I'm trying to find all the init scripts created for websphere.
I know all the scripts end up with -init, so the first part of the code is:
find /etc/rc.d/init.d -name "*-init"
Also, I need all the script that run on an specific path, so the second part would be
| grep -i "/opt/ibm"
Finally, I need help with the last part. I have found the scripts I need to run them with the stop argument.
find /etc/rc.d/init.d -name "*-init" | grep -i "/opt/ibm" | <<run script found with stop argument>>
How can I run the command found with find?
Use a loop so that we are a little more careful while executing them:
#!/bin/bash
shopt -s globstar
for file in /etc/rc.d/init.d/**/*-init; do # grab all -init scripts
script=$(readlink -f "$file") # grab the actual file in case of a symlink
[[ -f $script ]] || continue # skip if not a regular file
[[ $file = */opt/ibm/* ]] || continue # not "/opt/ibm/", skip
printf '%s\n' "Executing script '$script'"
"$script" stop; exit_code=$?
printf '%s\n' "Script '$script' finished with exit_code $exit_code"
done
If you omit the 'find' and use grep directly you could do something like this:
grep -i "/opt/ibm" /etc/rc.d/init.d/* | sed 's/:.*/ stop/g' | sort -u | bash
it uses grep directly, which adds the filename to the output: filename:matched line
since you only need the filename and not the match, use sed to replace the ':' and the rest of the line with ' stop' (see the space before stop)
use sort -u (make sure, to execute each script only once)
Pipe the result into a shell
How can I determine the current shell I am working on?
Would the output of the ps command alone be sufficient?
How can this be done in different flavors of Unix?
There are three approaches to finding the name of the current shell's executable:
Please note that all three approaches can be fooled if the executable of the shell is /bin/sh, but it's really a renamed bash, for example (which frequently happens).
Thus your second question of whether ps output will do is answered with "not always".
echo $0 - will print the program name... which in the case of the shell is the actual shell.
ps -ef | grep $$ | grep -v grep - this will look for the current process ID in the list of running processes. Since the current process is the shell, it will be included.
This is not 100% reliable, as you might have other processes whose ps listing includes the same number as shell's process ID, especially if that ID is a small number (for example, if the shell's PID is "5", you may find processes called "java5" or "perl5" in the same grep output!). This is the second problem with the "ps" approach, on top of not being able to rely on the shell name.
echo $SHELL - The path to the current shell is stored as the SHELL variable for any shell. The caveat for this one is that if you launch a shell explicitly as a subprocess (for example, it's not your login shell), you will get your login shell's value instead. If that's a possibility, use the ps or $0 approach.
If, however, the executable doesn't match your actual shell (e.g. /bin/sh is actually bash or ksh), you need heuristics. Here are some environmental variables specific to various shells:
$version is set on tcsh
$BASH is set on bash
$shell (lowercase) is set to actual shell name in csh or tcsh
$ZSH_NAME is set on zsh
ksh has $PS3 and $PS4 set, whereas the normal Bourne shell (sh) only has $PS1 and $PS2 set. This generally seems like the hardest to distinguish - the only difference in the entire set of environment variables between sh and ksh we have installed on Solaris boxen is $ERRNO, $FCEDIT, $LINENO, $PPID, $PS3, $PS4, $RANDOM, $SECONDS, and $TMOUT.
ps -p $$
should work anywhere that the solutions involving ps -ef and grep do (on any Unix variant which supports POSIX options for ps) and will not suffer from the false positives introduced by grepping for a sequence of digits which may appear elsewhere.
Try
ps -p $$ -oargs=
or
ps -p $$ -ocomm=
If you just want to ensure the user is invoking a script with Bash:
if [ -z "$BASH" ]; then echo "Please run this script $0 with bash"; exit; fi
or ref
if [ -z "$BASH" ]; then exec bash $0 ; exit; fi
You can try:
ps | grep `echo $$` | awk '{ print $4 }'
Or:
echo $SHELL
$SHELL need not always show the current shell. It only reflects the default shell to be invoked.
