Trying to translate BASIC code written in the 1990's to Python. I keep coming across two symbols, ! (exclamation mark) and . (period). I can't find any documentation online on what they do.
I have the code running but some of the outputs are not as expected - I am wondering if these might be the issue as I previously thought that the period may just be a typo for a multiplication.
Examples:
|
v
QWLOST = (((TW-TDAO)/(TWRT-TDAOR))^1.25)*((VISR/VIS)^0.25).(PW+PE)*DT
TFAVE = (TTO+TBO)/2!
^
|
In case anyone else in the future needs to know this.
! - defines a single
. - Was just a typo for * (multiplication)
I tried a few things in bwBasic (in Linux, in case that's relevant!).
bwBASIC: list
10: for i = 1 to 20
20: print i, ., . - i
30: next i
40: print ".="; .
This gave me:
bwBASIC: run
1 20 19
2 20 18
3 20 17
4 20 16
5 20 15
6 20 14
7 20 13
8 20 12
9 20 11
10 20 10
11 20 9
12 20 8
13 20 7
14 20 6
15 20 5
16 20 4
17 20 3
18 20 2
19 20 1
20 20 0
.= 20
Which would suggest that . (in bwBasic in any case) is the max number in a for loop.
Currently for a task, I am working with input files which give Matrix related test cases (Matrix Multiplication) i.e., example of an input file ->
N M
1 3 5 ... 6 (M columns)
....
5 4 2 ... 1 (N rows)
I was using simple read() to access them till now, but this is not efficient for large files of size > 10^2.
So I wanted to know is there some way to use processes to do this in parallel.
Also I was thinking of using multiple IO readers based on line, so then each process could read different segments of the file but couldn't find any helpful resources.
Thank you.
PS: Current code is using this:
io:fread(IoDev, "", "~d")
Did you consider to use re module? I did not make a performance test, but it may be efficient. In the following example I do not use the first "M N" line. So I did not put it in the matrix.txt file.
matrix file:
1 2 3 4 5 6 7 8 9
11 12 13 14 15 16 17 18 19
21 22 23 24 25 26 27 28 29
31 32 33 34 35 36 37 38 39
I made the conversion in the shell
1> {ok,B} = file:read_file("matrix.txt"). % read the complete file and store it in a binary
{ok,<<"1 2 3 4 5 6 7 8 9\r\n11 12 13 14 15 16 17 18 19\r\n21 22 23 24 25 26 27 28 29\r\n31 32 33 34 35 36 37 38 39">>}
2> {ok,ML} = re:compile("[\r\n]+"). % to split the complete binary in a list a binary, one for each line
{ok,{re_pattern,0,0,0,
<<69,82,67,80,105,0,0,0,0,0,0,0,1,8,0,0,255,255,255,255,
255,255,...>>}}
3> {ok,MN} = re:compile("[ ]+"). % to split the line into binaries one for each integer
{ok,{re_pattern,0,0,0,
<<69,82,67,80,73,0,0,0,0,0,0,0,17,0,0,0,255,255,255,255,
255,255,...>>}}
4> % a function to split a line and convert each chunk into integer
4> F = fun(Line) -> Nums = re:split(Line,MN), [binary_to_integer(N) || N <- Nums] end.
#Fun<erl_eval.7.126501267>
5> Lines = re:split(B,ML). % split the file into lines
[<<"1 2 3 4 5 6 7 8 9">>,<<"11 12 13 14 15 16 17 18 19">>,
<<"21 22 23 24 25 26 27 28 29">>,
<<"31 32 33 34 35 36 37 38 39">>]
6> lists:map(F,Lines). % map the function to each lines
[[1,2,3,4,5,6,7,8,9],
[11,12,13,14,15,16,17,18,19],
[21,22,23,24,25,26,27,28,29],
[31,32,33,34,35,36,37,38,39]]
7>
if you want to check the matrix size, you can replace the last line with:
[[NbRows,NbCols]|Matrix] = lists:map(F,Lines),
case (length(Matrix) == NbRows) andalso
lists:foldl(fun(X,Acc) -> Acc andalso (length(X) == NbCols) end,true,Matrix) of
true -> {ok,Matrix};
_ -> {error_size,Matrix}
end.
is there some way to use processes to do this in parallel.
Of course.
Also I was thinking of using multiple IO readers based on line, so
then each process could read different segments of the file but
couldn't find any helpful resources.
You don't seek to positions in a file by line, rather you seek to byte positions. While a file may look like a bunch of lines, a file is actually just one long sequence of characters. Therefore, you will need to figure out what byte positions you want to seek to in the file.
Check out file:position, file:pread.
I have this data in Excel.
A B C
--------------------------------------
Line Number Value #1 Value #2
1 21 35
2 21 27
3 21 18
4 10 47
5 50 5
6 37 68
7 10 21
8 75 21
I tried to calculate the total "21" based on odd line number. In this situation, the answer should be 3. However, neither" IF(MOD(A1:A8,2)=1,COUNTIF(B1:C8,21)) " nor " {IF(MOD(A1:A8,2)=1,COUNTIF(B1:C8,21))} "worked and Google didn't yield anything helpful. Could anyone help me? Thanks!!
This works for odd lines:
=SUM(COUNTIF(A:B,21)-SUMPRODUCT((A:B=21)*(MOD(ROW(A:B),2)=0)))
there may be a better way of writing this formula.
Use this to count even lines:
=SUMPRODUCT((A:B=21)*(MOD(ROW(A:B),2)=0))
While Reading the files in python using
f = open ("filename.txt")
and accessing the data with
f.read(1)
and finally finding the position of stream usibg
f.tell()
for every step; We get a continous numbering starting from 0 to the current position.
The problem i am facing is that i am actually getting a random number as f.tell() for some positions and then continung the numbers.
For examle, the f.tell() outputs look something ike the following
0
1
2
3
133454568679978
6
7
8...
Any idea why this is happening?
My Code :
f=open("temp_mcompress.cpp")
current = ' '
while current != '' :
print(f.tell())
current = f.read(1)
f.close()
Temp_mcompress.cpp file :
#include <iostream>
int main(int a)
{
}
OUtput :
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
18446744073709551636
18446744073709551638
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
18446744073709551655
40
41
43
44
It seems I might have found the problem which may still be applicable to python 3.x:
source: http://docs.python.org/2.4/lib/bltin-file-objects.html
tell()
Return the file's current position, like stdio's ftell().
Note: On Windows, tell() can return illegal values (after an fgets())
when reading files with Unix-style line-endings. Use binary mode
('rb') to circumvent this problem.
static void main(args){
System.in.withReader {
def input = it.readLine()
for(def i = 0; i < input; i++){
println i
}
}
}
The source code..simple one I guess but dont know why it is printing till 48..here is the output if the argument supplied is 1.
0
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
what could be the problem?
Tartar is right, the solution is to change
def input = it.readLine()
To
def input = Integer.parseInt( it.readLine() )
Or (more Groovy)
def input = it.readLine().toInteger()
(the reason it is using the ASCII value of 1 is that groovy will convert single char strings to their ASCII value if you try to coerce them into an int... It has been argued that this is confusing, and it may change in future versions of groovy, but for now it remains for backward compatibility reasons)
ascii value for character 1 is 49. so convert input to integer maybe?