What does the function ttyn(3) return? - tty

The man page is here: http://man.cat-v.org/unix-6th/3/ttyn
This example:
if (ttyn(0) = 'x'){
...
}
The man page says "x is returned if the indicated file does not correspond to a
typewriter."
The indicated file would be argument 0, so the standardinput, right?
And what is a typewriter? My keyboard?
What are you checking with this line?
if (ttyn(0) = 'x')

At that point in time, a typewriter (or teletype, or tty) was an RS-232 terminal connected to the computer via a serial port. The device entries in /dev corresponding to these ports were named /dev/tty0, /dev/tty1, /dev/ttya, etc. Each of those files was a character special file, as opposed to an ordinary file.
When a terminal was detected by the system, typically by being turned on or connected through a modem, the init process opened the device on file descriptors 0, 1, and 2 in a new process, and those file descriptors persisted through the login process, a user's shell, and any processes forked from the shell.
As you said in your question, file descriptor 0 is also called standard input.
The ttyn function calls fstat on its argument, which returns some info about the file such as its inode number, permissions, etc. ttyn then reads through /dev, looking at each file that starts with "tty", to see which one has the same inode number as ttyn's argument. When it finds a match, it returns the 4th character of the filename, which would be '0', '1', 'a', etc. If no matches are found, it returns 'x'.
There were generally a console and a few 8-port serial interfaces on a PDP-11. so there was no ttyx. And you could name devices in /dev anything you wanted. So it was easy to avoid /dev/ttyx being an actual device.
Commands like goto could use ttyn(0) != 'x' to determine whether the user was actually typing the command on a terminal.
Here is the default config file, /etc/ttys, used by init in V6. The console was tty8.
In V7 Unix, the functionality of ttyn was replaced by ttyname, which could accommodate longer device names, and isatty, which returned true if the fle descriptor was a terminal device. The goto command was not present in V7.

I've never seen this library call before; I'm used to the more familiar ttyname. The webpage doesn't give a return value, but based on what the text says, it would give the last char value in the string returned by ttynam(3). So if stdin (fd0) was connected to "/dev/tty2", then the return value would be the char 2. And in C, you would be able to check it with:
if (ttyn(0) == '2') { ... }
Granted the documentation is not clear. And it is using bad terminology; instead of "typewriter", it should be using "teletype" or "terminal", which are the accepted terms. Remember that stdin can be different from stdout; it is perfectly possible to do run cat </dev/tty1 > /dev/tty2, assuming you have the permissions for it.

Related

alsa: How to programmatically find if a device is busy/in use using it name and without opening it

We have a Linux device which has a speaker and MIC devices. These devices are shared among different modules - example a VOIP call can use speaker, a hazard Warning system can use speaker, a Voice prompt can use a speaker etc:
There seems to be a function in ALSA which uses pcm to provide the status.
int snd_pcm_status (snd_pcm_t * pcm, snd_pcm_status_t * status)
However the *pcm is returned by snd_pcm_open. We do not want to open the device as we would like to know the status of the device using its "name"
Alsa API is here
How can we check if a resource/device is busy without opening it and using its name?
The same information for playback stream X of device Y on card Z is available in the file /proc/asound/cardZ/pcmYp/subX/status; when the device is not open, it just says "closed".
Please note that you cannot use this information to decide if you can open the device, because some other process could have openend it just after you've read this information. The only way to check if you can open it is to actually try.
Though it requires /dev/dsp, this seems to work:
#!/bin/dash
## If the speaker is not used by any, returns 0, and prints "free"
## Otherwise, returns 1 and prints "not free"
iExit (){
trap '' 0
exit $1
}
iCatch (){
# The speaker is already in use
echo not free
iExit 1
}
trap iCatch 0
{
exec 3>&1 1>/dev/dsp
# If the execution reaches here, the speaker is not used by any
# Otherwise, it's catched by iCatch
exec 1>&3
echo free
iExit 0
} 2>/dev/null
Without PulseAudio, it seems on some PC only one output is accepted at one time; on others simultaneous playbacks are allowed. But even in the latter case, the above code works.
NB: The above code does not work with bash; for bash, simply use if/else rather than trap.
NB 2: /dev/dsp may be lacking depending on the kernel configuration.

