I'm running Arch-based Manjaro Linux and wrote myself a little update program, that starts every 7 hours and runs completely in the background. This update program is started by systemd.
What I wanna know is: How can I prevent any system shutdown/reboot during the time this program runs no matter if the user just wants to turn it off or any program wants to do so.
The best would be, if any shutdown/reboot action wouldn't be cancelled but delayed instead, so when the update program has finished its run, the shutdown/reboot continues.
My systemd parts are:
uupgrades.timer
[Unit]
Description=UU Upgrades Timer
[Timer]
OnBootSec=23min
OnUnitActiveSec=7h
Unit=uupgrades.target
[Install]
WantedBy=basic.target
uupgrades.target
[Unit]
Description=UU Upgrades Timer Target
StopWhenUnneeded=yes
and in the folder uupgrades.target.wants
uupgrades.service
[Unit]
Description=UU Update Program
[Service]
Nice=19
IOSchedulingClass=2
IOSchedulingPriority=7
ExecStart=/usr/bin/uupgrades
How can I achieve this?
If a user with sufficient permissions to reboot the server or manipulate processes wants to stop or reboot the machine you cant stop them. That's just how linux works. You should set up permissions and accounts such that no other users have root permissions or permissions sufficient to manipulate the process or user that the process is running as.
When I want to block myself from rebooting or shutdown, I alias my usual shutdown and reboot aliases to beep;beep;beep;.
In multiuser environments you could move the reboot, shutdown etc. binaries and move them back, when shutdown should be allowed again.
You could also temporarily move an executable shell script outputting information about the postponed shutdown possibility in place of the corresponding binaries. This script could set a flag, if a shutdown was requested.
Q&D example script:
#!/usr/bin/env bash
echo "preventing reboot"
BACKUPBINARY_REBOOT=$(mktemp);
mv /bin/reboot $BACKUPBINARY_REBOOT;
FLAGFILE=$(mktemp);
echo '#!/usr/bin/env bash' > /bin/reboot;
echo '# original reboot binary was moved to'"$BACKUPBINARY_REBOOT" >> /bin/reboot;
echo 'echo request-reboot > '"$FLAGFILE" >> /bin/reboot;
echo 'echo reboot is prevented, your request will trigger later' >> /bin/reboot;
chmod 666 "$FLAGFILE";
chmod +x /bin/reboot;
echo "postponed reboot - press enter to allow it again and make up for requested reboot";
read;
mv "$BACKUPBINARY_REBOOT" /bin/reboot;
if grep -q request-reboot "$FLAGFILE"; then
rm $FLAGFILE;
/bin/reboot;
fi
You can add another systemd service at /usr/lib/systemd/system-shutdown/ which will be run at shutdown, and have it check if your update script is running, and if so, cancel or delay the shutdown.
Related
I would like to make a shutdown-script for my raspberry pi to shut down anothe raspberry pi over ssh.
The script works if it is running itself but at the shutdown routine the ssh command is not executed.
So that I have done until now:
Made the script in /etc/init.d:
#!/bin/sh
# the first thing is to test if the shutdown script is working
echo "bla bla bla " | sudo tee -a /test.txt
ssh pi#10.0.0.98 sudo shutdown -h now
Made it executable
sudo chmod +x /etc/init.d/raspi.sh
Made a symlink to the rc0.d
sudo ln -s /etc/init.d/raspi.sh /etc/rc0.d/S01raspi.sh
Now I know so far that the shutdown script is working outside of the shutdown routing by calling itself and the shutdown symlink I made is also working partially because I see the changes in the test.txt file every time I shut down.
Can anyone help me how to solve my problem?
Have you tried with single quotes?
The first link in Google has it
http://malcontentcomics.com/systemsboy/2006/07/send-remote-commands-via-ssh.html
What about the sudo, how do you solve entering the password?
https://superuser.com/questions/117870/ssh-execute-sudo-command
Please check this or other links on the web that have useful information.
I would have send all this in a comment but I cant yet because of reputation.
I have now got the script running by myself. I do not really know why it is now working but I write it down beneath and maybe someone else can clearifiy it.
I don´t think the first two changes at my system makes a difference but I also write it down. In the meanwhile because I do not managed the script to get working I had made a button to shutdown the system manually. Also I made a script which backs the mysql-database up (which is on the Raspberry Pi which I would like to switch off with the script) and copies the backup to the raspberry pi which should switch of the other raspberry automatically via the shutdown-script. This happens with scp and also for the password is a key generated.
