my question is related to python. I have a .txt file that contains some text. I want to have a code that prompts the user to enter a string of forbidden letters and then print the number of words in the file that don’t contain any of them. I wrote this one:
letters=raw_input("Please enter forbidden letters")
text=open("p.txt", "r").read().split()
for word in text:
for i in letters:
if not j in word:
print word
and also have this one:
letters=raw_input("Please enter forbidden letters")
text=open("p.txt", "r").read().split()
for word in text:
for i in letters:
for j in i:
if not j in word:
print word
But both codes give me words that don't contain each of characters and not all characters. for example if my file have "Hello good friends" and user entered "oh", this codes print:
Hello
good
friends
friends
But I expect just "friends" that don't have nor "o" not "h". and expect to have "friends" one time and not two times.
How can I fix my problem?
Put them in a set to remove dupes. Then for each word you want to print it only if all letters do not appear in the word. Something like this:
letters = raw_input("Please enter forbidden letters")
words = set(open("p.txt", "r").read().split())
for word in words:
if all(letter not in word for letter in letters):
print word
Related
the input
sentence = input("Please enter a sentence:")
the for loop (incorrect here)
for i in sentence:
print(sentence)
space_loc = sentence.index(" ")
for c in sentence:
print(space_loc)
for b in range(space_loc):
print("%")
confused about how to get the answer out.
You can try using concatenation of strings and slicing in this one.
sentence = input()
After taking the input simply store the length of your string
length = len(sentence)
Then iterate through every characters in the string and when you find a " ", break the string into two halves using slicing such that each half has one side of the string from " ". And then, join it by a "%" :-
for i in range(length):
if sentence[i]==" ":
sentence = sentence[:i] + "%" + sentence[i+1:]
Here, sentence[:i] is the part of string before the space and sentence[i+1:] is the part of string after the space.
One way of solving your query:
Code
sentence = input("Please enter a sentence:")
ls=sentence.split() #Creating a list of words present in sentence
new_sentence='%'.join(ls) #Joining the list with '%'
print(new_sentence)
Output
Please enter a sentence:Hello there coders!
Hello%there%coders!
EDIT
I do not understand how exactly you want to use the for loop here. If you just want to include a for loop (no restrictions), then you can do this:
Code
ls=[]
a=0
sentence = input("Please enter a sentence:")
for i in range(0,len(sentence)): # This loop will find the words in the sentence and store them in a list. Words are determined by checking the white space. Each space is replaced with '%'
if sentence[i]==' ':
ls.append(sentence[a:i])
a=i
ls.append('%')
ls.append(sentence[a:]) # This is to save the last word
ls1=[]
for i in ls: # Removing any white space inside the list
j=i.replace(' ','')
ls1.append(j)
print(''.join(ls1)) # Displaying final output
Again, your question is very open ended and this is just one way of using for loop to get the desired result!
I have text file from which I need to find the the average number of words per sentence and the average number of sentences per paragraph where a sentence is a sequence of words followed by either a full-stop, comma or exclamation mark, which in turn must be followed either by a quotation mark (so the sentence is the end of a quote or spoken utterance), or white space (space, tab or new-line character) and where a paragraph is any number of sentences followed by a blank line or by the end of the text without using regex.
I created a list of words i.e [".", ",", "!", "\n", "\t", " "] as my problem says and then iterated over the entire text file.
with open("/Users/abhishekabhishek/downloads/l.txt") as f:
text_lis = f.read()
# print(text_lis)
sentence_count = 0
ens_sentence = [".", ",", "!", "\n", "\t", " "]
for word in ens_sentence:
if word in text_lis:
sentence_count += 1
#print(sentence_count)
# sentence_count gave me the wrong output so I tried splitting it
# using text_lis.split(".") so that I can count the sentences
s = text_lis.split(".")
