The cronjob does not pipe the output from another script to a file but it works I execute it (not same user, chmod for both files is set to 777).
#! /bin/sh
. /disk2/etc/env_cron
SUBJ="Test"
TEXT=/disk2/home/user/mailtxt
ADDR="mail#domain.com"
echo -e `date` > $TEXT
echo -e "1\n\n\nq" | menu >> $TEXT
mutt -s "$SUBJ" -i $TEXT -- $ADDR < /dev/null
I want it to pipe "echo -e 1\n\n\nq" to the script Menu and in turn get the output in a file. The output from Menu will just be text.
The problem (as suggested) was that the cronjob did not have the script 'menu' in it's path. Changing "menu" in the script to the absolute path fixed it.
echo -e "1\n\n\nq" | /folder/folder/menu >> $TEXT
EDIT: Do not forget to set the correct permissions on the textfile if the cronjob is run by another user.
Related
I want to echo the following line at the end of ~/.profile file using tee command:
export PATH="$HOME/.local/bin:$PATH"
To do this my bash script looks like this
#!/bin/bash
path_env="export PATH="$HOME/.local/bin:$PATH""
echo $path_env| sudo tee -a $HOME/.profile > /dev/null
But whenever I am executing the script it is also executing $PATH and $HOME value and inserts that in ~./profile file which I do not want. I only want the exact line to be passed by the bash script instead of replacing $PATH and $HOME with its own values.
I only want the exact line to be passed by the bash script instead of replacing $PATH and $HOME with its own values.
Och, right, so do not expand it. Quoting.
path_env='export PATH="$HOME/.local/bin:$PATH"'
echo "$path_env" | sudo tee -a "$HOME/.profile" > /dev/null
I've placed a bash file inside .zshrc and tried all different ways to run it every time I open a new terminal window or source .zshrc but no luck.
FYI: it was working fine on .bashrc
here is .zshrc script:
#Check if ampps is running
bash ~/ampps_runner.sh & disown
Different approach:
#Check if ampps is running
sh ~/ampps_runner.sh & disown
Another approach:
#Check if ampps is running
% ~/ampps_runner.sh & disown
All the above approaches didn't work (meaning it supposes to run an app named ampps but it doesn't in zsh.
Note: It was working fine before switching to zsh from bash. so it does not have permission or syntax problems.
Update: content of ampps_runner.sh
#! /usr/bin/env
echo "########################"
echo "Checking for ampps server to be running:"
check=$(pgrep -f "/usr/local/ampps" )
#[ -z "$check" ] && echo "Empty: Yes" || echo "Empty: No"
if [ -z "$check" ]; then
echo "It's not running!"
cd /usr/local/ampps
echo password | sudo -S ./Ampps
else
echo "It's running ..."
fi
(1) I believe ~/.ampps_runner.sh is a bash script, so, its first line should be
#!/bin/bash
or
#!/usr/bin/bash
not
#! /usr/bin/env
(2) Then, the call in zsh script (~/.zshrc) should be:
~/ampps_runner.sh
(3) Note: ~/.ampps_runner.sh should be executable. Change it to executable:
$ chmod +x ~/ampps_runner.sh
The easiest way to run bash temporarily from a zsh terminal is to
exec bash
or just
bash
Then you can run commands you previously could only run in bash. An example
help exec
To exit
exit
Now you are back in your original shell
If you want to know your default shell
echo $SHELL
or
set | grep SHELL=
If you want to reliably know your current shell
ps -p $$
Or if you want just the shell name you might use
ps -p $$ | awk "NR==2" | awk '{ print $4 }' | tr -d '-'
And you might just put that last one in a function for later, just know that it is only available if it was sourced in a current shell.
whichShell(){
local defaultShell=$(echo $SHELL | tr -d '/bin/')
echo "Default: $defaultShell"
local currentShell=$(ps -p $$ | awk "NR==2" | awk '{ print $4 }' | tr -d '-')
echo "Current: $currentShell"
}
Call the method to see your results
whichShell
If I do this:
#!/bin/bash
gnome-terminal --window-with-profile=KGDB -x bash -c 'VAR1=$(tty);
echo $VAR1; bash'
echo $VAR1
How can I get the last line from this script to work? I.e., be able to access the value of $VAR1 (stored on the new terminal window) from the original one? Currently, while the first echo is working, the last one only outputs an empty line.
The short version is that you can't share the variable. There's no shared channel for that.
You can write it to a file/pipe/etc. and then read from it though.
Something like the following should do what you want:
#!/bin/bash
if _file=$(mktemp -q); then
gnome-terminal --window-with-profile=KGDB -x bash -c 'VAR1=$(tty); echo "$VAR1"; declare -p VAR1 > '\'"$_file"\''; bash'
cat "$_file"
. "$_file"
echo "$VAR1"
fi
SOLVED! add #!/bin/bash at the top of all my scripts in order to make use of bash extensions. Otherwise it restricts itself to POSIX shell syntax. Thanks Barmar!
Also, I'll add that I had trouble with gpg decryption not working from cronjob after I got it executing, and the answer was to add the --no-tty option (no terminal output) to the gpg command.