I have also changed my script to get a log-message out of the script.
#!/bin/sh
ssh -t -t pi#10.0.0.99 'sudo shutdown -h now' >> /home/osmc/shutdown.log 2>&1
To get it into the shutdown-routine I used:
sudo update-rc.d raspi-b stop 01 0
I hope somebody can say me why my code now worked on the first day but not on the next few days until now.
I structured a command to suspend or shutdown a remote host over ssh. You may find this useful. This may be used to suspend / shutdown a remote computer without an interactive session and yet not keep a terminal busy. You will need to give permissions to the remote user to shutdown / suspend using sudo without a password. Additionally, the local and remote machines should be set up to SSH without an interactive login. The script is more useful for suspending the machine as a suspended machine will not disconnect the terminal.
local_user#hostname:~$ ssh remote_user#remote_host "screen -d -m sudo pm-suspend"
source: कार्यशाला (Kāryaśālā)
I want to send an email when the system is going to shutdown to an email ID. I have CentOS 6.4. Below is my Script.
cat /ect/init.d/sendshtmail
#!/bin/bash
EMAIL="example#example.com"
SHUTDOWNSUBJECT="["`hostname`"] - System Shutdown"
SHUTDOWNBODY="This is an automated message to notify you that "`hostname`" is shutting down.
LOCKFILE=/var/lock/subsys/SystemEmail
echo "${SHUTDOWNBODY}" | mutt -s "${SHUTDOWNSUBJECT}" ${EMAIL}
It has the appropriate permission. While running it manually it's working perfectly. I have just symlinked it to /etc/rc0.d/ folder. By issuing below command.
ln -s /etc/init.d/sendshtmail /etc/rc0.d/K00sendshtmail
But the script is not sending any email during shutdown. Thanks in Advance.
Place your shell script in /etc/init.d with executable permission and symlink name should start with K##. If you want to execute your script at first place immediately after shut down then name it with K00scriptname. Script started will K will be executed first based on ascending order then script with S.
ln -s /etc/init.d/script /etc/rc0.d/K00scriptname
Shutdown command will send the stop signal to script, your script (K00scriptname) should have stop function like example
stop()
{
echo "executing scriptname"
"Your script logic"
}
case "$1" in
stop)
stop
;;
esac
Most important, K00scriptname will execute only if there would be lock file present in /var/lock/subsys folder, so do "touch /var/lock/subsys/scriptname" then check by doing shutdown.
Try to set executable permissions for your script. Sometimes you need to do that to activate it.
chmod 755 /etc/init.d/sendshtmail
Also try to use absolute paths for your command, while quoting the other variable as well.
echo "${SHUTDOWNBODY}" | /usr/bin/mutt -s "${SHUTDOWNSUBJECT}" "${EMAIL}"
Another attempt is to switch your user to your current user e.g.
echo "${SHUTDOWNBODY}" | su -l -c "/usr/bin/mutt -s \"${SHUTDOWNSUBJECT}\" \"${EMAIL}\"" yourusername
ln -s /etc/init.d/sendshtmail /etc/rc0.d/S01sendshtmail
The symlink name should begin with a S - for Start (K for Kill)
The two-digit specifies the order of execution for your script, the lowest numbered being execute first.
I created the script file -
#!/bin/sh
echo "my application is here"
./helloworld # helloworld is our application
after creating the script file i copied it in init.d
I gave the command chmod +x /etc/init.d/vcc_app (vcc_app is the name of script which I have created)
Then I gave the command ln -s /etc/init.d/vcc_app /etc/rc.d/vcc_app (rc.d is the run level directory)
But when i reboot the board my application is not executed automatically. Can anyone help me out?
Scripts that are in /etc/init.d need to be LSB-compliant.
If you simply want to automatically run commands at the end of the boot process, try placing them in /etc/rc.local instead.
Not all linux systems use the same init daemon (ubuntu uses upstart: http://upstart.ubuntu.com/getting-started.html), but they all use start and stop functions in the script. Other common functions are status and restart, but again, there is no true across the board standard. Eg:
!#/bin/sh
start () {
echo "application started";
./helloworld # you should use an absolute path here instead of ./
}
stop () {
}
case "$1" in
start)
start
;;
stop)
stop
;;
*)
echo "Usage start|stop";
esac
exit $?
