I would like to write a function in Google Spreadsheets which simply gives me the week A given Start day B and End Day C.
A B C
201507 09/02/2015 15/02/2015
201508 16/02/2015 22/02/2015
201509 23/02/2015 01/03/2015
201510 02/03/2015 08/03/2015
201511 09/03/2015 15/03/2015
201512 16/03/2015 22/03/2015
201513 23/03/2015 29/03/2015
201514 30/03/2015 05/04/2015
201515 06/04/2015 12/04/2015
201516 13/04/2015 19/04/2015
I though about implementing a mod function mod(x,7)=0 which restarts the week after 7 days but that was somehow difficult to implement, at least for me.
Similar to #Munkey's solution, but shorter:
=year(B1)&text(weeknum(B1),"00")
Assumes 09/02/2015 is in B1.
So not the most elegant of solutions, but a start I guess.
Assuming your data starts at B2 and goes down. Try this in A2 and drag down
=CONCATENATE(right(B2,4),If(WEEKNUM(B2,2)<10,CONCATENATE(0,WEEKNUM(B2,2)),WEEKNUM(B2,2))
This formula assumes your weekday starts on Monday. If your weekday starts on a different day, Change the 2 in the weeknum to whatever suits. 1 being sunday, 2 being monday, etc.
Lastly this formula doesn't even look at end date.
Related
I have an excel with working hours in format Starting: 15:30 (A1) and finishing: 01:00 (B1). I would like to calculate the hours that i worked as nightshift (C1). The night shift is between 22:00 and 06:00. So if i work for example 17:00 to 02:15, i should get the number 04:15 as nightahift hours. I i work from 22:00 to 09.15 i should get 8 nightshift hours. I got the time difference with this
""=MOD(B2-A2;1)"" but this gets the whole shift and not the night ones only. Any suggestions?
It seems that this code works for one pair of columns, but i cannot figure out how to sum the results. The excel is seperated into columns, where every date has 2 columns for Starting and Ending shift
=MOD(D4-C4;1)24-(D4<C4)(22-6)-MEDIAN(D424;6;22)+MEDIAN(C424;6;22)
The ideal would be to have a formula to this result
=MOD(D4-C4;1)24-(D4<C4)(22-6)-MEDIAN(D424;6;22)+MEDIAN(C424;6;22)+
MOD(F4-E4;1)24-(F4<E4)(22-6)-MEDIAN(F424;6;22)+MEDIAN(E424;6;22)+
MOD(H4-G4;1)24-(H4<G4)(22-6)-MEDIAN(H424;6;22)+MEDIAN(G424;6;22) etc, but more compact way
Assuming that all input times are relative to 1/0/1900 (only time portion information). Therefore you need to consider when the date refers to the next day (adding 1). The condition for the end date is that if start > end, then the end date refers to the next day (+1). We take into account the above for the solution.
Assuming no excel version constraints as per the tags listed in the question, you can use the following formula in F2:
=LET(start, A2:A5, end, B2:B5, ns, D2, ne, D3+1, eEff, IF(end<start, end+1, end),
CALC, LAMBDA(isStart, MAP(start, eEff, LAMBDA(x,y, IF(y < ns, 0,
MEDIAN(IF(isStart, x, y), ns, ne))))), a, CALC(TRUE), b, CALC(FALSE),b-a)
I created a user LAMBDA function CALC just to avoid repetition of a similar calculation for the actual start (a) and end (b) of the working night interval. As you can see from the formula the night end (ne) has been adjusted to consider the next day. Similarly, we do the adjustment for the end time, calculating the effective end time (eEff) considering the next day when the end time (end) is lower than the start time (start).
We use MEDIAN to identify the actual interval in both cases. Here is the output:
where 0:00 means no time consumed during the night shift. The rest is just to use the correct format: hh:mm in the output to show durations during the night shift.
If you show the input data in numeric format, you can see the times referred to the first valid year in Excel (<= 1):
That is why we need to convert ne and end (in case it represents the next day), but it depends on whether or not you want to consider the next day in your input data. So for row 2 it represents 01:00 of the current day (0.04) so in the formula, we treat it as: 01:00 of the next day (1.04)
I have an excel sheet with about 50,000 records where I need to find the number of minutes between two date timestamps but I need to exclude any minutes that occurred during the times we are not working.
Our schedule is M-F 8:30am-5:30pm, Saturdays 8:30am-1:30pm
We don't work Sundays or holidays.