To test the above, say bash is the default shell, try echo $SHELL, and then in the same terminal, get into some other shell (KornShell (ksh) for example) and try $SHELL. You will see the result as bash in both cases.
To get the name of the current shell, Use cat /proc/$$/cmdline. And the path to the shell executable by readlink /proc/$$/exe.
There are many ways to find out the shell and its corresponding version. Here are few which worked for me.
Straightforward
$> echo $0 (Gives you the program name. In my case the output was -bash.)
$> $SHELL (This takes you into the shell and in the prompt you get the shell name and version. In my case bash3.2$.)
$> echo $SHELL (This will give you executable path. In my case /bin/bash.)
$> $SHELL --version (This will give complete info about the shell software with license type)
Hackish approach
$> ******* (Type a set of random characters and in the output you will get the shell name. In my case -bash: chapter2-a-sample-isomorphic-app: command not found)
ps is the most reliable method. The SHELL environment variable is not guaranteed to be set and even if it is, it can be easily spoofed.
I have a simple trick to find the current shell. Just type a random string (which is not a command). It will fail and return a "not found" error, but at start of the line it will say which shell it is:
ksh: aaaaa: not found [No such file or directory]
bash: aaaaa: command not found
I have tried many different approaches and the best one for me is:
ps -p $$
It also works under Cygwin and cannot produce false positives as PID grepping. With some cleaning, it outputs just an executable name (under Cygwin with path):
ps -p $$ | tail -1 | awk '{print $NF}'
You can create a function so you don't have to memorize it:
# Print currently active shell
shell () {
ps -p $$ | tail -1 | awk '{print $NF}'
}
...and then just execute shell.
It was tested under Debian and Cygwin.
The following will always give the actual shell used - it gets the name of the actual executable and not the shell name (i.e. ksh93 instead of ksh, etc.). For /bin/sh, it will show the actual shell used, i.e. dash.
ls -l /proc/$$/exe | sed 's%.*/%%'
I know that there are many who say the ls output should never be processed, but what is the probability you'll have a shell you are using that is named with special characters or placed in a directory named with special characters? If this is still the case, there are plenty of other examples of doing it differently.
As pointed out by Toby Speight, this would be a more proper and cleaner way of achieving the same:
basename $(readlink /proc/$$/exe)
My variant on printing the parent process:
ps -p $$ | awk '$1 == PP {print $4}' PP=$$
Don't run unnecessary applications when AWK can do it for you.
Provided that your /bin/sh supports the POSIX standard and your system has the lsof command installed - a possible alternative to lsof could in this case be pid2path - you can also use (or adapt) the following script that prints full paths:
#!/bin/sh
# cat /usr/local/bin/cursh
set -eu
pid="$$"
set -- sh bash zsh ksh ash dash csh tcsh pdksh mksh fish psh rc scsh bournesh wish Wish login
unset echo env sed ps lsof awk getconf
# getconf _POSIX_VERSION # reliable test for availability of POSIX system?
PATH="`PATH=/usr/bin:/bin:/usr/sbin:/sbin getconf PATH`"
[ $? -ne 0 ] && { echo "'getconf PATH' failed"; exit 1; }
export PATH
cmd="lsof"
env -i PATH="${PATH}" type "$cmd" 1>/dev/null 2>&1 || { echo "$cmd not found"; exit 1; }
awkstr="`echo "$#" | sed 's/\([^ ]\{1,\}\)/|\/\1/g; s/ /$/g' | sed 's/^|//; s/$/$/'`"
ppid="`env -i PATH="${PATH}" ps -p $pid -o ppid=`"
[ "${ppid}"X = ""X ] && { echo "no ppid found"; exit 1; }
lsofstr="`lsof -p $ppid`" ||
{ printf "%s\n" "lsof failed" "try: sudo lsof -p \`ps -p \$\$ -o ppid=\`"; exit 1; }
printf "%s\n" "${lsofstr}" |
LC_ALL=C awk -v var="${awkstr}" '$NF ~ var {print $NF}'
My solution:
ps -o command | grep -v -e "\<ps\>" -e grep -e tail | tail -1
This should be portable across different platforms and shells. It uses ps like other solutions, but it doesn't rely on sed or awk and filters out junk from piping and ps itself so that the shell should always be the last entry. This way we don't need to rely on non-portable PID variables or picking out the right lines and columns.
