I am trying to make a binary operation then add 0b to it then save it into an output.dat file. for example 0b1101. But it seems like binary operation overrides itself to the 0b.
#!/bin/bash
binary="0b"
while IFS=" ," read i1 i2 i3 #assigns each line into three seperate entity.
do
#checks if it's in binary, decimal or hexadecimal
if [[ $i1 == *"0b"* ]]; then #binary
i1=${i1//$binary/}
i3=${i3//$binary/}
if [ "$i2" = "+" ]; then
echo "0b" >$HOME/Desktop/Homework_1/output.dat
echo "ibase=2;obase=2; $i1+$i3" | bc -l
>$HOME/Desktop/Homework_1/output.dat
There are two errors here:
First, you're redirecting both outputs with >. You should be aware that this will clear the content of the target file before writing. To append, use >> as the redirection operator:
echo "ibase=2;obase=2; $i1+$i3" | bc -l >> $HOME/Desktop/Homework_1/output.dat
# ^^
Second, there's another issue with your bc calculation: You cannot specify obase=2 after ibase=2. You should change it into this:
echo "obase=2;ibase=2; $i1+$i3" | bc -l
# specify obase first
You can read more about this issue here #>> bc: Why does ibase=16; obase=10; FF returns FF and not 255?
so I'd like to remove parts within (NOT at beginning or the end, or I would have used dd) a binary file, when I encounter a certain binary string value. ie :
if FF FB FF FB A4 is found, remove 2048 bytes before the second FF FB here (meaning the first FF FB is deleted as well as the 2046 bytes preceeding it)
repeat till the end of the file.(no need to test/prevent "eating itself", range between that string occurences always much larger than 2048)
how can I do that in bash ?
thanks in advance
You can use grep to locate the "FF FB FF FB A4", then use dd to cut file:
pos=$(grep --only-matching --byte-offset --binary --text --perl-regexp "\xFF\xFB\xFF\xFB\xA4" filename|head -1|cut -d ':' -f1)
It will tell you where the string.
dd if=filename of=output bs=1 ibs=1 count=$pos
This get the leading part. I think you know how to deal with left staff
Is there an easy way to add an offset to the hex dump generated by xxd ?
i.e instead of
0000: <data>
0004: <data>
0008: <data>
I should get
Offset+0000: <data>
Offset+0004: <data>
Offset+0008: <data>
xxd now appears to come with offset support, using -o [offset]
for example: xxd -o 0x07d20000 file.bin
My version of xxd on Gentoo Linux has it, but I dug deeper to help folks on other distros:
xxd V1.10 27oct98 by Juergen Weigert -- Do not use the xxd version -- I have found this source code without the offset support!! So I tracked down where my binary comes from:
app-editors/vim-core-7.4.769 -- So apparently, as long as you have a modern VIM installed, you can reap the benefits of the added offset support; at least on Gentoo, but I'm steering you in the right direction.
If you find that your distro still ships an older xxd, considering manually compiling a newer VIM that you confirm has offset support.
This is what I am doing now..It works perfectly but its kind of lame approach for just adding an offset :)
xxd file.bin | xxd -r -s 0x2e00000 | xxd -s 0x2e00000 > file.hex
Reading your comment below:
I want the first byte of binary file to be present at the offset. i.e Just add an offset without seeking.
makes me believe the only way to do this is parsing the output and modifying it in order to add the desired offset.
I didn't found anything in the docs that would allow this to be done easily, sorry. :(
If you can live with AWK here's a proof of concept:
$ xxd random.bin | gawk --non-decimal-data ' # <-- treat 0x123 like numbers
> {
> offset = 0x1000 # <-- your offset, may be hex of dec
>
> colon = index($0, ":") - 1
> x = "0x" substr($0, 1, colon) # <-- add 0x prefix to original offset ...
> sub(/^[^:]*/, "") # <-- ... and remove it from line
>
> new = x + offset # <-- possible thanks to --non-decimal-data
> printf("%0"colon"x", new) # <-- print updated offset ...
> print # <-- ... and the rest of line
> }'
0001000: ac48 df8c 2dbe a80c cd03 06c9 7c9d fe06 .H..-.......|...
0001010: bd9b 02a1 cf00 a5ae ba0c 8942 0c9e 580d ...........B..X.
0001020: 6f4b 25a6 6c72 1010 8d5e ffe0 17b5 8f39 oK%.lr...^.....9
0001030: 34a3 6aef b5c9 5be0 ef44 aa41 ae98 44b1 4.j...[..D.A..D.
