How to set Excel column widths to a certain number of pixels? - excel

I have the following data set on a worksheet:
SheetName|ColumnIndex|Pixels
---------+-----------+------
abc |1 |50
abc |2 |150
def |1 |125
For each sheet, I'd like to set the column width to the appropriate number of pixels, using something like:
Sub setColumn (sheetName As string, columnIndex As long, pixels As long)
width=getWidthInCharacters(pixels)
ThisWorkbook.Sheets(sheetName).Cells(1, columnIndex).EntireColumn.ColumnWidth = width
End Sub
I haven't been able to figure out how to write the getWidthInCharacters() function. How do I convert pixels to characters, or possibly set .ColumnWidth to pixels directly?

I'm sorry to tell you, but in my experience, you can't. Column width is measured in points, and whilst you can - in theory - convert points to pixels, Excel won't listen very precisely when you assign them. They also seem to vary somewhat from monitor to monitor. Basically, points are fractions of inches, pixels are dots on the screen. Windows has a notion (right or wrong) of how many pixels there are to a point given a particular output device.
You can write a function that tweaks column width, but usually the approach has to be
Find the smallest contextual value that excel is willing to increment a column width by (say, store the original value, then assign .ColumnWidth = dblOriginal + 0.01. Check if columnwidth has changed - if it has, you just made a 1-pixel adjustment. If it hasn't, you need a bigger number than 0.01.
Find a final column width in pixels that you want, and repeat this first step until you've incremented the column width that many times.
Check the result, and see if it looks OK.
Word of warning: this is horrible, slow, and not good code, and if they've fixed column widths in versions of Excel after 2010, then you might be lucky and just be able to use a pixels-to-points function, convert and assign. There are some around, just in my experience they didn't give me consistent results on different screens on the same machine. Really weird that one.

.ColumnWidth does not depend on theme font selection, but pixel width does: https://support.microsoft.com/en-us/kb/214123
'pixel width of column A
Debug.Print (Columns("A").Width / 72) * ThisWorkbook.WebOptions.PixelsPerInch
After some reading and thinking, my solution:
Sub setColumnWidth(rColumnWidth As Range, iPixelWidth As Integer)
' set column width by pixels
' check status ScreenUpdating
Dim bScreenUpdatingState As Boolean
bScreenUpdatingState = Application.ScreenUpdating
' set status ScreenUpdating
If bScreenUpdatingState = True Then Application.ScreenUpdating = False
Dim iPointsPerInch As Byte
iPointsPerInch = 72
Dim iPixelsPerInch As Byte
iPixelsPerInch = ThisWorkbook.WebOptions.PixelsPerInch
' check 2 column widths: get iPointDelta
Dim rColumn As Range
Set rColumn = rColumnWidth.EntireColumn
rColumn.ColumnWidth = 1
Dim iPoint_1 As Single
iPoint_1 = rColumn.Width
rColumn.ColumnWidth = 2
Dim iPoint_2 As Single
iPoint_2 = rColumn.Width
Dim iPointDelta As Single
iPointDelta = iPoint_2 - iPoint_1
' set column width to iPixelWidth
Dim iPoint_New As Single
iPoint_New = iPixelWidth / iPixelsPerInch * iPointsPerInch
Dim iChar_New As Single
iChar_New = (iPoint_New - (iPointDelta - 1.5)) / iPointDelta
rColumn.ColumnWidth = iChar_New
' reset status ScreenUpdating
If bScreenUpdatingState = True Then Application.ScreenUpdating = True
End Sub
To run the sub setColumnWidth:
Sub call_setColumnWidth()
Dim r As Range
Set r = ActiveSheet.Range("C1")
setColumnWidth r, 70
End Sub

Related

Excel 2016 and newer VBA: how to maximize a chart within/to the worksheet size?

