwise:
=IFERROR(VLOOKUP(B1,$D$1:$E$6,2,FALSE),VLOOKUP(CHOOSE(2+SIGN(2-(SUMPRODUCT(MAX($D$1:$D$6*--($D$1:$D$6<=B1)*--($D$6>B1*0.95)))+SUMPRODUCT(MIN($D$1:$D$6+1E+99*(--($D$1:$D$6<B1)+--($D$1:$D$6>(B1*1.05))))))/B1),SUMPRODUCT(MAX($D$1:$D$6*--($D$1:$D$6<=B1)*--($D$6>B1*0.95))),SUMPRODUCT(MAX($D$1:$D$6*--($D$1:$D$6<=B1)*--($D$6>B1*0.95))),SUMPRODUCT(MIN($D$1:$D$6+1E+99*(--($D$1:$D$6<B1)+--($D$1:$D$6>(B1*1.05)))))),$D$1:E$7,2,FALSE))
(Obviously, change $D$1:$D$6 and $D$1:$E$6 to your actual data table ranges, and B1 to the input-value range)
I'm trying to write a SUM(IF(zero, add 8), A1:G1) kind of excel function.
What it should do:
If the cell contains a number, add that number to the sum.
If the cell contains a number = 0, add 8 to the sum.
if the cell is empty, add nothing to the sum
I have tried using SUMIF, but it only "adds the numbers if they meet a criteria", and I rather need "add this when the criteria is met"
You could just make a longer formula:
=SUM(A1:G1)+COUNTIF(A1:G1, 0)*8
The first sum will only do your numbers ignore blanks and 0's, the second part counts the number of 0's and multiplies it by 8.
You can do this with the following formula:
=SUMIF(A1:G1,">0")+8*COUNTIFS(A1:G1,0,A1:G1,"<>")
should be self-explaining :)
Method 1
If you can spare another column, just use an IF statement to replace all 0's by 8's and blanks by 0's (not really necessary) in a new column
=IF(A1=0,8,A1) and take a SUM of this column.
Method 2
Just SUM over your original data, count the number of zeros in your data and multiply this number by 8.
=SUM(A1:A10)+8*COUNTIF(A1:A10,"=0")
Note: The data is in A1:A10 in this case.
I have 3 different cells like this in my Excel table:
[B1] = 2
[N50] = 5
[V25] = 10
I want to find in those cells the nearest number greater than a specific value. For example, if the value is 1 then the number should be 2 in cell [B1]. If the value is 4 then the number should be 5 in cell [N50].
=IF(A2<LARGE(CHOOSE({1,2,3},D2,F3,H1),1),
IF(A2<LARGE(CHOOSE({1,2,3},D2,F3,H1),2),
IF(A2<LARGE(CHOOSE({1,2,3},D2,F3,H1),3),
LARGE(CHOOSE({1,2,3},D2,F3,H1),3),
LARGE(CHOOSE({1,2,3},D2,F3,H1),2)),
LARGE(CHOOSE({1,2,3},D2,F3,H1),1)),
"larger or equal to all searched numbers")
and in one nice straight line for copy and paste purposes:
=IF(A2<LARGE(CHOOSE({1,2,3},D2,F3,H1),1), IF(A2<LARGE(CHOOSE({1,2,3},D2,F3,H1),2), IF(A2<LARGE(CHOOSE({1,2,3},D2,F3,H1),3), LARGE(CHOOSE({1,2,3},D2,F3,H1),3), LARGE(CHOOSE({1,2,3},D2,F3,H1),2)), LARGE(CHOOSE({1,2,3},D2,F3,H1),1)), "larger or equal to all searched numbers")
The hardest part for me and I did not understand it and still do not...just accepting, is building your separate cells into an array. That part is done by the CHOOSE():
CHOOSE({1,2,3},D2,F3,H1)
Once it is in an array, perform a large function to sort it from largest to smallest. Then through a series of nested IF statements, checked to see if the specified number in A2 was smaller than the K largest number.
Here is a proof of concept scaled down to smaller range but give you the idea.
