Is there any way to reference an external document from DITA?
According to some guidelines it should be easy via (within <map>) <keydef> keys=keyID and (within <task>) <link>keyref=keyID,
but the validator simply does not accept it.
I intend to reference an xlsx-sheet:
<title>SpringerMaterials Content Enrichment - Annotation Guide - V01.00</title>
<keydef keys="protocolFile" href="examples/VIII6A3_CV_prototype.xlsx" format="xlsx" scope="external"/>
If the keydef you show is in a map then it looks correct.
Within a topic you can use to point to the key:
<p>See <xref keyref="protocolFile">Sample Protocol Data</xref>...
What validation message are you getting?
It seems your map is not valid. Hopefully this example helps you.
myMap.ditamap
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE map PUBLIC "-//OASIS//DTD DITA Map//EN" "map.dtd">
<map>
<title>Title of Your Map</title>
<!-- Reference to the Topic -->
<topicref keys="myTopic"/>
<!-- Your Keymap -->
<mapref href="myKeymap.ditamap" format="ditamap"/>
</map>
myKeymap.ditamap
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE map PUBLIC "-//OASIS//DTD DITA Map//EN" "map.dtd">
<map>
<title>My Keymap</title>
<keydef keys="myTopic" href="myTopic.dita"/>
<keydef keys="myFile" href="myFile.xlsx" navtitle="myFile" scope="external" format="xlsx"/>
</map>
myTopic.dita
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE topic PUBLIC "-//OASIS//DTD DITA Topic//EN" "topic.dtd">
<topic id="myTopic">
<title>myTopic</title>
<body>
<p>This is a link to myFile.xlsx: <xref keyref="myFile"/>.</p>
</body>
</topic>
Related
The WSDL in question is under the following URL: https://bmdweb.bmd.at/bmdntcswsdev/bmdntcsws.dll/wsdl/IBMDSOAPNTCS
I was provided with a sample log-output of how the XML should be constructed.
<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:tns="http://www.bmd.at/" xmlns:types="http://www.bmd.at/encodedTypes" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<soap:Body soap:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/">
<q1:Login xmlns:q1="http://www.bmd.at/wws">
<ALoginRequest href="#id1" />
</q1:Login>
<q2:TBMDLoginRequest id="id1" xsi:type="q2:TBMDLoginRequest" xmlns:q2="http://www.bmd.at/soap">
<Auth href="#id2" />
</q2:TBMDLoginRequest>
<q3:TBMDPlainText id="id2" xsi:type="q3:TBMDPlainText" xmlns:q3="http://www.bmd.at/soap">
<Username xsi:type="xsd:string">xxxxUSER</Username>
<Password xsi:type="xsd:string">xxxxPASSWORD</Password>
<DBAlias xsi:type="xsd:string">xxxxDBALIAS</DBAlias>
</q3:TBMDPlainText>
</soap:Body>
</soap:Envelope>
Problem
I simply cannot figure out how to construct this XML using https://www.npmjs.com/package/soap. The part, where ALoginRequest is within the Login element, while everything else is outside of it, confuses me.
Efforts
When I try this: const login = await client.LoginAsync({ALoginRequest: {Auth: {TBMDPlainText: auth}}}), I get the following output.
<?xml version="1.0" encoding="utf-8"?><soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tns="http://www.bmd.at/" xmlns:ns1="http://www.bmd.at/soap" xmlns:ns2="http://www.bmd.at/wws"><soap:Body><tns:Login><ALoginRequest><Auth><TBMDPlainText><Username>xxxx</Username><Password>xxxx</Password><DBAlias>xxxx</DBAlias></TBMDPlainText></Auth></ALoginRequest></tns:Login></soap:Body></soap:Envelope>
Can anyone provide me any hints?
I'm trying to figure out how to add attributes to an array element
I get an error Error: Invalid character in name when trying to build the following XML from an object.
