I have 5000 rows. In column A I have the salesperson , in column B the buyer. I am trying to find out how many times each combination appear together. e.g. Did salesman Abe sell to Buyer Bob 33 times, to buyer Carl 19?
ok takes a few extra columns to accomplish this but here goes...screenshot attached first.
First you need to concatenate the two columns (A and B)you want to enumerate in column C (the formula will accommodate a string in case names column is first last with spaces etc.)
=$A2&" "&$B2
Then in column D use the following formula to determine whether or not the name combination is duplicated but only true for one instance. I'll explain why in a second.
=$C1<>$C2
Then in column E count the matches.
=COUNTIF($C:$C,$C2)
After doing all that, filter results by "True" tally for all the True columns is the number of matching rep/customer relationships.
Related
I am creating a spreadsheet with a list of 90 names, these names need to match up for one to one meetings and this will be repeating many times. I need to randomize these pairings and not have any repeated matches.
There are only roughly 4000 combinations of numbers 1-90 giving you a rough total of 44 different rounds of meetings without duplicating any meetings.
I used the below website to generate the possible numbers and pasted them into an excel spreadsheet.
https://numbergenerator.org/randomnumbergenerator/combinations-generator#!numbers=2&lines=5000&low=1&high=90&unique=false&order_matters=false&csv=&oddeven=&oddqty=0&sorted=false&sets=
You are not starting from the first row but from the second row in this example
After this you will have column A with numbers 1-90 going down rows.
Column B will have names.
Column C will have =MOD(ROWS($D$2:D2)-1,90)+1 formula to make numbers 1-90 appear and once you get to 90 they will start back at 1
Column D will have formula =VLOOKUP( LEFT(C3,SEARCH(" ",C3,1))+0, $A$3:$B$92, 2, FALSE) to extract first number that you got from the website.
Column E will have formula =VLOOKUP( MID(C3,SEARCH(" ",C3,1),LEN(C3))+0, $A$3:$B$92, 2, FALSE) to extract second number that you got from the website.
A picture has been attached for clarification.
I am trying to create a formula that will count the number of "Overdue" people instead of "Overdue" cells. Each person has the multiple rows with their name in it. The criteria to determine if it's "overdue" is:
-Column F and G are not within 3 years
-Column G are blank
-Column F = 0 and Column G are not within 3 years
The following code counts the criteria accurately. And doesn't account for duplicate names.
=SUM(COUNTIFS(TT[Fiscal Law 301 CBT],"<"&TODAY()-1065,TT[Fiscal Law 301 CBT],">"&TODAY()-1095,TT[Fiscal Law In-Residence],"<"&TODAY()-1065,TT[Fiscal Law In-Residence],">"&TODAY()-1095),COUNTIFS(TT[Fiscal Law In-Residence],"",TT[Fiscal Law 301 CBT],"<"&TODAY()-1065,TT[Fiscal Law 301 CBT],">"&TODAY()-1095))
The formula I want should count based on the criteria above and check column Z TT[Name] for duplicates and count them only once. And also count unique values once.
I just thought of another approach to this problem. What if I use the formula I have to create an Array, have another formula count the number of duplicates in Column Z from that Array, and subtract the two numbers.
This way should get me the correct number, i will still need assistance creating the second formula.
What you are after is a distinct count. Excel has a function for that in the new Dynamic Array function set, which is in Office 365 Insider builds but not available to everyone. Right now, a distinct count requires a few tricks.
For example, you can create a pivot table with the names in the rows, filter the table to include only values where column X = Overdue and use a CountA() on the result rows.
You are close, but not quite there.
Use a countifs formula like above. Then, create a column next to it with the logic if(countcell>0, 1, 0). This will return 1 if the person has at least 1 book overdue, and 0 otherwise. Then, take the sum of that column.