In https://i.stack.imgur.com/s6gII.png and How to get the size (width and height) of the area with excel vsto c# excluding the ribbon area? a similar question has already been put.
Excluding all GUI elements outside/around the "inner/client" worksheet area, e.g. without the ribbon, "X/ok/fx" + cell contents, Sheet menu, "Ready + Record Macro" footer line + frame heights, left + right border + frame widths, etc.
And together with How to get the screen position of an active workbook? neither of these links has answered my needs yet. Or their instructions do not work for me, because neither of the .PageSetup.*Margin values corresponds to my worksheet "inner/client" OR "outside/GUI" borders + frames + overhead sizes.
I know, by writing
With ActiveChart.Parent 'access the chart container = the Shape
.Left = 0
.Top = 0
.Width = 4 * 72 'fixed size example
.Height = 3 * 72 'fixed size example
End With
I can set the chart position + size, in this example to a fixed size of 3 * 4 inches.
But HOW TO GET/fetch the whole currently visible dynamic worksheet "inner/client" size (at least once a method call) ?
In order to set the chart size, so that it covers/uses the whole currently visible dynamic worksheet "inner/client" size (at least once a method call). Hopefully: nothing more (no scrollbars shifting needed to see the whole chart), nothing less (no unneccessary "tiny" chart) ?
[I know, that size assignment will work for me only "for a moment" until a workbook resize happens. So I'll have to adjust the chart size again (and again (and again ...)), e.g. by using a timer (or a system timer). Or is there some "anchor/chain/nail" chart property, so that it ALWAYS keeps up with the "inner/client" worksheet size (within the workbook) ?]
Thanks for your help
This is about as good as you can do.
Sub SizeChartToWindow()
Dim VisibleRange As Range
Set VisibleRange = ActiveWindow.VisibleRange
Dim UsableRange As Range
Set UsableRange = VisibleRange.Resize(VisibleRange.Rows.Count - 1, _
VisibleRange.Columns.Count - 1)
With ActiveChart.Parent
.Left = UsableRange.Left
.Top = UsableRange.Top
.Width = UsableRange.Width
.Height = UsableRange.Height
End With
End Sub
Many thanks, that helped me a lot.
This also takes care of the worksheet scrollbars "scrolled away", wonderful.
And the right + bottom remainder of 0.00 .. 0.99 * cell sizes is "good enough" (and I have reduced the cell width to match the cell height = 20 pixels in order to reduce that remainder effect).
:)))

Excel VBA How do I compare values in two large datasets with a mass defect/error?