As an example
Cell B2: [7/3/2020 2:16:21 PM]
Cell C2: [7/6/2020 9:20:23 AM]
The manually calculated answer for this one should be about 244 minutes. Task started Friday afternoon, Saturday was a holiday, don't work Sundays, task completed at 9:20am on Monday.
Usually, I come here and start writing a question and by the time I've understood my own problem well enough to post a question I have figured it out on my own but not this time! Help!
Update:
#ForwardEd shared this...
=((I2-H2)
-MAX(0,(NETWORKDAYS.INTL(H2,I2,"0000011",$M$2:$M$12)-1+(WEEKDAY(I2,1)=7)))*TIME(15,0,0)
-MAX(0,(NETWORKDAYS.INTL(H2,I2,"1111101",$M$2:$M$12)-(WEEKDAY(I2,1)=7)))*TIME(19,0,0)
-NETWORKDAYS.INTL(H2,I2,"1111110",$M$2:$M$12)-(NETWORKDAYS.INTL(H2,I2,"0000000")
-NETWORKDAYS.INTL(H2,I2,"0000000",$M$2:$M$12)))*24*60
Where H:H is the Start Date Timestamp and I:I is the Response Date Timestamp and M2:M12 contains my holiday list.
It worked beautifully until I ran into an example like this:
H2 - 07/26/2020 7:48:45 PM
I2 - 07/27/2020 8:57:58 AM
The net result was -650.78333. It looks like anything that starts one one day and ends on the next is coming back as negative.
We want to measure the average response time in minutes for the applications that require manual underwriting. These start timestamps are times that loan applications were received online so they could come in any time of day. The stop times are timestamps that represent the system recorded response time. i.e. the timestamp where an underwriter first did something with the loan application. If a loan application was received at 7pm and was not auto-decisioned then a manual underwriter will need to do something with it the next day when we start working.
If that application came in at 7pm on Wed and is decisioned by an underwriter at 8:46am on Tuursday, we would want to document 16 minutes for that application - not 826 counting the hours between 7pm and 8:30am.
What you want to look at is NETWORKDAYS.INTL. Use this in conjunction with the custom settings to determine the number of Saturdays, Sundays and for the number of days in between your start and end time. You know you have X amount of time per day that is non working time, and Y amount per Saturday.
Then you formula in essence becomes
(End time - start time) - X * No. Weekdays - Y * No. Saturdays - No. Sundays - No. Holidays
Now there will be some tricks in there in order to count your days. but that is the gist of what it boils down to in a formula.
The formulas that are doing the brunt of the work are:
WORKDAY
NETWORKDAYS.INTL
TIME
I avoided the use of an if statement by using a boolean operation that excel will resolve from TRUE/FALSE to 1/0 when sent through a math operator. Side note: I read somewhere that this is also faster than an IF statement, but have no way of proving it and really does not matter on a small number of calculations.
WORKDAY
This formula will return the day of the week for a given date, and a set day of the week to be 1. It will be need in this solution to determine if the end date is a Saturday which has a value of 7 in default setup up as well when option 1 is picked. The format for the formula is:
WORKDAY(Excel Serial date, day 1 of the week)
For this solution
WEEKDAY(B3,1)
NETWORKDAYS.INTL
This formula will be used to count the number of specific days a start and an end date. It can exclude a custom weekend or count a custom week. If it is supplied with a list of dates that are holidays they can be excluded as well. The basic format of the formula is:
NETWORKDAYS.INTL(Start Date, End Date, Custom week choice or workweek pattern, range of holiday dates)
When entering the formula it will give you a list of predefined options for the weekend choices. It will not talk about the pattern.
The pattern is a string 7 digits long consisting of 1 or 0. 0's represents the days you want to count and 1's are days you want to ignore. An important part of the pattern is that the first entry is MONDAY. "1010111" would count only Tuesdays and Thursdays.
TIME
Excel stores date as an integer. 1 represents 1st of January 1900, 2 the 2nd of January 1900 and so on. Time is stored as a decimal or if you prefer the percentage/fraction of a day or 24 hour period. So rather than figuring out the math to determine what percentage of a day X number of hours is, it is simpler to let excel calculate it for us and make the number a little more understandable to someone who may be deciphering the formula later. The basic format of the formula is:
TIME(Hours, Minutes, Seconds)
So as stated earlier, 6 key components need to be determined:
X - Amount of non working time after a weekday
Y - Amount of non working time after a Saturday
Number of weekdays
Number of Saturdays
Number of Sundays
Number of holidays
1) Determine Weekday Non-Working Hours
Based on the supplied information that work day stops at 1730 and starts as 0830. There are a couple of ways of doing the math. Subtract the working hours from 24 hours or count the non work hours at the end of the day and add them to the non work hours at the start of the day.