Access file address of a particular file in Linux (lubuntu)

I am running a program that returns me address of the file.
How am i able to access these file address through terminal in Linux?
Reason i am looking for the command line for terminal in linux is to compare it to the address.
Example
a.txt = D#39d56e9
b.txt = D#4eb4dcd9
and so on..
Example of output program
[[D#39d56e9, [D#4eb4dcd9, [D#440f52ed, [D#4a0d6883, [D#36489670, [D#578caee7, [D#552eec98, [D#7baf1ad8, [D#250b9a58, [D#1cc21a68, [D#b53b098, [D#236ed0f7]
yeah. the excuting program is in Java
Modify your executing Java program, it is building an array of primitive double(s) and double [] doesn't override toString(). Easiest fix is probably to use Arrays.toString(double[]) like
// System.out.println(arr); // <--prints D[ and a 32-bit hashcode
System.out.println(Arrays.toString(arr));

file command generating 'invalid argument'

I have a perl script that traverses a set of directories and when it hits one of them it blows up with an Invalid Argument and I want to be able to programmatically skip it. I thought I could start by finding out the file type with the file command but it too blows up like this:
$ file /sys/devices/virtual/net/br-ex/speed
/sys/devices/virtual/net/br-ex/speed: ERROR: cannot read `/sys/devices/virtual/net/br-ex/speed' (Invalid argument)
If I print out the mode of the file with the perl or python stat function it tells me 33060 but I'm not sure what all the bits mean and I'm hoping a particular one would tell me not to try to look inside. Any suggestions?
To understand the stats number you got, you need to convert the number to octal (in python oct(...)).
Then you'll see that 33060 interprets to 100444. You're interested only in the last three digits (444). The first digit is file owner permissions, the second is group and the third is everyone else.
You can look at each of the numbers (in your case all are 4) as 3 binary bits in this order:
read-write-execute.
Since in your case owner, group & other has 4, it is translated (for all of them) to 100 (in binary) which means that only the read bit is on for all three - meaning that all three can only read the file.
As far as file permissions go, you should have been successful reading /sys/devices/virtual/net/br-ex/speed.
There are two reasons for the read to fail:
- Either speed is a directory, (directories require execute permissions to read inside).
- Or it's a special file - which can be tested using the -f flag in perl or bash, or using os.path.isfile(...) in python.
Anyhow, you can use the following links to filter files & directories according to their permissions in the 3 languages you mentioned:
ways to test permissions in perl.
ways to test permissions in python.
ways to test permissions in bash.
Not related to this particular case, but I hit the same error when I ran it on a malicious ELF (Linux executable) file. In that case it was because the program headers of the ELF was intentionally corrupted. Looking at the source code for file command, this is clear as it checks the ELF headers and bails out with the same error in case the headers are corrupted:
/*
* Loop through all the program headers.
*/
for ( ; num; num--) {
if (pread(fd, xph_addr, xph_sizeof, off) <
CAST(ssize_t, xph_sizeof)) {
file_badread(ms);
return -1;
}
TLDR; The file command checks not only the magic bytes, but it also performs other checks to validate a file type.