I am active in the field of analytical chemistry for my internship and wish to compare large datasets (two columns up to 15,000 rows). The main idea of this is that I have two columns with mass data (with 4 decimals) in which a macro should look for each mass in column one in column two, but with a mass defect/error.
What this means is that the value does not perfectly correspond (due to instrumental errors in measurements) but should fall within a lower limit and an upper limit. When the macro has cycled through dataset2 to check each value, dataset1's checked cell is offset to the next (.Offset(1,0)) to repeat the search for that specific value. The upperlimit and lowerlimit are automatically adjusted.
To give an example (code format used, otherwise the table would not display correctly):
Value to check from dataset1 is 101.1048, mass error is 5 ppm (parts-per-million, 0.000005%),
so the lower limit is 101.1043 and the upper limit is 101.1053. So in the example shown below,
the mass in dataset2 falls within the boundaries, after which the macro should sum the intensity
(linked to the mass column) of all mass values from dataset2 that fall within the dataset1 limits
for the checked cell. So SumIntensity=105+209 in the example, if no corresponding value is found,
the intensity of the dataset1 is used (so 100).
**Dataset1** " **Dataset2**
Mass ' Intensity " Mass ' Intensity
''''''''''''''''''''''''''''''''''''''''''''''''''''
101.1048 ' 100 " 101.1045 ' 105
101.1272 ' 300 " 101.1051 ' 209
I am however not well experienced with VBA (I have only written some basic macros to compare values in the same dataset with a mass defect/error) and after countless attempts I have not yet been able to get the macro to work.
My current code is as follows but keeps crashing (most likely due to the loops):
Sub CompareColumnsTest2()
Dim wscalc, wsdata, wscontrol As Worksheet
Set wscalc = Sheet2
Set wsdata = Sheet1
Set wscontrol = Sheet4
''-----------------------------------------------------------
''Compares datasets 1 and 2 in two steps:
''Looks up each Rounded Mass from dataset1 in dataset2 and substracting the relative intensity respectively
''Looks up each Rounded Mass from dataset 2 in dataset1 and if NOT present in dataset 1, copies Rounded Mass and (negative) Intensity
wscalc.Range("B3:B" & wscalc.Range("B" & Rows.Count).End(xlUp).Row).Copy
wscalc.Range("K3").PasteSpecial (xlPasteValues)
''Step one
Dim refcl, refint, massdefect, lowerlimit, upperlimit As Range
Set refcl = wscalc.Range("B3")
Set refint = wscalc.Range("D3")
Set pastecell = wscalc.Range("L3")
Set massdefect = wscontrol.Range("D4")
Set lowerlimit = wscalc.Range("Z2")
Set upperlimit = wscalc.Range("Z4")
Set checkcl = wscalc.Range("G3")
Set checkint = wscalc.Range("I3")
Dim refclnext, refintnext, checkclnext, pastecellnext As Range, sumint As Long
Do While Not IsEmpty(refcl)
Set refclnext = refcl.Offset(1, 0)
Set refintnext = refint.Offset(1, 0)
Set pastecellnext = pastecell.Offset(1, 0)
Set checkclnext = checkcl.Offset(1, 0)
Set checkintnext = checkint.Offset(1, 0)
sumint = 0
lowerlimit.Value = refcl / (1 + (massdefect / 1000000))
upperlimit.Value = refcl * (1 + (massdefect / 1000000))
Do While Not IsEmpty(checkcl)
If checkcl <= upperlimit And checkcl >= lowerlimit Then
sumint = sumint + checkint
End If
Set checkcl = checkclnext
Set checkint = checkintnext
Loop
Set pastecell.Value = refint - sumint
Set refcl = refclnext
Set refint = refintnext
Set pastecell = pastecellnext
Loop
End Sub
I hope my description is clear enough to be able to help me out. I do not ask of you to completely rewrite my code as that would ofcourse take a lot of time, but any tips/modifications would be highly appreciated.
Best,
JamesLooks
Edit 1:
Here are some screenshots showing some data and how the sheet is organized for cell references.
Overview of data and sheet layout,
Cells used for upper and lower limit
As suggested in the comments by Naresh Bhople I used excel functions (IF and SUMIFS) and incorporated these in a macro, which has solved my issue.
Best,
JamesLooks

Can I make a photo follow a number on excel or move it from cell to cell by VBA?

I just finished building a chess game on excel by VBA for my school project.
The way I built it is every piece has a number and a color (Green/Red):
1 - Pawn (x16)
2 - King (x2)
3 - Queen (x2)
4 - Bishop (x4)
5 - Night (x4)
6 - Rook (x4)
Just so it will look nicer I wanted to add pictures of each piece that will follow the number, Or that will move by a VBA commend that will come with the commend of moving the piece.
I prefer the first option if possible but the second one is good as well.
The way I move the pieces right now is like that:
MoveNum = Range(Range("j2").Value).Value
Range(Range("j2").Value).Value = 0
Range(Range("j2").Value).FormulaR1C1 = ""
Range(Range("j2").Value).Font.Color = -0
Range(Range("k2").Value).Value = MoveNum
Range(Range("k2").Value).Font.Color = RGB(210, 0, 0)
(This is the one that moves red pieces, the only difference between it and the green is that the RGB is (0, 175, 20) and not (210, 0, 0)
BTW my entire code is based on the numbers so changing/not using them isn't an option.
A time-saving alternative could be to use Unicode characters, instead of images:
♔♕♖♗♘♙♚♛♜♝♞♟
These are Unicode 9812 to 9823 and you can add them to Excel using either the UNICHAR worksheet function, or the ChrW function in VBA.
Also, you could just copy and paste them from above, right into your worksheet, and then manipulate them like you would any other text, including font size.
Here's the knight at 80pt:
My preferred place to look when I need a symbol or icon is (or to identify one) is https://codepoints.net. As of March 2019, Unicode contains almost 140,000 characters, with more being constantly added.
(Be sure to sign the petition to have a pot-leaf emoji added!) 🍁🍂🌿🍃🍀
If your assignment specifically requires you to use images then you can:
move the images with the .Top and .Left properties of the Shapes object
find the position of the cell with the .Top and .Left properties of the Range object.
Example:
Option Explicit
Sub movePicToCell()
'move the image named "Picture 2" on worksheet "Sheet1" to cell "C3"
Dim ws As Worksheet
Set ws = ThisWorkbook.Sheets("Sheet1")
ws.Shapes("Picture 2").Top = ws.Range("C3").Top
ws.Shapes("Picture 2").Left = ws.Range("C3").Left
End Sub

