I have a table like this:
Length 4
year 1 2 3 4 5
A 100 400 300 200 400
B
And in column B I want a sum of A from the past [length] years. For this I figured I needed an OFFSET, so my function is (for year 2):
=SUM.IF(OFFSET(B3;0;0;1;-B1);">0")
The if statement is used so it doesn't give an error when it reaches the edge of the table, but for years 2 and 3 the OFFSET range is outside of the worksheet so it doesn't work. How can I specify a condition that it just doesn't sum anything that isn't on the worksheet?
In A2:
=SUM(INDEX(1:1,COLUMNS($A:A)):INDEX(1:1,MAX(1,COLUMNS($A:A)-3)))
Copy to the right as required.
Regards
Ok, it was hard to decypher the question:
When you ask column B, I guess you mean row 4, right?
You don't need SUMIF, because SUM doesn't count empty cells or cells
with non-numeric value.
The reference to the length value should be absolute, so it doesn't
change as you copy the formula:
$B$1
OFFSET's Width value cannot be negative, rather have the Cols value =
-[Length]:
OFFSET(C3;0; -$B$1...
(Now you are referencing 4 columns left to C3)
Make sure it is not out of the worksheet by not letting more than the [column number of the given cell minus 1] be referenced left from the cell:
OFFSET(C3;0; -MIN(COLUMN(C3)-1;$B$1)...
That is the starting point of your range to sum; you should sum it
up to recent year's value. So the correct formula in C4 is:
=SUM(OFFSET(C3;0;-MIN(COLUMN(C3)-1;$B$1)):C3)
Related
I've got a table in excel with 10 rows and 10 columns.
The table contains 100 different values between 1 and 3.
I want to find the highest sum of 10 values using only 1 value from each row and 1 from each column.
Do u guys know a function that finds the highest sum? - I've tried to do i manually, but there are to many combinations!
Hope it makes sense.
Thanks in advance:)
My solution builds on what I wrote in the comment, i.e. you first take the maximum value in the 10x10 array, then the maximum in the 9x9 array (excluding the row/column of the first maximum), etc. My solution tries not to do everything in one formula, but I add a few helper columns, and a bit more helper rows (it is fast and dirty, but it works and is easily audited/understandable). You always can do this on a separate worksheet which you could hide if needed.
The screenshot above goes from cell A1 till Y31.
The key formulas:
3.55 is the result of =MAX(B2:K11)
The first gray cell is =IFNA(MATCH($M12;B2:B11;0);""), and you drag this 9 cells to the left. This tries to find a match with the max result in each column of the table;
The 10 left of the 3.55 is =MATCH(TRUE;INDEX(ISNUMBER(P12:Y12);0);0) , and gives the column number of the max value.
The 2 next to the 10 is =INDEX(P12:Y12;N12) and gives the row number of the max value.
The 1 in cell B12 is =IF(OR(B$1=$N12;$A12=$O12);0;1), and creates a 10x10 matrix with a row and column with zeroes where the previous max value was found.
Then you multiply this with the preceding matrix and create a new 10x10 matrix below (enter {=B2:K11*B12:K21} array formula (ctrl+shift+enter) in B22-K31
You then copy/paste rows 12 till 31 9 times below
The 23.02 is the total sum =SUM($M$12:$M$211) from all 10 maximum values and is the result you are looking for. The 10 is just a check with =COUNT($M$12:$M$211)
how can I merge two columns of data into one like the following:
Col1 Col2 Col3
========================
A 1 A
B 2 1
C 3 B
2
C
3
You can use the following formula in column D as per my example. Keep in mind to increase the $A$1:$B$6 range according to your data.
=INDEX($A$1:$B$6,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
Result:
Thank you to #Koby Douek for the answer. Just an addition--if you are using Open Office Calc, you replace the commas with semi-colons.
=INDEX($A$1:$B$6;INT((ROWS(D$2:D2)-1)/2)+1;MOD(ROWS(D$2:D2)-1;2)+1)
Expanding #koby Douek's answer to more columns and explaining some of the terms
Original Code for 2 columns to 1 alternating
=INDEX($A$1:$B$6,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
$A$1:$B$6 Defines the columns and rows to source the final set of data from, the $s are only present to keep the formula from changing the columns and rows selects if it is copied and pasted or dragged.
