How to use File.WriteAllText but don't overwrite the old text? - c#-4.0

i want to return all data to txt file from my csv
string fileName = "../../TechFiles/";
List<string> listA = new List<string>();
using (var reader = new StreamReader(ConfigurationManager.AppSettings["ConfigurationSource"]))
{
var hdr2 = "2012-05-09 12:52:00";
var hdr1 = "Account";
while (!reader.EndOfStream)
{
var line = reader.ReadLine();
var values = line.Split(',');
listA.Add(values[0]);
csv = new StringBuilder();
newLine = string.Format("HDR {0} {1}\r\n{2}{3}" , hdr1,line, Environment.NewLine);
csv.Append(newLine);
File.WriteAllText(String.Format("{0}{1}", fileName, values[4] + ".txt"), csv.ToString());
}
}

Use File.AppendAllText:
File.AppendAllText(String.Format("{0}{1}", fileName, values[4] + ".txt"), csv.ToString());

Related

How to create and download a zip file in ASP.NET Core?

We need to bundle a multiple files in a Zip format and download it. Could you please suggest a way to do this in ASP.NET core without using any third party libraries.
In ASP.NET MVC we can achieve this using https://msdn.microsoft.com/en-us/library/system.io.packaging.aspx. Whether is it possible in ASP.NET core 2.0 ?
I think this will help you a lot
protected FileStreamResult DownloadFolder(string path, string[] names, int count)
{
FileStreamResult fileStreamResult;
var tempPath = Path.Combine(Path.GetTempPath(), "temp.zip");
if (names.Length == 1)
{
path = path.Remove(path.Length - 1);
ZipFile.CreateFromDirectory(path, tempPath, CompressionLevel.Fastest, true);
FileStream fileStreamInput = new FileStream(tempPath, FileMode.Open, FileAccess.Read, FileShare.Delete);
fileStreamResult = new FileStreamResult(fileStreamInput, "APPLICATION/octet-stream");
fileStreamResult.FileDownloadName = names[0] + ".zip";
}
else
{
string extension;
string currentDirectory;
ZipArchiveEntry zipEntry;
ZipArchive archive;
if (count == 0)
{
string directory = Path.GetDirectoryName(path);
string rootFolder = Path.GetDirectoryName(directory);
using (archive = ZipFile.Open(tempPath, ZipArchiveMode.Update))
{
for (var i = 0; i < names.Length; i++)
{
currentDirectory = Path.Combine(rootFolder, names[i]);
foreach (var filePath in Directory.GetFiles(currentDirectory, "*.*", SearchOption.AllDirectories))
{
zipEntry = archive.CreateEntryFromFile(this.contentRootPath + "\\" + filePath, names[i] + filePath.Substring(currentDirectory.Length), CompressionLevel.Fastest);
}
}
}
}
else
{
string lastSelected = names[names.Length - 1];
string selectedExtension = Path.GetExtension(lastSelected);
if (selectedExtension == "")
{
path = Path.GetDirectoryName(Path.GetDirectoryName(path));
path = path.Replace("\\", "/") + "/";
}
using (archive = ZipFile.Open(tempPath, ZipArchiveMode.Update))
{
for (var i = 0; i < names.Length; i++)
{
extension = Path.GetExtension(names[i]);
currentDirectory = Path.Combine(path, names[i]);
if (extension == "")
{
foreach (var filePath in Directory.GetFiles(currentDirectory, "*.*", SearchOption.AllDirectories))
{
zipEntry = archive.CreateEntryFromFile(this.contentRootPath + "\\" + filePath, filePath.Substring(path.Length), CompressionLevel.Fastest);
}
}
else
{
zipEntry = archive.CreateEntryFromFile(this.contentRootPath + "\\" + currentDirectory, names[i], CompressionLevel.Fastest);
}
}
}
}
FileStream fileStreamInput = new FileStream(tempPath, FileMode.Open, FileAccess.Read, FileShare.Delete);
fileStreamResult = new FileStreamResult(fileStreamInput, "APPLICATION/octet-stream");
fileStreamResult.FileDownloadName = "folders.zip";
}
if (File.Exists(tempPath))
{
File.Delete(tempPath);
}
return fileStreamResult;
}