The last bit is a switch based on the first command line arg, since init will invoke the script myrcscript start.
In order to use stop() (and the also often useful restart()) you need to keep, or be able to get, the pid of the process launched by start(); sometimes this is done with a little "pid file" in /tmp (text file containing the pid, eg, /tmp/myscript.pid created in start()).
The "upstart" init daemon used on Ubuntu has its own specific features, but unless you need to use them, just keep it stop/start minimal and it will (probably) work anywhere.
I have a node.js script which need to start at boot and run under the www-data user. During development I always started the script with:
su www-data -c 'node /var/www/php-jobs/manager.js
I saw exactly what happened, the manager.js works now great. Searching SO I found I had to place this in my /etc/rc.local. Also, I learned to point the output to a log file and to append the 2>&1 to "redirect stderr to stdout" and it should be a daemon so the last character is a &.
Finally, my /etc/rc.local looks like this:
#!/bin/sh -e
#
# rc.local
#
# This script is executed at the end of each multiuser runlevel.
# Make sure that the script will "exit 0" on success or any other
# value on error.
#
# In order to enable or disable this script just change the execution
# bits.
#
# By default this script does nothing.
su www-data -c 'node /var/www/php-jobs/manager.js >> /var/log/php-jobs.log 2>&1 &'
exit 0
If I run this myself (sudo /etc/rc.local): yes, it works! However, if I perform a reboot no node process is running, the /var/log/php-jobs.log does not exist and thus, the manager.js does not work. What is happening?
In this example of a rc.local script I use io redirection at the very first line of execution to my own log file:
#!/bin/sh -e
#
# rc.local
#
# This script is executed at the end of each multiuser runlevel.
# Make sure that the script will "exit 0" on success or any other
# value on error.
#
# In order to enable or disable this script just change the execution
# bits.
#
# By default this script does nothing.
exec 1>/tmp/rc.local.log 2>&1 # send stdout and stderr from rc.local to a log file
set -x # tell sh to display commands before execution
/opt/stuff/somefancy.error.script.sh
exit 0
On some linux's (Centos & RH, e.g.), /etc/rc.local is initially just a symbolic link to /etc/rc.d/rc.local. On those systems, if the symbolic link is broken, and /etc/rc.local is a separate file, then changes to /etc/rc.local won't get seen at bootup -- the boot process will run the version in /etc/rc.d. (They'll work if one runs /etc/rc.local manually, but won't be run at bootup.)
Sounds like on dimadima's system, they are separate files, but /etc/rc.d/rc.local calls /etc/rc.local
The symbolic link from /etc/rc.local to the 'real' one in /etc/rc.d can get lost if one moves rc.local to a backup directory and copies it back or creates it from scratch, not realizing the original one in /etc was just a symbolic link.
I ended up with upstart, which works fine.
In Ubuntu I noticed there are 2 files. The real one is /etc/init.d/rc.local; it seems the other /etc/rc.local is bogus?
Once I modified the correct one (/etc/init.d/rc.local) it did execute just as expected.
You might also have made it work by specifying the full path to node. Furthermore, when you want to run a shell command as a daemon you should close stdin by adding 1<&- before the &.
I had the same problem (on CentOS 7) and I fixed it by giving execute permissions to /etc/local:
chmod +x /etc/rc.local
if you are using linux on cloud, then usually you don't have chance to touch the real hardware using your hands. so you don't see the configuration interface when booting for the first time, and of course cannot configure it. As a result, the firstboot service will always be in the way to rc.local. The solution is to disable firstboot by doing:
sudo chkconfig firstboot off
if you are not sure why your rc.local does not run, you can always check from /etc/rc.d/rc file because this file will always run and call other subsystems (e.g. rc.local).
I got my script to work by editing /etc/rc.local then issuing the following 3 commands.
sudo mv /filename /etc/init.d/
sudo chmod +x /etc/init.d/filename
sudo update-rc.d filename defaults
Now the script works at boot.
I am using CentOS 7.
$ cd /etc/profile.d
$ vim yourstuffs.sh
Type the following into the yourstuffs.sh script.
type whatever you want here to execute
export LD_LIBRARY_PATH=/usr/local/cuda-7.0/lib64:$LD_LIBRARY_PATH
Save and reboot the OS.