I've tested on Debian and macOS with Bash, Z shell (zsh), and fish (which doesn't work with most of these solutions without changing the expression specifically for fish, because it uses a different PID variable).
If you just want to check that you are running (a particular version of) Bash, the best way to do so is to use the $BASH_VERSINFO array variable. As a (read-only) array variable it cannot be set in the environment,
so you can be sure it is coming (if at all) from the current shell.
However, since Bash has a different behavior when invoked as sh, you do also need to check the $BASH environment variable ends with /bash.
In a script I wrote that uses function names with - (not underscore), and depends on associative arrays (added in Bash 4), I have the following sanity check (with helpful user error message):
case `eval 'echo $BASH#${BASH_VERSINFO[0]}' 2>/dev/null` in
*/bash#[456789])
# Claims bash version 4+, check for func-names and associative arrays
if ! eval "declare -A _ARRAY && func-name() { :; }" 2>/dev/null; then
echo >&2 "bash $BASH_VERSION is not supported (not really bash?)"
exit 1
fi
;;
*/bash#[123])
echo >&2 "bash $BASH_VERSION is not supported (version 4+ required)"
exit 1
;;
*)
echo >&2 "This script requires BASH (version 4+) - not regular sh"
echo >&2 "Re-run as \"bash $CMD\" for proper operation"
exit 1
;;
esac
You could omit the somewhat paranoid functional check for features in the first case, and just assume that future Bash versions would be compatible.
None of the answers worked with fish shell (it doesn't have the variables $$ or $0).
This works for me (tested on sh, bash, fish, ksh, csh, true, tcsh, and zsh; openSUSE 13.2):
ps | tail -n 4 | sed -E '2,$d;s/.* (.*)/\1/'
This command outputs a string like bash. Here I'm only using ps, tail, and sed (without GNU extesions; try to add --posix to check it). They are all standard POSIX commands. I'm sure tail can be removed, but my sed fu is not strong enough to do this.
It seems to me, that this solution is not very portable as it doesn't work on OS X. :(
echo $$ # Gives the Parent Process ID
ps -ef | grep $$ | awk '{print $8}' # Use the PID to see what the process is.
From How do you know what your current shell is?.
This is not a very clean solution, but it does what you want.
# MUST BE SOURCED..
getshell() {
local shell="`ps -p $$ | tail -1 | awk '{print $4}'`"
shells_array=(
# It is important that the shells are listed in descending order of their name length.
pdksh
bash dash mksh
zsh ksh
sh
)
local suited=false
for i in ${shells_array[*]}; do
if ! [ -z `printf $shell | grep $i` ] && ! $suited; then
shell=$i
suited=true
fi
done
echo $shell
}
getshell
Now you can use $(getshell) --version.
This works, though, only on KornShell-like shells (ksh).
Do the following to know whether your shell is using Dash/Bash.
ls –la /bin/sh:
if the result is /bin/sh -> /bin/bash ==> Then your shell is using Bash.
if the result is /bin/sh ->/bin/dash ==> Then your shell is using Dash.
If you want to change from Bash to Dash or vice-versa, use the below code:
ln -s /bin/bash /bin/sh (change shell to Bash)
Note: If the above command results in a error saying, /bin/sh already exists, remove the /bin/sh and try again.