Adding Excel File and .TXT file into same Field in XPages

I woulld like to create then add 2 files into same file as attachment.
How can i do that? Please find below what i tried so far.
Excel files comes from resource/files and TXT file is just created during document saving progress.
importPackage(org.apache.poi.ss.usermodel);
var resourcePath = "/SampleExcelFile.xlsx";
var bantfile = java.lang.System.getProperty("java.io.tmpdir");
var srtEk = "FileName1";
var excelName = srtEk + ".xlsx";
var textFileName = srtEk + +".txt";
var excelFilePath = bantfile+"\\"+ excelName;
var ledesFilePath = bantfile+"\\"+ textFileName;
var inp = facesContext.getExternalContext().getResourceAsStream(resourcePath);
var wb = WorkbookFactory.create(inp);
var sheet = wb.getSheetAt(0);
var row = sheet.getRow(2);
if (row == null)
{
row = sheet.createRow(2);
}
var cell = row.getCell(0);
if (cell == null)
{
cell = row.createCell(0);
}
cell.setCellType(Cell.CELL_TYPE_STRING);
cell.setCellValue(tempFilePath);
var fileOut = new java.io.FileOutputStream(excelFilePath);
wb.write(fileOut);
fileOut.close();
var fileOut = new java.io.FileOutputStream(ledesFilePath);
wb.write(fileOut);
fileOut.close();
var doc = database.createDocument();
doc.replaceItemValue("Form", "frmTest");
var rtitem = doc.createRichTextItem("Body");
rtitem.embedObject(lotus.domino.local.EmbeddedObject.EMBED_ATTACHMENT, null, excelFilePath , null);
doc.save(true, false);
You can add as much attachments to a RichText field as you like.
Just add another embedObject line to your code:
rtitem.embedObject(lotus.domino.local.EmbeddedObject.EMBED_ATTACHMENT, null, ledesFilePath, null);

Converting from HWPFDocument to XWPFDocument or vice versa

I have a Word document, where I have to replace text and save this document in Oracle database, in PDF format. Have someone any idea how to resolve this?
String inputFilename = "/root/GeneratorUmow/web/WEB-INF/umowy/kkb/wniosekozaciag.docx";
try(InputStream is = new FileInputStream(inputFilename)) {
dbd = new DokumentyBlobDAO();
db.setNazwaPliku("Wniosek_o_zaciagniecie.pdf");
db.setTypDokuemntu(876990);
if(du.getTypKlienta() == S_ID_Lead_Partner_Typ_Klienta_KKB) {
POIFSFileSystem fs = null;
fs = new POIFSFileSystem(is);
HWPFDocument doc = new HWPFDocument(fs); //funkcja zamyka inputstream
Range range = doc.getRange();
range.replaceText("my&&nazwa&&firmy", "KAKAOWY SZATAN");
//konwersja na pdf
FileOutputStream fos = new FileOutputStream(pathToDirectory + File.separator + folderName+File.separator + "wniosekzaciagniecie.docx");
doc.write(fos);
String inputChangeFile = pathToDirectory+ File.separator +folderName+File.separator+"wniosekzaciagniecie.docx";
InputStream inputstream = new FileInputStream(inputFilename);
length = inputChangeFile.length();
System.out.println("dlugosc lancucha " + length);
XWPFDocument document = new XWPFDocument(inputstream);
System.out.println("message3");
PdfOptions options = PdfOptions.create();
PdfOptions options = PdfOptions.create().fontEncoding("windows-1250");
System.out.println("message4");
OutputStream out = new FileOutputStream(new File(pathToDirectory+ File.separator +folderName+File.separator+"kakaowyszal.pdf"));
PdfConverter.getInstance().convert(document, out, options);
System.out.println("message5");
}
}
catch( Exception ex){
System.out.println("err" + ex);
return -1;
}

