Freeze position when object touches terrain - object

This script is attached to my trees. It should freeze the trees Y position and turn Kinematic to true when the tree touches the ground. Right now it freezes the trees as soon as the game is started (the trees don't fall to the ground). Originally the trees have isKinematic and FreezePositionY off.
function OnCollisionEnter(other:Collision) {
if(other.gameObject.tag == "Terrain") {
Debug.Log("Object interacted with terrain on loading");
rigidbody.isKinematic = true;
}
}

Related

Godot - Enemy does not move to player when player is on the left

The enemy in my game will not move towards the left when player is on the left but will move to the right. Then when the player is on the right the enemy will move to the player.
code for enemy:
extends KinematicBody2D
var run_speed = 100
var velocity = Vector2.ZERO
var collider = null
func _physics_process(delta):
velocity = Vector2.ZERO
if collider:
velocity = position.direction_to(collider.position) * run_speed
velocity = move_and_slide(velocity)
func _on_DetectRadius_body_entered(body):
collider = body
func _on_DetectRadius_body_exited(body):
collider = null
I suspect you are using an Area2D and it is detecting something other than the player character. I remind you can use collision_mask and collision_layer to narrow what objects are detected. For example, are you sure the Area2D is not detecting the enemy itself? For a quick check you can have Godot print the collider to double check it is what you expect.
Furthermore, notice that wen an object leaves the Area2D it will set collider to null regardless if there is still some object inside the Area2D or not. I remind you that an alternative approach is using get_overlapping_bodies.
And, of course, you can query each body you get to see if it is the player character (for example by checking its node group, name, class, etc...). I go over filtering in more detail in another answer.
If you are getting the player character, there is another possible source of problems: position vs global_position. The code you have like this:
position.direction_to(collider.position)
Is correct if both the enemy and the collider it got have the same parent. In that case their positions are in the same space. Otherwise, you may want to either work on global coordinates:
global_position.direction_to(collider.global_position)
Or you can bring the collider position to local coordinates:
position.direction_to(to_local(collider.global_position))
And of course, double check that the Area2D is positioned correctly. You can enable "Visible Collision Shapes" on the "Debug" menu, which will show it when running the game from the editor.

Collision detection & resolution: circle in a playfield of other circles and polygons

I am working on a game that has a player sprite surrounded by a collision circle of a known radius. The player sprite can move about a playfield that consists of other sprites with their own collision circles and other obstacles made up of polygons. The other obstacles are rectangles at a 45 degree angle.
In addition, I want the player to adjust its movement when it does collide. I want the player to try to "push through" past the object instead of being stopped by it.
For example, if the player were to collide with another sprite's bounding circle, it would be stopped if its vector was exactly perpendicular to the tangent of the two circles' intersection.
However, if not perfectly perpendicular, the player would be, slowly at first, then faster, pushed along the tangent of the circle until it can continue past it unimpeded.
This works similarly when encountering one of the 45 degree rectangles.
What I need help with is the following: I am trying to find an analytic solution to detect both other sprites and obsticles, have the player's movement adjusted, and possibly stopped when adjusted to wedge between two or more objects.
I can do the collision detection and deflection for one object type at a time, but am struggling to put everything together into a comprehensive algorithm. I am currently working on an iterative pairwise resolution approach that "tries" different locations to result in a best-guess solution, but I really want a mathematically analytic solution. I'm hoping to have a function something like what appears in this psuedocode.
x = [player's x location]
y = [player's y location]
r = [player's collision radius]
// Array of other sprites on the playfield,
spr = [other sprites array]
// which contains 3 parameters, x, y, r. E.g., spr[3].x or spr[3].r,
// for the x position or collision radius for the fourth sprite in the
// array.
// Array of 45 degree rectangles on the playfield,
rect = [array of rectangles]
// which contain 4 parameters, x1, y1, x2, y2, the two opposite points
// of the rectangle. E.g., rect[0].x1, for the x position of the first
// point of the first rectangle.
// For simplicity, assume the above variables are all directly accessable
// in the function below.
// requestX and requestY is the position to which the player would
// like to move the player sprite.
definefunction collisionAdjustor(requestX, requestY) {
// Here I'd like to adjust the requested position if needed because
// of an intersection with one or more other sprites or rectangles.
// Finally return the location at which the player will actually be
// arriving.
return destinationX, destinationY
}
Any advice or suggestions would be much appreciated.
--Richard