To extend to work on any values you dump into the columns instead of having to expand the range every time it should be amended to $A:$B or A:B so you can easily copy it to other sets of columns and create new merges, but it will also give the 1st value in every column as one of the alternating values so if you instead have headers you would be able to do this by instead using a large number so $A$1:$B$99999 or A$1:B$99999 if you want to past and move the columns ymmv which is better by situation.
lets assume you are fine including the values in the 1st row
This changes the formula to
=INDEX($A:$B,INT((ROWS(D$2:D2)-1)/2)+1,MOD(ROWS(D$2:D2)-1,2)+1)
Now on to D$2:D2
This is the row that is being used to calculate the difference between the current row the formula is in (D2) and the reference row (D$2) The important thing to make sure you do is to set the reference row number to the 1st row you will be putting values in, so if your 1st row is a header in the sort column you will use the 2nd row as the reference, if your values in the combined column D begin on the 3rd row then the reference row would be D$3
Since I like the more general form where the 1st row isn't a header row I'll use D$1:D1 but you could still mix source rows without headers into a combined row with a header of as many rows as you like just by incrementing that reference row number to be the 1st row where your values should begin.
This changes the formula to
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/2)+1,MOD(ROWS(D$1:D1)-1,2)+1)
Now INT((ROWS(D$1:D1)-1)/2)+1 and MOD(ROWS(D$1:D1)-1,2)+1
INT returns an integer value so any decimal places are dropped, it essentially functions like rounding down to the nearest whole number
MOD functions by returning the remainder of a division, it's result will be a whole number between 0 and n-1 where n is the number we are dividing by. (eg: 0/3=0; 1/3=1; 2/3=2; 3/3=0; 4/3=1 ... etc)
So -1)/2)+1 and -1,2)+1
the first value is again the difference between the current row and the reference row. but D$1:D1 is going to be the count of the rows, which is 1 so we have to correct for the rows count starting at 1 instead of 0 which would throw off our calculations, so both are using the -1 to reduce the count of the rows by 1
in the case of /2 and ,2 both are because we are dividing by 2 in the first statement it's a normal division by 2 /2 in the modulus statement it's an argument of the Mod function so ,2
finally we need to add 1 using +1 to correct for the index's need to have a value series which begins at 1.
INT((ROWS(D$2:D2)-1)/2)+1 is finding the row number to select the value from.
MOD(ROWS(D$1:D1)-1,2)+1 is finding the column number to select the value from
Thus we can change /2 and ,2 to /3 and ,3 to do this with 3 columns
This yields:
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/3)+1,MOD(ROWS(D$1:D1)-1,3)+1)
So maybe that's the confusing way to look at it but it's closer to how my mind works on it. Here is an alternative view:
=INDEX([RANGE],[ROW_#],[COLUMN_#]) returns the value from a range of rows and columns
Using the example:
=INDEX($A:$B,INT((ROWS(D$1:D1)-1)/3)+1,MOD(ROWS(D$1:D1)-1,3)+1)
[RANGE] = $A:$B this is the range of source columns.
[ROW_#] = INT((ROWS(D$1:D1)-1)/3)+1
INT([VALUE_A])+1 returns an integer value so any decimal places are dropped. Then adds one to it. we add one to the value because the result of the next steps will be 1 less than the value we need.
[Value_A] = (ROWS(D$1:D1)-1)/3
ROWS(D$1:D1) returns the number of rows in the Range to the current row in the results column, we use D$1 to designate the row number where the values in the results column begin. D1 is the current row in the results column giving us a range from the source row, allowing us to count the rows. we have to subtract 1 from this value using -1 to get the difference between the source and current. This is then divided by /3 because we have three columns we want to look through in this example so we only change rows when the result is divisible by 3. the INT drops any decimal places as mentioned so it only increments when cleanly divisible by 3.
[COLUMN_#] = MOD(ROWS(D$1:D1)-1,3)+1
MOD([VALUE],[Divisor])+1 returns the remainder of the value when divided by the divisor.
