Shell Extract Text Before Digits in a String - string

Question

I've found several examples of extractions before a single character and examples of extracting numbers, but I haven't found anything about extracting characters before numbers.
My question:
Some of the strings I have look like this:
NUC320 Syllabus Template - 8wk
SLA School Template - UL
CJ101 Syllabus Template - 8wk
TECH201 Syllabus Template - 8wk
Test Clone ID17
In cases where the string doesn't contain the data I want, I need it to be skipped. The desired output would be:
NUC-320
CJ-101
TECH-201
SLA School Template - UL & Test Clone ID17 would be skipped.
I imagine the process being something to the effect of:
Extract text before " "
Condition - Check for digits in the string
Extract text before digits and assign it to a variable x
Extract digits and assign to a variable y
Concatenate $x"-"$y and assign to another variable z
More information:
The strings are extracted from a line in a couple thousand text docs using a loop. They will be used to append to a hyperlink and rename a file during the loop.
Edit:
#!/bin/sh
# my files are named 1.txt through 9999.txt i both
# increments the loop and sets the filename to be searched
i=1
while [ $i -lt 10000 ]
do
x=$(head -n 31 $i.txt | tail -1 | cut -c 7-)
if [ ! -z "$x" -a "$x" != " " ]; then
# I'd like to insert the hyperlink with the output on the
# same line (1.txt;cj101 Syllabus Template - 8wk;www.link.com/cj101)
echo "$i.txt;$x" >> syllabus.txt
# else
# rm $i.txt
fi
i=`expr $i + 1`
sleep .1
done

Answer 1

sed for printing lines starting with capital letters followed by digits. It also adds a - between them:
sed -n 's/^\([A-Z]\+\)\([0-9]\+\) .*/\1-\2/p' input
Gives:
NUC-320
CJ-101
TECH-201

Answer 2

A POSIX-compliant awk solution:
awk '{ if (match($1, /[0-9]+$/)) print substr($1, 1, RSTART-1) "-" substr($1, RSTART) }' \
file |
while IFS= read -r token; do
# Process token here (append to hyperlink, ...)
echo "[$token]"
done
awk is used to extract the reformatted tokens of interest, which are then processed in a shell while loop.
match($1, /[0-9]+$/) matches the 1st whitespace-separated field ($1) against extended regex [0-9]+$, i.e., matches only if the fields ends in one or more digits.
substr($1, 1, RSTART-1) "-" substr($1, RSTART) joins the part before the first digit with the run of digits using -, via the special RSTART variable, which indicates the 1-based character position where the most recent match() invocation matched.

Answer 3

awk '$1 ~/[0-9]/{sub(/...$/,"-&",$1);print $1}' file
NUC-320
CJ-101
TECH-201