mongoose "_id" field can't be deleted - node.js

Question

I want to return the "id" field instead of "_id",using the solution in
MongoDB: output 'id' instead of '_id'
the following is my code:
ScenicSpotSchema.virtual('id').get(function () {
var id = this._id.toString();
delete this._id;
delete this.__v;
return id;
});
But the response still have the field "id" and "_id",It seems that the delete doesn't take effect. Why?

Answer 1

I'm estimating what you need is toJSON. This should do what you want:
schema.options.toJSON = {
transform: function(doc, ret) {
ret.id = ret._id;
delete ret._id;
delete ret.__v;
}
};

Answer 2

On Mongoose, the "id" property is created by default and it's a virtual one returning the value of "_id". You don't need to do that yourself.
If you want to disable the automatic creation of the "id" property, you can do that when defining the schema:
var schema = new Schema({ name: String }, { id: false })
For the _id field, you can tell Mongoose not to create one by default when you create a new Mongoose object, with the {_id: false} property. HOWEVER, when you .save() the document in MongoDB, the server WILL create an _id property for you.
See: http://mongoosejs.com/docs/guide.html#_id
What I do in my code is creating an instance method called something like returnable that returns a plain JS object with just the properties I need. For example:
userSchema.methods.returnable = function(context) {
// Convert this to a plain JS object
var that = this.toObject()
// Add back virtual properties
that.displayName = this.displayName
// Manually expose selected properties
var out = {}
out['id'] = that._id
var expose = ['name', 'displayName', 'email', 'active', 'verified', 'company', 'position', 'address', 'phone']
for(var i in expose) {
var key = expose[i]
out[key] = that[key]
// Change objects to JS objects
if(out[key] && typeof out[key] === 'object' && !Array.isArray(out[key])) {
// Change empty objects (not array) to undefined
if(!Object.keys(out[key]).length) {
out[key] = undefined
}
}
}
return out
}