<?xml version="1.0" encoding="UTF-8"?>
<Requests xmlns="http://example.com">
<Request>
</Request>
<Request>
</Request>
</Requests>
Here is my object
let myObject = {
Requests:[
{$:{xmlns:"http://example.com"}},
{Request:{}},
{Request:{}}
]
}
let builder = new xml2js.Builder();
let xml = builder.buildObject(myObject);
console.log(xml)
I've also tried wrapping the name in quotes
{"$":{"xmlns":"http://example.com"}},
Stripping out the attribute declaration altogether produces the desired XML but obviously leaves out the needed attribute
<?xml version="1.0" encoding="UTF-8"?>
<Requests>
<Request>
</Request>
<Request>
</Request>
</Requests>
I suppose you should try this:
let myObject = {
Requests:{
$:{xmlns:"http://example.com"},
Request:[{}, {}]
}
I am trying to get the value of the attribute IntegratorCode AND ProductType using groovy.
<?xml version="1.0" encoding="UTF-8"?>
<soap:Envelope
xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"
xmlns:SOAPNYK1="http://www.w3.org/2001/XMLSchema"
xmlns:SOAPNYK2="http://www.w3.org/2001/XMLSchema-instance"
xmlns:SOAPNYK3="http://schemas.xmlsoap.org/soap/encoding/">
<soap:Header>
<Authentication
xmlns="urn:iQQ:API:22:iQQMessages.xsd" EmployeeCode="*****" IntegratorCode="GENERIC" Pwd="******" Usr="SYSUSER"/>
</soap:Header>
<soap:Body>
<CanOfferProduct
xmlns="urn:iQQ:API:22:iQQMessages.xsd">
<OnQuotePackage
xmlns="" ProductType="GAP" QuoteNumber="74859">test
</OnQuotePackage>/>
</CanOfferProduct>
</soap:Body>
</soap:Envelope>
I tried the following method using XmlSlurpur
def result = new XmlSlurper().parseText(xml)
println(result.Envelope.Header[1].Authentication.#IntegratorCode)
//output = IntegratorCode
I wanted to print the value of IntegratorCode which is "GENERIC".
I am not sure what I am doing wrong in this case. please help.
what you called result is soap:Envelope, so you essentially had Envelope.Envelope... This works:
println result.Header.Authentication.#IntegratorCode
As a precaution I normally use it like this:
def Envelope = new XmlSlurper().parseText(xml)
I have a string describing a XML object, containing line-breaks and spaces, like so:
<?xml version="1.0" encoding="UTF-8"?>
<play>
<scenario>
<author>Arthur Drake</author>
<title> ...til I get there</title>
</scenario>
</play>
And I'd like to convert it like so all unnecessary characters are removed:
<?xml version="1.0" encoding="UTF-8"?><play><scenario><author>Arthur Drake</author><title> ...til I get there</title></scenario></play>
Note that the whitespaces inside the nodes should be left untouched.
What is the best solution to do so in Node.js ?
This code should give you the result you're looking for:
let xml =
`<?xml version="1.0" encoding="UTF-8"?>
<play>
<scenario>
<author>Arthur Drake</author>
<title> ...til I get there</title>
</scenario>
</play>`;
console.log('Initial xml:', xml);
function trimXml(xml) {
return xml.replace(/>\s+</g, "><");
}
console.log('\nTrimmed xml:', trimXml(xml));
I have an xml that looks like this
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Samples>
<Sample>
<Name>
Sample1
</Name>
<Date>
01/20/2016
</Date>
</Sample>
</Samples>
I want to simply change the tag name from "Samples" to "SampleList". How will I do it?
replaceNode can be used to rename the node as below:
def xml = '''<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Samples>
<Sample>
<Name>
Sample1
</Name>
<Date>
01/20/2016
</Date>
</Sample>
</Samples>
'''
def result = new XmlSlurper().parseText(xml)
result.replaceNode {
'SampleList' it.children()
}
groovy.xml.XmlUtil.serialize(result)
replaceNode takes a closure as method parameter which delegates to a builder. Specifically in this case the node is replaced instead of appending it to main document. 'SampleList' it.children() is similar to 'SampleList(it.children())'.
Parsed xml's root element being Samples (which needs replacement), replaceNode was directly done on the result.