Ray Trace Refraction looks "fake"

So in my ray tracer that I'm building I've gotten refraction to work for spheres along with caustic effects, however the glass spheres don't look particularly good. I believe the refracted math is correct because the light appears to be bending in inverting the way you'd expect it to however it doesn't look like glass, it just looks like paper or something.
I've read that total internal reflection is responsible for much of what makes glass look like it does, however when I tested to see if any of my refracted rays go above the critical angle, none of them do, so my glass sphere has no total internal reflection. I'm not sure if this is normal or if I've done something wrong. I've posted my refraction code below so if anyone has any suggestions I'd love to hear them.
/*
* Parameter 'dir' lets you know whether the ray is starting
* from outside the sphere going in (0) or from in the sphere
* going back out (1).
*/
void Ray::Refract(Intersection *hit, int dir)
{
float n1, n2;
if(dir == 0){ n1 = 1.0; n2 = hit->mat->GetRefract(); }
if(dir == 1){ n1 = hit->mat->GetRefract(); n2 = 1.0; }
STVector3 N = hit->normal/hit->normal.Length();
if(dir == 1) N = -N;
STVector3 V = D/D.Length();
double c1 = -STVector3::Dot(N, V);
double n = n1/n2;
double c2 = sqrt(1.0f - (n*n)*(1.0f - (c1*c1)));
STVector3 Rr = (n * V) + (n * c1 - c2) * N;
/*These are the parameters of the current ray being updated*/
E = hit->point; //Starting point
D = Rr; //Direction
}
This method is called during my main ray-tracing method RayTrace() which runs recursively. Here's a small section of it below that is in charge of refraction:
if (hit->mat->IsRefractive())
{
temp.Refract(hit, dir); //Temp is my ray that is being refracted
dir++;
result += RayTrace(temp, dir); //Result is the return RGB value.
}
You're right, you'll never get total internal reflection in a sphere (seen from the outside). That's because of symmetry: a ray inside a sphere will hit the surface at the same angle at both ends, meaning that, if it exceeds the critical angle at one end, it would have to exceed it at the other one as well (and so would not have been able to enter the sphere from the outside in the first place).
However, you'll still get a lot of partial reflection according to Fresnel's law. It doesn't look like your code accounts for that, which is probably why your glass looks fake. Try including that and see if it helps.
(Yes, it means that your rays will split in two whenever they hit a refractive surface. That happens in reality, so you'll just have to live with it. You can either trace both paths, or, if you're using a randomized ray tracing algorithm anyway, just sample one of them randomly with the appropriate weights.)
Ps. If you don't want to deal with stuff like light polarization, you may want to just use Schlick's approximation to the Fresnel equations.

How does inkscape calculate the coordinates for control points for "smooth edges"?