Formulas
I have provided a screenshots of the code that we would use (the E and F columns are dates). As you can see, the G column counts how many books are overdue. The H column provides a 1 if at least 1 book is overdue for each user. Then, we can simply sum the H column to find the total number of users with overdue books.
If this helps you, please consider choosing this as the answer.
I have two values in different columns. Column A have Department name i.e. HR, Admin and Ops. and column be have date. I want Unique ID in column C based on Combination of Column A & B and Unique number at the end.
Unique ID: HR-Aug-16-1
Admin-Aug-16-1
this number will be repeat till the combination of Column A and B repeated 50 times after 50 times last value will be increased by +1. i.e.
HR-Aug-16-2
Admin-Aug-16-2
Right now I am using formula,
=A1&"-"&TEXT(B1,"mmm-yy")&"-1"
In C1 as a standard formula,
=A1&"-"&TEXT(B1,"mmm-yy")&CHAR(45)&INT((SUMPRODUCT(--(A$1:A1&TEXT(B$1:B1, "mmm-yy")=A1&TEXT(B1, "mmm-yy")))-1)/5)+1
I've set this to repeat after 5 for an example. I'll leave it to you to change the modifier to 50. Fill down as necessary.
For example, I need to create a merit list of few student based on total marks (column C), then higher marks in math (column B) -
A B C D
-------------------------
Student1 80 220 1
Student2 88 180 3
Student3 90 180 2
Expected merit position is given in column D.
I can use RANK function but I can only do that for one column (total number). If total number of multiple student is equal, I could not find any solution of this.
You can try this one in D1
=COUNTIF($C$1:$C$99,">"&C1)+1+SUMPRODUCT(--($C$1:$C$99=C1),--($B$1:$B$99>B1))
and then copy/fill down.
let me know if this helps.
Explanation
Your first criteria sits in column C, and the second criteria sits in Column B.
Basically, first it is counting the number of entries ($C$1:$C$99) that are bigger than the entry itself ($C1). For the first one in the ranking, you will get zero, therefore you need to add 1 to each result (+1).
Until here, you will get duplicate rankings if you have the same value twice. Therefore you need to add another argument to do some extra calculations based on the second criteria:
To resolve the tie situation, you need to sumproduct two array formulas and add the result to the previous argument, the goal is to find the number of entries that are equal to this entry with $C$1:$C$99=C1 and have a bigger value in the second criteria column $B$1:$B$99>B1:
you add -- to convert TRUE and FALSE to 0s and 1s so that you can multiply them:
SUMPRODUCT(--($C$1:$C$99=C1),--($B$1:$B$99>B1))
the first array is to see how many ties you have in the first criteria. And the second array is to find the number of bigger values than the entry itself.
Note you can add as many entries as you like to your columns, but remember to update the ranges in the formula, currently it is set to 99, you can extend it to as many rows as you want.
Sometimes a helper column will provide a quick and calculation-efficient solution. Adding the math marks to the total marks as a decimal should produce a number that will rank according to your criteria. In an unused column to the right, use this formula in row 2,
=C2+B2/1000
Fill down as necessary. You can now use a conventional RANK function on this helper column like =RANK(D2, D$2:D$9) for your ranking ordinals.
Very simple (or, at least, much more simpler that the one provided by the best answer) 'math' solution: do a linear combination with weights.
Do something like
weighted_marks = 10*colC + colB
then sort weighted marks using simple rank function.
It does solve your problem, bulding the ranking you need.
If you don't like to limit the number of rows or the numbers used in the criteria, Jeeped's approach can be extended. You can use the following formulas in cells D2 to L2, assuming that there are three criteria, the first one in column A, the second one in column B, and the third one in column C:
=RANK($A2,$A:$A,1)
=RANK($B2,$B:$B,1)
=D2*2^27+E2
=RANK(F2,F:F,1)
=RANK($C2,$C:$C,1)
=G2*2^27+H2
=RANK(I2,I:I,1)
=J2*2^27-ROW()
=RANK(K2,K:K,0)
The formulas have to be copied down. The result is in column L. Ties are broken using the row number.
