Cron job delete file by name like - cron

I need a script for delete file with name like:
MT11255-ML-LS-FLANNEL-ELEMENTAL-1-cropped-800x80064.jpg
my script now :
find /home/path_ke_folder/*-cropped-x.jpg -exec rm {}
but there's nothing happen

The pattern you gave doesn't match the file. That filename doesn't end in -cropped-x.jpg.
The shell will expand the wildcard, there's no need for find.
rm /home/path_ke_folder/*-cropped-*.jpg

Related

Simple Bash Script that recursively searches in subdirs for a certain string

i recently started learning linux because a ctf contest is coming in the next months. The problem that I struggle with is that i am trying to make a bash script that starts from a directory, checks if the content is a directory or other kind of file. If it is a file,image etc apply strings $f | grep -i 'abcdef', if it is a directory cd to that directory and start over. i have c++ experience and i understand the logic but i can't really make it work.I can't succesfully implement the loop that goes thru all the subdirectories. All help would be appreciated!
you don not need a loop for this implementation. The find command can do what you are looking after.
for instance:
find /home -type f -exec sh -c " strings {} | grep abcd " \;
explain:
/home is you base directory can be anything
-type f: means a regular file
-exec from the man page:
"Execute command; true if 0 status is returned. All
following arguments to find are taken to be arguments to
the command until an argument consisting of ;' is encountered. The string {}' is replaced by the current
file name being processed everywhere it occurs in the
arguments to the command, not just in arguments where it
is alone, as in some versions of find. Both of these
constructions might need to be escaped (with a `') or
quoted to protect them from expansion by the shell. See
the EXAMPLES section for examples of the use of the -exec
option. The specified command is run once for each
matched file. The command is executed in the starting
directory. There are unavoidable security problems
surrounding use of the -exec action; you should use the
-execdir option instead."
If you want to just find the string in a file and you do not HAVE TO first find a directory and then a file and then search, you can just simply find the text with grep.
Go to the the parent directory and execute :
grep -iR "abcd"
Or from any place,
grep -iR "abcd" /var/log/mylogs/
Suggesting a grep command on find filter results:
grep "abcd" $(find . -type f)

Linux find command explanation

Can someone explain me what does this command do and if I want to try the same thing using git, how should I modify this command?
find . -name CVS -print -exec rm -fr {} \;
This command looks in your current working directory for any directories or files named "CVS" and prints the full path. Then executes a forced recursive removal for each result returned by the find command.
Since there is no filetype present in the name, this command will remove any directory, within your current working directory, named CVS, including all subdirectories and files housed within.

Recursively find a directory and rename it in Shell Script

Im putting together a simple Shell script to run on a Linux Machine where I would:
1) Look for specific sub-directories within a main directory. These sub-dirs have a very specific naming convention (see below) and they are always 2 -max depth below the main directory.
2) Rename those sub-dirs to PART of its original name.
For example,
The sub directories are named:
andrew-11111
andrew-11112
andrew-11113
andrew-11114
The path to get to these sub dirs would look something like this:
myphotos/sailing/photos/andrew-1111
myphotos/sailing/photos/andrew-1112
myphotos/biking/photos/andrew-1113
myphotos/hiking/photos/andrew-1114
Id like take out the 'andrew-' from each of these sub dirs:
myphotos/sailing/photos/1111
myphotos/sailing/photos/1112
myphotos/biking/photos/1113
myphotos/hiking/photos/1114
Ive gotten as far as "finding" the sub dirs and listing them. I also understand how to copy and rename in command line. But putting it together at my level of shell scripting knowledge has been taking much more time than I can afford. Just a disclaimer, I am more than willing to learn, and have written a handful of shell scripts, but still new to this. Any help or examples are much appreciated!
Use wildcards to match the files in the nested directories
You can use bash parameter expansion operators to manipulate the filenames.
for file in myphotos/*/photos/*; do
name=${file##*/} # remove everything up to last /
dir=${file%/*} # remove everything from last /
newname=${name##*-} # remove everything up to last -
mv "$file" "$dir/$newname"
done
If you have the perl-based rename command, you can do:
rename 's#[^/]*-##' myphotos/*/photos/*
You can do it with this one-liner:
find -type d -name andrew\* -exec sh -c 'mv {} $(dirname {})/$(basename {} | cut -d"-" -f2)' \;
Explanation:
-type d find only directories
-name andrew\* self-explaining, you have to escape the * though
-exec sh -c '...' execute it in a subshell, so you can do the command substitution ($(...)) without problems
mv {} the {} holds whatever find finds
dirname gives you the path to a directory (try it out with a random path, my english is too bad now to explain better)
basename gives you the last directory of a given path
cut -d"-" -f2 use cut to cut off "andrew-". For this set the delimiter to - and select the field number 2

How can i get the last word of a string linux

For example:
im in this directory, for example, "home/linux/downloads/dir1" and I want to show the files in another directory.
I use: find /home/linux/files/
This command shows the files of the previous path like this:
/home/linux/files/file1.txt
/home/linux/files/file2.txt
using cut -d "/" -f4 i get file1.txt but if you change the path, this command no longer serves me.
There is a command that allows me to always get the last word of a string separated by /?
basename is what you want, because you're asking about paths. In Python it's os.path.basename().
You can use find's -exec for this:
find <directory> -exec basename {} \;
This will work in any directory. -exec tells find to execute the command for every file found. Here the command is basename, which returns only the file name without directory prefixes. Hope it helps.
Something like this:
path = '/home/linux/files/dir1'
lastdir = path.split('/')[-1]
yields 'dir1'

Rename file in Linux if file exist in a single command

There is need that I want to rename file in Linux if file exist in a single command.
Suppose I want to search test.text file and I want to replace it with test.text.bak then I fire the following command
find / -name test.text
if it exist then I fire the command
mv test.text test.text.bak
In this scenario I am executing two commands but I want this should be happen in single command.
Thanks
Just:
mv test.text test.test.bak
If the file doesn't exist nothing will be renamed.
To supress the error message, when no file exits, use that syntax:
mv test.text test.test.bak 2>/dev/null
If you want to find test.txt somewhere in a subdirectory of dir and move it, try
find dir -name test.txt -exec mv {} {}.bak \;
This will move all files matching the conditions. If you want to traverse from the current directory, use . as the directory instead of dir.
Technically, this will spawn a separate command in a separate process for each file matched by find, but it's "one command" in the sense that you are using find as the only command you are actually starting yourself. (Think of find as a crude programming language if you will.)
for FILE in `find . -name test.test 2>/dev/null`; do mv $FILE $FILE.bak; done
This will search all the files named "test.test" in current as well as in child direcroties and then rename each file to .bak

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