Assigning ColumnWidths with textbox data

I want to control the different column widths of a listbox with the use of textbox input. This is my code:
Sub code()
Dim x1 as integer
Dim x2 as integer
x1 = Me.TB1.value ‘x1 is assigned the number 40
x2 = Me.TB2.value ‘x2 is assigned the number 40
With Me.listbox1
.Clear
.ColumnCount = 2
.ColumnWidths = ‘’x1;x2’’
.list = getArray(SQLinput)
End with
End sub
Thanks for any help!
Edit:
The question, to be more precise, is that the code does not work. I am not allowed to write: .ColumnWidths = «x1;x2» So how can I write the code so that is it possible to control these variables from a textbox?
aListBox.ColumnWidths = newStringValue
or
StringValue = aListBox.ColumnWidths
A list of comma-separated values, with each value controlling the width of the associated column. A value can be an absolute value (in pixels), a percentage, a relative length expressed as i* where i is an integer, or an "*" that indicates "fill in the remaining width." If you use percentages, you can use non-integer values to specify fractions of a percent, e.g., 43.52%. The percentage value can be greater than 100%.
Notes
If you use pixels, the last column doesn't grow to the size of the rest of the ListBox. You should set the width of the last column to "" and it will automatically take up the remaining width of the ListBox.
Without any column width specifications, the headers will be divided evenly. If there are fewer column widths specified than the total number of columns, the remaining columns will divide up the remaining width equally.
An element with a length of "3" will be allotted three times the space of an element with length "1*". The value "" is equivalent to "1" and can be used to mean "fill the remaining space."

