How can I change the #NA to 0 in this function. As is, it's returning #NA, which is correct. But I want it to return 0 instead.
=VLOOKUP(R11,Lookup!$Z$2:$AB$332,2,0)
Where VLOOKUP is applied with its fourth parameter 0 (FALSE):
If an exact match is not found, the error value #N/A is returned.
But this can be detected (trapped) within a formula and an alternative result shown instead of #N/A. This alternative could be almost anything but OP has chose 0 so:
=IFERROR(VLOOKUP(R11,Lookup!$Z$2:$AB$332,2,0),0)
In early versions of Excel IFERROR is not available but, though longer, an alternative is:
=IF(ISERROR(VLOOKUP(R11,lookup!$Z$2:$AB$332,2,0)),0,VLOOKUP(R11,lookup!$Z$2:$AB$332,2,0))
Related
I am using a VLOOKUP formula between two sheets to get a value. However, I want to return another value from a different column if my VLOOKUP returns 0 or #N/A. I have tried something like this, but it is still giving me either 0 or #N/A.
=IFERROR(VLOOKUP(B2,Sheet1!B1:C100,2,FALSE),Sheet1!A2)
The data I want to return if my VLOOKUP returns 0 or #N/A is in column A.
Try this:
=IFERROR(INDEX(Sheet1!C$1:C$100,MATCH(B2,Sheet1!B$1:B$100,0)),Sheet1!A2)
Now include the requirements:
=IF(ISNUMBER(MATCH(B2,Sheet1!B$1:B$100,0)),IF(INDEX(Sheet1!C$1:C$100,MATCH(B2,Sheet1!B$1:B$100,0))=0,Sheet1!A2,INDEX(Sheet1!C$1:C$100,MATCH(B2,Sheet1!B$1:B$100,0))),Sheet1!A2)
=IF(VLOOKUP($E5;$'S_BIP Purchase'.$G$3:$H$35;2;0)="PWP";SUMIFS($'S_BIP Purchase'.$L$3:$L$35;$'S_BIP Purchase'.$G$3:$G$35;$E5))
Problem:
This formula works but it returns an #n/a. Can you please help me rephrase or enhance the formula so that it returns 0 instead of #n/a? I am using an openoffice calc
=IFERROR(IF(VLOOKUP($E5;$'S_BIP Purchase'.$G$3:$H$35;2;0)="PWP";SUMIFS($'S_BIP Purchase'.$L$3:$L$35;$'S_BIP Purchase'.$G$3:$G$35;$E5));"0")
IFERROR allows you to pick the value of the cell you want in case the formula returns error. IFERROR(Formula;Value)
I want to match the value in Sheet1!A to Sheet3!A and where they match SUM() the matching values in Sheet2!B
I tried this formula, but it is returning a 0 value even when a manual count returns > 0.
What did I set-up incorrectly in this formula?
=SUMIF(A:A,Sheet3!A:A,Sheet3!B:B)
Use this:
=SUMPRODUCT(SUMIF(Sheet3!A:A,$A$2:INDEX(A:A,MATCH("zzz",A:A)),Sheet3!B:B))
If you column A is numbers and not text change the "zzz" to 1E+99.
Edit
By you comments put this in the first cell:
=SUMIF(Sheet3!A:A,A2,Sheet3!B:B)
And copy down.
I have a very seriously weird problems with Excel formula. Refer the following formula:
=INDEX(C7:D9, MATCH(H2, B7:B9, 0), MATCH(H3, C6:D6, 0))
Please assume the H2 and H3 is linked from some other formula which yield the value from B7:B9 and C6:D6 respectively. My problem is that the result is #N/A instead of returning value from the INDEX ARRAY.
The main problem is, that we don't know what H2:H3 returns
Taking your formula:
=INDEX(C7:D9, MATCH(H2, B7:B9, 0), MATCH(H3, C6:D6, 0))
H2 needs an output like Below 42°!
if there is only a number like 53 replace MATCH(H2, B7:B9, 0) with something like 1+(H2>=42)+(H2>58). However, if you got 53° you also need to replace H2 with something like NUMBERVALUE(LEFT(H2,LEN(H2)-1))
Same goes for H3: You need to get a return like "< 25". Asuming you only get a number, you need to replace MATCH(H3, C6:D6, 0) with something like 1+(H3>=25).
At least, it's not clear if thats the real problem. We really need to know the return values from H2 and H3.
You get #N/A because the MATCH-function fails. I'm almost certain it fails because the content of H2 is not type compatible with the contents in B7:B9 (or H3 not compatible with C6:D6).
Since you have string-type in B7:B9, H2 must also be string-type and the string must identically match one of the strings in B7:B9. If it matches none of them it throws #N/A.
If MATCH is unsuccessful in finding a match, it returns the #N/A error
value.
https://support.office.com/en-us/article/MATCH-function-e8dffd45-c762-47d6-bf89-533f4a37673a
If there is a type-mismatch, the function will automatically fail unless Excel can cast it to the right type on the fly (and understands that it is supposed to do that), because failure to complete the comparison naturally defaults to "no match" ~~> #N/A.
Examine the datatypes you are comparing and fix the discrepancies, and your formula will work.
Sorry guys for being unclear in my post. Well I finally fixed the problem by replacing "1" instead of "0" on my MATCH functions. I don't know why but it fixes the #N/A error.
I am using the following formula:
=MIN(IF(A1:A5>B1,A1:A5)) use Ctrl-Shift-Enter
My value for B1 is 10 and my array is {1,5,4,2,7} so in this case no value is greater than 10.
The problem is that excel returns 0 as the result of the empty set which is a problem as 0 is not greater than 10.
In this case, I can test if the result 0 is greater than 10 and see that the result is invalid, however, if B1 is -10 for an array of {-15,-24,-11,-37-60} than the 0 seems like a valid value when no correct value exists.
So anybody know of how I can find the min or max value of a set with constraints, but return either an error or something distinct if the solution set is empty?
Thank you.
Try using SMALL instead of MIN, i.e.
=SMALL(IF(A1:A5>B1,A1:A5),1)
Unlike MIN the SMALL function will return an error [#NUM!] for your example
....or if you want a text value instead of an error then use IFERROR function, too, i.e.
=IFERROR(SMALL(IF(A1:A5>B1,A1:A5),1),"None")
Your IF statement will return False if none of the numbers in the range are greater than 10. It appears that MIN is converting False to numeric (0). You need to add behavior to handle the False.
If you know that all valid values must be >=0, then you could use the "else" section of the IF formula to return -1.
MIN(IF(A1:A5>B1,A1:A5,-1))