24 - (17.5 - 8.5) = 15
or
(24 - 17.5) + (8.5 - 0) = 15
For this example 15 will be hard coded into the final formula
2) Determine Saturday Non-Working Hours
Similar to above. Note that we are ignoring Sunday as it is a designated non working day which we already know is 24 hours or 1 day. We are just interested in the time between end of shift Saturday and start of the next normal working Monday. So it really gets calculated the same with just with difference end of shift time.
24 - (13.5 - 8.5) = 19
or
(24- 13.5) - (8.5 - 0) = 19
For this example 19 will be hard coded into the final formula
3) Determine Number of Weekdays
Based on the description earlier of of NETWORKDAYS.INT and working with the assumption that holidays are stored in the range F2:F2, and using a pattern of "0000011" the number of weekdays the formula will be as follows:
=NETWORKDAYS.INTL(B2,B3,"0000011",F2)
For this example the formula is place in cell F6
4) Determine Number of Saturdays
Similar 3) adjust the pattern to only select Saturdays by using "1111101"
=NETWORKDAYS.INTL(B2,B3,"1111101",F2)
For this example the formula is place in cell F7
5) Determine Number of Sundays
Similar 4) adjust the pattern to only select Saturdays by using "1111110"
=NETWORKDAYS.INTL(B2,B3,"1111110",F2)
For this example the formula is place in cell F8
6) Determine Number of Holidays
To get the number of holidays there is not a direct way of doing it. Instead take the difference between all days counted without holidays being factored in and all days counted with holidays counted in.
=NETWORKDAYS.INTL(B2,B3,"0000000")-NETWORKDAYS.INTL(B2,B3,"0000000",$F$2:F2)
For this example the formula is place in cell F9
Now at this point I would love to say just substitute all of the above into the generic formula, but there are a couple of special cases that need to be taken care of. You may have also noted I have not used the WEEKDAY formula yet.
So in order to count the number of days to which X is going to apply, its really the number of days minus 1. The minus 1 is because you want to cont the intervals between days, not the number of days themselves. This gets a little bit more trickier when the end day is a Saturday because there is still an interval there but Saturday is not counted as a weekday. So the True count for number of weekday intervals is:
=MAX(0,(F6-1+(WEEKDAY(B3,1)=7)))
I originally had the MAX(0, calc) in there to prevent the posibility of the day count being negative. After arriving at this final format it may not be needed and you might get away with the following but its untested:
=F6-1+(WEEKDAY(B3,1)=7)
This same concept needs to be applied to your Saturday count. If you job ends on Saturday you do not need to subtract the non working hours after the last Saturday. You formula will look like:
=MAX(0,(F7-(WEEKDAY(B3,1)=7)))
and again further testing is required to make sure MAX can be removed, but if it can then the formula would look like:
=F7-(WEEKDAY(B3,1)=7)
So now with the understanding how dates and times are stored, determine the time difference between start end end time and subtract all the non working hours.
=(B3-B2)-MAX(0,(F6-1+(WEEKDAY(B3,1)=7)))*TIME(15,0,0)-MAX(0,(F7-(WEEKDAY(B3,1)=7)))*TIME(19,0,0)-F8-F9
Now you will not want to use helper cells, so you can take each of the individual formula from F6 to F9 and wind up with:
=(B3-B2)-MAX(0,(NETWORKDAYS.INTL(B2,B3,"0000011",F2)-1+(WEEKDAY(B3,1)=7)))*TIME(15,0,0)-MAX(0,(NETWORKDAYS.INTL(B2,B3,"1111101",F2)-(WEEKDAY(B3,1)=7)))*TIME(19,0,0)-NETWORKDAYS.INTL(B2,B3,"1111110",F2)-(NETWORKDAYS.INTL(B2,B3,"0000000")-NETWORKDAYS.INTL(B2,B3,"0000000",$F$2:F2))
The formula looks unruly, but is easier to understand when broken down into its parts.
