Server Type Count
Enterprise 3
Standard 24
Enterprise Core 6
In Excel, I am looking for to check if server type (A2-A5) contains both 'Enterprise' and 'Enterprise Core' or just 'Enterprise'. If it contains both, then add the two numbers together, otherwise, just display the number for 'Enterprise'.
Perhaps just this:
=SUMIF(A:A,"Enterprise",B:B)+SUMIF(A:A,"Enterprise Core",B:B)
If it doesn't have both .. then it'll only find one to add ..
=SUMIF(A2:A5,"Enterprise*",B2:B5)
You can use the asterisk as a wildcard in sumif & countif.
Related
I'm building a monitoring system that takes a log (where people register their work in a set format) and returns a counter, which I can use for analysis. The monitor and log are two separate workbooks. The log has entries like this: INITALS;DATE;HOUR:RESULT|
Each cell can contain multiple entries.
My first attempt was to do a simple countif and look for a string (note that I use ; instead of , in formulas since I work on a Dutch excel):
=COUNTIF('LOCATION'!Table[LOG];"*NB;??/??/????;??:??:#A*|*")
This worked fine, but the formula only counted the number of cells where this string was present, not the actual number of occurences. I then tried this solution.
=SUM(LEN('LOCATION'!Tabel13[LOG])-LEN(SUBSTITUTE('LOCATION'!Tabel13[LOG];"NB";"")))
This indeed counted the number of times "NB" was present in the LOG. However, when I tried to use the original search string, this solution stopped working:
=SUM(LEN('LOCATION'!Tabel13[LOG])-LEN(SUBSTITUTE('LOCATION'!Tabel13[LOG];"*NB;??/??/????;??:??:#A*|*";"")))
It seems to me that SUM does not recognize symbols like ? or * which are necessary to define the correct search string. Where did I go wrong? Or can this be solved in another way? I can still look into VBA, but the workbooks are slow as hell already.
"?" and "*" are wildcards. Some functions support these (like COUNTIFS()) where others don't. Like you found out, SUBSTITUTE() does not.
Here is one way to count, assuming ms365:
Formula in C1:
=REDUCE(0,A1:A2,LAMBDA(a,b,a+LET(X,SEQUENCE(LEN(b)),SUM(--(IFERROR(SEARCH("NB;??/??/????;??:??:#A*|*",b,X),0)=X)))))
Note: I removed the asterisk in front of "NB" just to make searching for a position valid in comparison to what i called variable "X".
I'm trying to extract sections of text from an Excel cell then put some of those parts together.
Using LEFT, MID, TRIM, SUBSTITUTE & REPT (mainly helped by contributions on this site), I've managed to split each section down (they are separated by dashes) into it's constituent parts.
I've managed to do the easy bit which is to add sections 2 and 3 together (separated by dashes) using =L2&"-"&M2&"-"&.
I want to add the last section but the problem I have is that some of the names have 5 sections, some 6 and some 7 so I need a formula that says something like "If cells 9 & 10 are empty, use cell 8, if cell 10 is empty use 9 and if neither 9 or 10 are empty, use 10".
I've had a go with IF and AND but keep getting error messages, mainly about too many arguments. Any help would be much appreciated, I still quite a newbie to formula writing.
Assuming sections 8,9 and 10 are in columns R:T, you could use:
=LOOKUP(2,1/(R2:T2<>""),R2:T2)
I would like to count the number of times a specific number lies between multiple ranges.
For instance,
Specific number: 2.5 (let's say this one is in AD1)
J3=14
K3=22
L3=0
M3=6
N3=6
O3=14
P3=2
Q3=8
I need to find how many times 2.5 is between:
J3&K3
L3&M3
N3&O3
P3&Q3
The reason I would like a formula for this is because I have many "specific numbers" that there are many numbers that I need to test within the same range.
I know I can combine multiple CountIf, but the formula would be way too long.