Send DataSet data email via attachment Excel File xls ( Not Creating Excel File ) C#

I want to send DataSet data with email excel file attachment in C# but I don't want to create Excel file physically. It can be do with MemoryStream but I couldn't.
Another problem I want to set Excel file's encoding type because data may be Russian or Turkish special character.
Please help me...
Here is my sample code...
<!-- language: c# -->
var response = HttpContext.Response;
response.Clear();
response.Charset = "utf-8";
response.ContentEncoding = System.Text.Encoding.Default;
GridView excelGridView = new GridView();
excelGridView.DataSource = InfoDataSet;
excelGridView.DataBind();
excelStringWriter = new StringWriter();
HtmlTextWriter htw = new HtmlTextWriter(excelStringWriter);
excelGridView.RenderControl(htw);
byte[] ExcelData = emailEncoding.GetBytes(excelStringWriter.ToString());
MemoryStream ms = new MemoryStream(ExcelData);
mailMessage.Attachments.Add(new Attachment(ms, excelFileName, "application/ms-excel"));
<!-- language: c# -->
here is another one simple and easy with excel attchment
public string SendMail(string LastId)
{
SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["con"].ConnectionString);
SqlCommand cmd = new SqlCommand("sp_GetMailData", con);
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("#LastID", LastId);
con.Open();
string result = "0";
string temptext = "";
SqlDataAdapter da = new SqlDataAdapter(cmd);
DataTable dt=new DataTable();
da.Fill(dt);
//ExportToSpreadsheet(dt,"My sheet");
GridView gv = new GridView();
gv.DataSource = dt;
gv.DataBind();
AttachandSend(gv);
con.Close();
return result.ToString();
}
public void AttachandSend(GridView gv)
{
StringWriter stw = new StringWriter();
HtmlTextWriter hw = new HtmlTextWriter(stw);
gv.RenderControl(hw);
System.Text.Encoding Enc = System.Text.Encoding.ASCII;
byte[] mBArray = Enc.GetBytes(stw.ToString());
System.IO.MemoryStream mAtt = new System.IO.MemoryStream(mBArray, false);
System.Net.Mail.MailMessage mailMessage = new System.Net.Mail.MailMessage();
MailAddress address = new
MailAddress("xxxxxxxxxxxxx", "Admin");
mailMessage.Attachments.Add(new Attachment(mAtt, "sales.xls"));
mailMessage.Body = "Hi PFA";
mailMessage.From = address;
mailMessage.To.Add("xxxxxxxxxxxx");
mailMessage.Subject = "xxxxxxxxxxxxxx";
mailMessage.IsBodyHtml = true;
var smtp = new SmtpClient();
smtp.Send(mailMessage);
}
Here is your solution
private static Stream DataTableToStream(DataTable table)
{
const string semiColon = ";";
var ms = new MemoryStream();
var sw = new StreamWriter(ms);
foreach (DataColumn column in table.Columns)
{
sw.Write(column.ColumnName);
sw.Write(semiColon);
}
sw.Write(Environment.NewLine);
foreach (DataRow row in table.Rows)
{
for (int i = 0; i < table.Columns.Count; i++)
{
sw.Write(row[i].ToString().Replace(semiColon, string.Empty));
sw.Write(semiColon);
}
sw.Write(Environment.NewLine);
}
return ms;
}
private static MailMessage CreateMail(string from,
string to,
string subject,
string body,
string attname,
Stream tableStream)
{
// using System.Net.Mail
var mailMsg = new MailMessage(from, to, subject, body);
tableStream.Position = 0;
mailMsg.Attachments.Add(
new Attachment(tableStream, attname, CsvContentType));
return mailMsg;
}
private const string CsvContentType = "application/ms-excel";
private static void ExportToSpreadsheetInternal(Stream tableStream, string name)
{
HttpContext context = HttpContext.Current;
context.Response.Clear();
context.Response.ContentType = CsvContentType;
context.Response.AppendHeader(
"Content-Disposition"
, "attachment; filename=" + name + ".xls");
tableStream.Position = 0;
tableStream.CopyTo(context.Response.OutputStream);
context.Response.End();
}
public static void ExportToSpreadsheet(DataTable table, string name)
{
var stream = DataTableToStream(table);
var mailMsg = CreateMail("from#ddd.com",
"to#ddd.com",
"spread",
"the spread",
name,
stream);
//ExportToSpreadsheetInternal(stream, name);
// send the mailMsg with SmtpClient (config in your web.config)
var smtp = new SmtpClient();
smtp.Send(mailMsg);
}
Call this method
ExportToSpreadsheet(DataTable table, string name)