I have used rc.local in the past. But I have learned from my experience that the most reliable way to run your script at the system boot time is is to use #reboot command in crontab. For example:
#reboot path_to_the_start_up_script.sh
This is most probably caused by a missing or incomplete PATH environment variable.
If you provide full absolute paths to your executables (su and node) it will work.
It is my understanding that if you place your script in a certain RUN Level, you should use ln -s to link the script to the level you want it to work in.
first make the script executable using
sudo chmod 755 /path/of/the/file.sh
now add the script in the rc.local
sh /path/of/the/file.sh
before exit 0
in the rc.local,
next make the rc.local to executable with
sudo chmod 755 /etc/rc.local
next to initialize the rc.local use
sudo /etc/init.d/rc.local start
this will initiate the rc.local
now reboot the system.
Done..
I found that because I was using a network-oriented command in my rc.local, sometimes it would fail. I fixed this by putting sleep 3 at the top of my script. I don't know why but it seems when the script is run the network interfaces aren't properly configured or something, and this just allows some time for the DHCP server or something. I don't fully understand but I suppose you could give it a try.
I had exactly same issue, the script was running fine locally but when I reboot/power-on it was not.
I resolved the issue by changing the file path. Basically need to give the complete path in the script. While running locally, file can be accessed but when running on reboot, local path will not be understood.
1 Do not recommend using root to run the apps such as node app.
Well you can do it but may catch more exceptions.
2 The rc.local normally runs as root user.
So if the your script should runs as another user such as www U should make sure the PATH and other environment is ok.
3 I find a easy way to run a service as a user:
sudo -u www -i /the/path/of/your/script
Please prefer the sudo manual~
-i [command]
The -i (simulate initial login) option runs the shell specified by the password database entry of the target user as a loginshell...
rc.local only runs on startup. If you reboot and want the script to execute, it needs to go into the rc.0 file starting with the K99 prefix.
I'm trying to ensure a script remains running on a development server. It collates stats and provides a web service so it's supposed to persist, yet a few times a day, it dies off for unknown reasons. When we notice we just launch it again, but it's a pain in the rear and some users don't have permission (or the knowhow) to launch it up.
The programmer in me wants to spend a few hours getting to the bottom of the problem but the busy person in me thinks there must be an easy way to detect if an app is not running, and launch it again.
I know I could cron-script ps through grep:
ps -A | grep appname
But again, that's another hour of my life wasted on doing something that must already exist... Is there not a pre-made app that I can pass an executable (optionally with arguments) and that will keep a process running indefinitely?
In case it makes any difference, it's Ubuntu.
I have used a simple script with cron to make sure that the program is running. If it is not, then it will start it up. This may not be the perfect solution you are looking for, but it is simple and works rather well.
#!/bin/bash
#make-run.sh
#make sure a process is always running.
export DISPLAY=:0 #needed if you are running a simple gui app.
process=YourProcessName
makerun="/usr/bin/program"
if ps ax | grep -v grep | grep $process > /dev/null
then
exit
else
$makerun &
fi
exit
Then add a cron job every minute, or every 5 minutes.
Monit is perfect for this :)
You can write simple config files which tell monit to watch e.g. a TCP port, a PID file etc
monit will run a command you specify when the process it is monitoring is unavailable/using too much memory/is pegging the CPU for too long/etc. It will also pop out an email alert telling you what happened and whether it could do anything about it.
We use it to keep a load of our websites running while giving us early warning when something's going wrong.
-- Your faithful employee, Monit
Notice: Upstart is in maintenance mode and was abandoned by Ubuntu which uses systemd. One should check the systemd' manual for details how to write service definition.
Since you're using Ubuntu, you may be interested in Upstart, which has replaced the traditional sysV init. One key feature is that it can restart a service if it dies unexpectedly. Fedora has moved to upstart, and Debian is in experimental, so it may be worth looking into.
This may be overkill for this situation though, as a cron script will take 2 minutes to implement.
#!/bin/bash
if [[ ! `pidof -s yourapp` ]]; then
invoke-rc.d yourapp start
fi
If you are using a systemd-based distro such as Fedora and recent Ubuntu releases, you can use systemd's "Restart" capability for services. It can be setup as a system service or as a user service if it needs to be managed by, and run as, a particular user, which is more likely the case in OP's particular situation.
The Restart option takes one of no, on-success, on-failure, on-abnormal, on-watchdog, on-abort, or always.