I am wondering what algorithm (or formula) Inkscape uses to calculate the control points if the nodes on a path are made "smooth".
That is, if I have a path with five nodes whose d attribute is
M 115.85065,503.57451
49.653441,399.52543
604.56143,683.48319
339.41126,615.97628
264.65997,729.11336
And I change the nodes to smooth, the d attribute is changed to
M 115.85065,503.57451
C 115.85065,503.57451 24.747417,422.50451
49.653441,399.52543 192.62243,267.61777 640.56491,558.55577
604.56143,683.48319 580.13686,768.23328 421.64047,584.07809
339.41126,615.97628 297.27039,632.32348 264.65997,729.11336
264.65997,729.11336
Obviously, Inkscape calculates the control point coordinates (second last and last coordinate pair on lines on or after C). I am interested in the algorithm Inkscape uses for it.
I have found the corresponding piece of code in Inkscape's source tree under
src/ui/tool/node.cpp, method Node::_updateAutoHandles:
void Node::_updateAutoHandles()
{
// Recompute the position of automatic handles.
// For endnodes, retract both handles. (It's only possible to create an end auto node
// through the XML editor.)
if (isEndNode()) {
_front.retract();
_back.retract();
return;
}
// Auto nodes automaticaly adjust their handles to give an appearance of smoothness,
// no matter what their surroundings are.
Geom::Point vec_next = _next()->position() - position();
Geom::Point vec_prev = _prev()->position() - position();
double len_next = vec_next.length(), len_prev = vec_prev.length();
if (len_next > 0 && len_prev > 0) {
// "dir" is an unit vector perpendicular to the bisector of the angle created
// by the previous node, this auto node and the next node.
Geom::Point dir = Geom::unit_vector((len_prev / len_next) * vec_next - vec_prev);
// Handle lengths are equal to 1/3 of the distance from the adjacent node.
_back.setRelativePos(-dir * (len_prev / 3));
_front.setRelativePos(dir * (len_next / 3));
} else {
// If any of the adjacent nodes coincides, retract both handles.
_front.retract();
_back.retract();
}
}
I'm not 100% sure of the quality of this information.
But at least at some point in time for calculating some curves
inkscape seems to have used >>spiro<<.
http://www.levien.com/spiro/
Take a quick look at the page, he's providing a link to his PhD-thesis:
http://www.levien.com/phd/thesis.pdf
in which he's introducing the theory/algorithms ...
Cheers
EDIT:
I'm currently investigating a bit into the matter for a similar purpose, so I stumbled across ...
http://www.w3.org/TR/SVG11/paths.html#PathDataCurveCommands ... the specification of curves for SVG.
So curves, like not circles or arcs, are cubic or quadratic beziers then ...
Have a look at wikipedia for bezier formulas as well:
http://en.wikipedia.org/wiki/B-spline#Uniform_quadratic_B-spline