Now the last step is to get the answer to display in minutes. There are two choices.
You can leave it as it is in an excel serial date format and change the formatting of to a custom format of [m]. The [ ] will force it into minutes and prevent spill over to hours. It will also round to the nearest minute.
You can convert the results to minutes by multiplying by 24*60 and the value will be in minutes and decimal of minutes.
Note that:
A11 has Time formatting applied
A12 has General formatting applied
A14 has custom formatting of [m] applied
It should be something like this:
Create a calendar table with the workinghours for each days in the year you have data in
Date | StartTime | End time
1/1/2020 1/1/2020 8:30:00 PM 1/1/2020 5:30:00 PM
...
7/3/2020 7/3/2020 8:30:00 PM 7/6/2020 5:30:00 PM
...
12/31/2020
Then paste this code in a module
Function CalcDays(dStart As Date, dEnd As Date, daysCalendar As Range)
Dim Cell As Range
Dim MinDaysCalendar As Date, MaxDaysCalendar As Date
Dim aWSF As WorksheetFunction
Set aWSF = Application.WorksheetFunction
'check the minimum en the maximum date in the calendar
With aWSF
MinDaysCalendar = .Min(daysCalendar)
MaxDaysCalendar = .Max(daysCalendar)
End With
'if the date you check is not in the calendar, exit the function
If dStart < MinDaysCalendar Or dStart > MaxDaysCalendar Then
MsgBox "Date not in calendar"
Exit Function
End If
If dEnd < MinDaysCalendar Or dEnd > MaxDaysCalendar Then
MsgBox "date not in calendar"
Exit Function
End If
'sum the time of all the dates between the start and the end
'pick min and max in order to start and stop at the right time per day
Dim tempTime As Integer
With daysCalendar
For i = 1 To .Rows.Count
If .Cells(i, 2).Value >= CLng(dStart) And .Cells(i, 3).Value <= CLng(dEnd) Then
daytime = aWSF.Max(.Cells(i, 2).Value, dStart) - aWSF.Min(.Cells(i, 3).Value, dEnd)
End If
tempTime = tempTime + daytime
Next i
End With
'return the total time
CalcDays = tempTime
End Function
You can call the function by typing =calcdays in a cell and then give the startDay, endDay and calendar column as parameters.
There might still be some flaws in this code but I think we can manage those.
As I was new to excel, I am working on a use case where I want to get week start and week end dates of a given month,
I am using following formulae which is giving me next month date followed by weekend.
=A7+(6-WEEKDAY(A7,2)+1)
Week Start Week End
7/1/18 7/1/18
7/2/18 7/8/18
7/9/18 7/15/18
7/16/18 7/22/18
7/23/18 7/29/18
7/30/18 8/5/18
How can I modify or have a new formulae which gives me month end date, if my weekend is on next month
Expected output should be
Week Start Week End
7/1/18 7/1/18
7/2/18 7/8/18
7/9/18 7/15/18
7/16/18 7/22/18
7/23/18 7/29/18
7/30/18 7/31/18
For month like Feb as it is unable to caluculate the formula it should return 0
Week Start Week End
2/1/18 2/4/18
2/5/18 2/11/18
2/12/18 2/18/18
2/19/18 2/25/18
2/26/18 2/28/18
1/0/00 1/1/00
You just need to wrap the result of your original formula in MIN and compare it to EOMONTH.
=MIN(A7+(6-WEEKDAY(A7,2)+1), EOMONTH(A7, 0))
As far as Feb goes, you need to compare te current value with the one either above or below to determine whether month(date)<>month(date+7) and you have not shown enough of how your data structure transcends months to do that.
I have a date in column H10 and need to add 45 days to this date in the next Column I
If there are not dates Column I must be blank
If the 45th day falls on a weekend the calculation must move to the next workday which is Monday
You need to combine two fundamental functions.
First, DATE + INT = DATE. For example, if H10 = 1/8/2015 and H11 = H10 + 10 then H11 will show 1/18/2015.
In your case, you want to use H10 + 45.
Second, you can use the Weekday(date,mode) function to determine the day of the week. Personally, for your purpose, you could use weekday(h10 + 45, 2) which would give a 1-5 for MTWRF, and a 6-7 for a weekend day. So something like
=if(weekday(h10+45,2) < 6, "weekday", "weekend")
=if(weekday(h10+45,2) = 1, "Monday!!", "not monday...")