Passing key material to openssl commands

Is it safe to pass a key to the openssl command via the command line parameters in Linux? I know it nulls out the actual parameter, so it can't be viewed via /proc, but, even with that, is there some way to exploit that?
I have a python app that I want to use OpenSSL to do the encryption/description through stdin/stdout streaming in a subprocess, but I want to know my keys are safe.
Passing the credentials on the command line is not safe. It will result in your password being visible in the system's process listing - even if openssl erases it from the process listing as soon as it can, it'll be there for an instant.
openssl gives you a few ways to pass credentials in - the man page has a section called "PASS PHRASE ARGUMENTS", which documents all the ways you can pass credentials into openssl. I'll explain the relevant ones:
env:var
Lets you pass the credentials in an environment variable. This is better than using the process listing, because on Linux your process's environment isn't readable by other users by default - but this isn't necessarily true on other platforms.
The downside is that other processes running as the same user, or as root, will be able to easily view the password via /proc.
It's pretty easy to use with python's subprocess:
new_env=copy.deepcopy(os.environ)
new_env["MY_PASSWORD_VAR"] = "my key data"
p = subprocess.Popen(["openssl",..., "-passin", "env:MY_PASSWORD_VAR"], env=new_env)
fd:number
This lets you tell openssl to read the credentials from a file descriptor, which it will assume is already open for reading. By using this you can write the key data directly from your process to openssl, with something like this:
r, w = os.pipe()
p = subprocess.Popen(["openssl", ..., "-passin", "fd:%i" % r], preexec_fn=lambda:os.close(w))
os.write(w, "my key data\n")
os.close(w)
This will keep your password secure from other users on the same system, assuming that they are logged in with a different account.
With the code above, you may run into issues with the os.write call blocking. This can happen if openssl waits for something else to happen before reading the key in. This can be addressed with asynchronous i/o (e.g. a select loop) or an extra thread to do the write()&close().
One drawback of this is that it doesn't work if you pass closeFds=true to subprocess.Popen. Subprocess has no way to say "don't close one specific fd", so if you need to use closeFds=true, then I'd suggest using the file: syntax (below) with a named pipe.
file:pathname
Don't use this with an actual file to store passwords! That should be avoided for many reasons, e.g. your program may be killed before it can erase the file, and with most journalling file systems it's almost impossible to truly erase the data from a disk.
However, if used with a named pipe with restrictive permissions, this can be as good as using the fd option above. The code to do this will be similar to the previous snippet, except that you'll need to create a fifo instead of using os.pipe():
pathToFifo = my_function_that_securely_makes_a_fifo()
p = subprocess.Popen(["openssl", ..., "-passin", "file:%s" % pathToFifo])
fifo = open(pathToFifo, 'w')
print >> fifo, "my key data"
fifo.close()
The print here can have the same blocking i/o problems as the os.write call above, the resolutions are also the same.
No, it is not safe. No matter what openssl does with its command line after it has started running, there is still a window of time during which the information is visible in the process' command line: after the process has been launched and before it has had a chance to null it out.
Plus, there are many ways for an accident to happen: for example, the command line gets logged by sudo before it is executed, or it ends up in a shell history file.
Openssl supports plenty of methods of passing sensitive information so that you don't have to put it in the clear on the command line. From the manpage:
pass:password
the actual password is password. Since the password is visible to utilities (like 'ps' under Unix) this form should only be used where security is not important.
env:var
obtain the password from the environment variable var. Since the environment of other processes is visible on certain platforms (e.g. ps under certain Unix OSes) this option should be used with caution.
file:pathname
the first line of pathname is the password. If the same pathname argument is supplied to -passin and -passout arguments then the first line will be used for the input password and the next line for the output password. pathname need not refer to a regular file: it could for example refer to a device or named pipe.
fd:number
read the password from the file descriptor number. This can be used to send the data via a pipe for example.
stdin
read the password from standard input.
All but the first two options are good.

How to get the name of a file acting as stdin/stdout?

I'm having the following problem. I want to write a program in Fortran90 which I want to be able to call like this:
./program.x < main.in > main.out
Additionally to "main.out" (whose name I can set when calling the program), secondary outputs have to be written and I wanted them to have a similar name to either "main.in" or "main.out" (they are not actually called "main"); however, when I use:
INQUIRE(UNIT=5,NAME=sInputName)
The content of sInputName becomes "Stdin" instead of the name of the file. Is there some way to obtain the name of files that are linked to stdin/stdout when the program is called??
Unfortunately the point of i/o redirection is that you're program doesn't have to know what the input/output files are. On unix based systems you cannot look at the command line arguments as the < main.in > main.out are actually processed by the shell which uses these files to set up standard input and output before your program is invoked.
You have to remember that sometimes the standard input and output will not even be files, as they could be a terminal or a pipe. e.g.
./generate_input | ./program.x | less
So one solution is to redesign your program so that the output file is an explicit argument.
./program.x --out=main.out
That way your program knows the filename. The cost is that your program is now responsible for openning (and maybe creating) the file.
That said, on linux systems you can actually find yout where your standard file handles are pointing from the special /proc filesystem. There will be symbolic links in place for each file descriptor
/proc/<process_id>/fd/0 -> standard_input
/proc/<process_id>/fd/1 -> standard_output
/proc/<process_id>/fd/2 -> standard_error
Sorry, I don't know fortran, but a psudeo code way of checking the output file could be:
out_name = realLink( "/proc/"+getpid()+"/fd/1" )
if( isNormalFile( out_name ) )
...
Keep in mind what I said earlier, there is no garauntee this will actually be a normal file. It could be a terminal device, a pipe, a network socket, whatever... Also, I do not know what other operating systems this works on other than redhat/centos linux, so it may not be that portable. More a diagnostic tool.
Maybe the intrinsic subroutines get_command and/or get_command_argument can be of help. They were introduced in fortran 2003, and either return the full command line which was used to invoke the program, or the specified argument.

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