Ball to Ball Collision - Detection and Handling

With the help of the Stack Overflow community I've written a pretty basic-but fun physics simulator.
You click and drag the mouse to launch a ball. It will bounce around and eventually stop on the "floor".
My next big feature I want to add in is ball to ball collision. The ball's movement is broken up into a x and y speed vector. I have gravity (small reduction of the y vector each step), I have friction (small reduction of both vectors each collision with a wall). The balls honestly move around in a surprisingly realistic way.
I guess my question has two parts:
What is the best method to detect ball to ball collision?
Do I just have an O(n^2) loop that iterates over each ball and checks every other ball to see if it's radius overlaps?
What equations do I use to handle the ball to ball collisions? Physics 101
How does it effect the two balls speed x/y vectors? What is the resulting direction the two balls head off in? How do I apply this to each ball?
Handling the collision detection of the "walls" and the resulting vector changes were easy but I see more complications with ball-ball collisions. With walls I simply had to take the negative of the appropriate x or y vector and off it would go in the correct direction. With balls I don't think it is that way.
Some quick clarifications: for simplicity I'm ok with a perfectly elastic collision for now, also all my balls have the same mass right now, but I might change that in the future.
Edit: Resources I have found useful
2d Ball physics with vectors: 2-Dimensional Collisions Without Trigonometry.pdf
2d Ball collision detection example: Adding Collision Detection
Success!
I have the ball collision detection and response working great!
Relevant code:
Collision Detection:
for (int i = 0; i < ballCount; i++)
{
for (int j = i + 1; j < ballCount; j++)
{
if (balls[i].colliding(balls[j]))
{
balls[i].resolveCollision(balls[j]);
}
}
}
This will check for collisions between every ball but skip redundant checks (if you have to check if ball 1 collides with ball 2 then you don't need to check if ball 2 collides with ball 1. Also, it skips checking for collisions with itself).
Then, in my ball class I have my colliding() and resolveCollision() methods:
public boolean colliding(Ball ball)
{
float xd = position.getX() - ball.position.getX();
float yd = position.getY() - ball.position.getY();
float sumRadius = getRadius() + ball.getRadius();
float sqrRadius = sumRadius * sumRadius;
float distSqr = (xd * xd) + (yd * yd);
if (distSqr <= sqrRadius)
{
return true;
}
return false;
}
public void resolveCollision(Ball ball)
{
// get the mtd
Vector2d delta = (position.subtract(ball.position));
float d = delta.getLength();
// minimum translation distance to push balls apart after intersecting
Vector2d mtd = delta.multiply(((getRadius() + ball.getRadius())-d)/d);
// resolve intersection --
// inverse mass quantities
float im1 = 1 / getMass();
float im2 = 1 / ball.getMass();
// push-pull them apart based off their mass
position = position.add(mtd.multiply(im1 / (im1 + im2)));
ball.position = ball.position.subtract(mtd.multiply(im2 / (im1 + im2)));
// impact speed
Vector2d v = (this.velocity.subtract(ball.velocity));
float vn = v.dot(mtd.normalize());
// sphere intersecting but moving away from each other already
if (vn > 0.0f) return;
// collision impulse
float i = (-(1.0f + Constants.restitution) * vn) / (im1 + im2);
Vector2d impulse = mtd.normalize().multiply(i);
// change in momentum
this.velocity = this.velocity.add(impulse.multiply(im1));
ball.velocity = ball.velocity.subtract(impulse.multiply(im2));
}
Source Code: Complete source for ball to ball collider.
If anyone has some suggestions for how to improve this basic physics simulator let me know! One thing I have yet to add is angular momentum so the balls will roll more realistically. Any other suggestions? Leave a comment!
To detect whether two balls collide, just check whether the distance between their centers is less than two times the radius. To do a perfectly elastic collision between the balls, you only need to worry about the component of the velocity that is in the direction of the collision. The other component (tangent to the collision) will stay the same for both balls. You can get the collision components by creating a unit vector pointing in the direction from one ball to the other, then taking the dot product with the velocity vectors of the balls. You can then plug these components into a 1D perfectly elastic collision equation.
Wikipedia has a pretty good summary of the whole process. For balls of any mass, the new velocities can be calculated using the equations (where v1 and v2 are the velocities after the collision, and u1, u2 are from before):
If the balls have the same mass then the velocities are simply switched. Here's some code I wrote which does something similar:
void Simulation::collide(Storage::Iterator a, Storage::Iterator b)
{
// Check whether there actually was a collision
if (a == b)
return;
Vector collision = a.position() - b.position();
double distance = collision.length();
if (distance == 0.0) { // hack to avoid div by zero
collision = Vector(1.0, 0.0);
distance = 1.0;
}
if (distance > 1.0)
return;
// Get the components of the velocity vectors which are parallel to the collision.
// The perpendicular component remains the same for both fish
collision = collision / distance;
double aci = a.velocity().dot(collision);
double bci = b.velocity().dot(collision);
