This question already has answers here:
How to run two commands with sudo?
(11 answers)
Closed 7 years ago.
Can we use heredocs to run multiple commands using sudo?
I am facing an issue (need to pass password for every command) while running
multiple commands:
echo 'password'| sudo -S ls
echo 'password'| sudo -S cat /var/log/abc.log
Can anyone help me how to automate this in a script? Like:
echo 'password' | sudo -S << ENDBLOCK
ls
cat
ENDBLOCK
you can run sh -c ..., but remember to quote properly.
sudo sh -c 'id; echo another command ; id'
sudo must see this as a single argument for the sh command.
Of course you can use new line instead of semicolon:
sudo sh -c '
echo "I am root"
id
echo "another command"
id
'
One way is to write a script with all the things you need to do with sudo and then run the script with sudo.
you could put all your commands in a script. Then
sudo ./script.sh
put permissions for script.sh in /etc/sudoers.d; that way you'll never need to type your password again (for that script)
Related
This question already has answers here:
Pipe multiple verbatim lines into command in bash
(2 answers)
Closed 2 months ago.
Here is the case. I have bash script that requires a couple of command to be executed. First of all, it requires sudo, then answer (y/n) and then password one more time. What I want to do is I want to execute it in one command.
Let's say I have my bash script - myscript.sh. This script requires sudo to be executed. So, to execute it in one line I can write:
echo 'mypassword' | sudo -S bash myscript.sh
And this will work. But after script is executed I need to answer y and type password one more time. How can I do that?
Here is what I have tried:
printf '%s\n mypassword y mypassword' | sudo -S bash myscript.sh
echo 'y\nmypassword\n' | echo 'mypassword' | sudo -S bash myscript.sh
And there were a couple more of what I have tried, but it didn't work.
You can:
printf '%s\n' mypassword y mypassword | ...
( echo mypassword; echo y; echo mypassword ) | ...
This script requires sudo to
Note that typing that on the command line or in a script will publish your password. Instead, configure sudoers to allow the user to login without a password. Consider configuring credential caching in sudoers, so you don't have to type password twice.
I am trying to write a small script that aims to login to a remote server, load environment variables and print one of them. (In the actual script, instead of an echo, the parameters that are read are to be used. For the sake of simplicity here I am using just echo.)
The structure of the script and the commands that I tried are as follows but unfortunately none succeeds:
ssh -i lightsail.pem ubuntu#production <<< '
sudo echo $TEST_PARAMETER
sudo sh -c "~/Environment/environment-variables.sh && echo $TEST_PARAMETER"
sudo bash -c "~/Environment/environment-variables.sh && echo $TEST_PARAMETER"
sudo bash -c "source ~/Environment/environment-variables.sh && echo $TEST_PARAMETER"
sudo bash <<< "source ~/Environment/environment-variables.sh && echo $TEST_PARAMETER"
';
How environment variables can be read from a file when going into a login shell with here-string and using the sudo command?
If your environment variable is set for ubuntu and not root you will need to use sudo -E
-E Indicates to the security policy that the user wishes to preserve their existing environment variables
As the title says, within linux how can I feed input to the bash when I do sudo bash
Lets say I have a bash script that reads the name.
The way I execute the script is through sudo using:
cat read-my-name-script.sh | sudo bash
Lets just say this is how I execute the script throught the network.
Now I want to fill the name automatically, is there a way to feed the input. I tried doing this: cat read-my-name-script.sh < name-input-file | sudo bash where the name-input-file is a file for the input that the user will be using to feed the script.
I am new to linux and learning to automate the input and wanted to create a file for input where the user can fill it and feed it to my script.
This is convoluted, but might do what you want.
sudo bash -c "$(cat read-my-name.sh)" <name-input-file
The -c says the next quoted argument are the commands to run (so, read the script as a string on the command line, instead of from a file), and the calling shell interpolates the contents of the file inside the double quotes before the sudo command gets evaluated. So if read-my-name.sh contains
#!/bin/bash
read -p "I want your name please"
then the command gets expanded into
sudo bash -c '#!/bin/bash
read -p "I want your name please"' <name-input-file
(where of course at this time the shell has actually removed the outer double quotes altogether; I put in single quotes in their place instead to show how this would look as actually executable, syntactically valid code).
I think you need that:
while read -r arg; do sudo bash read-my-name-script.sh "$arg";done <name-input-file
So each line of name-input-file will be passed as argument to sudo bash read-my-name-script.sh
If your argslist located on http server, you can do that:
while read -r arg; do sudo bash read-my-name-script.sh "$arg";done < <(wget -q -O- http://some/address/in/internet/name-input-file)
UPD
add [[ -f name-input-file ]] && readarray -t args <name-input-file
to read-my-name-script.sh
and use "${args[#]}" as arguments of command in the script.
For example echo "${args[#]}" or cmd "${args[0]}" "${args[1]}" ... "${args[100]}" in any order.
In this case you can use
wget -q -O- http://some/address/in/internet/read-my-name-script.sh | bash
for run your script with arguments from name-input-file whitout saving script to the local machine
This question already has answers here:
Usage of expect command within a heredoc
(1 answer)
Pass commands as input to another command (su, ssh, sh, etc)
(3 answers)
Closed 4 years ago.
I have a script that I need to execute through ssh as another use, is there a way to pass whole script like this:
ssh -t user#server.com sudo -u user2 sh -c << EOF
cd /home
ls
dir=$(pwd)
echo "$dir"
echo "hello"
....
EOF
Returns: sh: -c: option requires an argument
ssh'ing and sudo'ing separately is not an option and putting .sh file directly on the machine is not possible.
sh -c requires a command string as the argument. Since you are reading the commands from standard input (through heredoc), you need to use sh -s option:
ssh -t user#server.com sudo -u user2 sh -s << 'EOF'
cd /home
ls
dir=$(pwd)
echo "$dir"
echo "hello"
...
EOF
From man sh:
-c
string If the -c option is present, then commands are read from string. If there are arguments after the string, they are assigned to the positional parameters, starting with $0.
-s
If the -s option is present, or if no arguments remain after option processing, then commands are read from the standard input. This option allows the positional parameters to be set when invoking an interactive shell.
Need to quote the heredoc marker to prevent the parent shell from interpreting the content.
My script is as below.
#!/bin/bash
version = 1.1
echo "Enter username"
read UserName
ssh -t $UserName#server bash -c " '
./runSomeScript
echo "Entering Sudo"
sudo -s -u user1 -c "cd random; ./randomscrip xx-$version-yy"
'"
But this is not working.
Basically i want to do a ssh to a account. And then runSomeScript
Then do a sudo with user as user1 and then run commands cd random and ./randomscrip (with xx-Version-yy as argument) as the sudo user only.
But the commands inside sudo are not working.
Your quoting is a little careless. You're using double-quotes for the first and third levels of quoting, and the shell can't tell one from the other. Do something like this instead:
sudoScript="cd random; ./randomscrip xx-${version}-yy"
sshScript='
./runSomeScript
echo "Entering Sudo"
sudo -s -u user1 bash -c '"'${sudoScript}'"'
'
ssh -t ${UserName}#server "${sshScript}"
But beware that if you embed any single-quotes, it will still go wrong unless you add a layer of shell-quoting.
Finally, remove the spaces around = when you assign to version.