^^^^
updated offsets (+0x1000)
I bet it would be shorter in Perl or Python, but AWK just feels more "script-ish" :-)
Say I have generated the following binary file:
# generate file:
python -c 'import sys;[sys.stdout.write(chr(i)) for i in (0,0,0,0,2,4,6,8,0,1,3,0,5,20)]' > mydata.bin
# get file size in bytes
stat -c '%s' mydata.bin
# 14
And say, I want to find the locations of all zeroes (0x00), using a grep-like syntax.
The best I can do so far is:
$ hexdump -v -e "1/1 \" %02x\n\"" mydata.bin | grep -n '00'
1: 00
2: 00
3: 00
4: 00
9: 00
12: 00
However, this implicitly converts each byte in the original binary file into a multi-byte ASCII representation, on which grep operates; not exactly the prime example of optimization :)
Is there something like a binary grep for Linux? Possibly, also, something that would support a regular expression-like syntax, but also for byte "characters" - that is, I could write something like 'a(\x00*)b' and match 'zero or more' occurrences of byte 0 between bytes 'a' (97) and 'b' (98)?
EDIT: The context is that I'm working on a driver, where I capture 8-bit data; something goes wrong in the data, which can be kilobytes up to megabytes, and I'd like to check for particular signatures and where they occur. (so far, I'm working with kilobyte snippets, so optimization is not that important - but if I start getting some errors in megabyte long captures, and I need to analyze those, my guess is I would like something more optimized :) . And especially, I'd like something where I can "grep" for a byte as a character - hexdump forces me to search strings per byte)
EDIT2: same question, different forum :) grepping through a binary file for a sequence of bytes
EDIT3: Thanks to the answer by #tchrist, here is also an example with 'grepping' and matching, and displaying results (although not quite the same question as OP):
$ perl -ln0777e 'print unpack("H*",$1), "\n", pos() while /(.....\0\0\0\xCC\0\0\0.....)/g' /path/to/myfile.bin
ca000000cb000000cc000000cd000000ce # Matched data (hex)
66357 # Offset (dec)
To have the matched data be grouped as one byte (two hex characters) each, then "H2 H2 H2 ..." needs to be specified for as many bytes are there in the matched string; as my match '.....\0\0\0\xCC\0\0\0.....' covers 17 bytes, I can write '"H2"x17' in Perl. Each of these "H2" will return a separate variable (as in a list), so join also needs to be used to add spaces between them - eventually:
$ perl -ln0777e 'print join(" ", unpack("H2 "x17,$1)), "\n", pos() while /(.....\0\0\0\xCC\0\0\0.....)/g' /path/to/myfile.bin
ca 00 00 00 cb 00 00 00 cc 00 00 00 cd 00 00 00 ce
66357
Well.. indeed Perl is very nice 'binary grepping' facility, I must admit :) As long as one learns the syntax properly :)
This seems to work for me:
grep --only-matching --byte-offset --binary --text --perl-regexp "<\x-hex pattern>" <file>
Short form:
grep -obUaP "<\x-hex pattern>" <file>
Example:
grep -obUaP "\x01\x02" /bin/grep
Output (Cygwin binary):
153: <\x01\x02>
33210: <\x01\x02>
53453: <\x01\x02>
So you can grep this again to extract offsets. But don't forget to use binary mode again.
Someone else appears to have been similarly frustrated and wrote their own tool to do it (or at least something similar): bgrep.
One-Liner Input
Here’s the shorter one-liner version:
% perl -ln0e 'print tell' < inputfile
And here's a slightly longer one-liner:
% perl -e '($/,$\) = ("\0","\n"); print tell while <STDIN>' < inputfile
The way to connect those two one-liners is by uncompiling the first one’s program:
% perl -MO=Deparse,-p -ln0e 'print tell'
BEGIN { $/ = "\000"; $\ = "\n"; }
LINE: while (defined(($_ = <ARGV>))) {
chomp($_);
print(tell);
}
Programmed Input
If you want to put that in a file instead of a calling it from the command line, here’s a somewhat more explicit version:
#!/usr/bin/env perl
use English qw[ -no_match_vars ];
$RS = "\0"; # input separator for readline, chomp
$ORS = "\n"; # output separator for print
while (<STDIN>) {
print tell();
}
And here’s the really long version:
#!/usr/bin/env perl
use strict;
use autodie; # for perl5.10 or better
use warnings qw[ FATAL all ];
use IO::Handle;
IO::Handle->input_record_separator("\0");
IO::Handle->output_record_separator("\n");
binmode(STDIN); # just in case
while (my $null_terminated = readline(STDIN)) {
# this just *past* the null we just read:
my $seek_offset = tell(STDIN);
print STDOUT $seek_offset;
}
close(STDIN);
close(STDOUT);
One-Liner Output
BTW, to create the test input file, I didn’t use your big, long Python script; I just used this simple Perl one-liner:
% perl -e 'print 0.0.0.0.2.4.6.8.0.1.3.0.5.20' > inputfile
You’ll find that Perl often winds up being 2-3 times shorter than Python to do the same job. And you don’t have to compromise on clarity; what could be simpler that the one-liner above?