// Solve for the new velocities using the 1-dimensional elastic collision equations.
// Turns out it's really simple when the masses are the same.
double acf = bci;
double bcf = aci;
// Replace the collision velocity components with the new ones
a.velocity() += (acf - aci) * collision;
b.velocity() += (bcf - bci) * collision;
}
As for efficiency, Ryan Fox is right, you should consider dividing up the region into sections, then doing collision detection within each section. Keep in mind that balls can collide with other balls on the boundaries of a section, so this may make your code much more complicated. Efficiency probably won't matter until you have several hundred balls though. For bonus points, you can run each section on a different core, or split up the processing of collisions within each section.
Well, years ago I made the program like you presented here.
There is one hidden problem (or many, depends on point of view):
If the speed of the ball is too
high, you can miss the collision.
And also, almost in 100% cases your new speeds will be wrong. Well, not speeds, but positions. You have to calculate new speeds precisely in the correct place. Otherwise you just shift balls on some small "error" amount, which is available from the previous discrete step.
The solution is obvious: you have to split the timestep so, that first you shift to correct place, then collide, then shift for the rest of the time you have.
You should use space partitioning to solve this problem.
Read up on
Binary Space Partitioning
and
Quadtrees
As a clarification to the suggestion by Ryan Fox to split the screen into regions, and only checking for collisions within regions...
e.g. split the play area up into a grid of squares (which will will arbitrarily say are of 1 unit length per side), and check for collisions within each grid square.
That's absolutely the correct solution. The only problem with it (as another poster pointed out) is that collisions across boundaries are a problem.
The solution to this is to overlay a second grid at a 0.5 unit vertical and horizontal offset to the first one.
Then, any collisions that would be across boundaries in the first grid (and hence not detected) will be within grid squares in the second grid. As long as you keep track of the collisions you've already handled (as there is likely to be some overlap) you don't have to worry about handling edge cases. All collisions will be within a grid square on one of the grids.
A good way of reducing the number of collision checks is to split the screen into different sections. You then only compare each ball to the balls in the same section.
One thing I see here to optimize.
While I do agree that the balls hit when the distance is the sum of their radii one should never actually calculate this distance! Rather, calculate it's square and work with it that way. There's no reason for that expensive square root operation.
Also, once you have found a collision you have to continue to evaluate collisions until no more remain. The problem is that the first one might cause others that have to be resolved before you get an accurate picture. Consider what happens if the ball hits a ball at the edge? The second ball hits the edge and immediately rebounds into the first ball. If you bang into a pile of balls in the corner you could have quite a few collisions that have to be resolved before you can iterate the next cycle.
As for the O(n^2), all you can do is minimize the cost of rejecting ones that miss:
1) A ball that is not moving can't hit anything. If there are a reasonable number of balls lying around on the floor this could save a lot of tests. (Note that you must still check if something hit the stationary ball.)
2) Something that might be worth doing: Divide the screen into a number of zones but the lines should be fuzzy--balls at the edge of a zone are listed as being in all the relevant (could be 4) zones. I would use a 4x4 grid, store the zones as bits. If an AND of the zones of two balls zones returns zero, end of test.
3) As I mentioned, don't do the square root.
I found an excellent page with information on collision detection and response in 2D.
http://www.metanetsoftware.com/technique.html (web.archive.org)
They try to explain how it's done from an academic point of view. They start with the simple object-to-object collision detection, and move on to collision response and how to scale it up.
Edit: Updated link
You have two easy ways to do this. Jay has covered the accurate way of checking from the center of the ball.
The easier way is to use a rectangle bounding box, set the size of your box to be 80% the size of the ball, and you'll simulate collision pretty well.
Add a method to your ball class:
public Rectangle getBoundingRect()
{
int ballHeight = (int)Ball.Height * 0.80f;
int ballWidth = (int)Ball.Width * 0.80f;
int x = Ball.X - ballWidth / 2;
int y = Ball.Y - ballHeight / 2;
return new Rectangle(x,y,ballHeight,ballWidth);
}
Then, in your loop:
// Checks every ball against every other ball.
// For best results, split it into quadrants like Ryan suggested.
// I didn't do that for simplicity here.
for (int i = 0; i < balls.count; i++)
{
Rectangle r1 = balls[i].getBoundingRect();
for (int k = 0; k < balls.count; k++)
{
if (balls[i] != balls[k])
{
Rectangle r2 = balls[k].getBoundingRect();
if (r1.Intersects(r2))
{
// balls[i] collided with balls[k]
}
}
}
}
I see it hinted here and there, but you could also do a faster calculation first, like, compare the bounding boxes for overlap, and THEN do a radius-based overlap if that first test passes.