Export xml data to Excel using OpenXML

The file is downloading an xlsx file but when i tried to open the file it is saying file is corrupted. Here is the code i'm trying to use please let me know if any changes has to be done for the following.
private void button1_Click(object sender, EventArgs e)
{
ArrayList DataNode = new ArrayList();
XmlDocument xmlobj = new XmlDocument();
ArrayList FinalXML = new ArrayList();
XslCompiledTransform xXslt = new XslCompiledTransform();
xmlobj.Load(#"D:\ExcelImport\Input.xml");
xXslt.Load(#"D:\ExcelImport\demoxsl.xslt");
XmlNodeList DN ;
DN = xmlobj.DocumentElement.GetElementsByTagName("Data");
for (int i = 0; i < DN.Count; i++)
{
DataNode.Add("<ShaleDataExport><Data Flag = '" + i + "' >" + DN.Item(i).InnerXml + "</Data></ShaleDataExport>");
}
string ShaleDataExportXML;
int k = 0 ;
while (k < DN.Count)
{
ShaleDataExportXML = DataNode[k].ToString();
XmlDocument xml = new XmlDocument();
xml.LoadXml(ShaleDataExportXML);
StringWriter sw = new StringWriter();
xXslt.Transform(xml, null, sw);
FinalXML.Add(sw);
sw.Close();
k++;
}
using (SpreadsheetDocument doc = SpreadsheetDocument.Create(#"D:\ExcelImport\OutPut\OutPut.xlsx", DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook))
{
WorkbookPart workbook = doc.AddWorkbookPart();
string XML;
string WorbookXML;
WorbookXML = #"<?xml version=""1.0"" encoding=""UTF-8"" standalone=""yes""?><workbook xmlns=""schemas.openxmlformats.org/.../main"" xmlns:r=""schemas.openxmlformats.org/.../relationships""><sheets>";
for (int j = 0; j < DN.Count; j++)
{
WorksheetPart[] sheet = new WorksheetPart[DN.Count];
sheet[j] = workbook.AddNewPart<WorksheetPart>();
string sheetId = workbook.GetIdOfPart(sheet[j]);
XML = #"<?xml version=""1.0"" encoding=""UTF-8"" standalone=""yes""?><worksheet xmlns=""schemas.openxmlformats.org/.../main"" >";
XML += FinalXML[j].ToString() + "</worksheet>";
string SheetXML = XML.ToString();
XmlDocument SXML = new XmlDocument();
SXML.LoadXml(SheetXML);
byte[] byteArray = Encoding.ASCII.GetBytes(SXML.OuterXml);
MemoryStream stream = new MemoryStream(byteArray);
StreamReader reader = new StreamReader(stream);
string text = reader.ReadToEnd();
WorbookXML += "<sheet name="+ AddPartXml(sheet[j], text) + " sheetId=" + j.ToString() + " r:id=" + sheetId.ToString() + " />";
}
WorbookXML += "</sheets></workbook>";
AddPartXml(workbook, WorbookXML);
doc.Close();
}
}
public string AddPartXml(OpenXmlPart part, string xml)
{
Uri uri = part.Uri;
String[] sheetNames = uri.OriginalString.Split('/');
string sheetName = sheetNames[sheetNames.Length - 1].Split('.')[0];
using (Stream stream = part.GetStream())
{
byte[] buffer = (new UTF8Encoding()).GetBytes(xml);
stream.Write(buffer, 0, buffer.Length);
}
return sheetName;
}
Thanks in advance
Vineet Mangal