I remember I can use Sum(CountIf("INSERTFORMULA")) but I think somehow using a combination of Sum(CountIf(Median())) will be simpler to read
SUM(Countif(MEDIAN($AD$1,J3,K3)=$AD$1,TRUE),MEDIAN($AD$1,L3,M3)=$AD$1,TRUE),MEDIAN($AD$1,N3,O3)=$AD$1,TRUE),MEDIAN($AD$1,P3,Q3)=$AD$1,TRUE))
Expected result: 2 (i.e. between L3&M3 and between P3&Q3)
Try: (Edited to correct typo)
=SUMPRODUCT(($AD$1>=INDEX(J3:Q3,1,N(IF(1,{1,3,5,7}))))*($AD$1<=INDEX(J3:Q3,1,N(IF(1,{2,4,6,8})))))*emphasized text*
The N(IF(1,{array})) is a method of returning discontinuous elements of an array using the INDEX function.
Depending on whether you want to include/exclude the bounds of the ranges when you write between, you may want to remove the equal = sign from the comparisons.
Try:
=SUMPRODUCT((J3:P3<=AD1)*(K3:Q3>=AD1))
divide your formula on two parts:
first one - just calculate MEDIAN($AD$1,J3,K3) and put it in J4 (for example), then drag and copy this formula on the all raw (so in K4 will be MEDIAN($AD$1,K3,L3), and so on)
second one - just summarize raw 4 with formulas - SUM(A4:AA4)
it takes more space on the sheet, but more simple for creation and checking.
I would like to ask for your help with the formulation of a formula in Excel in order to compare the total number of search results upon using different sets of separator characters.
As I have multiple columns with content, as in the example below, I thought it would be possible to Count the search results in some way and do this for each column separately ( I would actually prefer to treat each column separately).
A
1 L-516-S-221-S-223
2 H-140.STR3
3 ST0 XP 23-9
4 etc.......
Preferably, I would like to use a varying a set of separator characters in order to determine the impact on the number of search results based on this set of separator characters. Logically, with an increasing number of separators more results will be returned (depending on separators included in the cell values of course).
The set of characters that I would like to experiment with is: “-_ .,;: “
Hopefully this makes sense and someone is able to help me out. Thank you.
Kind regards,
P
In your example - on its own will detect all three instances but for an overview you might construct a grid (say B1:H1 of your separators, including a space rather than an empty cell) and ColumnA each column in turn (maybe via links) then a formula in B2 such as:
=--ISNUMBER(FIND(B$1,$A2))
copied across to ColumnH and down to suit.
Alternative formula (for different question):
=IF(LEN($A2)-LEN(SUBSTITUTE($A2,B$1,""))>0,LEN($A2)-LEN(SUBSTITUTE($A2,B$1,""))+1,0)
Assumes, for example, no trailing spaces and separators are always separated. Results are not necessarily cumulative.
I've found some tools that can do what I want, but despite trying various options I can't work out how to put them in my existing formula!
I'm trying to generate an invoice reference number, which would look like 'ABC000012' - with the first row being ABC000001 and increasing in number as each row is added. I can currently generate 'ABC1' and so on, but can't work out how to add the preceding 0s.
I'm currently using CONCATENATE as follows:
=IF(ISBLANK(B2),,CONCATENATE("ABC",(ROW(1:1))))
What do I need to add to this, and where, in order to get the references I'm looking for?
I'm also happy to be advised that I should change the whole formula if there's something different that will work better
Thanks
Use TEXT() to set the preceding 0:
=IF(ISBLANK(B2),"",CONCATENATE("ABC",TEXT(ROW(1:1),"000000")))
=IF(ISBLANK(B2),"","ABC"&RIGHT("000000"&ROW(1:1),6))
This is based off Scott Craner's answer. The difference is that is will limit the number of digits in your invoice to 6 characters. if you want it to always be 8 characters long change the 6 to an 8 and increase the number of 0 between the " ". Alternatively you could also do:
=IF(ISBLANK(B2),"","ABC"&RIGHT(rept(0,6)&ROW(1:1),6))
In the above formula to change the number of digits n the invoice number, you would need to change both 6's
Caveat:
If there is a blank cell in the middle of your list, that number will be skipped for each blank cell. To avoid this, you will need a different counting method than row(1:1).