To run it as a user, simply place a file like the following into ~/.config/systemd/user/something.service:
[Unit]
Description=Something
[Service]
ExecStart=/path/to/something
Restart=on-failure
[Install]
WantedBy=graphical.target
then:
systemctl --user daemon-reload
systemctl --user [status|start|stop|restart] something
No root privilege / modification of system files needed, no cron jobs needed, nothing to install, flexible as hell (see all the related service options in the documentation).
See also https://wiki.archlinux.org/index.php/Systemd/User for more information about using the per-user systemd instance.
I have used from cron "killall -0 programname || /etc/init.d/programname start". kill will error if the process doesn't exist. If it does exist, it'll deliver a null signal to the process (which the kernel will ignore and not bother passing on.)
This idiom is simple to remember (IMHO). Generally I use this while I'm still trying to discover why the service itself is failing. IMHO a program shouldn't just disappear unexpectedly :)
Put your run in a loop- so when it exits, it runs again... while(true){ run my app.. }
I couldn't get Chris Wendt solution to work for some reason, and it was hard to debug. This one is pretty much the same but easier to debug, excludes bash from the pattern matching. To debug just run: bash ./root/makerun-mysql.sh. In the following example with mysql-server just replace the value of the variables for process and makerun for your process.
Create a BASH-script like this (nano /root/makerun-mysql.sh):
#!/bin/bash
process="mysql"
makerun="/etc/init.d/mysql restart"
if ps ax | grep -v grep | grep -v bash | grep --quiet $process
then
printf "Process '%s' is running.\n" "$process"
exit
else
printf "Starting process '%s' with command '%s'.\n" "$process" "$makerun"
$makerun
fi
exit
Make sure it's executable by adding proper file permissions (i.e. chmod 700 /root/makerun-mysql.sh)
Then add this to your crontab (crontab -e):
# Keep processes running every 5 minutes
*/5 * * * * bash /root/makerun-mysql.sh
The supervise tool from daemontools would be my preference - but then everything Dan J Bernstein writes is my preference :)
http://cr.yp.to/daemontools/supervise.html
You have to create a particular directory structure for your application startup script, but it's very simple to use.
first of all, how do you start this app? Does it fork itself to the background? Is it started with nohup .. & etc? If it's the latter, check why it died in nohup.out, if it's the first, build logging.
As for your main question: you could cron it, or run another process on the background (not the best choice) and use pidof in a bashscript, easy enough:
if [ `pidof -s app` -eq 0 ]; then
nohup app &
fi
You could make it a service launched from inittab (although some Linuxes have moved on to something newer in /etc/event.d). These built in systems make sure your service keeps running without writing your own scripts or installing something new.
It's a job for a DMD (daemon monitoring daemon). there are a few around; but I usually just write a script that checks if the daemon is running, and run if not, and put it in cron to run every minute.
Check out 'nanny' referenced in Chapter 9 (p197 or thereabouts) of "Unix Hater's Handbook" (one of several sources for the book in PDF).
A nice, simple way to do this is as follows:
Write your server to die if it can't listen on the port it expects
Set a cronjob to try to launch your server every minute
If it isn't running it'll start, and if it is running it won't. In any case, your server will always be up.
I think a better solution is if you test the function, too. For example, if you had to test an apache, it is not enough only to test, if "apache" processes on the systems exist.
If you want to test if apache OK is, then try to download a simple web page, and test if your unique code is in the output.
If not, kill the apache with -9 and then do a restart. And send a mail to the root (which is a forwarded mail address to the roots of the company/server/project).
It's even simplier:
#!/bin/bash
export DISPLAY=:0
process=processname
makerun="/usr/bin/processname"
if ! pgrep $process > /dev/null
then
$makerun &
fi
You have to remember though to make sure processname is unique.
One can install minutely monitoring cronjob like this:
crontab -l > crontab;echo -e '* * * * * export DISPLAY=":0.0" && for
app in "eiskaltdcpp-qt" "transmission-gtk" "nicotine";do ps aux|grep
-v grep|grep "$app";done||"$app" &' >> crontab;crontab crontab
disadvantage is that the app names you enter have to be found in ps aux|grep "appname" output and at same time being able to be launched using that name: "appname" &
also you can use the pm2 library.
sudo apt-get pm2
And if its a node app can install.
Sudo npm install pm2 -g
them can run the service.
linux service:
sudo pm2 start [service_name]
npm service app:
pm2 start index.js