private void button1_Click(object sender, EventArgs e)
{
XmlDocument xmlobj = new XmlDocument();
xmlobj.Load(#"C:\Excel Import\\Input.xml");
XslCompiledTransform xXslt = new XslCompiledTransform();
xXslt.Load(#"C:\ExportToexcel\Data.xslt");
StringWriter sw = new StringWriter();
xXslt.Transform(xmlobj, null, sw);
richTextBox2.Text = sw.ToString();
sw.Close();
XmlDocument Xdoc = new XmlDocument();
Xdoc.LoadXml(sw.ToString());
Xdoc.Save(#"c:\temp\output.xml");
StreamReader sr = File.OpenText(#"c:\temp\output.xml");
string strSheetData = sr.ReadToEnd();
ArrayList DataNode = new ArrayList();
ArrayList FinalXML = new ArrayList();
XmlNodeList DN;
DN = xmlobj.DocumentElement.GetElementsByTagName("Data");
for (int i = 0; i < DN.Count; i++)
{
DataNode.Add("<ShaleDataExport><Data Flag = '" + i + "' >" + DN.Item(i).InnerXml + "</Data></ShaleDataExport>");
}
string ShaleDataExportXML;
int k = 0;
while (k < DN.Count)
{
ShaleDataExportXML = DataNode[k].ToString();
XmlDocument xml = new XmlDocument();
xml.LoadXml(ShaleDataExportXML);
StringWriter sw1 = new StringWriter();
xXslt.Transform(xml, null, sw1);
FinalXML.Add(sw1);
sw.Close();
k++;
}
using (SpreadsheetDocument doc = SpreadsheetDocument.Create(#"c:\\temp\\output.xlsx", DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook))
{
WorkbookPart workbook1 = doc.AddWorkbookPart();
string XML;
string WorbookXML;
WorbookXML = #"<?xml version=""1.0"" encoding=""UTF-8"" standalone=""yes""?><workbook xmlns=""http://schemas.openxmlformats.org/spreadsheetml/2006/main"" xmlns:r=""http://schemas.openxmlformats.org/officeDocument/2006/relationships""><sheets>";
for (int j = 0; j < DN.Count; j++)
{
WorksheetPart[] sheet = new WorksheetPart[DN.Count];
sheet[j] = workbook1.AddNewPart<WorksheetPart>();
string sheetId = workbook1.GetIdOfPart(sheet[j]);
XML = #"<?xml version=""1.0"" encoding=""UTF-8"" standalone=""yes""?><worksheet xmlns=""http://schemas.openxmlformats.org/spreadsheetml/2006/main"" >";
XML += FinalXML[j].ToString() + "</worksheet>";
string SheetXML = XML.ToString();
XmlDocument SXML = new XmlDocument();
SXML.LoadXml(SheetXML);
byte[] byteArray = Encoding.ASCII.GetBytes(SXML.OuterXml);
MemoryStream stream = new MemoryStream(byteArray);
StreamReader reader = new StreamReader(stream);
string text = reader.ReadToEnd();
**WorbookXML += "<sheet name=" + "\"sheet" + (j + 1).ToString() + "\" " + " sheetId=\"" + (j + 1).ToString() + "\" r:id=\"" + sheetId.ToString() + "\" />";
AddPartXml(sheet[j], text);**
}
WorbookXML += "</sheets></workbook>";
AddPartXml(workbook1, WorbookXML);
doc.Close();
}
}
public void AddPartXml(OpenXmlPart part, string xml)
{
**using (Stream stream = part.GetStream())
{
byte[] buffer = (new UTF8Encoding()).GetBytes(xml);
stream.Write(buffer, 0, buffer.Length);
}**
}

Resources