Color cells by absolute value in a range in Excel 2010

I'm looking to color a table of values in Excel 2010 by their absolute value. Basically, if I have the table:
...the cells are colored by the cell's raw value. What I would like to do is color by the cell's absolute value, so with the cell coloring of this table:
...but with the values of the first table (the real values). Any ideas on how one might do this? Through the GUI or with VBA?
I don't think that there is any way to do this with three colors (red, yellow, green), but you can do it with two colors (for example yellow and green). Simply make the color for the low value and the color for the high value the same. That way, the cells with the lower absolute value will have the middle color and cells with the higher absolute value will have the other color.
Select Your data
Conditional Formatting
Color Scale
More Rules
Select "3-Point Scale" under Format Style
Change the colors so that the Maximum and Minimum colors are the same
Here is my solution to this problem. The conditional format formula reads
=AND(ABS(B3)>0,ABS(B3)<=500)
for the darkest green, the scale changes to 500 to 1000, 1000 to 1500, and finally 1500 to 2000 for the red band.
Conditional Formats
Color Scale Values
Here is a picture of the dataset that I used to test these conditional formats:
A variation on this simple conditional formatting illustration may work for you.
Highlight the whole of the data range (you need the top LH cell to be the anchor for relative addressing) and enter the Formula: in 'relative notation' i.e. cell references without the dollar signs. You also have to consider the order of the rules.
The uppermost formula is obscured but reads =(ABS(B3)>39) * (ABS(B3)<41) Note that the * symbol applies an AND operation.
Ok, I have a solution that works with 3 color conditioning. Basically you supply a region to my code. It then creates two ranges, one of neg numbers and one of positive ones. It then applies conditional formatting
red-low yellow-mid green-high to the positive range and
red-high yellow-mid green-low to the negative range.
It was a quick solution so its sloppy and not robust (for instance it only works in columns A-Z because of a lazy ascii conversion for column numbers), but it works. (i'd post a pic but I don't have enough points)
---------------------edit-------------------------------
#pnuts is right, unless the data is symmetric this solution wont work as is. so with that in mind I came up with a new solution. First I will explain the general idea, then basically just dump the code, if you understand the logic the code should be fairly clear. It is a rather involved solution for such a seemingly simple problem, but isn't that always the way? :-P
We are still using the basic idea of the original code, create a negative range and apply colorscale to it, then create a positive range and apply the inverted color scale to it. As seen below
Negative ........... 0 ................ positive
green yellow red | red yellow green
So with our skewed data data_set={-1,-1,-2,-2,-2,-2,-3,-4,1,5,8,13} what I do is mirror the the extreme value. In this case 13, so now data_set={-13,-1,-1,-2,-2,-2,-2,-3,-4,1,5,8,13} Notice the additional -13 element. I assume you have a button to enact this macro so I store the extra -13 in a cell that is underneath the button so even though its there it isn't visible (yeah I know they can move the button etc, but it was the easiest thing I could think of)
Well that's all well and good green maps to 13 AND -13 but the color gradient is based on percentiles (in fact the color bar code uses the 50th percentile to determine the midpoint, or in our case where the yellow section is)
Selection.FormatConditions(1).ColorScaleCriteria(2).Value = 50
so with our distribution {-13,-1,-1,-2,-2,-2,-2,-3,-4,1,5,8,13} we could start seeing the yellow in the positive range around the number 8.5 Since 8.5 is 50th percentile. but in the neg range (even if we add a mirrored -13) the 50th percentile is -2, so our yellow in the negative range would start at 2!! Hardly ideal. just like pnuts mentioned, but we are getting closer. if you have fairly symmetric data this issue won't be present, but again we are looking at worst case of skewed datasets
What I did next is statistically match the midpoints....or at least their colors. So since our extreme value (13) is in the positive range we leave the yellow at the 50th percentile and try to mirror it to the negative range by changing what percentile the yellow color appears at (if the negative range had the extreme value we would leave the yellow at that 50th percentile and try to mirror it to the positive range). That means in our negative range we want to shift our yellow (50th percentile) from -2 to a number around -8.5 so it matches the positive range. I wrote a function called