I am fairly new to linux, so bear with me...
I am able to execute a simple script with crontab -e when logged in as ubuntu:
* * * * * /ngage/extract/bin/echoer.sh
and this bash script simply prints output to a file:
echo "Hello" >> output.txt
But when I try to execute my more complex bash script in exactly the same way, it doesn't work:
* * * * * /ngage/extract/bin/superMasterExtract.sh
This script called into other bash scripts. There are 4 scripts in total, which 3 levels of hierarchy. It goes superMasterExtract > masterExtract > (decrypt, unzip)
Here is the code for superMasterExtract.sh (top level):
shopt -s nullglob # ignore empty file
cd /str/ftp
DIRECTORY='writeable'
for d in */ ; do # for all directories in /str/ftp
if [ -d "$d$DIRECTORY" ]; then # if the directory contains a folder called 'writeable'
files=($d$DIRECTORY/*)
dirs=($d$DIRECTORY/*/)
numdirs=${#dirs[#]}
numFiles=${#files[#]}
((numFiles-=$numdirs))
if [ $numFiles -gt 0 ]; then # if the folder has at least one file in it
bash /ngage/extract/bin/masterExtract.sh /str/ftp ${d:0:${#d} - 1} # execute this masterExtract bash script with two parameters passed in
fi
fi
done
masterExtract.sh:
DATE="$(date +"%m-%d-%Y_%T")"
LOG_FILENAME="log$DATE"
LOG_FILEPATH="/ngage/extract/logs/$2/$LOG_FILENAME"
echo "Log file is $LOG_FILEPATH"
bash /ngage/extract/bin/decrypt.sh $1 $2 $DATE
java -jar /ngage/extract/bin/sftp.jar $1 $2
bash /ngage/extract/bin/unzip.sh $1 $2 $DATE
java -jar /ngage/extract/bin/sftp.jar $1 $2
echo "Log file is $LOG_FILEPATH"
decrypt.sh:
shopt -s nullglob
UPLOAD_FILEPATH="$1/$2/writeable"
DECRYPT_FOLDER="$1/decryptedFiles/$2"
HISTORY_FOLDER="$1/encryptHistory/$2"
DONE_FOLDER="$1/doneFiles/$2"
LOG_FILENAME="log$3"
LOG_FILEPATH="/ngage/extract/logs/$2/$LOG_FILENAME"
echo "DECRYPT_FOLDER=$DECRYPT_FOLDER" >> $LOG_FILEPATH
echo "HISTORY_FOLDER=$HISTORY_FOLDER" >> $LOG_FILEPATH
cd $UPLOAD_FILEPATH
for FILE in *.gpg;
do
FILENAME=${FILE%.gpg}
echo ".done FILE NAME=$UPLOAD_FILEPATH/$FILENAME.done" >> $LOG_FILEPATH
if [[ -f $FILENAME.done ]]; then
echo "DECRYPTING FILE=$UPLOAD_FILEPATH/$FILE INTO $DECRYPT_FOLDER/$FILENAME" >> $LOG_FILEPATH
cat /ngage/extract/.sftpPasswd | gpg --passphrase-fd 0 --output "$DECRYPT_FOLDER/$FILENAME" --decrypt "$FILE"
mv $FILE $HISTORY_FOLDER/$FILE
echo "MOVING FILE=$UPLOAD_FILEPATH/$FILE INTO $HISTORY_FOLDER/$FILE" >> $LOG_FILEPATH
else
echo "Done file not found!" >> $LOG_FILEPATH
fi
done
cd $DECRYPT_FOLDER
for FILE in *
do
mv $FILE $DONE_FOLDER/$FILE
echo "DECRYPTED FILE=$DONE_FOLDER/$FILE" >> $LOG_FILEPATH
done
If anyone has a clue why it refuses to execute my more complicated script, I'd love to hear it. I have also tried setting some environment variables at the beginning of crontab as well:
SHELL=/bin/bash
PATH=/sbin:/bin:/usr/sbin:/usr/local/bin:/usr/bin
MAILTO=jgardnerx85#gmail.com
HOME=/
* * * * * /ngage/extract/bin/superMasterExtract.sh
Note, I don't know that these are the appropriate variables for my installation or my script. I just pulled them off other posts and tried it to no avail. If these aren't the correct environment variables, can someone tell me how I can deduce the right ones for my particular application?
You need to begin your script with
#!/bin/bash
in order to make use of bash extensions. Otherwise it restricts itself to POSIX shell syntax.
If I run
grep -i "echo" *
I get the results I want, but if I try the following simple bash script
#search.sh
grep -i "$1" *
echo "####--DONE--####"
and I run it with sh -x search.sh "echo" I get the following error output:
' grep -i echo '*
: No such file or directory
' echo '####--DONE--####
####--DONE--####
How come? I'm on CentOS
Add the sha-bang line at the top of your script
#!/bin/bash
and after making it executable, run the script using
./search.sh "echo"
The "sh -x" should print the files that '*' matches. It looks like it's not matching any files. Are you maybe running it in a directory with no readable files?