I have a directory that I want to copy all of it, but to a directory with a different name.
Example:
/Home/user/DirA-Web
copy its contents to (but it needs to be created)
/Home/user/version1/DirB-Img
/Home/user/version2/DirB-Img
I could always copy it and the rename it, I suppose.
Edit: I currently rsync the directories to the desired location and them mv in a for loop to rename them. I am looking for something cleaner.
If the directory
/Home/user/version1/
exists, a simple cp will do:
cp -r /Home/user/DirA-Web /Home/user/version1/DirB-Img
If not, you need to use mkdir beforehand, because cp has no option to
create your target directory recursively:
mkdir -p /Home/user/version1/DirB-Img && cp -r /Home/user/DirA-Web /Home/user/version1/DirB-Img
Related
I want to mimic copying a directory structure recursively (as in cp -r or rsync -a), but only touch the copied files, i.e. make all the copied files empty.
The specific use case is for a Snakemake pipeline; Snakemake looks for existing files in order to decide whether to re-run a pipeline step, and I want to make it believe the steps have already been run while avoiding fully downloading all the files.
This is a little kludgy, but you could pipe the output of find or rsync -nv into a little bash loop with mkdir -p and touch:
find /some/dir -type f | while read FILE; do
mkdir -p $(dirname $FILE)
touch $FILE
done
I'm attempting to create a script that will create a folder based on the current time and date. I then need the script to copy the files from a source folder to the newly created folder. I then need it to copy folders from a second source folder to the original source folder, overwriting everything that's in there.
Below is what I've tried, and it's failing in quite an epic fashion.
#!/bin/bash
d="/home/$(date +%d-%m-%y")"
mkdir "$d"
cp /home/test "$d"
cp /home/test2 /home/test
I'm aware that I don't have to define the variable, as the time between copies should be seconds and not lapse a day, but I wanted to make sure and honestly, I'm interested in learning to use variables in scripting.
There is one too many double quote here:
d="/home/$(date +%d-%m-%y")"
Actually no quoting is necessary here at all, write like this:
d=/home/$(date +%d-%m-%y)
In the rest of the script, if you want to copy directories, you will need to use cp -r instead of simply cp.
Finally, note that when you do cp -r dir1 dir2 when dir2 already exists, then dir1 will be copied inside dir2, rather than overwriting its content. That is, it will create dir2/dir1. If dir1 doesn't contain hidden files, then you can write like this to overwrite the content of dir2:
cp -r dir1/* dir2/
Is there an easy way to copy an specific file nested in an already nested directory creating an structure of directories nested in the same way its file path (in linux)?
for instance;
copy_command A/B/C/a.txt OTHER_DIR
would create
OTHER_DIR/A/B/C/a.txt
creating the directory structure A/B/C into OTHER_DIR and copying the file a.txt on his corresponding dir.
With GNU cp
cp --parents -- A/B/C/a.txt OTHER_DIR
The ${var_name%pattern} syntax removes pattern from the variable's value. With that in mind:
file="A/B/C/a.txt"
mkdir -p "OTHER_DIR/${file%/*}"
cp "$file" "OTHER_DIR/${file%/*}/"
Which is equivalent to:
mkdir -p OTHER_DIR/A/B/C
cp A/B/C/a.txt OTHER_DIR/A/B/C/
I'm working with a CentOS server. I have a folder named test located in /home/server/folder/test. I need to copy the directory test to /home/server/. How can I do it?
cp -r /home/server/folder/test /home/server/
To copy all files, including hidden files use:
cp -r /home/server/folder/test/. /home/server/
As I understand, you want to recursively copy test directory into /home/server/ path...
This can be done as:
-cp -rf /home/server/folder/test/* /home/server/
Hope this helps
This works for me.
cp -r /home/server/folder/test/. /home/server
For copy directory use following command
cp -r source Destination
For example
cp -r /home/hasan /opt
For copy file use command without -r
cp /home/file /home/hasan/
I have a directory with the following structure:
file_1
file_2
dir_1
dir_2
# etc.
new_subdir
I'd like to make a copy of all the existing files and directories located in this directory in new_subdir. How can I accomplish this via the linux terminal?
This is an old question, but none of the answers seem to work (they cause the destination folder to be copied recursively into itself), so I figured I'd offer up some working examples:
Copy via find -exec:
find . ! -regex '.*/new_subdir' ! -regex '.' -exec cp -r '{}' new_subdir \;
This code uses regex to find all files and directories (in the current directory) which are not new_subdir and copies them into new_subdir. The ! -regex '.' bit is in there to keep the current directory itself from being included. Using find is the most powerful technique I know, but it's long-winded and a bit confusing at times.
Copy with extglob:
cp -r !(new_subdir) new_subdir
If you have extglob enabled for your bash terminal (which is probably the case), then you can use ! to copy all things in the current directory which are not new_subdir into new_subdir.
Copy without extglob:
mv * new_subdir ; cp -r new_subdir/* .
If you don't have extglob and find doesn't appeal to you and you really want to do something hacky, you can move all of the files into the subdirectory, then recursively copy them back to the original directory. Unlike cp which copies the destination folder into itself, mv just throws an error when it tries to move the destination folder inside of itself. (But it successfully moves every other file and folder.)
You mean like
cp -R * new_subdir
?
cp take -R as argument which means recursive (so, copy also directories), * means all files (and directories).
Although * includes new_subdir itself, but cp detects this case and ignores new_subdir (so it doesn't copy it into itself!)
Try something like:
cp -R * /path_to_new_dir/