Function iGetPercentileFromNumber(my_range As Range, num_to_find As Double) That does just that! More Specifically it takes a range and reads the values into an array. It then adds num_to_find to the array and figures out what percentile num_to_find belongs to as an integer 0-100 (hence the i in the function name). Again using our example data we would call something like
imidcolorpercentile = iGetPercentileFromNumber(negrange with extra element -13, -8.5)
Where the -8.5 is the negative(50th percentile number of positive range = 8.5). Don't worry the code automatically supplies the ranges and the numbers, this is just for your understanding. The function would add -8.5 to our array of negative values {-13,-1,-1,-2,-2,-2,-2,-3,-4,-8.5} then figure out what percentile it is.
Now we take that percentile and pass it in as the midpoint for our negrange conditional formatting. so we changed the yellow from 50th percentile
Selection.FormatConditions(1).ColorScaleCriteria(2).Value = 50
to our new value
Selection.FormatConditions(1).ColorScaleCriteria(2).Value = imidcolorpercentile 'was 50
which now deskewed the colors!! we have basically created a symmetric in appearance color bar. Even if our numbers are far from symmetric.
Ok, I know that was a TON to read and digest. but here are the main takeaways this code
- uses full 3-color conditional formatting (not simply setting the two extreme colors the same to look like abs value)
- creates symmetric color ranges by using a obstructed cell (say under a button) to hold the extreme values
- uses statistical analysis to match the color gradients even in skewed data sets
both steps are necessary and neither one on its own is sufficient to create a true mirror color scale
Since this solution requires statistical analysis of the data set, you would need to run it again any time you changed a number (which was actually the case before, I just never said it)
and now the code. Put it in vba or some other highlighting program. It is nearly impossible to read as is ..... takes deep breath
Sub main()
Dim Rng As Range
Dim Cell_under_button As String
Set Rng = Range("A1:H10") 'change me!!!!!!!
Cell_under_button = "A15"
Call AbsoluteValColorBars(Rng, Cell_under_button)
End Sub
Function iGetPercentileFromNumber(my_range As Range, num_to_find As Double)
If (my_range.Count <= 0) Then
Exit Function
End If
Dim dval_arr() As Double
'this is one bigger than the range becasue we will add "num_to_find" to it
ReDim dval_arr(my_range.Count + 1)
Dim icurr_idx As Integer
Dim ipos_num As Integer
icurr_idx = 0
'creates array of all the numbers in your range
For Each cell In my_range
dval_arr(icurr_idx) = cell.Value
icurr_idx = icurr_idx + 1
Next
'adds the number we are searching for to the array
dval_arr(icurr_idx) = num_to_find
'sorts array in descending order
dval_arr = BubbleSrt(dval_arr, False)
'if match_type is 0, MATCH finds an exact match
ipos_exact = Application.Match(CLng(num_to_find), dval_arr, 0)
'there is a runtime error that can crop up when num_to_find isn't formated as long
'so we converted it, if it was a double we may not find an exact match so ipos_Exact
'may fail. now we have to find the closest numbers below or above clong(num_to_find)
'If match_type is -1, MATCH finds the value <= num_to_find
ipos_small = Application.Match(CLng(num_to_find), dval_arr, -1)
If (IsError(ipos_small)) Then
Exit Function
End If
'sorts array in ascending order
dval_arr = BubbleSrt(dval_arr, True)
'now we find the index of our mid color point
'If match_type is 1, MATCH finds the value >= num_to_find
ipos_large = Application.Match(CLng(num_to_find), dval_arr, 1)
If (IsError(ipos_large)) Then
Exit Function
End If
'barring any crazy errors descending order = reverse order (ascending) so
ipos_small = UBound(dval_arr) - ipos_small
'to minimize color error we pick the value closest to num_to_find
If Not (IsError(ipos_exact)) Then
'barring any crazy errors descending order = reverse order (ascending) so
'since the index was WRT descending subtract that from the length to get ascending
ipos_num = UBound(dval_arr) - ipos_exact
Else
If (Abs(dval_arr(ipos_large) - num_to_find) < Abs(dval_arr(ipos_small) - num_to_find)) Then
ipos_num = ipos_large
Else
ipos_num = ipos_small
End If
End If
'gets the percentile as an integer value 0-100
iGetPercentileFromNumber = Round(CDbl(ipos_num) / my_range.Count * 100)