Using the example:
MOD(ROWS(D$1:D1)-1,3)+1
In this case we still divide by 3 but it's an argument to the MOD function, we still need to count the number of rows and subtract 1 before dividing it, this will return a 0, 1, or 2 for the column, but as above we are shifted backwards by 1 as the column numbers begin with the number 1, so as before we must add 1
And here we add column A and D
two different formulas depending on if you add the formula to an odd row or an even row.
https://1drv.ms/x/s!AncAhUkdErOkguUaToQkVkl5Qw-l_g?e=5d9gVM
Odd Start row
=INDEX($A$2:$D$9;ROUND(ROW(A1)/2;0);IF(MOD(ROW()-ROW($A$2);2)=1;4;1))
Even Start row
=INDEX($A$2:$D$9;ROUND(ROW(A1)/2;0);IF(MOD(ROW()-ROW($A$1);2)=1;4;1))
What is A1 in the picture is the cell directly above your first data cell.
If you want to place it on a different sheet you just add the sheet name:
=INDEX(MySheet!$A$2:$D$9;ROUND(ROW(MySheet!A1)/2;0);IF(MOD(ROW()-ROW(MySheet!$A$2);2)=1;4;1))
=INDEX(MySheet!$A$2:$D$9;ROUND(ROW(MySheet!A1)/2;0);IF(MOD(ROW()-ROW(MySheet!$A$1);2)=1;4;1))
I have
Year 1 2 3 4 5 6
I'm trying to make it so that each year number 1-6 is equal to another number value i.e. Year 1 is equal to 5. Year 2 is equal to 6.
You will not be able to store one value in a cell and use a different value for calculation. However you may do this calculation with the help of a lookup from another table,
Assuming you have the years in Column A and the corresponding mappings are in Column E and F, you can use the below formula in Column B,
=INDEX(E:F,MATCH(A1,E:E,0),2) * 2
This formula lookups the value in A1 in the table E:F and returns the corresponding Column F element. That is finally multiplied with the 2 to show your result. Instead of just using just A1 for multiplying by 2, you should be using INDEX(E:F,MATCH(A1,E:E,0),2). Hope this helps.
Assume I have the following table:
A B C
1 Week 1 Week 2
2 Melissa 114.7 82.8
3 Mike 105.5 122.5
4 Andrew 102.3 87.5
5 Rich 105.3 65.2
The names are in column A, the Week values are in Row 1. (So A1 is blank, B1 = Week 1, and A2 = Melissa.)
I'm trying to build a formula that looks at all the values in a known range (in this example, B2:C5), chooses the highest value of the bunch (here, 122.5) and returns the name of the person from Column A that got that value. If I use this formula, it works for the values in range B2:B5:
=INDEX(A2:A5,MATCH(MAX(B2:B5),B2:B5,0))
That returns Melissa but if I expand the range to include more than just column B's values, I get an #N/A returned:
=INDEX(A2:A5,MATCH(MAX(B2:C5),B2:C5,0))
The weird part (to my simple brain) is that the MATCH portion of the formula works fine, if I just put in this formula, it returns the highest value of 122.5 from C3:
=MAX(B2:C5,B2:C5,0)
So clearly something it going wrong when I'm using either the MATCH or INDEX commands.
Hopefully this makes sense and someone can point out my error?
Try this:
=INDEX(A:A,MAX((B2:C5=MAX(B2:C5))*ROW(B2:C5)))
This is an array formula and must be confirmed with Ctrl+Shift+Enter.
Note: Match can only search one vector at a time. It can be one row or one column or one array. It cannot be two or more rows or columns or a 2D array.
Do it "twice"? Please try:
=INDEX(A2:A5,IFERROR(MATCH(MAX(B2:C5),B2:B5,0),MATCH(MAX(B2:C5),C2:C5,0)))
If you are going to have up to 52/53 weeks to cope with I'd suggest instead inserting a helper column with the MAX for each row. Make that an new (inserted) ColumnA (say =MAX(C2:BC2) etc.) and a simple VLOOKUP should serve, say:
=VLOOKUP(MAX(A:A),A:B,2,0)
A B
1 5
2 10
2 15
3 20
I want to calculate percentile for a column of values B if A is equal say 2. That's I want to get range of B2,B3 and calculate percentile of this.
So basically the question is: how do I select range in one column with the checking with another column?
I.e. it works perfectly with SumIf and CountIf, I just need the same with PercentileIf. Thx!
This will give you the 25th percentile of A1:A6 for all cells where the value in B1:B6 equals 2:
=PERCENTILE.INC(IF(B1:B6=2,A1:A6,""),0.25)
It's an array formula and must be entered with Ctrl-Shift-Enter.