The addition/difference math is much faster for a bounding box than all the trig for the radius, and most times, the bounding box test will dismiss the possibility of a collision. But if you then re-test with trig, you're getting the accurate results that you're seeking.
Yes, it's two tests, but it will be faster overall.
This KineticModel is an implementation of the cited approach in Java.
I implemented this code in JavaScript using the HTML Canvas element, and it produced wonderful simulations at 60 frames per second. I started the simulation off with a collection of a dozen balls at random positions and velocities. I found that at higher velocities, a glancing collision between a small ball and a much larger one caused the small ball to appear to STICK to the edge of the larger ball, and moved up to around 90 degrees around the larger ball before separating. (I wonder if anyone else observed this behavior.)
Some logging of the calculations showed that the Minimum Translation Distance in these cases was not large enough to prevent the same balls from colliding in the very next time step. I did some experimenting and found that I could solve this problem by scaling up the MTD based on the relative velocities:
dot_velocity = ball_1.velocity.dot(ball_2.velocity);
mtd_factor = 1. + 0.5 * Math.abs(dot_velocity * Math.sin(collision_angle));
mtd.multplyScalar(mtd_factor);
I verified that before and after this fix, the total kinetic energy was conserved for every collision. The 0.5 value in the mtd_factor was the approximately the minumum value found to always cause the balls to separate after a collision.
Although this fix introduces a small amount of error in the exact physics of the system, the tradeoff is that now very fast balls can be simulated in a browser without decreasing the time step size.
Improving the solution to detect circle with circle collision detection given within the question:
float dx = circle1.x - circle2.x,
dy = circle1.y - circle2.y,
r = circle1.r + circle2.r;
return (dx * dx + dy * dy <= r * r);
It avoids the unnecessary "if with two returns" and the use of more variables than necessary.
After some trial and error, I used this document's method for 2D collisions : https://www.vobarian.com/collisions/2dcollisions2.pdf
(that OP linked to)
I applied this within a JavaScript program using p5js, and it works perfectly. I had previously attempted to use trigonometrical equations and while they do work for specific collisions, I could not find one that worked for every collision no matter the angle at the which it happened.
The method explained in this document uses no trigonometrical functions whatsoever, it's just plain vector operations, I recommend this to anyone trying to implement ball to ball collision, trigonometrical functions in my experience are hard to generalize. I asked a Physicist at my university to show me how to do it and he told me not to bother with trigonometrical functions and showed me a method that is analogous to the one linked in the document.
NB : My masses are all equal, but this can be generalised to different masses using the equations presented in the document.
Here's my code for calculating the resulting speed vectors after collision :
//you just need a ball object with a speed and position vector.
class TBall {
constructor(x, y, vx, vy) {
this.r = [x, y];
this.v = [0, 0];
}
}
//throw two balls into this function and it'll update their speed vectors
//if they collide, you need to call this in your main loop for every pair of
//balls.
function collision(ball1, ball2) {
n = [ (ball1.r)[0] - (ball2.r)[0], (ball1.r)[1] - (ball2.r)[1] ];
un = [n[0] / vecNorm(n), n[1] / vecNorm(n) ] ;
ut = [ -un[1], un[0] ];
v1n = dotProd(un, (ball1.v));
v1t = dotProd(ut, (ball1.v) );
v2n = dotProd(un, (ball2.v) );
v2t = dotProd(ut, (ball2.v) );
v1t_p = v1t; v2t_p = v2t;
v1n_p = v2n; v2n_p = v1n;
v1n_pvec = [v1n_p * un[0], v1n_p * un[1] ];
v1t_pvec = [v1t_p * ut[0], v1t_p * ut[1] ];
v2n_pvec = [v2n_p * un[0], v2n_p * un[1] ];
v2t_pvec = [v2t_p * ut[0], v2t_p * ut[1] ];
ball1.v = vecSum(v1n_pvec, v1t_pvec); ball2.v = vecSum(v2n_pvec, v2t_pvec);
}
I would consider using a quadtree if you have a large number of balls. For deciding the direction of bounce, just use simple conservation of energy formulas based on the collision normal. Elasticity, weight, and velocity would make it a bit more realistic.
Here is a simple example that supports mass.
private void CollideBalls(Transform ball1, Transform ball2, ref Vector3 vel1, ref Vector3 vel2, float radius1, float radius2)
{
var vec = ball1.position - ball2.position;
float dis = vec.magnitude;
if (dis < radius1 + radius2)
{
var n = vec.normalized;
ReflectVelocity(ref vel1, ref vel2, ballMass1, ballMass2, n);
var c = Vector3.Lerp(ball1.position, ball2.position, radius1 / (radius1 + radius2));
ball1.position = c + (n * radius1);
ball2.position = c - (n * radius2);
}
}
public static void ReflectVelocity(ref Vector3 vel1, ref Vector3 vel2, float mass1, float mass2, Vector3 intersectionNormal)
{
float velImpact1 = Vector3.Dot(vel1, intersectionNormal);
float velImpact2 = Vector3.Dot(vel2, intersectionNormal);
float totalMass = mass1 + mass2;
float massTransfure1 = mass1 / totalMass;
float massTransfure2 = mass2 / totalMass;
vel1 += ((velImpact2 * massTransfure2) - (velImpact1 * massTransfure2)) * intersectionNormal;
vel2 += ((velImpact1 * massTransfure1) - (velImpact2 * massTransfure1)) * intersectionNormal;
}

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