End Function
'fairly well known algorithm doesn't need muxh explanation
Public Function BubbleSrt(ArrayIn, Ascending As Boolean)
Dim SrtTemp As Variant
Dim i As Long
Dim j As Long
If Ascending = True Then
For i = LBound(ArrayIn) To UBound(ArrayIn)
For j = i + 1 To UBound(ArrayIn)
If ArrayIn(i) > ArrayIn(j) Then
SrtTemp = ArrayIn(j)
ArrayIn(j) = ArrayIn(i)
ArrayIn(i) = SrtTemp
End If
Next j
Next i
Else
For i = LBound(ArrayIn) To UBound(ArrayIn)
For j = i + 1 To UBound(ArrayIn)
If ArrayIn(i) < ArrayIn(j) Then
SrtTemp = ArrayIn(j)
ArrayIn(j) = ArrayIn(i)
ArrayIn(i) = SrtTemp
End If
Next j
Next i
End If
BubbleSrt = ArrayIn
End Function
Sub AbsoluteValColorBars(Rng As Range, Cell_under_button As String)
negrange = ""
posrange = ""
'deletes existing rules
Rng.FormatConditions.Delete
'makes a negative and positive range
For Each cell In Rng
If cell.Value < 0 Then
' im certain there is a better way to get the column character
negrange = negrange & Chr(cell.Column + 64) & cell.Row & ","
Else
' im certain there is a better way to get the column character
posrange = posrange & Chr(cell.Column + 64) & cell.Row & ","
End If
Next cell
'removes trailing comma
If Len(negrange) > 0 Then
negrange = Left(negrange, Len(negrange) - 1)
End If
If Len(posrange) > 0 Then
posrange = Left(posrange, Len(posrange) - 1)
End If
'finds the data extrema
most_pos = WorksheetFunction.Max(Range(posrange))
most_neg = WorksheetFunction.Min(Range(negrange))
'initial values
neg_range_percentile = 50
pos_range_percentile = 50
'if the negative range has the most extreme value
If (most_pos + most_neg < 0) Then
'put the corresponding positive number in our obstructed cell
Range(Cell_under_button).Value = -1 * most_neg
'and add it to the positive range, to reskew the data
posrange = posrange & "," & Cell_under_button
'gets the 50th percentile number from neg range and tries to mirror it in pos range
'this should statistically skew the data
the_num = WorksheetFunction.Percentile_Inc(Range(negrange), 0.5)
pos_range_percentile = iGetPercentileFromNumber(Range(posrange), -1 * the_num)
Else
'put the corresponding negative number in our obstructed cell
Range(Cell_under_button).Value = -1 * most_pos
'and add it to the positive range, to reskew the data
negrange = negrange & "," & Cell_under_button
'gets the 50th percentile number from pos range and tries to mirror it in neg range
'this should statistically skew the data
the_num = WorksheetFunction.Percentile_Inc(Range(posrange), 0.5)
neg_range_percentile = iGetPercentileFromNumber(Range(negrange), -1 * the_num)
End If
'low red high green for positive range
Call addColorBar(posrange, False, pos_range_percentile)
'high red low green for negative range
Call addColorBar(negrange, True, neg_range_percentile)
End Sub
Sub addColorBar(my_range, binverted, imidcolorpercentile)
If (binverted) Then
'ai -> array ints
adcolor = Array(8109667, 8711167, 7039480)
' green , yellow , red
Else
adcolor = Array(7039480, 8711167, 8109667)
' red , yellow , greeb
End If
Range(my_range).Select
'these were just found using the record macro feature
Selection.FormatConditions.AddColorScale ColorScaleType:=3
Selection.FormatConditions(Selection.FormatConditions.Count).SetFirstPriority
'assigns a color for the lowest values in the range
Selection.FormatConditions(1).ColorScaleCriteria(1).Type = _
xlConditionValueLowestValue
With Selection.FormatConditions(1).ColorScaleCriteria(1).FormatColor
.Color = adcolor(0)
.TintAndShade = 0
End With
'assigns color to... midpoint of range
Selection.FormatConditions(1).ColorScaleCriteria(2).Type = _
xlConditionValuePercentile
Selection.FormatConditions(1).ColorScaleCriteria(2).Value = imidcolorpercentile 'originally 50
With Selection.FormatConditions(1).ColorScaleCriteria(2).FormatColor
.Color = adcolor(1)
.TintAndShade = 0
End With
'assigns colors to highest values in the range
Selection.FormatConditions(1).ColorScaleCriteria(3).Type = _
xlConditionValueHighestValue
With Selection.FormatConditions(1).ColorScaleCriteria(3).FormatColor
.Color = adcolor(2)
.TintAndShade = 0
End With
End Sub
I am going to borrow heavily from the answer of #barryleajo (won't hurt my feelings if you select that answer). As was stated in that answer the order of the conditional formatting is the key, start with the smallest absolute values and work your way up. The difference between that answer and this one is that there is no need to use an "and" statement, since the OP seems to indicate that all values within a certain range of absolute value should receive the same color format. Here is a small example:

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