I want to program a cell to calculate the number of days I have left before I meet a deadline.
I would like to do this without reference cells, unlike this tutorial.
An (incorrectly formatted) example of the kind of formula I want would be:=(3/2/2015-TODAY()), where 3/2/2015 is my deadline. This yields some negative serial number,-42051.00, which yields a #NUM! error when put into the DAY formula.
Any idea how to do this without putting TODAY() and 3/2/2015 into their own reference cells? I would like to use functions to keep these paraments completely embedded in the formula.
Right clock the cell with the answer and reformat it as NUMBER. You want to use the Days function not the date function.
=DATE(2015,3,2)-TODAY() is what you want, but I would recommend doing the date in a separate cell for a number of reasons and using "today()" in the formula.
EDIT: Anyone trying to find midpoints would use the date function in this case.
Also, as a general rule for people trying to subtract dates the two trouble shooting methods you want are
A) Check your format-If you want number of dates, it needs to be set as number, if you want a date, you need it to set as date. If you get a long decimal it means you have it formatted as general OR your expression returns a date value rather than a number value. Refer to my original answer.
B) Reverse your dates. Depending on the function and what you want, you may need to move the dates around.
=DATEDIF(DATEVALUE("03/02/2015"), TODAY(), "d")
Related
I am trying to find a difference between 2 dates using networkdays and additionally if both dates are equal, have to make the value as 0. But unable to get the result.
You can try
if(DATEVALUE(A1)=DATEVALUE(A2),0,NETWORKDAYS(A1+1,B1)
#Ron Rosenfeld has pointed out that my testing led to wrong conclusions. Therefore I increased the volume of my tests. They continue to show that ...
Comparing the two dates and adding a day gives erratic results, and that
The naked NETWORKDAYS function as designed by Microsoft gives the most useful result.
In the table below the original function is in column C, your function (modified to work by #Ron Rosenfeld) in column D and two variations thereof in columns E and F. The lower part of the table shows results where both days are the same while the dates are 2 days apart in the upper part.
The tables show that the original formula counts both the start and the end days as well as all days between them, subtracting weekend days, except when start and end days are the same. In other words, the original function already treats the case of A1=B1 differently.
However, if an adjustment is to be made it should preferably be made to the result of the formula, not be modifying the date before they are processed. This is demonstrated in column F.
The formula in column E takes up your attempt to modify one of the dates (the end date could be modified too) and makes this conditional. The difference as compared to your formula is that you apply in fact two separate calculations, one where the result is always 0 (when dates are equal) and the other where the start date is advanced by one day unconditionally. If it suits your purposes that method can still be applied but the formula in column E shows how the date modification can be made conditional.
The need to apply conditions arises from the essential shortcoming of your formula in that it applies the wrong condition. Different treatment for when dates are equal is already incorporated in the basic function. Any further modification must take the involved weekdays into account, not (necessarily) only the interval between the dates.
Why do you put your formula arguments in quotes? That just changes them into strings, which is why your formula doesn't work.
I assume from your formula that you just don't want to count the first day. In which case it will work as you have it, if you merely remove the double quote marks.
I am trying to find the minimum date in a row that has both dates and number data types. I tried to use the MINIFS function but that still produces the number value as the minimum, rather than the date. I am restricted to doing this as an in-cell function, rather than in VBA. Also, the data structure is a bit wonky, I know, but it can't be changed.
=MINIFS(A2:C2,A2:C2,CELL("format",A2:C2)="D4")
When I enter =MIN(IF(A6:C6>40000,A6:C6)) I get a #Value error. Excel doesn't like the range before the > symbol.
Remember that dates in Excel are calculated as number of days starting from January 1st, 1900.
Thus, if you look at your dates as numbers, you will see that it's in fact a number '44042'.
Knowing that, you can use MIN together with IF formula:
=MIN(IF(B5:D5>43831,B5:D5))
Where your suggested numbers are in cells B5:D5 and '43831' is 2020/01/01.
Of course, if you have numbers with high values, this solution should be adapted.
Here's a screenshot I made:
img
I have written a conditional formula to recognize two dates (greater than and last than). However, there are a few dates that are returning 'false'. All of the columns are formatted as a date. Can someone please help?
This is not a direct answer to the question asked, but as Scott said, the formula you use is much more complex than necessary. If you need to return a number for a date that falls within a period and the periods do not overlap, the following formula can be used:
=SUMPRODUCT((AQ3>=$DF$3:$DF$15)*(AQ3<=$DF$3:$DF$15),$DH$3:$DH$15)
If you need to process text values, it is more complicated. For example, if 'expired' is the only value (also for dates that do not fit into any period), then we can add the IF function to the previous formula:
=IF(SUMPRODUCT((AQ3>=$DF$3:$DF$15)*(AQ3<=$DF$3:$DF$15),$DH$3:$DH$15)>0,SUMPRODUCT((AQ3>=$DF$3:$DF$15)*(AQ3<=$DF$3:$DF$15),$DH$3:$DH$15),"expired")
I was creating a frequency worksheet for the new classes i'll be taking this semester, but when i try to use the COUNTIF function as a sum of three different parameters, i always get a date (like 00/jan) as the result, not a natural number as i'd expect.
I've tried using the function COUNTIFS instead, only to achieve the same result.
The function i was trying to create is
=COUNTIF(B5:B23;"*criteria1*")+COUNTIF(B5:B23;"*criteria2*")+COUNTIF(B5:B23;"*criteria3*")
With COUNTIFS, it is as follows:
=COUNTIFS(B5:B23;"*criteria1*";B5:B23;"*criteria2*";B5:B23;"*criteria3*")
There is no error message, and all i want to get is a real number, that is, the real sum of those "criteria" appearing in the given interval.
Excel tries to be helpful and takes a guess at the data type of the formula cell.
Unfortunately, Excel often gets it wrong. Especially when the formula processes dates, Excel will often format the cell as a date, too, even though the result may not be a date at all.
Your only option is to manually apply a different format to the cell. General or Number will show the real number.
Hi there I am trying to use the =NETWORKDAYS formula in Excel to calculate the number of workdays passed between two dates minus public holidays on a separate sheet. When I enter the correct formula I get an unreasonably large negative number like -29221 workdays between 2017-04-28 to 2018-04-24. I've tried to change the NumberFormat of the cells, ignoring public holidays etc. but I still get these numbers. Am I doing something wrong?
Here's my formula:
=NETWORKDAYS(2018-4-24,D2,PUBLIC_HOLIDAYS!E44:E61)
Couldn't find anything on the internet that would solve this.
2018-4-24 probably isn't being read as a date value, insert it into a cell and change to general to get it's "value" or use it in Date() like so:
=NETWORKDAYS(DATE(2018,4,24),D2,PUBLIC_HOLIDAYS!E44:E61)
Static date is being read as text. Enclose it in quotes or use date function. Consider these options:
=NETWORKDAYS("2018-4-24",D2,PUBLIC_HOLIDAYS!E44:E61)
OR
=NETWORKDAYS(DATE(2018,4,24),D2,PUBLIC_HOLIDAYS!E44:E61)
If it still doesn't work, check the cells that you're referencing. Make sure you're referencing dates or its equivalent value and not some random numbers.
Hope this helps..