Programmed Output
I know, I know. If you don’t already know the language, this might be clearer:
#!/usr/bin/env perl
#values = (
0, 0, 0, 0, 2,
4, 6, 8, 0, 1,
3, 0, 5, 20,
);
print pack("C*", #values);
although this works, too:
print chr for #values;
as does
print map { chr } #values;
Although for those who like everything all rigorous and careful and all, this might be more what you would see:
#!/usr/bin/env perl
use strict;
use warnings qw[ FATAL all ];
use autodie;
binmode(STDOUT);
my #octet_list = (
0, 0, 0, 0, 2,
4, 6, 8, 0, 1,
3, 0, 5, 20,
);
my $binary = pack("C*", #octet_list);
print STDOUT $binary;
close(STDOUT);
TMTOWTDI
Perl supports more than one way to do things so that you can pick the one that you’re most comfortable with. If this were something I planned to check in as school or work project, I would certainly select the longer, more careful versions — or at least put a comment in the shell script if I were using the one-liners.
You can find documentation for Perl on your own system. Just type
% man perl
% man perlrun
% man perlvar
% man perlfunc
etc at your shell prompt. If you want pretty-ish versions on the web instead, get the manpages for perl, perlrun, perlvar, and perlfunc from http://perldoc.perl.org.
The bbe program is a sed-like editor for binary files. See documentation.
Example with bbe:
bbe -b "/\x00\x00\xCC\x00\x00\x00/:17" -s -e "F d" -e "p h" -e "A \n" mydata.bin
11:x00 x00 xcc x00 x00 x00 xcd x00 x00 x00 xce
Explanation
-b search pattern between //. each 2 byte begin with \x (hexa notation).
-b works like this /pattern/:length (in byte) after matched pattern
-s similar to 'grep -o' suppress unmatched output
-e similar to 'sed -e' give commands
-e 'F d' display offsets before each result here: '11:'
-e 'p h' print results in hexadecimal notation
-e 'A \n' append end-of-line to each result
You can also pipe it to sed to have a cleaner output:
bbe -b "/\x00\x00\xCC\x00\x00\x00/:17" -s -e "F d" -e "p h" -e "A \n" mydata.bin | sed -e 's/x//g'
11:00 00 cc 00 00 00 cd 00 00 00 ce
Your solution with Perl from your EDIT3 give me an 'Out of memory'
error with large files.
The same problem goes with bgrep.
The only downside to bbe is that I don't know how to print context that precedes a matched pattern.
One way to solve your immediate problem using only grep is to create a file containing a single null byte. After that, grep -abo -f null_byte_file target_file will produce the following output.
0:
1:
2:
3:
8:
11:
That is of course each byte offset as requested by "-b" followed by a null byte as requested by "-o"
I'd be the first to advocate perl, but in this case there's no need to bring in the extended family.
What about grep -a? Not sure how it works on truly binary files but it works well on text files that the OS thinks is binary.
Does anyone know how I can read the first two characters from a file, using a bash script. The file in question is actually an I/O driver, it has no new line characters in it, and is in effect infinitely long.
The read builtin supports the -n parameter:
$ echo "Two chars" | while read -n 2 i; do echo $i; done
Tw
o
ch
ar
s
$ cat /proc/your_driver | (read -n 2 i; echo $i;)
I think
dd if=your_file ibs=2 count=1 will do the trick
Looking at it with strace shows it is effectively doing a two bytes read from the file.
Here is an example reading from /dev/zero, and piped into hd to display the zero :
dd if=/dev/zero bs=2 count=1 | hd
1+0 enregistrements lus
1+0 enregistrements écrits
2 octets (2 B) copiés, 2,8497e-05 s, 70,2 kB/s
00000000 00 00 |..|
00000002
echo "Two chars" | sed 's/../&\n/g'
G'day,
Why not use od to get the slice that you need?
od --read-bytes=2 my_driver
Edit: You can't use head for this as the head command prints to stdout. If the first two chars are not printable, you don't see anything.
The od command has several options to format the bytes as you want.