If you like to add a fourth criterion, you can do the following after having the formulas above in place:
Add the new criterion between columns C and D.
Insert three new columns between columns I and J.
Copy columns G:I to the new columns J:L.
Copy column G to column M, overwriting its content.
Change the formula in column L to point to the new criterion.
The factor 2^27 used in the formulas balances the precision of 53 bits available in double-precision numbers. This is enough to cover the row limit of current versions of Excel.
I have several columns of data in my Excel spreadsheet.
Originally, I had two different spreadsheets, as they were generated from reports in a software application.
One of the spreadsheets contains the names of individuals who have had transactions with us in the past year. The other spreadsheet contains the names and the phone numbers. I copied and pasted the columns with the names and phone numbers into my spreadsheet with just the names of people who have purchased something from us in the past year.
My ultimate goal is to extract the names and phone numbers of only the names that have purchased something in the past year.
My column for the past year contains 1,002 names, while my master customer list (with phone numbers) contains over 20,000 individuals. I need the phone numbers of all of the individuals that have purchased something from us in the past year, but I don't want to have to manually go through 1,000 names (and, essentially, 20,000+ to find the match).
If I can achieve my goal without having to use VBA, that would be great. If this is the only route I can take, then I will go that route, but I would like to avoid coding if possible. (This is simply due to time constraints.)
The VLOOKUP function is likely the best solution for you. From the Excel documentation, it:
Looks for a value in the leftmost column of a table, and then returns
a value in the same row from a column you specify. By default, the
table must be sorted in an ascending order.
Note well the implication of that last sentence: the column you're searching in (leftmost column of the lookup table) must be sorted in ascending order for this function to produce the correct results.
Taking a simple example, let's say you have Sheet1 in your Excel workbook with the following information:
A B C
1 Name Transactions Phone
2 Sally 3
3 Alice 5
4 Joe 2
5 Jon 1
You need to add their phone numbers to this sheet, from another workbook. Let's say your phone number information in the other workbook looks like this:
A B
1 Name Phone
2 Alice 2222222
3 Bill 3333333
4 Bob 4444444
5 Jim 5555555
6 Joe 6666666
7 Sally 7777777
8 Sue 8888888
9 Tom 9999999
Take the following steps to add the phone numbers to Sheet1 in the first workbook:
Copy the phone information into a blank sheet in the first workbook. Let's call this Sheet2 for this example.
Make sure the phone information is sorted ascending by the Name column (A), because that's the leftmost column and thus the lookup column.
In cell C2 of Sheet1 (the empty phone cell for Sally), enter: =VLOOKUP(A2, Sheet2!A$2:B$9, 2,FALSE).
Drag-copy this formula down to the remaining cells in the Phone column.
Result:
A B C
1 Name Transactions Phone
2 Sally 3 7777777
3 Alice 5 2222222
4 Joe 2 6666666
5 Jon 1 #N/A
Notes:
The second parameter (Table_array - the lookup data range) should not include the column headings. As you can see, it's Sheet2!A$2:B$9 so it includes the information from rows 2 to 9 in columns A and B.
The last parameter (Range_lookup) should be set to FALSE so you don't pick up the information from the closest match. Note how Jon has no matching phone number record, so his Phone is set to "#N/A" - otherwise he would have been assigned Joe's phone number since that's closest match to Jon.
Parameter documentation:
Lookup_value is the value to be found in the first column of the table, and can be a value, a reference, or a text string.
Table_array is a table of text, numbers, or logical values, in which data is retrieved. Table_array can be a reference to a range or
a range name.
Col_index_num is the column number in Table_array from which the matching value should be returned. The first column of values in
the table is column 1.
Range_lookup is a logical value: to find the closest match in the first column (sorted in ascending order) = TRUE or omitted; find
an exact match = FALSE.