Syntax error of ";; unexpected" on simple init script for Debian - linux

Question

I have this init script to run uwsgi. It works, but only on the start command. All the other commands give me this error:
/etc/init.d/uwsgi: 27: /etc/init.d/uwsgi: Syntax error: ";;" unexpected
It seems like the colons should be there from the tutorials I am reading, and yet it is telling me to remove them?
#!/bin/sh
### BEGIN INIT INFO
# Provides: uwsgi
# Required-Start: $local_fs $remote_fs $network
# Required-Stop: $local_fs $remote_fs $network
# Default-Start: 2 3 4 5
# Default-Stop: 0 1 6
# Description: This script manages uWSGI.
### END INIT INFO
DAEMON=/var/www/app/venv/bin/uwsgi
PIDFILE=/var/run/uwsgi.pid
DAEMON_ARGS="--ini /var/www/app/conf/uwsgi/app.ini --pidfile /var/run/uwsgi.pid"
. /lib/init/vars.sh
. /lib/lsb/init-functions
case "$1" in
start)
echo "Starting"
start-stop-daemon --start --quiet --pidfile $PIDFILE --exec $DAEMON --test > /dev/null \
|| return 1
start-stop-daemon --start --quiet --pidfile $PIDFILE --exec $DAEMON -- \
$DAEMON_ARGS 1> /dev/null 2>&1 \
|| return 2
esac
;;
stop)
echo "Stopping"
start-stop-daemon --stop --quiet --retry=QUIT/30/KILL/5 --pidfile $PIDFILE --name uwsgi
RETVAL="$?"
[ "$RETVAL" = 2 ] && return 2
start-stop-daemon --stop --quiet --oknodo --retry=0/30/KILL/5 --exec $DAEMON
[ "$?" = 2 ] && return 2
rm -f $PIDFILE
return "$RETVAL"
esac
;;
status)
status_of_proc "$DAEMON" "uwsgi" && exit 0 || exit $?
;;
reload)
echo "Reloading"
start-stop-daemon --stop --signal 1 --quiet --pidfile $PIDFILE --name uwsgi
return 0
;;
*)
echo "Usage: /etc/init.d/uwsgi {start|stop|status|reload|force-reload}" >&2
exit 3
;;
esac
exit 0

Answer 1

Get rid of the esac keywords before the ;;s. There should only be one at the very end to match the initial case keyword.