But we aren't done yet - you need to make sure your day actually ends up on a weekday. So we can do something like this - when determining a weekday, we can use that to determine how much we need to add. If we end up with a 6 (Saturday) we want to add 2 days to push it to a Monday. In the case of a 7, we want to add 1 day to push it to a Monday. Thus, we can simply take the 8 - weekday(h10+45) to add when it's a weekday. So our add value becomes
// determine day type weekday weekend, so add the offset
= if(weekday(h10+45) < 5, h10+45, h10 + 45 + (8 - weekday(h10+45))
You also have a requirement about being blank, so you'll want to wrap whatever you use with
=if(isblank(h10),"", /* your real function here */)
You can combine the functions for IF(), WEEKDAY() and WORKDAY() to calculate your finish date and ensure that it does not fall on a weekend.
I've used
WEEKDAY(WORKDAY(H10+45),16)
to have Saturday and Sunday be represented as days 1&2 respectively.
IF(WEEKDAY(WORKDAY(H10,45),16)=1,WORKDAY(H10,45)+2,IF(WEEKDAY(WORKDAY(H10,45),16)=2,WORKDAY(H10,46),H10))
I need to calculate the working hours elapsed between two dates and times, for example:
Holiday taken between 01/09/2014 and 05/09/2014
5 working days # 8 hours per day.
I need the result to show me how many working hours that would be. For example:
ANNUAL ENTITLEMENT: 89.9 Hours
DATE FROM DATE TO RETURN TO WORK HOURS REQUIRED HOURS REMAINING DATE
01/09/2014 05/09/2014 06/09/2014 40 49.90
I have no idea if this is even possible!
I am assuming these are given cells. if you type in the date to a cell you can click on a new cell and put uptop by the fx this
for example. In C1 you can type this into the fx. Make sure you put the equal sign.
=B1-A1
This is what is the dates in the cells
A1 = 1/9/2014
B1 = 5/9/2014
This will give you 120 which is the total days inbetween.
You will want to get the number of weeks so you can divide by 7.
You will multiply weeks by number of days worked which is 5
Then you want the weeks times 8 hours you can do this in C1
=(B1 - A1)/7 * 5 * 8
which gives you 685.7143
you need to also take into account weekends which a simple subtraction will not do. Firstly find the total number of days:
TOTAL_NUMBER_DAYS = B1-A1 + 1
then calculate how many weekends:
TOTAL_WEEKENDS = WEEKNUM(B1) - WEEKNUM(A1)
finally take the total days and subtract weekends:
NET_TOTAL_DAYS = TOTAL_NUMBER_DAYS - (TOTAL_WEEKENDS * 2)
TOTAL_HOURS = NET_TOTAL_DAYS * 8
I solved this recently and had a working solution initially in Excel 2013. Slightly adapted to work in 2007 (lack of 'Days()' function). We use it for reporting on support tickets (length of time between opening and closing a ticket).
Inputs are "Workday start", "Workday end" from which "Hours worked" and "Hours not worked" are calulated.
Hours worked =HOUR(WorkEnd-WorkStart)+(MINUTE(WorkEnd)+MINUTE(WorkStart))/60
Hours not worked = 24 - Hours worked
Further inputs are a table ("Data") with first two columns "Open" and "Close", which are dateserial cells.
Next column is standard numeric value "Gross hours" =(Data[[#This Row],[Close]]-Data[[#This Row],[Open]])*24
Next column is standard numeric value "Net workdays" =NETWORKDAYS(Data[[#This Row],[Open]],Data[[#This Row],[Close]])
Next column is standard numeric value "Net days" =MAX(1,DAY(Data[[#This Row],[Close]])-DAY(Data[[#This Row],[Open]]))
Next column is standard numeric value "Gross workhours" =IF(Data[[#This Row],[Gross hours]]>0,Data[[#This Row],[Gross hours]]-24*(Data[[#This Row],[Net days]]-Data[[#This Row],[Net workdays]]),0)
Last column is standard numeric value "Total work hours" =IF(Data[[#This Row],[Gross workhours]]<24,Data[[#This Row],[Gross workhours]],Data[[#This Row],[Gross workhours]]-(HoursNotWorked*Data[[#This Row],[Net workdays]]+HoursWorked))
This solution makes it trivial to adjust start and end work times, as well as accounting for any holidays (via a small change to the NETWORKDAYS() function to utilise the optional parameter).