Now I did it with a large, you could have done it with a small function as well, you would just need to alter your logic in the if statements.
This is an alternative approach without the if statements:
=IF(A2>=MAX(A7,C8,E6),"Greater than or equal to all options",INDEX(CHOOSE({1,2,3},A7,C8,E6),IFERROR(MATCH(A2,CHOOSE({1,2,3},A7,C8,E6),1)+1,1)))
I'm trying to make something of a pattern recognize counting cell and calculate their probability of occurrence.
Set 1 is from a database that looks like this (consists of 6+1 columns):
ABABAB 1
CACACA 2
CACACA 2
CACACA 2
CACACA 1
ABABAB 1
Set 2 is what I input manually (only 6 columns, without the 7th column information)
CACACA
If I want to know the probability of the 7th column as "2", pattern recognize counting cell should return 75, where if its "1" it should return 25.
Been cracking my brain using countifs function but nothing seems to work.
From my understanding you have seven columns, like this:
You would like to make a ratio between a combination that includes all seven columns (from A to G in the picture), and the combination of the first six columns (from A to F in the picture).
In this case you may use COUNTIFS as follows (I will use your same example CACACA):
=COUNTIFS(A1:A6,"C",B1:B6,"A",C1:C6,"C",D1:D6,"A",E1:E6,"C",F1:F6,"A",G1:G6,"2")/COUNTIFS(A1:A6,"C",B1:B6,"A",C1:C6,"C",D1:D6,"A",E1:E6,"C",F1:F6,"A")
The result will be 0.75, so if you want 75 you can just multiply the result by 100.
If you want to check the result also for CACACA 1, you just need to change the last value of the first COUNTIFS in the formula from "2" to "1" and you will get 0.25.
In case my understanding was wrong or you need more support do not hesitate to drop me a note!
I am have a string with 6 spaces, e.g. 000000. Each space can hold one of three digits - 0, 1, or 2. I know that I can get a total of 120 permutations using the Permut function in Excel, i.e. =PERMUT(6,3) = 120. But I would actually like to have each individual permutation in a cell, e.g. 000001, 000010, etc.. Ideally, the end result would be 120 rows of unique 6-digit IDs.
Please help if you know a faster way of accomplishing this without entering the figures manually.
Thanks!
There is a VBA functionin the last post on this page. Copy it into a VBA module, then in Excel, create a column of integers from 0 to n where n = the number of IDs you want. In the next column, call the VBA function with the value from the first column as the first argument, and 3 as the second argument. Something like
Column A Column b
0 =baseconv(A1, 3)
1 =baseconv(A2, 3)
2 =baseconv(A3, 3)
... etc.
Your IDs are really just incremental values using a base 3 counting system. You can format the output to get leading zeros with a custom format of '000000'.
Incidentally, with 6 positions and 3 available values, you can get 3 ^ 6, or 729 unique IDs
First, I don't think you're using PERMUT correctly here. What PERMUT(6,3) gives you is the total number of ways to arrange three things picked out of a set of six things. So the result is 120 because you could have 6*5*4 possible permutations. In your case you have 3^6 = 729 possible strings, because each position has one of three possible characters.
Others have posted perfectly fine VBA-based solutions, but this isn't that hard to do in the worksheet. Here is an array formula that will return an array of the last six digits of the ternary (base-3) representation of a number:
=FLOOR(MOD(<the number>,3^({5,4,3,2,1,0}+1))/(3^{5,4,3,2,1,0}),1)
(As WarrenG points out, just getting a bunch of base-3 numbers is one way to solve your problem.)
You would drag out the numbers 0 through 728 in a column somewhere, say $A$1:$A$729. Then in $B$1:$G$1, put the formula:
=FLOOR(MOD(A1,3^({5,4,3,2,1,0}+1))/(3^{5,4,3,2,1,0}),1)
remembering to enter it as an array formula with Ctrl-Shift-Enter. Then drag that down through $B$729:$G$729.
Finally in cell $H$1, put the formula:
=CONCATENATE(B1,C1,D1,E1,F1,G1)
and drag that down through $H$729. You're done!