I like Nahuel Fouilleul's solution particularly, but I had to run the following variant of it on Ubuntu 18.04 (Bionic Beaver) with the built-in Bash shell:
bash -c 'shellPID=$$; ps -ocomm= -q $shellPID'
Without the temporary variable shellPID, e.g. the following:
bash -c 'ps -ocomm= -q $$'
Would just output ps for me. Maybe you aren't all using non-interactive mode, and that makes a difference.
Get it with the $SHELL environment variable. A simple sed could remove the path:
echo $SHELL | sed -E 's/^.*\/([aA-zZ]+$)/\1/g'
Output:
bash
It was tested on macOS, Ubuntu, and CentOS.
On Mac OS X (and FreeBSD):
ps -p $$ -axco command | sed -n '$p'
Grepping PID from the output of "ps" is not needed, because you can read the respective command line for any PID from the /proc directory structure:
echo $(cat /proc/$$/cmdline)
However, that might not be any better than just simply:
echo $0
About running an actually different shell than the name indicates, one idea is to request the version from the shell using the name you got previously:
<some_shell> --version
sh seems to fail with exit code 2 while others give something useful (but I am not able to verify all since I don't have them):
$ sh --version
sh: 0: Illegal option --
echo $?
2
One way is:
ps -p $$ -o exe=
which is IMO better than using -o args or -o comm as suggested in another answer (these may use, e.g., some symbolic link like when /bin/sh points to some specific shell as Dash or Bash).
The above returns the path of the executable, but beware that due to /usr-merge, one might need to check for multiple paths (e.g., /bin/bash and /usr/bin/bash).
Also note that the above is not fully POSIX-compatible (POSIX ps doesn't have exe).
Kindly use the below command:
ps -p $$ | tail -1 | awk '{print $4}'
This one works well on Red Hat Linux (RHEL), macOS, BSD and some AIXes:
ps -T $$ | awk 'NR==2{print $NF}'
alternatively, the following one should also work if pstree is available,
pstree | egrep $$ | awk 'NR==2{print $NF}'
You can use echo $SHELL|sed "s/\/bin\///g"
And I came up with this:
sed 's/.*SHELL=//; s/[[:upper:]].*//' /proc/$$/environ
What is the linux command to find if a process say aa.sh is running or not.
ps command does not seem to work and it does not show the shell script names.
Please advise.
Check this
ps aux | grep "aa.sh"
The simplest and efficient solution is :
pgrep -fl aa.sh
Adding to the answers above -
To use in a script, use the following :-
result=`ps aux | grep -i "myscript.sh" | grep -v "grep" | wc -l`
if [ $result -ge 1 ]
then
echo "script is running"
else
echo "script is not running"
fi
Check this
ps -ef | grep shellscripname.sh
You can also find your running process in
ps -ef
The solutions above are great for interactive use, where you can eyeball the result and weed out false positives that way.
False positives can occur if the executable itself happens to match, or any arguments that are not script names match - the likelihood is greater with scripts that have no filename extensions.
Here's a more robust solution for scripting, using a shell function:
getscript() {
pgrep -lf ".[ /]$1( |\$)"
}
Example use:
# List instance(s) of script "aa.sh" that are running.
getscript "aa.sh" # -> (e.g.): 96112 bash /Users/jdoe/aa.sh
# Use in a test:
if getscript "aa.sh" >/dev/null; then
echo RUNNING
fi
Matching is case-sensitive (on macOS, you could add -i to the pgrep call to make it case-insensitive; on Linux, that is not an option.)
The getscript function also works with full or partial paths that include the filename component; partial paths must not start with / and each component specified must be complete. The "fuller" the path specified, the lower the risk of false positives. Caveat: path matching will only work if the script was invoked with a path - this is generally true for scripts in the $PATH that are invoked directly.
Even this function cannot rule out all false positives, as paths can have embedded spaces, yet neither ps nor pgrep reflect the original quoting applied to the command line. All the function guarantees is that any match is not the first token (which is the interpreter), and that it occurs as a separate word, optionally preceded by a path.