# the for average number of words per sentence
char_len = 0
for line in s:
words = line.split(" ")
for word in words:
char_len += len(word.split)
average_number_of words = char_len/len(words)
The actual output must be the average number of sentences and average number of words per sentence in that paragraph.The approach that I tried gave me the wrong the output because, there are certain words in the file which also use such punctuations like .' for ex Dr. etc and when I used text_lis.split() it also counts those words as the end of the sentence.
here is the sample text
I would love to try or hear the sample audio your app can produce. I do not want to purchase, because I've purchased so many apps that say they do something and do not deliver.
Can you please add audio samples with text you've converted? I'd love to see the end results.
Thanks!
THE AUTHOR.
I've tried this code but it didn't work:
word = input("Enter a word to be tested: ")
for character in word:
if character[0] == character.lower() and character[1:] != character.lower:
result = False
print(result)
Your first line is great, we'll just keep it.
word = input("Enter a word to be tested: ")
Now, we don't care about the first character, so let's see if the others are in lowercase, using str.islower().
result = word[1:].islower()
assert result, 'Your string wasn\'t in lowercase from the second char onwards'
text='I miss Wonderland #feeling sad #omg'
prefix=('#','#')
for line in text:
if line.startswith(prefix):
text=text.replace(line,'')
print(text)
The output should be:
'I miss Wonderland'
But my output is the original string with the prefix removed
So it seems that you do not in fact want to remove the whole "string" or "line", but rather the word? Then you'll want to split your string into words:
words = test.split(' ')
And now iterate through each element in words, performing your check on the first letter. Lastly, combine these elements back into one string:
result = ""
for word in words:
if !word.startswith(prefix):
result += (word + " ")
for line in text in your case will iterate over each character in the text, not each word. So when it gets to e.g., '#' in '#feeling', it will remove the #, but 'feeling' will remain because none of the other characters in that string start with/are '#' or '#'. You can confirm that your code is going character by character by doing:
for line in text:
print(line)
Try the following instead, which does the filtering in a single line:
text = 'I miss Wonderland #feeling sad #omg'
prefix = ('#','#')
words = text.split() # Split the text into a list of its individual words.
# Join only those words that don't start with prefix
print(' '.join([word for word in words if not word.startswith(prefix)]))
I was trying to code this on codecademy.com , but due to some bug it it shows the lesson is completed. so I can't take a hint.
Break It Down
Now let's take what we've learned so far and write a Pig Latin translator.
Pig Latin is a language game, where you move the first letter of the word to the end and add "ay." So "Python" becomes "ythonpay." To write a Pig Latin translator in Python, here are the steps we'll need to take:
Ask the user to input a word in English.
Make sure the user entered a valid word.
Convert the word from English to Pig Latin.
Display the translation result.
word=raw.input("Please enter a word: ")
if word.isalpha():
print "Thanks the word is valid"
else
print "Please enter a valid word"
x =len(word)
for m in range [0,x]
word=word[1]+word[2]
so far I entered a word and checked if it is valid.
I was trying a loop but I failed .. but I haven't been taught the loop in codeacademy so I guess I have to achieve the pyglatin word without it.
I can't think of anything please help
word = raw_input ("give me a word: ")
if len(word) > 3 and word.isalpha():
print word.lower() + " Pyg Latin: " + word[1:] + word[0] + "ay"
else:
print "Try nex time, by!"
try this. It should give lohaAay for Aloha what is accordance with definition PygLatin.
In line 3 is clue :
word.lower is printing lower cases original word.
then we print " Pyg Latin: "
and now stright to target:
word[1:] - original word without first letter
word[0] - it is only first letter
"ay" that our tail.
a = raw_input('tape :')
if a.isalpha():
print a[1:] + a[0] + 'ay'
This should work. It ask user to input an English word. It validates the word and confirms with a Thank you message (if the input is not an English word, it will post a message for that). It will then translates it to PygLatin by moving the first alphabet to last and adding ay in the end.
pyg = 'ay'
word = raw_input ("Type a word: ").lower()
if word.isalpha():
print "Thanks, the word is valid"
first=word [0]
new_word= word +first +pyg
new_word= new_word[1:len(new_word)]
print "The pyg_latin translation is: ",new_word
else:
print "The word is not a valid english word"