Another approach to minimizing the risk of false positives could be to match the executable name (i.e., interpreter, such as bash) as well - assuming it is known; e.g.
# List instance(s) of a running *bash* script.
getbashscript() {
pgrep -lf "(^|/)bash( | .*/)$1( |\$)"
}
If you're willing to make further assumptions - such as script-interpreter paths never containing embedded spaces - the regexes could be made more restrictive and thus further reduce the risk of false positives.
pgrep -f aa.sh
To do something with the id, you pipe it. Here I kill all its child tasks.
pgrep aa.sh | xargs pgrep -P ${} | xargs kill
If you want to execute a command if the process is running do this
pgrep aa.sh && echo Running
I was quite inspired by the last answer by mklement0 - I have few scripts/small programs I run at every reboot via /etc/crontab. I built on his answer and built a login script, which shows if my programs are still running.
I execute this scripts.sh via .profile -file on every login, to get instant notification on each login.
cat scripts.sh
#!/bin/bash
getscript() {
pgrep -lf ".[ /]$1( |\$)"
}
script1=keepalive.sh
script2=logger_v3.py
# test if script 1 is running
if getscript "$script1" >/dev/null; then
echo "$script1" is RUNNING
else
echo "$script1" is NOT running
fi
# test if script 2 is running:
if getscript "$script2" >/dev/null; then
echo "$script2" is RUNNING
else
echo "$script2" is NOT running
fi
here a quick script to test if a shell script is running
#!/bin/sh
scripToTest="your_script_here.sh"
scriptExist=$(pgrep -f "$scripToTest")
[ -z "$scriptExist" ] && echo "$scripToTest : not running" || echo "$scripToTest : runnning"
Give an option to ps to display all the processes, an example is:
ps -A | grep "myshellscript.sh"
Check http://www.cyberciti.biz/faq/show-all-running-processes-in-linux/ for more info
And as Basile Starynkevitch mentioned in the comment pgrep is another solution.
I am trying to do an if/then statement, where if there is non-empty output from a ls | grep something command then I want to execute some statements. I am do not know the syntax I should be using. I have tried several variations of this:
if [[ `ls | grep log ` ]]; then echo "there are files of type log";
Well, that's close, but you need to finish the if with fi.
Also, if just runs a command and executes the conditional code if the command succeeds (exits with status code 0), which grep does only if it finds at least one match. So you don't need to check the output:
if ls | grep -q log; then echo "there are files of type log"; fi
If you're on a system with an older or non-GNU version of grep that doesn't support the -q ("quiet") option, you can achieve the same result by redirecting its output to /dev/null:
if ls | grep log >/dev/null; then echo "there are files of type log"; fi
But since ls also returns nonzero if it doesn't find a specified file, you can do the same thing without the grep at all, as in D.Shawley's answer:
if ls *log* >&/dev/null; then echo "there are files of type log"; fi
You also can do it using only the shell, without even ls, though it's a bit wordier:
for f in *log*; do
# even if there are no matching files, the body of this loop will run once
# with $f set to the literal string "*log*", so make sure there's really
# a file there:
if [ -e "$f" ]; then
echo "there are files of type log"
break
fi
done
As long as you're using bash specifically, you can set the nullglob option to simplify that somewhat:
shopt -s nullglob
for f in *log*; do
echo "There are files of type log"
break
done
Or without if; then; fi:
ls | grep -q log && echo 'there are files of type log'
Or even:
ls *log* &>/dev/null && echo 'there are files of type log'
The if built-in executes a shell command and selects the block based on the return value of the command. ls returns a distinct status code if it does not find the requested files so there is no need for the grep part. The [[ utility is actually a built-in command from bash, IIRC, that performs arithmetic operations. I could be wrong on that part since I rarely stray far from Bourne shell syntax.
Anyway, if you put all of this together, then you end up with the following command:
if ls *log* > /dev/null 2>&1
then
echo "there are files of type log"
fi